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JEE • PHYSICS • WAVES
Waves practice · Medium
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 151-180 of 524 questions
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151
Medium
151 of 524
Application
+4 | -1
An observer is standing away from a vertically hill. Starting between the observer and the hill a police van having a siren of frequency moves towards the hill with a uniform speed. If the frequency of the sound heard directly from the siren is , the frequency of the sound heard after reflection from the hill (in Hz) is about, (velocity of sound =
View answer and explanation
Correct option: B
Option B () is correct because it accounts for the Doppler effect twice: once as the van approaches the hill and again as the reflection approaches the observer.
152
Medium
152 of 524
Application
+4 | -1
For an interference pattern, the maximum and minimum intensity ratio is , then what will be the ratio of amplitudes?
View answer and explanation
Correct option: B
Option B () is correct because the ratio of amplitudes is derived from the ratio of maximum and minimum intensities in an interference pattern.
153
Medium
153 of 524
Understanding
+4 | -1
Phase difference between a particle at a compression and a particle at the next rare fraction is
View answer and explanation
Correct option: C
The correct answer is C () because the phase difference between a compression and the next rarefaction in a longitudinal wave is half a wavelength, which corresponds to a phase difference of radians.
154
Medium
154 of 524
Analyzing
+4 | -1
Two waves travelling in a medium in the x-direction are represented by , and where are the displacements of the particles of the medium, t is time, and are constants. The two waves have different
View answer and explanation
Correct option: B
Directions of propagation
Option B (Directions of propagation) is correct. The waves have different signs in front of the x and t terms, indicating opposite directions of propagation.
155
Medium
155 of 524
Application
+4 | -1
a segment of wire vibrates with a fundamental frequency of under a tension of . then tension at which the fundamental frequency of the same wire becomes is
View answer and explanation
Correct option: A
Option A () is correct because the frequency is proportional to the square root of the tension, so doubling the frequency requires quadrupling the tension.
156
Medium
156 of 524
Application
+4 | -1
The path difference between two interfering waves at a point on screen is 171.5 times the wavelength. If the path difference is 0.01372 cm. Find the wavelength?
View answer and explanation
Correct option: D
Option D () is correct because the wavelength is calculated by dividing the path difference by 171.5.
157
Medium
157 of 524
Understanding
+4 | -1
Statement I: Sonometer is used to determine frequency of unknown T.F.
Statement II: In sonometer riders used as indicator.
Statement II: In sonometer riders used as indicator.
View answer and explanation
Correct option: B
If both Statement - I and Statement - II are true but Statement - II is not the correct explanation of Statement - I.
Option B is correct because both statements are true, but Statement II doesn't explain Statement I. A sonometer determines frequency, and riders indicate resonance, but the riders' function isn't the reason the sonometer works.
158
Medium
158 of 524
Understanding
+4 | -1
Assertion: Transverse waves are not produced in liquids and gases.
Reason: Light waves are transverse-like waves.
Reason: Light waves are transverse-like waves.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not correct explanation of the assertion
Option B (If both assertion and reason are true but reason is not correct explanation of the assertion) is correct because transverse waves require elasticity of shape, which liquids and gases lack, and light waves are indeed transverse, but this doesn't explain the assertion.
159
Medium
159 of 524
Analyzing
+4 | -1
Assertion: In reflection of waves, frequency of waves remains same but their phase changes continuously.
Reason: When same sound note is heard after reflection from an obstacle, then it is known as echo.
Reason: When same sound note is heard after reflection from an obstacle, then it is known as echo.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of assertion
Option B (If both assertion and reason are true but reason is not the correct explanation of assertion) is correct because both statements are true independently, but the phenomenon of echo doesn't explain the phase change during reflection.
160
Medium
160 of 524
Application
+4 | -1
The energy per unit area associated with a progressive sound wave will be doubled if
View answer and explanation
Correct option: C
The amplitude of the wave is increased by 41.4%
Option C (The amplitude of the wave is increased by 41.4%) is correct because the energy per unit area is proportional to the square of the amplitude, so to double the energy, the amplitude must increase by a factor of .
161
Medium
161 of 524
Analyzing
+4 | -1
A fork of unknown frequency when sounded with one of frequency gives 4 beats per second and when loaded with a piece of wax again gives 4 beats per second. How do you account for this and what was the unknown frequency?
View answer and explanation
Correct option: C
Option C is correct because the frequency increases after loading with wax, indicating the original frequency was higher than 288 Hz.
162
Medium
162 of 524
Application
+4 | -1
Transverse waves are generated in two uniform steel wires and by attaching their free ends to a fork of frequency . The diameter of wire is half that of and tension in wire is half the tension in wire . What is the ratio of velocities of waves in and ?
View answer and explanation
Correct option: B
Option B () is correct because the ratio of velocities is proportional to the square root of the ratio of tensions and inversely proportional to the square root of the ratio of mass per unit length.
163
Medium
163 of 524
Application
+4 | -1
A man stands in a narrow, steep-sided valley. When he shouts, he hears two echoes, one after and other after . If the velocity of sound in air is , the width of the valley is
View answer and explanation
Correct option: B
Option B (495 m) is correct because the width of the valley is half the product of the speed of sound and the sum of the echo times.
164
Medium
164 of 524
Understanding
+4 | -1
At a certain instant a stationary transverse wave is found to have maximum kinetic energy. The appearance of string at that instant is
View answer and explanation
Correct option: D
Straight line
Option D (Straight line) is correct because at the instant of maximum kinetic energy, all particles are passing through their equilibrium positions.
165
Medium
165 of 524
Application
+4 | -1
A transverse wave described by
propagates on a stretched string having a linear mass density of . Find the tension in the string.
propagates on a stretched string having a linear mass density of . Find the tension in the string.
