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JEE • PHYSICS • WAVES

Waves practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 524 questions
1 Medium
1 of 524
Application +4 | -1
The source of sound generating a frequency of 3  kHz3\,\,kHz reaches an observer with a speed of 0.50.5 times, the velocity of sound in air. The frequency heard by the observer is
View answer and explanation
Correct option: D
6kHz6\mathrm{ }kHz
Option D (6kHz6\mathrm{ }kHz) is correct because it is the frequency observed when the source is moving towards the observer at half the speed of sound, calculated using the Doppler effect formula.
2 Medium
2 of 524
Application +4 | -1
A source of sound emits waves with frequency fHzf\mathrm{ }Hz and speed Vm/secV\mathrm{ }m/sec. Two observers move away from this source in opposite directions each with a speed 0.2  V0.2\,\,V relative to the source. The ratio of frequencies heard by the two observers will be
View answer and explanation
Correct option: C
1:11:1
Option C (1:1) is correct because both observers are moving away from the source at the same speed, so the Doppler shift will be the same in magnitude, resulting in the same observed frequency ratio.
3 Medium
3 of 524
Analyzing +4 | -1
Assertion: The wave function of a pulse is given by y=3(2x+3t)2+4,y = \frac{3}{{{{\left( {2x + 3t} \right)}^2} + 4}}, it propagates in (–ve) x(– \mathrm{ve}) \,x-direction.
Reason: The given wave function is of the form y=f(kx+ωt),y = f(kx +\omega t), which represent a wave travelling in negative XX-direction.
View answer and explanation
Correct option: A
If both Assertion & reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because the wave function's form and the sign convention of the argument (kx + ωt) indicate propagation in the negative x-direction.
4 Medium
4 of 524
Application +4 | -1
In the fundamental mode, time taken by the wave to reach the closed end of the air filled pipe is 0.01  s0.01\,\,s. the fundamental frequency is
View answer and explanation
Correct option: A
25
Option A (25) is correct because the fundamental frequency is calculated using the time taken for the wave to reach the closed end of the pipe.
5 Medium
5 of 524
Application +4 | -1
A rope 5 m5 \mathrm{~m} long has a total mass of 245 g245 \mathrm{~g}. It is stretched with a constant tension of 1 kg1 \mathrm{~kg} wt. If it is fixed at one end and shaken by hand at the other end, what frequency of shaking will make it break up into three vibrating segments? Take g=980 cm s−2g=980 \mathrm{~cm} \mathrm{~s}^{-2}.
View answer and explanation
Correct option: D
4.24 Hz4.24 \mathrm{~Hz}
Option D (4.24 Hz4.24 \mathrm{~Hz}) is correct because it is calculated using the formula for the frequency of vibration in a string fixed at one end, considering the number of segments.
6 Medium
6 of 524
Remembering +4 | -1
If TT is the reverberation time of an auditorium of volume VV then
View answer and explanation
Correct option: D
T∝VT \propto V
Option D (T∝VT \propto V) is correct because the reverberation time is directly proportional to the volume of the auditorium.
7 Medium
7 of 524
Understanding +4 | -1
In stationary waves, antinodes are the points where there is
View answer and explanation
Correct option: D
Maximum displacement and minimum pressure change
Option D (Maximum displacement and minimum pressure change) is correct because antinodes in stationary waves have maximum displacement and minimum pressure change.
8 Medium
8 of 524
Understanding +4 | -1
Assertion: The reverberation time dependent on the volume of enclosure.
Reason: The unit of absorption coefficient is sabine.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of assertion
Option B is correct because both the assertion and the reason are true, but the reason does not explain the assertion. Reverberation time depends on volume, and the unit of absorption coefficient is sabine, but these are independent facts.
9 Medium
9 of 524
Application +4 | -1
When the length of the vibrating segment of a sonometer wire is increased by 1%1\% the percentage changes its frequency is
View answer and explanation
Correct option: C
1
Option C (1) is correct because a 1% increase in length results in approximately a 1% decrease in frequency, given the inverse relationship.
10 Medium
10 of 524
Understanding +4 | -1
Resonance occurs, when:
View answer and explanation
Correct option: C
A body is set into vibrations with its natural frequency, by another body vibrating with the same frequency
Option C (A body is set into vibrations with its natural frequency, by another body vibrating with the same frequency) is correct because resonance occurs when the driving frequency matches the natural frequency.
