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NEET • BIOLOGY • MOLECULAR BASIS OF INHERITANCE
Molecular basis of inheritance practice · Medium
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181
Medium
181 of 201
Understanding
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In Meselson and Stahl’s experiment using E. coliculture, the duration between the appearance of equal amount of light and hybrid DNA was
I. Two generation, II. 40 minutes, III. 20 minutes, IV. Three generation
Choose the correct option for given statement of question.
I. Two generation, II. 40 minutes, III. 20 minutes, IV. Three generation
Choose the correct option for given statement of question.
View answer and explanation
Correct option: A
I and II
Option A (I and II) is correct because the appearance of equal amounts of light and hybrid DNA occurs after one generation (20 minutes), and the second generation starts showing light DNA.
182
Medium
182 of 201
Analyzing
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An E. coli cell with a mutated lac-z gene, due to which it is unable to synthesise the corresponding enzyme, is still growing in the nutrient medium. It indicates that medium is supplemented with energy source/enzyme
View answer and explanation
Correct option: B
Glucose
Option B (Glucose) is correct because if the mutated E. coli cannot synthesize β-galactosidase, it can still grow if provided with an alternative energy source like glucose.
183
Medium
183 of 201
Remembering
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In a hair pin model of RNA, which nitrogen base is present at the short end?
View answer and explanation
Correct option: B
Guanine
Option B (Guanine) is correct because Guanine is known to form stable base pairs in RNA hairpin loops.
184
Medium
184 of 201
Application
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If the sequence of bases in one strand of DNA is ATGCATGCA, what would be the sequence of bases on complementary strand?
View answer and explanation
Correct option: C
TACGTACGT
Option C (TACGTACGT) is correct because DNA base pairing rules state that Adenine (A) pairs with Thymine (T), and Guanine (G) pairs with Cytosine (C).
185
Medium
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Understanding
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Choose the correct statements about biochemical characterisation of transforming principle in Griffith's experiment.
I. It was done by Oswald Avery, Colin MacLeod and Maclyn McCarty.
II. Scientists purified biochemicals (proteins, DNA, RNA, etc.) from heat killed S-cell.
III. It was seen that DNA alone from S-bacteria caused R-bacteria to become transformed.
IV. Proteases and RNases did not affect transformation.
I. It was done by Oswald Avery, Colin MacLeod and Maclyn McCarty.
II. Scientists purified biochemicals (proteins, DNA, RNA, etc.) from heat killed S-cell.
III. It was seen that DNA alone from S-bacteria caused R-bacteria to become transformed.
IV. Proteases and RNases did not affect transformation.
View answer and explanation
Correct option: D
All statements are correct
Option D (All statements are correct) is correct because all the statements accurately describe the biochemical characterization of the transforming principle in Griffith's experiment.
186
Medium
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Remembering
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In his bacteriophage experiments, Hershey and Chase demonstrated that DNA is genetic material in
View answer and explanation
Correct option: C
bacteriophage
Option C ( bacteriophage) is correct because Hershey and Chase used T2 bacteriophage in their experiments.
187
Medium
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Application
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If the DNA has 20% Adenine, then what is the % of Guanine?
View answer and explanation
Correct option: B
Option B () is correct because in DNA, A=T and G=C. If Adenine is 20%, Thymine is also 20%. The remaining 60% is split equally between Guanine and Cytosine.
188
Medium
188 of 201
Understanding
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Number of ester bonds in a helics of B-DNA?
View answer and explanation
Correct option: C
18
Option C (18) is correct because each nucleotide has one ester bond, and there are approximately 9-10 base pairs per turn in B-DNA, with each base pair having two ester bonds on the backbone, hence around 18.
189
Medium
189 of 201
Remembering
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All of the given are stop codons, except
View answer and explanation
Correct option: B
AUG
Option B (AUG) is correct because AUG is the start codon, while the others are stop codons.
190
Medium
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Remembering
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DNA fingerprinting involves identifying differences in some specific regions in DNA sequence, called as
View answer and explanation
Correct option: D
Repetitive DNA
Option D is correct because DNA fingerprinting relies on identifying differences in repetitive DNA sequences, also known as VNTRs or microsatellites.
