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JEE • PHYSICS • WAVES

Waves practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 181-210 of 524 questions

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181 Medium
181 of 524
Understanding +4 | -1
A stretched string of length ll fixed at both ends can sustain stationary waves of wavelength λ\lambda given by
View answer and explanation
Correct option: B
λ=2l/n\lambda = 2l/n
Option B (λ=2l/n\lambda = 2l/n) is correct because for stationary waves on a string fixed at both ends, the wavelength is related to the length of the string by the formula λ=2l/n\lambda = 2l/n, where n is an integer representing the mode number.
182 Medium
182 of 524
Understanding +4 | -1
Which of the following equations represents a travelling wave?
View answer and explanation
Correct option: A
y=A  sin⁡ (15 x−2 t)y = A\,\,\sin \,(15\,x - 2\,t)
Option A (y=A,sin⁡ (15,x−2,t)y = A\\,\sin \,(15\\,x - 2\\,t)) is correct because it matches the standard form of a traveling wave equation: y=Asin⁡(kx−ωt)y = A \sin (kx - \omega t).
183 Medium
183 of 524
Understanding +4 | -1
There are two organ pipes of the same length and the same material but of different radii. When they are emitting fundamental notes -
View answer and explanation
Correct option: A
broader pipe gives note of smaller frequency
Option A (broader pipe gives note of smaller frequency) is correct because the effective length of the pipe increases with the radius, decreasing the frequency.
184 Medium
184 of 524
Application +4 | -1
A tuning fork of frequency 340 Hz340 \mathrm{~Hz} is vibrated just above a cylindrical tube of length 120 cm120 \mathrm{~cm}. Water is slowly poured in the tube. If the speed of sound in air is 340 m/s340 \mathrm{~m} / \mathrm{s}. Find the minimum height of water required for resonance. (v=(v= 340 m/s340 \mathrm{~m} / \mathrm{s} )
View answer and explanation
Correct option: A
45 cm
Option A (45 cm) is correct because it represents the minimum height of water required for resonance, calculated using the formula for a closed pipe.
185 Medium
185 of 524
Application +4 | -1
A tuning fork produces 4 beats/s when sounded with a tuning fork of frequency 512 Hz512 \mathrm{~Hz}. The same tuning fork when sounded with another tuning fork of frequency 514 Hz514 \mathrm{~Hz} produces 6 beats/s. Find the frequency of the tuning fork.
View answer and explanation
Correct option: B
508 Hz508 \mathrm{~Hz}
The correct answer is B (508 Hz508 \mathrm{~Hz}). By considering the possible frequencies based on the beat frequencies with the two given tuning forks, the common frequency is 508 Hz.
186 Medium
186 of 524
Understanding +4 | -1
Assertion: Sound would travel faster on a hot summer day than on cold winterday.
Reason: Velocity of sound is directly proportional to the square of its absolute temperature
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion
Option A is correct because the speed of sound increases with temperature, and the reason correctly states the relationship between velocity and temperature.
187 Medium
187 of 524
Understanding +4 | -1
Two wires are producing fundamental notes of the same frequency. Change in which of the following factors of one wire will not produce beats between them
View answer and explanation
Correct option: A
Amplitude of the vibrations
Option A is correct because the amplitude of vibration does not affect the fundamental frequency of a wire.
188 Medium
188 of 524
Analyzing +4 | -1
When two tuning forks AA and BB are sounded together, 4 beats per second are heard. The frequency of the fork BB is 384 Hz384 \mathrm{~Hz}. When one of the prongs of the fork AA is filled and sounded with BB, the beat frequency increases, then the frequency of the fork AA is
View answer and explanation
Correct option: D
388 Hz388 \mathrm{~Hz}
Option D (388 Hz388 \mathrm{~Hz}) is correct because filling the prong increases the frequency of A, and since the beat frequency increased, the original frequency of A must have been higher than B.
189 Medium
189 of 524
Understanding +4 | -1
Which one of the following does not represent a travelling wave?
View answer and explanation
Correct option: D
y=f(x2−vt2)y=f\left(x^2-v t^2\right)
Option D (y=f(x2−vt2)y=f(x^2-vt^2)) is correct because a travelling wave must be of the form f(ax±bt)f(ax \pm bt), and this option does not fit that form.
