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JEE • PHYSICS • WAVES

Waves practice · Hard

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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1 Hard

1 of 6

Application +4 | -1

Two wires of different densities but same area of cross section are soldered together at one end and are stretched to a tension

T

. The velocity of a transverse wave in the first wire is double of that in the second wire. Find the ratio of the density of the first wire to that of the second wire.

View answer and explanation

Correct option: A

0.25

Option A (0.25) is correct because the ratio of densities is inversely proportional to the square of the ratio of velocities, given the same tension and area.

2 Hard

2 of 6

Understanding +4 | -1

Statement – 1: Newton’s equation for speed of sound in air was found wrong because, he assumed process as isothermal
Statement – 2: Flow of sound wave in a medium is very fast. Quick process suppress heat exchange, hence this process must be adiabatic in nature.

View answer and explanation

Correct option: A

Statement – 1 is true, Statement – 2 is true; Statement – 2 is a correct explanation for Statement – 1

Option A (Statement – 1 is true, Statement – 2 is true; Statement – 2 is a correct explanation for Statement – 1) is correct because Newton's isothermal assumption was incorrect, and the adiabatic process better describes sound wave propagation due to the speed of the process.

3 Hard

3 of 6

Understanding +4 | -1

In the first overtone position of the resonance tube, the pressure anti-node is present at (L is the length of the tube) which positions from the closed end.

View answer and explanation

Correct option: A

\frac{\mathrm{L}}{3}, \mathrm{L}

Option A (

\frac{\mathrm{{L}}}{{3}}, \mathrm{{L}}

) is correct because in the first overtone of a closed pipe, pressure antinodes occur at L/3 and L from the closed end.

4 Hard

4 of 6

Application +4 | -1

A sound has an intensity of

2 \times 10^{-8} \mathrm{~W} / \mathrm{m}^2

. Its intensity level (in decibel) is :

\left(\log _{10} 2=0.3\right) \text { :- }

View answer and explanation

Correct option: A

Option A (43) is correct because it is the intensity level calculated using the formula L = 10 log₁₀(I/I₀), where I₀ is the threshold of hearing (10⁻¹² W/m²).

5 Hard

5 of 6

Application +4 | -1

A SONAR system fixed in a submarine operates at a frequency

40 \mathrm{~kHz}

. An enemy submarine moves towards the SONAR with a speed of

360 \mathrm{~km} / \mathrm{h}

. The frequency of sound is reflected by submarine is (Speed of sound in water

=1400 \mathrm{~m} / \mathrm{s}

)

View answer and explanation

Correct option: B

\frac{600}{13} \mathrm{kHz}

Option B (

\frac{{600}}{{13}} \mathrm{{kHz}}

) is correct because it accounts for the Doppler effect twice, once when the sound reaches the submarine and again when it's reflected back.

6 Hard

6 of 6

Analyzing +4 | -1

Equation of progressive wave is:

y=a \sin ^2 \frac{\pi}{4} \cos ^2 \frac{\pi}{4} \sin (\omega t-k x \pm \phi)

where symbols having their usual meanings then for given wave equation:

(a) Amplitude

=a \sin ^2 \frac{\pi}{4} \cos ^2 \frac{\pi}{4}

(b) Wavelength

=\frac{2 \pi}{{K}}

y=

unit of amplitude, unit of wavelength

=

unit of

x

(d) Frequency

=\frac{\omega}{2 \pi}

View answer and explanation

Correct option: C

a, b, c, d are correct

Option C (a, b, c, d are correct) is correct because all the given statements about the wave equation are true.

Revision notes and key takeaways

Review WAVES in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

✓ This set contains 6 single-correct-answer MCQs on WAVES.
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

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