191
Medium
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Analyzing
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While analysing the DNA of an organism a total number of
5386 nucleotides were found out of which the proportion of
different bases were Adenine = 29% Guanine = 17% Cytosine
= 32%, Thymine = 17%. Considering the Chargaffs rule it can
be concluded that
5386 nucleotides were found out of which the proportion of
different bases were Adenine = 29% Guanine = 17% Cytosine
= 32%, Thymine = 17%. Considering the Chargaffs rule it can
be concluded that
View answer and explanation
Correct option: B
it is single-stranded DNA
Option B (it is single-stranded DNA) is correct because Chargaff's rules (A=T and G=C) do not hold true for the given nucleotide proportions, indicating that it is single-stranded DNA.
192
Medium
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Understanding
+4 | -1
In lac operon, when repressor protein binds to operator then
View answer and explanation
Correct option: B
RNA polymerase cannot bind to the promoter
Option B (RNA polymerase cannot bind to the promoter) is correct because the repressor protein physically blocks RNA polymerase from binding to the promoter region.
193
Medium
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Remembering
+4 | -1
The scientists involved in discovery of DNA as chemical basis of heredity were
View answer and explanation
Correct option: C
Avery, Mac Leod and Mc Carty
Option C (Avery, Mac Leod and Mc Carty) is correct because they provided experimental evidence that DNA is the substance that causes bacterial transformation, demonstrating it as the chemical basis of heredity.
194
Medium
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Understanding
+4 | -1
Chemically RNA is __(i)__ reactive and __(ii)__ stable as compared to DNA.
View answer and explanation
Correct option: C
i – More, ii – less
Option C (i – More, ii – less) is correct because RNA is more reactive due to the presence of the 2'-OH group and less stable compared to DNA.
195
Medium
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Understanding
+4 | -1
Which of the following process represents
the dominance of RNA world?
the dominance of RNA world?
View answer and explanation
Correct option: C
Splicing
Option C (Splicing) is correct because splicing, the removal of introns from pre-mRNA, is a process that highlights the catalytic role of RNA, supporting the RNA world hypothesis.
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196
Medium
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Remembering
+4 | -1
In Hershey and Chase experiment the viral DNA can be labelled with?
View answer and explanation
Correct option: A
Option A () is correct because DNA contains phosphorus, and is a radioactive isotope of phosphorus that can be used to label DNA.
197
Medium
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Application
+4 | -1
There is a tRNA with anticodon UAC. If we apply the wobble hypothesis, then this tRNA can decode which
of these codons?
of these codons?
View answer and explanation
Correct option: C
It can decode AUG but not AUC, AUU and AUA
Option C (It can decode AUG but not AUC, AUU and AUA) is correct because, according to the wobble hypothesis, UAC can only decode AUG. The wobble base is the 3' base of the codon and the 5' base of the anticodon.
198
Medium
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Application
+4 | -1
If there are 999 bases in an RNA that codes for a protein with 333 amino acids, and the base at position 901 is deleted such that the length of the RNA becomes 998 bases, how many codons will be altered?
View answer and explanation
Correct option: D
33
Option D (33) is correct because the deletion shifts the reading frame, altering all codons from the point of deletion until the end of the mRNA. 998 - 900 = 98 bases. 98/3 = 32.66, rounded up to 33 codons.
199
Medium
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Remembering
+4 | -1
The DNA fragments separated on an agarose gel can be visualised after staining with
View answer and explanation
Correct option: A
Ethidium bromide
Option A is correct because ethidium bromide is the standard dye used to visualize DNA fragments in agarose gels, as it intercalates between DNA bases and fluoresces under UV light.
200
Medium
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Application
+4 | -1
ATCCAG DNA form which mRNA
View answer and explanation
Correct option: A
UAGGUC
Option A (UAGGUC) is correct because in transcription, adenine (A) pairs with uracil (U), thymine (T) pairs with adenine (A), cytosine (C) pairs with guanine (G), and guanine (G) pairs with cytosine (C).
201
Medium
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Understanding
+4 | -1
What is the criterion for DNA fragments movement on agarose gel during gel electrophoresis?
View answer and explanation
Correct option: C
The smaller the fragments size, the farther it moves
Option C (The smaller the fragments size, the farther it moves) is correct because smaller DNA fragments migrate faster and farther through the agarose gel matrix.
Revision notes and key takeaways
Review MOLECULAR BASIS OF INHERITANCE in your textbook or class notes, then use this set to check your understanding.
Showing 181-201 of 201 questions