11 Medium
11 of 524
Application +4 | -1
Calculate the ratio of the speed of sound in neon to that in water vapour at any temperature. [Molecular weight of neon =2.02×10−2 kg/mol=2.02 \times 10^{-2} \mathrm{~kg} / \mathrm{mol} and for water vapours =1.8×=1.8 \times 10−2 kg/mol]\left.10^{-2} \mathrm{~kg} / \mathrm{mol}\right]
View answer and explanation
Correct option: A
1.05
Option A (1.05) is correct because it is the ratio of the speed of sound in neon to that in water vapor, calculated using the formula v=γRTMv = \sqrt{\frac{\gamma RT}{M}}.
12 Medium
12 of 524
Analyzing +4 | -1
Assertion: A balloon filled with CO2CO_2 gas acts as a converging lens for a sound wave.
Reason: Sound waves travel faster in air than in CO2.CO_2.
View answer and explanation
Correct option: A
If both Assertion & reason are True & the Reason is a correct explanation of the Assertion
Option A is correct. A CO2 balloon acts as a converging lens because sound travels slower in CO2 than in air, and sound waves travel faster in air than in CO2 is the correct reason.
13 Medium
13 of 524
Understanding +4 | -1
What is the phase difference between two successive crests in the wave?
View answer and explanation
Correct option: C
2π\pi
Option C (2π\pi) is correct because the phase difference between two successive crests (or troughs) in a wave is one full wavelength, which corresponds to 2π\pi radians.
14 Medium
14 of 524
Analyzing +4 | -1
A tunning fork of frequency of 512 Hz512 \mathrm{~Hz} when sounded with unknown tunning fork produces 5 beats/sec. If arms of the unknown fork are filed then it produces only 3 beats / sec. Find the frequency of unknown tunning fork.
View answer and explanation
Correct option: A
517 Hz
Option A (517 Hz) is correct because filing the arms of the unknown fork increases its frequency, and the beat frequency decreases, indicating that the unknown frequency was initially higher than 512 Hz.
15 Medium
15 of 524
Understanding +4 | -1
Doppler’s effect in sound is due to
View answer and explanation
Correct option: C
Relative motion of source and observer
Option C (Relative motion of source and observer) is correct because Doppler's effect depends on the relative velocity between the source of the sound and the observer.
16 Medium
16 of 524
Understanding +4 | -1
A source emits sound of frequency 600 Hz600 \mathrm{~Hz} inside water. The frequency heard in air will be equal to (velocity of sound in water =1500 m/s=1500 \mathrm{~m} / \mathrm{s}, velocity of sound in air =300=300 m/s)\mathrm{m} / \mathrm{s}) :
View answer and explanation
Correct option: C
600 Hz600 \mathrm{~Hz}
Option C (600 Hz600 \mathrm{~Hz}) is correct because the frequency of sound remains the same when it travels from one medium to another.
17 Medium
17 of 524
Application +4 | -1
A glass tube of length 1.0 m1.0 {~m} is completely filled with water. A vibrating tuning fork of frequency 500 Hz500 {~Hz} is kept over the mouth of the tube and the water is drained out slowly at the bottom of the tube. If the velocity of sound in air is 330 ms−1330 {~ms}^{-1}, then the total number of resonances that occur will be
View answer and explanation
Correct option: B
3
Option A (3) is correct because there are three resonance lengths within the 1-meter tube length for the given frequency.
18 Medium
18 of 524
Application +4 | -1
A person can hear sound waves in the frequency range 20 Hz20 \mathrm{~Hz} to 20 kHz20\,\mathrm{kHz}. Find the minimum and the maximum wavelengths of sound that is audible to the person. The speed of sound is 360 ms−1360 \mathrm{~ms}^{-1}.
View answer and explanation
Correct option: A
18 mm, 18 m
Option A (18 mm, 18 m) is correct because it correctly calculates the minimum and maximum wavelengths using the given frequency range and speed of sound.
19 Medium
19 of 524
Understanding +4 | -1
An empty vessel is partially filled with water, then the frequency of vibration of air column in the vessel
View answer and explanation
Correct option: C
Increases
Option C (Increases) is correct because as the water level rises, the length of the air column decreases, leading to a higher frequency of vibration.
20 Medium
20 of 524
Remembering +4 | -1
Law of superposition is applicable to
View answer and explanation
Correct option: D
All kinds of waves
Option D (All kinds of waves) is correct because the principle of superposition applies to all types of waves, including light, sound, and transverse waves, as long as the waves are in a linear medium.
