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JEE • PHYSICS • WAVES

Waves practice · Medium

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 524 questions

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211 Medium
211 of 524
Analyzing +4 | -1
Assertion(A): The fundamental frequency of an open organ pipe increases as the temperature is increased.

Reason(R): As the temperature increases, the velocity of sound increases more rapidly than length of the pipe.
View answer and explanation
Correct option: A
Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
Option A is correct. The fundamental frequency of an open organ pipe increases with temperature because the velocity of sound increases more rapidly than the length of the pipe.
212 Medium
212 of 524
Application +4 | -1
An open pipe and a closed pipe having same length. The ratio of pth{p^{th}} overtones of two pipes is
View answer and explanation
Correct option: C
2(p+1)2p+1\frac{{2(p + 1)}}{{2p + 1}}
Option C (2(p+1)2p+1\frac{{2(p + 1)}}{{2p + 1}}) is correct because it represents the ratio of the frequencies of the p-th overtones in an open and a closed pipe of the same length.
213 Medium
213 of 524
Analyzing +4 | -1
The three lowest resonant frequencies of a system are 50 Hz,150 Hz50 \mathrm{~Hz}, 150 \mathrm{~Hz} and 250 Hz250 \mathrm{~Hz}. The system could be:
View answer and explanation
Correct option: B
A tube of air open at one end
The system is a tube of air open at one end (Option B) because the resonant frequencies are odd multiples of the fundamental frequency.
214 Medium
214 of 524
Application +4 | -1
The temperature at which the velocity of sound in air will be 1.5 times its velocity at 0∘C0^\circ C is
View answer and explanation
Correct option: C
341.2∘C341.2^\circ C
Option C (341.2∘C341.2^\circ C) is correct because the velocity of sound is proportional to the square root of the absolute temperature.
215 Medium
215 of 524
Understanding +4 | -1
Velocity of sound in air
I. increases with temperature