190 Medium
190 of 524
Analyzing +4 | -1
A resonating column has resonant frequencies as 100 Hz,300 Hz,500 Hz100 \mathrm{~Hz}, 300 \mathrm{~Hz}, 500 \mathrm{~Hz}. Then, it may be
View answer and explanation
Correct option: C
Pipe closed at one end
Option C (Pipe closed at one end) is correct because the frequencies are in the ratio 1:3:5, which is characteristic of a closed pipe.
191 Medium
191 of 524
Remembering +4 | -1
A device used for investigating the vibration of a fixed string of wire is
View answer and explanation
Correct option: A
Sonometer
Option A (Sonometer) is correct because a sonometer is specifically designed to study the vibrations of strings.
192 Medium
192 of 524
Application +4 | -1
Equation of progressive wave is
y=a  sin⁡[10 πx+11 πt+π3]y = a\,\,\sin \left[ {10\,\pi x + 11\,\pi t + \frac{\pi }{3}} \right]
View answer and explanation
Correct option: A
Its wavelength is 0.20.2 units
Option A (Its wavelength is 0.20.2 units) is correct because the wavelength is derived from the given wave equation by comparing it to the standard form.
193 Medium
193 of 524
Application +4 | -1
The transverse displacement of a stretched string which is connected between two rigid supports is given by y=0.06sin⁡(2πx5−80πt)y = 0.06\sin \left( {\frac{{2\pi x}}{5} - 80\pi t} \right) where x and y are in metre and t in sec. Length of string is 1.5 m and its mass is 3×10−2 kg.3 \times {10^{ - 2}}\,kg. Then tension in string will be:-
View answer and explanation
Correct option: C
800 N
Option C (800 N) is correct because the tension in the string is calculated using the formula T=μv2=μ(ωk)2T = \mu v^2 = \mu (\frac{\omega}{k})^2, where μ\mu is the linear mass density, ω\omega is the angular frequency, and k is the wave number.
194 Medium
194 of 524
Understanding +4 | -1
When we hear a sound, we can identify its source from
View answer and explanation
Correct option: D
Overtones present in the sound
Option D (Overtones present in the sound) is correct because the unique combination of overtones determines the timbre or quality of a sound, allowing us to identify its source.
195 Medium
195 of 524
Application +4 | -1
A string of length 0.4  m0.4\,\,m and mass 10−2{10^{ - 2}} kg is tightly clamped at the ends. The tension in the string is 1.6N1.6\mathrm{ }N. Identical wave pulses are produced at one end at equal intervals of time Δt\Delta t. The minimum value of Δt\Delta t, which allows constructive interference between successive pulses is
View answer and explanation
Correct option: B
0.10s0.10\mathrm{ }s
The correct answer is B (0.10s0.10\mathrm{ }s) because the minimum time interval for constructive interference is equal to the time it takes for the wave to travel twice the length of the string.
196 Medium
196 of 524
Analyzing +4 | -1
The displacement yy of a particle is given by y=4  cos⁡2(t2)  sin⁡(1000t)y = 4\,\,{\cos ^{ 2}}\left( {\frac{t}{2}} \right)\,\,\sin \left( {1000t} \right). This expression may be considered to be a result of the superposition of how many simple harmonic motions?
View answer and explanation
Correct option: B
33
Option B (3) is correct because the given expression can be rewritten as a superposition of three simple harmonic motions with different frequencies.
197 Medium
197 of 524
Application +4 | -1
A uniform wire of length LL, diameter DD and density SS is stretched under a tension TT. the correct relation between its fundamental frequency ff, the length LL and the diameter DD is
View answer and explanation
Correct option: A
f∝1LDf \propto \frac{1}{{LD}}
Option A (f∝1LDf \propto \frac{1}{{LD}}) is correct because the fundamental frequency is inversely proportional to both the length and the diameter of the wire.
198 Medium
198 of 524
Understanding +4 | -1
The equation of a progressive wave is y=asin⁡(ωt−kx)y = a\sin (\omega t - kx) then the velocity of the wave is
View answer and explanation
Correct option: C
ω/k\omega /k
Option C (ω/k\omega /k) is correct because the velocity of a wave is given by the angular frequency divided by the wave number, v=ωkv = \frac{\omega}{k}.
199 Medium
199 of 524
Analyzing +4 | -1
Assertion: When a stone is dropped in water the amplitude of progressive wave decreases with distance.
