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JEE • PHYSICS • WAVES
Waves practice · Medium
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Practice format and chapter quiz
These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.
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Showing 211-240 of 524 questions
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211
Medium
211 of 524
Analyzing
+4 | -1
Assertion(A): The fundamental frequency of an open organ pipe increases as the temperature is increased.
Reason(R): As the temperature increases, the velocity of sound increases more rapidly than length of the pipe.
Reason(R): As the temperature increases, the velocity of sound increases more rapidly than length of the pipe.
View answer and explanation
Correct option: A
Both Assertion and Reason are correct and Reason is the correct explanation of the Assertion.
Option A is correct. The fundamental frequency of an open organ pipe increases with temperature because the velocity of sound increases more rapidly than the length of the pipe.
212
Medium
212 of 524
Application
+4 | -1
An open pipe and a closed pipe having same length. The ratio of overtones of two pipes is
View answer and explanation
Correct option: C
Option C () is correct because it represents the ratio of the frequencies of the p-th overtones in an open and a closed pipe of the same length.
213
Medium
213 of 524
Analyzing
+4 | -1
The three lowest resonant frequencies of a system are and . The system could be:
View answer and explanation
Correct option: B
A tube of air open at one end
The system is a tube of air open at one end (Option B) because the resonant frequencies are odd multiples of the fundamental frequency.
214
Medium
214 of 524
Application
+4 | -1
The temperature at which the velocity of sound in air will be 1.5 times its velocity at is
View answer and explanation
Correct option: C
Option C () is correct because the velocity of sound is proportional to the square root of the absolute temperature.
215
Medium
215 of 524
Understanding
+4 | -1
Velocity of sound in air
I. increases with temperature
II. Decreases with temperature
III. Increase with pressure
IV. Is independent of pressure
V. Is independent of temperature
Choose the correct answer
I. increases with temperature
II. Decreases with temperature
III. Increase with pressure
IV. Is independent of pressure
V. Is independent of temperature
Choose the correct answer
View answer and explanation
Correct option: D
Only are true
Option D (Only are true) is correct because the velocity of sound in air increases with temperature and is independent of pressure.
216
Medium
216 of 524
Application
+4 | -1
A tube of length is closed at one end. If the velocity of sound in air is , then the fundamental and the next higher overtone (in ) are respectively
View answer and explanation
Correct option: B
Option B () is correct because the fundamental frequency is calculated as v/4l and the next higher overtone is three times the fundamental frequency for a tube closed at one end.
217
Medium
217 of 524
Understanding
+4 | -1
The minimum intensity of sound is zero at a point due to two sources of nearly equal frequencies, when
View answer and explanation
Correct option: C
At the point of observation, the amplitudes of two S.H.M. produced by two sources are equal and both the S.H.M. are along the same straight line
Option C (At the point of observation, the amplitudes of two S.H.M. produced by two sources are equal and both the S.H.M. are along the same straight line) is correct because minimum intensity is zero when amplitudes are equal and the waves are in opposite phase.
218
Medium
218 of 524
Application
+4 | -1
If the maximum speed of a particle carrying a travelling wave is , then find the speed of a particle when the displacement is half that of the maximum value
View answer and explanation
Correct option: C
Option C () is correct because it is derived from the wave equation and the given condition where displacement is half the maximum value.
219
Medium
219 of 524
Remembering
+4 | -1
The speed of sound in a gas of density at a pressure is proportional to
View answer and explanation
Correct option: D
Option D () is correct because the speed of sound in a gas is proportional to the square root of the pressure divided by the density.
220
Medium
220 of 524
Application
+4 | -1
A train moves towards a stationary observer with speed . The train sounds a whistle and its frequency registered by the observer is . If the train’s speed is reduced to , the frequency registered is. If the peed of sound is , then the ratio is
View answer and explanation
Correct option: D
The correct answer is D (19/18). The ratio of frequencies is calculated using the Doppler effect formula for a moving source approaching a stationary observer, considering the two different speeds of the train.
221
Medium
221 of 524
Application
+4 | -1
A boy is walking away from a wall towards an observer at a speed of and blows a whistle whose frequency is . The number of beats heard by the observer per second is (Velocity of sound in air
View answer and explanation
Correct option: D
4
Option D (4) is correct because the number of beats heard by the observer is the difference between the frequencies heard directly from the source and from its reflection.
222
Medium
222 of 524
Understanding
+4 | -1
A stretched string instead of being plucked in the middle is plucked at a point (1/4)th of its length from either of its ends. The frequency of vibration would be
View answer and explanation
Correct option: B
Twice when plucked in the middle
Option B (Twice when plucked in the middle) is correct because plucking at 1/4th length creates a higher frequency, specifically twice the frequency when plucked in the middle.
223
Medium
223 of 524
Application
+4 | -1
Two forks exited together produced 3 beats per second. What is the time interval between the maximum intensity and the next minimum?
View answer and explanation
Correct option: A
Option A () is correct because the time interval between maximum intensity and the next minimum is half the time period of the beat frequency.
224
Medium
224 of 524
Application
+4 | -1
A closed organ pipe and an open pipe of same length produce beats when they are set into vibrations together in fundamental mode. The length of open pipe is now halved and that of closed pipe is doubled. The number of beats produced will be
View answer and explanation
Correct option: A
7
Option A (7) is correct because the number of beats produced is calculated by finding the difference in frequencies after changing the lengths of the pipes.
225
Medium
225 of 524
Application
+4 | -1
A closed organ pipe has fundamental frequency . What frequency will be produced, if its other end is also opened?