II. Decreases with temperature

III. Increase with pressure

IV. Is independent of pressure

V. Is independent of temperature

Choose the correct answer
View answer and explanation
Correct option: D
Only I  and  IVI\,\,and\,\,IV are true
Option D (Only I;and;IVI\\;and\\;IV are true) is correct because the velocity of sound in air increases with temperature and is independent of pressure.
216 Medium
216 of 524
Application +4 | -1
A tube of length 1.05 m1.05 \mathrm{~m} is closed at one end. If the velocity of sound in air is 336 ms−1336 \mathrm{~ms}^{-1}, then the fundamental and the next higher overtone (in Hz\mathrm{Hz} ) are respectively
View answer and explanation
Correct option: B
80,24080,240
Option B (80,24080,240) is correct because the fundamental frequency is calculated as v/4l and the next higher overtone is three times the fundamental frequency for a tube closed at one end.
217 Medium
217 of 524
Understanding +4 | -1
The minimum intensity of sound is zero at a point due to two sources of nearly equal frequencies, when
View answer and explanation
Correct option: C
At the point of observation, the amplitudes of two S.H.M. produced by two sources are equal and both the S.H.M. are along the same straight line
Option C (At the point of observation, the amplitudes of two S.H.M. produced by two sources are equal and both the S.H.M. are along the same straight line) is correct because minimum intensity is zero when amplitudes are equal and the waves are in opposite phase.
218 Medium
218 of 524
Application +4 | -1
If the maximum speed of a particle carrying a travelling wave is v0v_0, then find the speed of a particle when the displacement is half that of the maximum value
View answer and explanation
Correct option: C
3v02\frac{\sqrt{3} v_0}{2}
Option C (3v02\frac{\sqrt{3} v_0}{2}) is correct because it is derived from the wave equation and the given condition where displacement is half the maximum value.
219 Medium
219 of 524
Remembering +4 | -1
The speed of sound in a gas of density ρ\rho at a pressure PP is proportional to
View answer and explanation
Correct option: D
Pρ\sqrt {\frac{P}{\rho }}
Option D (Pρ\sqrt {\frac{P}{\rho }}) is correct because the speed of sound in a gas is proportional to the square root of the pressure divided by the density.
220 Medium
220 of 524
Application +4 | -1
A train moves towards a stationary observer with speed 34  ms−134\,\,\mathrm{m}{\mathrm{s}^{ - 1}}. The train sounds a whistle and its frequency registered by the observer is f1{f_1}. If the train’s speed is reduced to 17 ms−117\,\mathrm{m}{\mathrm{s}^{ - 1}}, the frequency registered isf2{f_2}. If the peed of sound is 340  ms−1340\,\,\mathrm{m}{\mathrm{s}^{ - 1}}, then the ratio f1/f2{f_1}/{f_2} is
View answer and explanation
Correct option: D
1918\frac{{19}}{{18}}
The correct answer is D (19/18). The ratio of frequencies is calculated using the Doppler effect formula for a moving source approaching a stationary observer, considering the two different speeds of the train.
221 Medium
221 of 524
Application +4 | -1
A boy is walking away from a wall towards an observer at a speed of 1   metre/sec⁡1\,\,\,metre/\sec and blows a whistle whose frequency is 680  Hz680\,\,Hz. The number of beats heard by the observer per second is (Velocity of sound in air =340  metres/sec⁡= 340\,\,metres/\sec
View answer and explanation
Correct option: D
4
Option D (4) is correct because the number of beats heard by the observer is the difference between the frequencies heard directly from the source and from its reflection.
222 Medium
222 of 524
Understanding +4 | -1
A stretched string instead of being plucked in the middle is plucked at a point (1/4)th of its length from either of its ends. The frequency of vibration would be
View answer and explanation
Correct option: B
Twice when plucked in the middle
Option B (Twice when plucked in the middle) is correct because plucking at 1/4th length creates a higher frequency, specifically twice the frequency when plucked in the middle.
223 Medium
223 of 524
Application +4 | -1
Two forks exited together produced 3 beats per second. What is the time interval between the maximum intensity and the next minimum?
View answer and explanation
Correct option: A
16sec⁡\frac{1}{6}\sec
Option A (16sec⁡\frac{1}{6}\sec) is correct because the time interval between maximum intensity and the next minimum is half the time period of the beat frequency.
224 Medium
224 of 524
Application +4 | -1
A closed organ pipe and an open pipe of same length produce 22 beats s−1{\mathrm{s}^{ - 1}} when they are set into vibrations together in fundamental mode. The length of open pipe is now halved and that of closed pipe is doubled. The number of beats produced will be
View answer and explanation
Correct option: A
7
Option A (7) is correct because the number of beats produced is calculated by finding the difference in frequencies after changing the lengths of the pipes.
225 Medium
225 of 524
Application +4 | -1
A closed organ pipe has fundamental frequency 100Hz100\mathrm{ }Hz. What frequency will be produced, if its other end is also opened?
View answer and explanation
Correct option: A
200,400,600,800…\begin{array}{llllllllllllllllllll} {200,400,600,800 \ldots } \end{array}
Option A (200,400,600,800...) is correct because opening the other end of a closed organ pipe doubles the fundamental frequency, and all subsequent harmonics are integer multiples of this new fundamental frequency.
226 Medium
226 of 524
Understanding +4 | -1
The speed of sound in air at STP is 300 m/s.300 \mathrm{~m} / \mathrm{s}. If the air pressure becomes double, the temperature remaining the same, the speed of sound would become
View answer and explanation
Correct option: C
300 m/s300 \mathrm{~m} / \mathrm{s}
Option C (300 m/s300 \mathrm{~m} / \mathrm{s}) is correct because the speed of sound in air is independent of pressure at a constant temperature.
227 Medium
227 of 524
Understanding +4 | -1
Velocity of sound in vacuum is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because sound requires a medium to travel and cannot propagate through a vacuum.
228 Medium
228 of 524
Application +4 | -1
The electric field part of an electromagnetic wave in vacuum is

E=3.1 N C−1×cos⁡[(1.8 rad m−1)y+(5.4×108 rad s−1)t]i^\mathrm{E}=3.1 \mathrm{~N~C}^{-1} \times \cos \left[\left(1.8 \mathrm{~rad} \mathrm{~m}^{-1}\right) \mathrm{y}+\left(5.4 \times 10^8 \mathrm{~rad} \mathrm{~s}^{-1}\right) \mathrm{t}\right] \hat{\mathrm{i}}

The wavelength of this part of electromagnetic wave is
View answer and explanation
Correct option: D
3.5 m3.5 \mathrm{~m}
Option D (3.5 m3.5 \mathrm{~m}) is correct because it is the wavelength calculated from the wave number (k) in the given electromagnetic wave equation.
229 Medium
229 of 524
Application +4 | -1
The displacement of a particle is given by
x=3  sin⁡(5πt)+4  cos⁡(5πt)x = 3\,\,\sin \left( {5\pi t} \right) + 4\,\,\cos \left( {5\pi t} \right)
The amplitude of the particle is
View answer and explanation
Correct option: C
5
Option C (5) is correct because the amplitude of the resultant wave is calculated using the Pythagorean theorem since the two SHMs are perpendicular.
230 Medium
230 of 524
Understanding +4 | -1
Assertion(A): To hear different beats, difference of the frequencies of two sources should be less than 10 .