21 Medium
21 of 524
Understanding +4 | -1
Statement-I: When a sound wave is propagating through the medium the acceleration of a particle is directly proportional to its displacement.
Statement-II: Wave velocity depends on the properties of the medium and is independent of time and position.
View answer and explanation
Correct option: C
Both statement-I &\& II are correct
Option C is correct because both statements are true: acceleration is proportional to displacement in a sound wave, and wave velocity depends on medium properties.
22 Medium
22 of 524
Understanding +4 | -1
Assertion: Solids can support both longitudinal and transverse waves but only longitudinal waves can propagate in gases.
Reason: For the propagation of transverse waves, medium must also necessarily have the property of rigidity.
View answer and explanation
Correct option: A
If both assertion and reason are true and reason is the correct explanation of the assertion
Option A is correct because transverse waves require rigidity, which solids possess but gases do not, while longitudinal waves can propagate in both.
23 Medium
23 of 524
Application +4 | -1
The ratio of intensities between two coherent sound sources is 4:14:1. The difference of loudness in decibels (dB)\left( {\mathrm{dB}} \right) between maximum and minimum intensities, on their interference in space is
View answer and explanation
Correct option: C
20  log⁡320\,\,\log 3
Option C (20  log⁡320\,\,\log 3) is correct because the difference in loudness is calculated using the ratio of maximum to minimum intensities, which depends on the amplitude ratio of the sound sources.
24 Medium
24 of 524
Understanding +4 | -1
A progressive wave y=a sin[(kx−ωt)]\mathrm{y = a}\,\mathrm{sin}\left[ {\left( {\mathrm{kx} - \mathrm{\omega t}} \right)} \right] is reflected by a rigid wall at x=0\mathrm{x} = 0. Then the reflected wave can be represented by
View answer and explanation
Correct option: D
y=−asin(kx+ωt)\begin{array}{llllllllllllllllllll} {\mathrm{y = } - \mathrm{asin}\left( {\mathrm{kx + \omega t}} \right)} \end{array}
Option D is correct because reflection from a rigid wall introduces a phase change of π, resulting in a negative sign and a change in direction.
25 Medium
25 of 524
Understanding +4 | -1
In a stationary wave system, all the particles of the medium;
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because in a stationary wave, all particles reach zero displacement, maximum displacement, and are at rest simultaneously at some instant.
26 Medium
26 of 524
Understanding +4 | -1
Assertion: A tuning fork is made of an alloy of steel, nickel and chromium.
Reason: The alloy of steel, nickel and chromium is called elinvar.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not correct explanation of the assertion
Option B is correct because both the assertion and reason are true, but the reason does not explain why that particular alloy is used for tuning forks.
27 Medium
27 of 524
Analyzing +4 | -1
The wavelength of two notes in air are 36195m\frac{{36}}{{195}}m and 36193m\frac{{36}}{{193}}m each note produces 1010 beats per second separately with a third note of fixed frequency. The velocity of sound in air in m/sm/s is
View answer and explanation
Correct option: D
360360
Option D (360360) is correct because it is calculated using the beat frequency formula and the given wavelengths.
28 Medium
28 of 524
Application +4 | -1
Two points on a travelling wave having frequency 500  Hz500\,\,Hz and velocity 300  ms−1300\,\,\mathrm{m}{\mathrm{s}^{ - 1}} are 60∘60^\circ out of phase, then the minimum distance between two points is
View answer and explanation
Correct option: B
0.1
Option B (0.1) is correct because the minimum distance between two points with a 60-degree phase difference is calculated using the wavelength and the phase difference.
29 Medium
29 of 524
Understanding +4 | -1
A wave is reflected from a rigid support. The change in phase on reflection will be
View answer and explanation
Correct option: C
π\pi
Option C is correct because a wave reflected from a rigid support undergoes a phase change of \π\pi radians.
30 Medium
30 of 524
Understanding +4 | -1
If the temperature of the atmosphere is increased, the following character of the sound wave is effected
View answer and explanation
Correct option: C
Velocity
Option C (Velocity) is correct because the speed of sound in a gas is directly proportional to the square root of the temperature, so an increase in temperature increases the velocity of sound.
Revision notes and key takeaways

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Key Takeaways

  • ✓ This set contains 524 single-correct-answer MCQs on WAVES.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
  • ✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.
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