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NEET • BIOLOGY • PRINCIPLE OF INHERITANCE AND VARIATION

Principle of inheritance and variation practice · Mixed difficulty

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271 Medium
271 of 365
Analyzing +4 | -1
A child has heterozygous allele for blood group A. What can be most possible interpretation w.r.t. blood group of his/her parents?
A) Both the parents have same genotype IA  IO{\mathrm{I}^\mathrm{A}}\,\,{\mathrm{I}^\mathrm{O}} and IA  IO{\mathrm{I}^\mathrm{A}}\,\,{\mathrm{I}^\mathrm{O}}
B) Both the parents are of blood group O
C) One of the parent may have blood group AB while other have blood O.
View answer and explanation
Correct option: B
A and C
Option B (A and C) is correct because both scenarios A and C can result in a child with a heterozygous blood group A (IA IO{\mathrm{I}^\mathrm{A}}\,{\mathrm{I}^\mathrm{O}}).
272 Hard
272 of 365
Understanding +4 | -1
Genetic variation cannot be effectively brought about by
View answer and explanation
Correct option: D
Amplification
Option D (Amplification) is correct because amplification refers to increasing the number of copies of a gene, which doesn't inherently introduce new genetic variation.
273 Easy
273 of 365
Application +4 | -1
A gene locus has two alleles A, a. If the frequency of dominant allele A is 0.4, then what will be the frequency of homozygous dominant, heterozygous and homozygous recessive individuals in the population?
View answer and explanation
Correct option: C
0.16 (AA); 0.48 (Aa); 0.36 (aa)
Option C (0.16 (AA); 0.48 (Aa); 0.36 (aa)) is correct because it correctly applies the Hardy-Weinberg equilibrium to calculate the frequencies of homozygous dominant, heterozygous, and homozygous recessive individuals.
274 Easy
274 of 365
Understanding +4 | -1
Which of the following blood groups’ person can not donate blood to other?
View answer and explanation
Correct option: A
AB blood group
Option A (AB blood group) is correct because individuals with AB blood group have both A and B antigens on their red blood cells and therefore cannot donate to individuals with A, B, or O blood groups.
275 Medium
275 of 365
Analyzing +4 | -1
The genotypes of a plant variety were TtHh, Tthh, ttHh and tthh, where T = tallness and H = hairy stem. Which one of the following crosses would produce progeny giving a phenotypic ratio approximately 1:1:1:11: 1: 1: 1?
View answer and explanation
Correct option: D
TtHh ×\times tthh
Option D (TtHh ×\times tthh) is correct because this cross represents a dihybrid test cross, which typically results in a 1:1:1:1 phenotypic ratio.
276 Medium
276 of 365
Understanding +4 | -1
Which of the following pairs of features is a good example of polygenic inheritance?
View answer and explanation
Correct option: A
Human height and skin colour
The correct answer is A (Human height and skin colour) because both are influenced by multiple genes, showing continuous variation characteristic of polygenic inheritance.
277 Medium
277 of 365
Application +4 | -1
In a plant, red fruit (R) dominant over yellow fruit (r) and tallness (T) is dominant over shortness (t). If a plant with RRTT genotype is crossed with a plant that is rrtt. Then
View answer and explanation
Correct option: D
All of the offsprings will be tall with red fruits
Option D (All of the offsprings will be tall with red fruits) is correct because when RRTT is crossed with rrtt, all offspring will be RrTt, which expresses the dominant phenotypes of tallness and red fruit.
278 Medium
278 of 365
Understanding +4 | -1
After examining the blood groups of husband and wife, the doctor advised them not to have more than one child, the blood group of the couple are likely to be
View answer and explanation
Correct option: B
Female Rh−andmaleRh+\mathrm{R}{\mathrm{h}^ - }\mathrm{and male R}{\mathrm{h}^ + }
Option B (Female Rh−andmaleRh+\mathrm{R}{\mathrm{h}^ - }\mathrm{and male R}{\mathrm{h}^ + }) is correct because it can lead to erythroblastosis fetalis in the fetus during the second pregnancy.