Reason(R): More the number of beats more is the confusion.
View answer and explanation
Correct option: B
Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
Option B (Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion) is correct because both statements are true, but the reason doesn't explain the assertion.
231 Medium
231 of 524
Understanding +4 | -1
Statement-I: The velocity of sound increases with increase of temperature.
Statement-II: Sound wave travel through longer distances during night than during day.
View answer and explanation
Correct option: A
Statement-I is correct
Option A (Statement-I is correct) is correct because the velocity of sound increases with temperature due to increased molecular kinetic energy.
232 Medium
232 of 524
Application +4 | -1
Find out the ratio of speed of sound in H2\mathrm{H}_2 & He\mathrm{He} at same temperature.
View answer and explanation
Correct option: B
4225\sqrt{\frac{42}{25}}
Option B (4225\sqrt{{\frac{{42}}{{25}}}}) is correct because it correctly applies the formula for the speed of sound in a gas, accounting for the ratio of specific heats and molar masses.
233 Medium
233 of 524
Understanding +4 | -1
A standing wave is produced in a string fixed at both ends. In this case
View answer and explanation
Correct option: C
All alternate antinodes vibrate in phase
Option C is correct because in a standing wave, all particles between two consecutive nodes vibrate in phase, and adjacent segments vibrate in opposite phases, so alternate antinodes vibrate in phase.
234 Medium
234 of 524
Application +4 | -1
If the amplitude ratio of two sources producing interference is 3 : 5, the ratio of intensities at maximum and minima is
View answer and explanation
Correct option: C
0.667361111
Option C (16:01) is correct because the ratio of maximum to minimum intensities is calculated using the squares of the sum and difference of the amplitudes.
235 Medium
235 of 524
Understanding +4 | -1
Two waves having sinusoidal waveforms have different wavelengths and different amplitude. They will be having
View answer and explanation
Correct option: C
Different quality and different intensity
The correct answer is C (Different quality and different intensity) because waves with different amplitudes have different intensities, and waves with different wavelengths have different qualities (timbres).
236 Medium
236 of 524
Application +4 | -1
A progressive wave of frequency 600 Hz600 \mathrm{~Hz} is travelling with a velocity of 300 m/s300 \mathrm{~m} / \mathrm{s}. Distance between two points of medium having phase difference of 30∘30^{\circ} will be nearly
(1) 0.021 m0.021 \mathrm{~m}
View answer and explanation
Correct option: C
0.041 m0.041 \mathrm{~m}
Option A (0.041 m) is correct because it is the calculated distance between two points with a 30-degree phase difference for a wave with the given frequency and velocity.
237 Medium
237 of 524
Analyzing +4 | -1
Assertion: Under given conditions of pressure and temperature, sound travels faster in a monoatomic gas than in diatomic gas.
Reason: Opposition for wave to travel is more in diatomic gas than monoatomic gas.
View answer and explanation
Correct option: C
If assertion is true, but reason is false
Option C is correct. The assertion is true because the velocity of sound is greater in monoatomic gases, but the reason is false as diatomic gases have more degrees of freedom, leading to more energy absorption and thus, a slower speed of sound.
238 Medium
238 of 524
Remembering +4 | -1
Ultrasonic waves are produced by
View answer and explanation
Correct option: A
Piezoelectric effect
Option A (Piezoelectric effect) is correct because ultrasonic waves are commonly produced using the piezoelectric effect, where certain materials generate an electric potential in response to mechanical stress, or vice versa.
239 Medium
239 of 524
Application +4 | -1
Ultrasonic waves of frequency 4.5MHz4.5 \mathrm{MHz} are used to detect tumour in soft tissues. The speed of sound in tissue is 1.5 km s−11.5 \mathrm{~km} \mathrm{~s}^{-1} and that in air is 340 ms−1340 \mathrm{~ms}^{-1}. Find the wavelength of this ultrasonic wave in air and in tissue.
View answer and explanation
Correct option: A
7.36×10−5 m;  3.3×10−4 m7.36 \times 10^{-5} \mathrm{~m};\,\,3.3 \times 10^{-4} \mathrm{~m}
Option A (7.36×10−5 m;  3.3×10−4 m7.36 \times 10^{-5} \mathrm{~m};\,\,3.3 \times 10^{-4} \mathrm{~m}) is correct because it correctly calculates the wavelengths in air and tissue using the given speeds and frequency.
240 Medium
240 of 524
Application +4 | -1
The displacement yy of a wave travelling in the xx -direction is given by y=10−4sin⁡(600 t−2x+π3)y = {10^{ - 4}}\sin \left( {600\,t - 2x + \frac{\pi }{3}} \right) meters, where xx is expressed in meters and tt is second. The speed of the wave-motion, in ms−1\mathrm{m}{\mathrm{s}^{ - 1}}, is
View answer and explanation
Correct option: B
300
Option B (300) is correct because the speed of the wave is calculated by dividing the angular frequency by the wave number.
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