View answer and explanation
Correct option: A
Option A (200,400,600,800...) is correct because opening the other end of a closed organ pipe doubles the fundamental frequency, and all subsequent harmonics are integer multiples of this new fundamental frequency.
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226
Medium
226 of 524
Understanding
+4 | -1
The speed of sound in air at STP is If the air pressure becomes double, the temperature remaining the same, the speed of sound would become
View answer and explanation
Correct option: C
Option C () is correct because the speed of sound in air is independent of pressure at a constant temperature.
227
Medium
227 of 524
Understanding
+4 | -1
Velocity of sound in vacuum is
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because sound requires a medium to travel and cannot propagate through a vacuum.
228
Medium
228 of 524
Application
+4 | -1
The electric field part of an electromagnetic wave in vacuum is
The wavelength of this part of electromagnetic wave is
The wavelength of this part of electromagnetic wave is
View answer and explanation
Correct option: D
Option D () is correct because it is the wavelength calculated from the wave number (k) in the given electromagnetic wave equation.
229
Medium
229 of 524
Application
+4 | -1
The displacement of a particle is given by
The amplitude of the particle is
The amplitude of the particle is
View answer and explanation
Correct option: C
5
Option C (5) is correct because the amplitude of the resultant wave is calculated using the Pythagorean theorem since the two SHMs are perpendicular.
230
Medium
230 of 524
Understanding
+4 | -1
Assertion(A): To hear different beats, difference of the frequencies of two sources should be less than 10 .
Reason(R): More the number of beats more is the confusion.
Reason(R): More the number of beats more is the confusion.
View answer and explanation
Correct option: B
Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion.
Option B (Both Assertion and Reason are correct but Reason is not the correct explanation of Assertion) is correct because both statements are true, but the reason doesn't explain the assertion.
231
Medium
231 of 524
Understanding
+4 | -1
Statement-I: The velocity of sound increases with increase of temperature.
Statement-II: Sound wave travel through longer distances during night than during day.
Statement-II: Sound wave travel through longer distances during night than during day.
View answer and explanation
Correct option: A
Statement-I is correct
Option A (Statement-I is correct) is correct because the velocity of sound increases with temperature due to increased molecular kinetic energy.
232
Medium
232 of 524
Application
+4 | -1
Find out the ratio of speed of sound in & at same temperature.
View answer and explanation
Correct option: B
Option B () is correct because it correctly applies the formula for the speed of sound in a gas, accounting for the ratio of specific heats and molar masses.
233
Medium
233 of 524
Understanding
+4 | -1
A standing wave is produced in a string fixed at both ends. In this case
View answer and explanation
Correct option: C
All alternate antinodes vibrate in phase
Option C is correct because in a standing wave, all particles between two consecutive nodes vibrate in phase, and adjacent segments vibrate in opposite phases, so alternate antinodes vibrate in phase.
234
Medium
234 of 524
Application
+4 | -1
If the amplitude ratio of two sources producing interference is 3 : 5, the ratio of intensities at maximum and minima is
View answer and explanation
Correct option: C
0.667361111
Option C (16:01) is correct because the ratio of maximum to minimum intensities is calculated using the squares of the sum and difference of the amplitudes.
235
Medium
235 of 524
Understanding
+4 | -1
Two waves having sinusoidal waveforms have different wavelengths and different amplitude. They will be having
View answer and explanation
Correct option: C
Different quality and different intensity
The correct answer is C (Different quality and different intensity) because waves with different amplitudes have different intensities, and waves with different wavelengths have different qualities (timbres).
236
Medium
236 of 524
Application
+4 | -1
A progressive wave of frequency is travelling with a velocity of . Distance between two points of medium having phase difference of will be nearly
(1)
(1)
View answer and explanation
Correct option: C
Option A (0.041 m) is correct because it is the calculated distance between two points with a 30-degree phase difference for a wave with the given frequency and velocity.
237
Medium
237 of 524
Analyzing
+4 | -1
Assertion: Under given conditions of pressure and temperature, sound travels faster in a monoatomic gas than in diatomic gas.
Reason: Opposition for wave to travel is more in diatomic gas than monoatomic gas.
Reason: Opposition for wave to travel is more in diatomic gas than monoatomic gas.
View answer and explanation
Correct option: C
If assertion is true, but reason is false
Option C is correct. The assertion is true because the velocity of sound is greater in monoatomic gases, but the reason is false as diatomic gases have more degrees of freedom, leading to more energy absorption and thus, a slower speed of sound.
238
Medium
238 of 524
Remembering
+4 | -1
Ultrasonic waves are produced by
View answer and explanation
Correct option: A
Piezoelectric effect
Option A (Piezoelectric effect) is correct because ultrasonic waves are commonly produced using the piezoelectric effect, where certain materials generate an electric potential in response to mechanical stress, or vice versa.
239
Medium
239 of 524
Application
+4 | -1
Ultrasonic waves of frequency are used to detect tumour in soft tissues. The speed of sound in tissue is and that in air is . Find the wavelength of this ultrasonic wave in air and in tissue.
View answer and explanation
Correct option: A
Option A () is correct because it correctly calculates the wavelengths in air and tissue using the given speeds and frequency.
240
Medium
240 of 524
Application
+4 | -1
The displacement of a wave travelling in the -direction is given by meters, where is expressed in meters and is second. The speed of the wave-motion, in , is
View answer and explanation
Correct option: B
300
Option B (300) is correct because the speed of the wave is calculated by dividing the angular frequency by the wave number.
Revision notes and key takeaways
Review WAVES in your textbook or class notes, then use this set to check your understanding.
Showing 211-240 of 524 questions
