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NEET • BIOLOGY • PRINCIPLE OF INHERITANCE AND VARIATION

Principle of inheritance and variation practice · Mixed difficulty

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301 Hard
301 of 365
Application +4 | -1
What is the probability of production of dwarf offsprings in a cross between two heterozygous tall pea plants.
View answer and explanation
Correct option: C
0.25
Option C (0.25) is correct because in a cross between two heterozygous tall pea plants (Tt x Tt), the probability of getting a dwarf offspring (tt) is 1/4 or 0.25.
302 Easy
302 of 365
Remembering +4 | -1
Frequency of recombination between gene pairs on same chromosome as a measure of the distance
between genes to map their position on chromosome, was used for the first time by
View answer and explanation
Correct option: A
Alfred Sturtevant
Option A (Alfred Sturtevant) is correct because Alfred Sturtevant was the first to use recombination frequencies to map gene positions on chromosomes.
303 Easy
303 of 365
Remembering +4 | -1
Human females have
View answer and explanation
Correct option: A
22 pairs of autosomes and one pair of sex chromosome
Option A (22 pairs of autosomes and one pair of sex chromosome) is correct because human females have 22 pairs of autosomes and one pair of sex chromosomes (XX).
304 Medium
304 of 365
Understanding +4 | -1
Pedigree analysis indicated that Mendel’s principal are also applicable to …A… genetics with some modifications find out like …B… inheritance, sex linked inheritance and others.
Choose the correct option for AA and BB
View answer and explanation
Correct option: C
A-human; B-quantitative
The correct answer is C (A-human; B-quantitative) because pedigree analysis applies Mendel's principles to human genetics with modifications for quantitative inheritance.
305 Medium
305 of 365
Application +4 | -1
Probability of genotype TTrr in F2{\mathrm{F}_2}-generation of a dihybrid cross is
View answer and explanation
Correct option: A
116\frac{1}{{16}}
Option A (116\frac{1}{{16}}) is correct because in the F2 generation of a dihybrid cross, the probability of obtaining the TTrr genotype is 1/16.
306 Hard
306 of 365
Application +4 | -1
An individual homozygous for genes cd\text{cd} is crossed with wild type and F1F_1 crossed back with
the double recessive. The appearance of the offspring is as follows.
++→903cd→897+d→98c+→102\begin{array}{cccccccccccccccccccc} { + + }& \to &{903} \\ {{\text{cd}}}& \to &{897} \\ { + {\text{d}}}& \to &{98} \\ {{\text{c}} + }& \to &{102} \end{array}
The distance between the genes c\text{c} and d\text{d} is
View answer and explanation
Correct option: D
10 map units
Option D (10 map units) is correct because the recombination frequency is calculated as (number of recombinants / total offspring) * 100, which in this case is ((98 + 102) / (903 + 897 + 98 + 102)) * 100 = 10.
307 Easy
307 of 365
Understanding +4 | -1
Which of the following statement is true for colour blindness?
View answer and explanation
Correct option: C
The son of the carrier woman has 50%50\% chances of being colour blind
Option C (The son of the carrier woman has 50%50\% chances of being colour blind) is correct because color blindness is an X-linked recessive trait, and a carrier mother has a 50% chance of passing the affected X chromosome to her son.
308 Easy
308 of 365
Understanding +4 | -1
Blood grouping is the example of
View answer and explanation
Correct option: C
Both (1) and (2)
Option C (Both (1) and (2)) is correct because blood grouping demonstrates both multiple alleles (A, B, O) and codominance (A and B are both expressed in AB blood type).
309 Medium
309 of 365
Remembering +4 | -1
Jumping genes in maize were discovered by
View answer and explanation
Correct option: B
Barbara McClintock
Option B (Barbara McClintock) is correct because Barbara McClintock discovered jumping genes (transposons) in maize.
310 Medium
310 of 365
Remembering +4 | -1
Mendelism was rediscovered by
I. Morgan
II. De Vries
III. Correns
IV. Tschermark
Choose the correct option
View answer and explanation
Correct option: C
II, III and IV
Option C (II, III and IV) is correct because De Vries, Correns, and Tschermark independently rediscovered Mendel's work.
311 Medium
311 of 365
Remembering +4 | -1
Linkage group in E .coli is/are
View answer and explanation
Correct option: C
1
Option C (1) is correct because E. coli has a single, circular chromosome, thus only one linkage group.
312 Medium
312 of 365
Remembering +4 | -1
Emasculation is the removal of
View answer and explanation
Correct option: B
Anthers before dehiscence
The correct answer is B (Anthers before dehiscence) because emasculation involves removing the anthers from a flower before they release pollen (dehiscence) to prevent self-pollination.
313 Medium
313 of 365
Analyzing +4 | -1
Choose the incorrect statement regarding F2F_2 generation of Mendelian dibybrid cross.
View answer and explanation
Correct option: C
Heterozygous tall plants are present in 37.5%
Option A (Tall plants and round seeds are present in 1 : 1 ratio) is incorrect. The correct ratio is 3:1.
314 Medium
314 of 365
Application +4 | -1
In fruit flies, dumpy wings are shorter and broader than normal wings. The allele for normal wings (D) is dominant to the allele for dumpy wings (d). Seventy five normal-winged and twenty five dumpy-winged flies. The genotype of parents would be
View answer and explanation
Correct option: C
Dd and Dd
Option C (Dd and Dd) is correct because a cross between two heterozygotes will produce a 3:1 phenotypic ratio, which matches the given data.
315 Easy
315 of 365
Application +4 | -1
In the previous question, find out the chances of fifth child to be albino
View answer and explanation
Correct option: B
1 in 4
Option B (1 in 4) is correct because if both parents are heterozygous carriers for albinism (Aa), the probability of having an albino child (aa) is 1/4.
316 Medium
316 of 365
Application +4 | -1
The total number of progeny obtained through dihybrid cross of Mendel is 1280 in F2{\mathrm{F}_2}-generation. How many are recombinants?
View answer and explanation
Correct option: C
480
Option C (480) is correct because in a dihybrid cross, the recombinant phenotypes occur in 6/16 of the progeny. Therefore, with a total of 1280 progeny, the number of recombinants is (6/16) * 1280 = 480.
317 Medium
317 of 365
Remembering +4 | -1
Who clearly proved and define linkage?
View answer and explanation
Correct option: A
Morgan
Option A (Morgan) is correct because T.H. Morgan and his colleagues provided experimental evidence and clearly defined the concept of linkage through their work with Drosophila.
318 Hard
318 of 365
Understanding +4 | -1
Assertion (A): In a person with AB-blood group, the erythrocytes carry both A and B antigen on their surface.