View answer and explanation
Correct option: A
0.108 N
Option A (0.108 N) is correct because it is calculated using the wave equation and the linear mass density to find the tension in the string.
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166
Medium
166 of 524
Remembering
+4 | -1
The waves associated with the motion of microscopic particles such as electrons, protons, neutrons are called
View answer and explanation
Correct option: A
Matter waves
Option A (Matter waves) is correct because the waves associated with microscopic particles are known as matter waves or de Broglie waves.
167
Medium
167 of 524
Analyzing
+4 | -1
The equation of the standing wave in a string clamped at both ends, vibrating in its third harmonic is given by
where and are in cm and is in sec-
where and are in cm and is in sec-
View answer and explanation
Correct option: D
All of the above
Option D (All of the above) is correct because the frequency is 300 Hz, the length is 30 cm, and the nodes are located at the specified positions, all derived from the given standing wave equation.
168
Medium
168 of 524
Application
+4 | -1
The rms speed of hydrogen at is . The rms speed of oxygen at is
View answer and explanation
Correct option: C
Option C () is correct because the rms speed is inversely proportional to the square root of the molar mass and directly proportional to the square root of the temperature.
169
Medium
169 of 524
Application
+4 | -1
The equation of a transverse wave on a stretched string is given by , where and are expressed in metre and in second. The speed of the wave is
View answer and explanation
Correct option: B
Option B () is correct because the speed of the wave is the ratio of the coefficient of t to the coefficient of x in the wave equation.
170
Medium
170 of 524
Application
+4 | -1
If speed of sound in air at is then at what temperature speed of sound becomes ?
View answer and explanation
Correct option: D
Option D () is correct because the speed of sound is proportional to the square root of the absolute temperature.
171
Medium
171 of 524
Application
+4 | -1
A stone is dropped into a lake from a tower high. The sound of the splash will be heard by the man approximately after
View answer and explanation
Correct option: A
Option A (11.5 seconds) is correct because it accounts for both the time the stone takes to fall and the time the sound takes to travel back up.
172
Medium
172 of 524
Understanding
+4 | -1
A sound carried by air from a guitar to a listener is a wave of following type
View answer and explanation
Correct option: D
Longitudinal progressive
Option D (Longitudinal progressive) is correct because sound waves are longitudinal, and they propagate through the air from the guitar to the listener.
173
Medium
173 of 524
Application
+4 | -1
It takes for a sound wave to travel between two fixed points when the day temperature is . if the temperature rises to the sound wave travels between the same fixed parts in
View answer and explanation
Correct option: A
Option A () is correct because the speed of sound is proportional to the square root of the absolute temperature, so as temperature increases, time decreases.
174
Medium
174 of 524
Application
+4 | -1
Amplitude of a mass -spring system, which is executing simple harmonic motion decreases with time. If mass decay constant then how much time is required for the amplitude of the system to drop to half of its initial value?
View answer and explanation
Correct option: A
34.65 s
Option A (34.65 s) is correct because it calculates the time required for the amplitude to drop to half its initial value using the damped oscillation formula.
175
Medium
175 of 524
Understanding
+4 | -1
Change in temperature of the medium changes
View answer and explanation
Correct option: C
Wavelength of sound waves
Option C (Wavelength of sound waves) is correct because the speed of sound changes with temperature, and since frequency is constant, the wavelength must also change.
176
Medium
176 of 524
Remembering
+4 | -1
Two sources of sound are in resonance when
View answer and explanation
Correct option: C
They produce the sound of same frequency
Option C (They produce the sound of same frequency) is correct because resonance occurs when two sources have the same natural frequency, allowing one to efficiently transfer energy to the other.
177
Medium
177 of 524
Understanding
+4 | -1
Assertion: Resonance is a special case of forced vibration in which the natural frequency of vibration of the body is the same as the impressed frequency and the amplitude of forced vibration, is maximum.
Reason: The amplitude of forced vibration of a body increases with an increase in the frequency of the externally impressed periodic force.
Reason: The amplitude of forced vibration of a body increases with an increase in the frequency of the externally impressed periodic force.
View answer and explanation
Correct option: C
If assertion is true, but reason is false
Option C is correct because the assertion about resonance is true, but the reason stating that amplitude increases with frequency is false.
178
Medium
178 of 524
Analyzing
+4 | -1
Assertion :- A tuning fork is in resonance with a closed pipe in fundamental mode but the same tuning fork cannot be in resonance in fundamental mode with an open pipe of same lengths
Reason :- The same tuning fork will not be in Resonance with open pipe of same length is due to end correction of pipe
Reason :- The same tuning fork will not be in Resonance with open pipe of same length is due to end correction of pipe
View answer and explanation
Correct option: C
Assertion is True but the Reason is False.
Option C is correct because the assertion is true, but the reason is false. The end correction is not the primary reason why the tuning fork won't resonate with an open pipe of the same length.
179
Medium
179 of 524
Application
+4 | -1
A string is producing transverse vibration whose equation is , Where and are in meters and is in seconds. If the linear density of the string is , then the tension in the string is will be
View answer and explanation
Correct option: D
0.117
Option D (0.117) is correct because the tension in the string is calculated using the wave speed formula and the linear density.
180
Medium
180 of 524
Understanding
+4 | -1
The ratio of frequencies of fundamental harmonic produced by an open pipe to that of closed pipe having the
same length is
same length is
View answer and explanation
Correct option: D
Option D () is correct because the fundamental frequency of an open pipe is twice that of a closed pipe of the same length.
Revision notes and key takeaways
Review WAVES in your textbook or class notes, then use this set to check your understanding.
Showing 151-180 of 524 questions
