Molecular basis of inheritance practice · Easy

Option A (Promoter) is correct because the promoter defines the position and presence of the template and coding strands in a transcription unit.

Option A (Determining sex of child) is correct because DNA fingerprinting is not used to determine the sex of a child; other methods like karyotyping or PCR are used.

Option A (If both the assertion and the reason are true and the reason is a correct explanation of the assertion) is correct because DNA's stability and replication ability make it suitable as the genetic material.

Option B (Both are polymers of nucleotides) is correct because both DNA and RNA are polymers made up of nucleotide monomers.

Option B is correct because sickle cell anemia is a classical example of a point mutation where a single nucleotide change in the beta-globin gene leads to a change in the amino acid sequence.

Option D (It was earlier named as soluble RNA) is correct because tRNA was initially known as soluble RNA due to its small size and solubility.

Option D (Uracil) is correct because uracil is a nitrogenous base found in RNA, not DNA. DNA contains thymine instead.

Option D is correct. With 6 coils, there are 60 base pairs. 22 are A-T pairs, leaving 38 G-C pairs, meaning there are 38 cytosine bases.

Option A (T- 32%, A-32%, G-18%) is correct because in DNA, A=T and G=C. Given C=18%, G is also 18%. The remaining percentage is split equally between A and T.