Reason: Amplitude of spherical wavefront is inversely proportional to radius.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B is correct. Both the assertion and reason are true, but the reason does not fully explain why the amplitude decreases with distance. Energy conservation is the primary reason.
200 Medium
200 of 524
Understanding +4 | -1
The property of a medium necessary for wave propagation is:
View answer and explanation
Correct option: D
All of the above
Option D is correct because inertia, elasticity, and low resistance are all necessary properties for a medium to support wave propagation.
201 Medium
201 of 524
Understanding +4 | -1
The equation of wave is given by y=Asin⁡ω[xv−k]y=A \sin \omega\left[\frac{x}{v}-k\right], where ω\omega is the angular velocity and vv is the linear velocity. The dimensional formula of ω\omega is
View answer and explanation
Correct option: C
[T−1]\left[{T}^{-1}\right]
Option C ([T−1{{T}}^{-1}]) is correct because angular velocity has dimensions of inverse time.
202 Medium
202 of 524
Application +4 | -1
Consecutive frequencies emitted from a closed organ pipe are 75 Hz,125 Hz,175 Hz75 {~Hz}, 125 {~Hz}, 175 {~Hz}. The frequency of the tenth overtone will be;
View answer and explanation
Correct option: C
525 Hz525 {~Hz}
Option C (525 Hz525 {~Hz}) is correct because it is calculated using the properties of a closed organ pipe and its harmonics.
203 Medium
203 of 524
Understanding +4 | -1
In a stationary wave, all the particles
View answer and explanation
Correct option: B
in the region between two nodes vibrate in same phase
Option B (in the region between two nodes vibrate in same phase) is correct because in a stationary wave, particles between two consecutive nodes oscillate in phase.
204 Medium
204 of 524
Remembering +4 | -1
The waves in which the particles of the medium vibrate in a direction perpendicular to the direction of wave motion is known as
View answer and explanation
Correct option: A
Transverse wave
Option A (Transverse wave) is correct because in transverse waves, the particle's motion is perpendicular to the wave's direction of travel.
205 Medium
205 of 524
Application +4 | -1
If the pressure amplitude in a sound wave is tripled, then the intensity of sound is increased by a factor of
View answer and explanation
Correct option: A
99
Option A (99) is correct because intensity is proportional to the square of the pressure amplitude.
206 Medium
206 of 524
Analyzing +4 | -1
Statement-I: The intensity of sound increases with increase in the density of the medium.
Statement-II: The sound heard is more intense in carbon dioxide in comparison to air.
View answer and explanation
Correct option: A
Statement-I is correct
Option A is correct because the intensity of sound is directly proportional to the density of the medium.
207 Medium
207 of 524
Application +4 | -1
Fundamental frequency of an open pipe of length 0.5  m0.5\,\,m is equal to the frequency of the first overtone of a closed pipe of length ll. The value of lc{l_c} is (m)\left( m \right)
View answer and explanation
Correct option: B
0.75
Option B (0.75) is correct because the length of the closed pipe is calculated by equating the fundamental frequency of the open pipe to the first overtone of the closed pipe.
208 Medium
208 of 524
Understanding +4 | -1
A uniform heavy string of mass M hangs vertically from a rigid ceiling. A transverse wave is sent from its free end towards fixed end. As the wave moves upward
View answer and explanation
Correct option: B
Its speed and wavelength increases
Option B (Its speed and wavelength increases) is correct because as the wave moves upward, the tension increases, leading to an increase in speed and wavelength.
209 Medium
209 of 524
Understanding +4 | -1
The periodic waves of amplitudes A1A_1 and A2A_2 pass through a region. If A1>A2A_1 > A_2, the difference in the maximum and minimum resultant amplitudes possible is
View answer and explanation
Correct option: B
2A22 {A}_2
Option B (2A22 {A}_2) is correct because the difference between the maximum and minimum resultant amplitudes is twice the smaller amplitude.
210 Medium
210 of 524
Understanding +4 | -1
In stationary waves all particles between two nodes pass through the mean position
View answer and explanation
Correct option: D
at the same time with different velocities
Option D (at the same time with different velocities) is correct because in a stationary wave, all particles between two nodes reach their mean position simultaneously, but their velocities depend on their distance from the nodes.
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