279 Medium
279 of 365
Understanding +4 | -1
In blood group typing in human, if an allele contributed by one parent is IA{\mathrm{I}^\mathrm{A}}and an allele contributed by the other parent is i, the resulting blood group of the offspring will be
View answer and explanation
Correct option: A
A
Option A (A) is correct because the genotype IA{\mathrm{I}^\mathrm{A}}i results in blood type A, as the IA{\mathrm{I}^\mathrm{A}} allele is dominant over the i allele.
280 Easy
280 of 365
Remembering +4 | -1
Chromosomes are made up of
View answer and explanation
Correct option: C
DNA and histone
Option C (DNA and histone) is correct because chromosomes are primarily composed of DNA tightly wound around histone proteins.
281 Medium
281 of 365
Remembering +4 | -1
The nucleoprotein structures that occur at the ends of the chromosomes are
View answer and explanation
Correct option: B
Telomeres
Option B (Telomeres) is correct because telomeres are specialized structures at the ends of chromosomes that protect them from degradation and fusion.
282 Medium
282 of 365
Remembering +4 | -1
Chromosome is made up of
View answer and explanation
Correct option: C
DNA +histone
Option C (DNA +histone) is correct because chromosomes are composed of DNA tightly packed and organized around histone proteins.
283 Hard
283 of 365
Analyzing +4 | -1
Assertion (A): Gynacomastia is observed in Turner's syndrome.

Reason (R): Such a disorder is caused due to the presence of extra copy of X-chromosome.
View answer and explanation
Correct option: D
Both (A) and (R) are false
Option D (Both (A) and (R) are false) is correct because Gynaecomastia is observed in Klinefelter's syndrome, not Turner's syndrome, and is caused by an extra X chromosome in males (XXY).
284 Medium
284 of 365
Analyzing +4 | -1
A man and a woman, who do not show any apparent sign of a certain inherited disease, have seven children (two daughter and five sons). Three of the sons suffer from the given disease but none of the daughters are affected. Which of the following mode of inheritance do you suggest for this disease?
View answer and explanation
Correct option: D
Sex –linked recessive
Option C (2) is correct. It is a trihybrid cross (Aa, Bb, Cc) and 8 types of gametes are formed (23 = 8).
285 Medium
285 of 365
Understanding +4 | -1
Multiple allele can be manifested only when there is the study of
View answer and explanation
Correct option: C
Population
Option C (Population) is correct because multiple alleles can only be observed and studied at the population level, not in individual organisms.
286 Medium
286 of 365
Remembering +4 | -1
Genes for cytoplasmic male sterility in plants are generally located in
View answer and explanation
Correct option: A
Mitochondrial genome
Option A (Mitochondrial genome) is correct because genes for cytoplasmic male sterility are often located in the mitochondrial genome in plants.
287 Medium
287 of 365
Understanding +4 | -1
Select the correct statement from the ones given below with respect to dihybrid cross.
View answer and explanation
Correct option: D
Tightly linked genes on the same chromosome show very few recombinations
Option D (Tightly linked genes on the same chromosome show very few recombinations) is correct because tightly linked genes are physically close together, making them less likely to be separated during crossing over.
288 Medium
288 of 365
Remembering +4 | -1
Two crosses between the same pair of genotypes or phenotypes, in which the sources of the gametes are reversed in one cross, is known as
View answer and explanation
Correct option: D
Reciprocal cross
Option D (Reciprocal cross) is correct because a reciprocal cross involves reversing the sources of gametes to determine the role of parental sex on inheritance patterns.
289 Medium
289 of 365
Remembering +4 | -1
Ishihara chart is used to detect
View answer and explanation
Correct option: C
Colour blindness
Option C (Colour blindness) is correct because the Ishihara chart is specifically designed to detect deficiencies in color vision, indicating color blindness.
290 Medium
290 of 365
Application +4 | -1
What will be the linkage strength present between two genes A & B, which are 6 cM far from each other on a chromosome?
View answer and explanation
Correct option: C
0.94
Option C (0.94) is correct because linkage strength is calculated as 1 - recombination frequency, and 6 cM corresponds to a recombination frequency of 0.06.