Reason (R): The alleles IA\mathrm{I}^{\mathrm{A}} and IB\mathrm{I}^{\mathrm{B}} that produce AB blood group are codominant and both are expressed.
View answer and explanation
Correct option: A
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Option A (Both (A) & (R) are true and the (R) is the correct explanation of the (A)) is correct because both the assertion and the reason are true, and the reason correctly explains why AB blood group individuals express both A and B antigens.
319 Easy
319 of 365
Understanding +4 | -1
Sexual reproducation leads to
View answer and explanation
Correct option: A
Genetic recombination
Option A (Genetic recombination) is correct because sexual reproduction involves the fusion of gametes, leading to the shuffling of genes and creating new combinations of alleles.
320 Medium
320 of 365
Application +4 | -1
A pure tall and a pure dwarf plant were crossed to produced offsprings. Offsprings were self crossed, then find out the ratio between true breeding tall to true breeding dwarf?
View answer and explanation
Correct option: A
1:11\mathrm{ }:\mathrm{ }1
Option A (1:11\mathrm{ }:\mathrm{ }1) is correct because after selfing the F1 generation (Tt), the F2 generation will have a 1:2:1 genotypic ratio (TT:Tt:tt), resulting in a 1:1 ratio of true-breeding tall (TT) to true-breeding dwarf (tt).
321 Medium
321 of 365
Application +4 | -1
A marriage between normal visioned man and colourblind woman will produce, which of the following types of offspring’s?
View answer and explanation
Correct option: B
Colourblind sons and carrier daughters
Option B (Colourblind sons and carrier daughters) is correct because the colourblind woman (XcXc) can only pass on the Xc allele, and the normal man (XY) passes on either X or Y, resulting in colourblind sons (XcY) and carrier daughters (XXc).
322 Easy
322 of 365
Understanding +4 | -1
In case of incomplete dominance, what will be the phenotypic ratio of F2{F_2}generation?
View answer and explanation
Correct option: B
1:2:11\mathrm{ }:\mathrm{ }2\mathrm{ }:\mathrm{ }1
Option B (1:2:11\mathrm{ }:\mathrm{ }2\mathrm{ }:\mathrm{ }1) is correct because in incomplete dominance, the heterozygous genotype results in a distinct phenotype, leading to a 1:2:1 phenotypic ratio in the F2 generation.
323 Easy
323 of 365
Remembering +4 | -1
How many pairs of contrasting characters in pea pod were chosen by Mendel?
View answer and explanation
Correct option: D
2
Option D (2) is correct because Mendel chose two contrasting characters for pea pod: shape and color.
324 Medium
324 of 365
Understanding +4 | -1
Incomplete linkage is …A… . Complete linkage is …B… . Choose correct option for A and B
View answer and explanation
Correct option: A
A-common, B-rare
Option A (A-common, B-rare) is correct because incomplete linkage allows for some recombination, making it more common, while complete linkage prevents recombination, making it rare.
325 Medium
325 of 365
Understanding +4 | -1
The phenotype of F1 hybrid resemble both of the parents in
View answer and explanation
Correct option: A
Co-dominance
Option A (Co-dominance) is correct because in co-dominance, both alleles are expressed equally in the heterozygote, resulting in a phenotype that resembles both parents.
326 Medium
326 of 365
Remembering +4 | -1
Principle or laws of inheritance were enunciated by
View answer and explanation
Correct option: A
Mendel
Option A (Mendel) is correct because Gregor Mendel is credited with formulating the principles or laws of inheritance through his experiments with pea plants.
327 Medium
327 of 365
Application +4 | -1
A plant heterozygous for three allelic pairs, undergoes selfing, then how many genotypes regarding these alleles will be produced in F1F_1 generation?
View answer and explanation
Correct option: D
27
Option D (27) is correct because for n heterozygous allelic pairs, the number of genotypes in the F1 generation after selfing is 3n3^n, and in this case, 33=273^3 = 27.
328 Medium
328 of 365
Remembering +4 | -1
Mendel was a
View answer and explanation
Correct option: B
Austrian monk
Option B (Austrian monk) is correct because Gregor Mendel was an Austrian monk known for his work on genetics.
329 Easy
329 of 365
Remembering +4 | -1
Which one of the following was the rediscoverer of Mendel’s work?
View answer and explanation
Correct option: C
Correns
Option C is correct because Carl Correns was one of the three scientists who independently rediscovered Mendel's work in 1900.
330 Medium
330 of 365
Application +4 | -1
A normal woman, whose father was colour blind is married to a normal man. The sons would be
View answer and explanation
Correct option: B
50 % colour blind
Option B (50 % colour blind) is correct because the woman is a carrier, and there's a 50% chance her sons will inherit the colorblindness allele from her.
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