291 Medium
291 of 365
Analyzing +4 | -1
Assertion : Sickle-cell anaemia is a genetically
determined disorder affecting many new born
babies.

Reason : It is caused by heterozygosity for
allele HbsH{b^s}
producing a single amino acid
substitution in the a-chain of the normal
haemoglobin molecule determined by allele HbAH{b^A}
.
View answer and explanation
Correct option: C
If Assertion is true but Reason is false
Option C (Assertion is true but Reason is false) is correct because sickle-cell anemia is caused by homozygosity for the Hb^s allele, not heterozygosity.
292 Hard
292 of 365
Understanding +4 | -1
Mendel work later formulated into laws of
I. Linkage
II. Segregation
III. Incomplete dominance
IV. Independent assortment
Choose the correct option
View answer and explanation
Correct option: B
II and IV
Option B (II and IV) is correct because Mendel's work was formulated into the laws of segregation and independent assortment.
293 Medium
293 of 365
Application +4 | -1
In which cross will you get most pink flowers?
View answer and explanation
Correct option: D
Red ×\timeswhite
Option D (Red ×\timeswhite) is correct because it will produce 100% pink flowers, assuming incomplete dominance.
294 Easy
294 of 365
Understanding +4 | -1
In Mendel's experiment the study of inheritance of one gene (cross between tall and dwarf plant) in F2\mathrm{F}_2 generation showed :
View answer and explanation
Correct option: B
75%75 \% tall and 25%25 \% dwarf plants in F2\mathrm{F}_2 progeny
Option B (75%75 \% tall and 25%25 \% dwarf plants in F2\mathrm{F}_2 progeny) is correct because in a monohybrid cross with a tall (TT) and dwarf (tt) plant, the F2 generation shows a 3:1 phenotypic ratio, resulting in 75% tall and 25% dwarf plants.
295 Medium
295 of 365
Understanding +4 | -1
Cytoplasmic inheritance always shows
View answer and explanation
Correct option: B
Maternal characters
Option B (Maternal characters) is correct because cytoplasmic inheritance involves genes present in organelles like mitochondria and chloroplasts, which are primarily inherited from the mother.
296 Easy
296 of 365
Application +4 | -1
Total number of progeny of a dihybrid cross is 640 in F2F_2 generation. How many are recombinants:
View answer and explanation
Correct option: C
240
Option C (240) is correct because in a dihybrid cross, the recombinant phenotypes occur in 6/16 of the progeny. Therefore, with a total of 640 progeny, the number of recombinants is (6/16) * 640 = 240.
297 Easy
297 of 365
Understanding +4 | -1
A person is suffering from disease phenylketonuria, which is an autosomal recessive disease. Which of these is lacking in the person?
View answer and explanation
Correct option: B
Phenylalanine hydroxylase
Option B (Phenylalanine hydroxylase) is correct because phenylketonuria is caused by a deficiency in this enzyme, which is needed to convert phenylalanine to tyrosine.
298 Medium
298 of 365
Application +4 | -1
In Snapdragon, pure line tall plant with red flower was crossed with dwarf and white flowered plant; F1F_1 was test crossed to obtain F2F_2. What is the probability of getting progeny with dominant parental traits?
View answer and explanation
Correct option: D
0%0 \%
Option D (0%0 \%) is correct because a test cross of F1 (dihybrid) will not produce progeny with dominant parental traits if the genes are completely linked.
299 Medium
299 of 365
Remembering +4 | -1
Incomplete dominance is seen in?
View answer and explanation
Correct option: A
dog flower
Option A (dog flower) is correct because incomplete dominance is commonly observed in snapdragons (dog flower), where a heterozygous genotype results in a pink phenotype.
300 Medium
300 of 365
Remembering +4 | -1
Linkage group is
View answer and explanation
Correct option: A
Linearly arranged group of linked gene
Option A (Linearly arranged group of linked gene) is correct because a linkage group consists of genes that are physically located on the same chromosome and tend to be inherited together.
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