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JEE • PHYSICS • THERMODYNAMICS

Thermodynamics practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 211-240 of 384 questions

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211 Medium
211 of 384
Application +4 | -1
A gas is suddenly expanded such that its final volume becomes 3 times its initial volume. If the specific heat at constant volume of the gas is 2RR, then the ratio of initial to final pressure is nearly equal to
View answer and explanation
Correct option: A
5
Option A (5) is correct because the ratio of initial to final pressure is approximately 5, calculated using the adiabatic process equation and the given specific heat at constant volume.
212 Medium
212 of 384
Understanding +4 | -1
STATEMENT(A): A quasi-static process is
an infinitely slow process such that the
system remains in thermal and mechanical
equilibrium with the surroundings
throughout.

STATEMENT(B): Spontaneous processes of
nature are irreversible.
View answer and explanation
Correct option: C
Both A and B are true
Option C (Both A and B are true) is correct because a quasi-static process is indeed infinitely slow, and spontaneous processes are irreversible.
213 Medium
213 of 384
Application +4 | -1
5 mole of an ideal gas with (γ=7/5)(\gamma = 7/5) initially at STP are compressed adiabatically so that its temperature becomes 400∘C{400^ \circ }C .The increase in the internal energy of gas in kJ is
View answer and explanation
Correct option: B
41.55
Option B (41.55) is correct because the increase in internal energy is calculated using the formula ∆U = nCv∆T, with Cv derived from γ, resulting in approximately 41.55 kJ.
214 Medium
214 of 384
Understanding +4 | -1
Heat is given to an ideal gas in an isothermal process.

A. Internal energy of the gas will decrease.

B. Internal energy of the gas will increase.

C. Internal energy of the gas will not change.

D. The gas will do positive work.

E. The gas will do negative work.

Choose the correct answer from the options given below:
View answer and explanation
Correct option: B
C and D only
Option C and D only is correct because in an isothermal process, the internal energy remains constant, and the gas does positive work when heat is added.
215 Medium
215 of 384
Understanding +4 | -1
Assertion: In free expansion of an ideal gas internal energy is constant.
Reason: No heat is added and no work is done in free expansion.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A is correct because in free expansion, no external pressure opposes the expansion, hence no work is done, and if no heat is exchanged, the internal energy remains constant.
216 Medium
216 of 384
Analyzing +4 | -1
By opening the door of a refrigerator inside a closed room
View answer and explanation
Correct option: C
You ultimately warm the room slightly
The correct answer is A because it represents a thermodynamic identity for an ideal gas derived from partial derivatives of pressure, temperature, and volume.
217 Medium
217 of 384
Application +4 | -1
A Carnot engine with its cold body at 17∘C17^{\circ} \mathrm{C} has 50%50 \% efficiency. If the temperature of its hot body is now increased by 145∘C145^{\circ} \mathrm{C}, the efficiency becomes
View answer and explanation
Correct option: B
60%60 \%
Option B (60%60 \% ) is correct because increasing the hot reservoir temperature increases the Carnot efficiency.
218 Medium
218 of 384
Analyzing +4 | -1
Two identical cylinders AA and BB with frictionless pistons contain the same ideal gas at the same temperature and the same volume VV. The mass of gas AA is mAm_A and that of BB is mBm_{B}. The gas in each cylinder is now allowed to expand isothermally to the same final volume 2V2 {V}. The change in the pressure in A{A} and BB are found to be ΔP\Delta P and 2ΔP2 \Delta P respectively. Then,
View answer and explanation
Correct option: C
2mA=mB2 m_A=m_B
Option C (2mA=mB2 m_A=m_B) is correct because it is derived from the isothermal expansion and pressure change relationships for ideal gases.
219 Medium
219 of 384
Application +4 | -1
An ideal gas is made to go through a cyclic thermodynamical process in four steps. The amount of heat involved are Q1=600J,Q2=−400J,Q3=−300J{Q_1} = 600J,{Q_2} = - 400J,{Q_3} = - 300J and Q4{Q_4}=200 J respectively. The corresponding work involved are W1=300J,W2=−200J,W3=−150J{W_1} = 300J,{W_2} = - 200J,{W_3} = - 150J and W4{W_4}. What is the value of W4{W_4}
View answer and explanation
Correct option: C
150J150J
Option C (150 J) is correct because it applies the first law of thermodynamics for a cyclic process, where the net heat equals the net work done.
220 Medium
220 of 384
Application +4 | -1
One mole of an ideal monatomic gas at temperature T0T_0 expands slowly according to the law P/V=P / V= constant. If the final temperature is 3T03 T_0, heat supplied to the gas is:
View answer and explanation
Correct option: C
4RT04 {R} T_{{0}}
Option C (4RT04 {R} T_{{0}}) is correct because the heat supplied is calculated using the molar heat capacity for the given process and the change in temperature.
221 Medium
221 of 384
Analyzing +4 | -1
CvandCp{C_v}and{C_p} denote the molar specific heat capacities of a gas at constant volume and constant pressure, respectively. Then
View answer and explanation
Correct option: B
Cp+Cv{C_p} + {C_v} is larger for a diatomic ideal gas than for a monoatomic ideal gas
Option B (Cp+Cv{C_p} + {C_v} is larger for a diatomic ideal gas than for a monoatomic ideal gas) is correct because both CpC_p and CvC_v are larger for diatomic gases compared to monatomic gases.
222 Medium
222 of 384
Application +4 | -1
What will be the change in internal energy for 1 g1 \mathrm{~g} of water when its phase changes from liquid phase to vapour phase? At atmospheric pressure, 1 g1 \mathrm{~g} of water has a volume 1 cm31 \mathrm{~cm}^3 in liquid phase and 1671 cm31671 \mathrm{~cm}^3 in vapour phase. (Latent heat of water is 2256 J/g2256 \mathrm{~J} / \mathrm{g}.)
View answer and explanation
Correct option: A
2086.8 J
Option A (2086.8 J) is correct because it is calculated by subtracting the work done during phase change from the latent heat.
223 Easy
223 of 384
Understanding +4 | -1
Assertion: In adiabatic process work is independent of path.
Reason: In adiabatic process work done is equal to negative of change in internal energy.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and Reason is the correct explanation of Assertion
Option A is correct because in an adiabatic process, the work done is independent of the path and is equal to the negative change in internal energy, which is the correct explanation.
224 Medium
224 of 384
Understanding +4 | -1
Statement I: In an isothermal process (quasistatic), the heat exchange between the system and surroundings takes place even though the gas has the same temperature as that of the surrounding.

Statement II: There is an infinitesimal difference in temperature between the system and the surroundings.
View answer and explanation
Correct option: A
Statement I is true, Statement II is true; Statement II is the correct explanation for Statement I
Statement I is true, Statement II is true; Statement II is the correct explanation for Statement I because heat exchange in an isothermal process requires an infinitesimal temperature difference.
225 Medium
225 of 384
Understanding +4 | -1
An ideal gas undergoing adiabatic change has the following pressure-temperature relationship
View answer and explanation
Correct option: D
P1−γTγ=P^{1-\gamma} T^\gamma= constant
The correct answer is P1−γTγ=P^{1-\gamma} T^{\gamma}= constant because this relationship is derived from the adiabatic process equation and the ideal gas law.
226 Medium
226 of 384
Application +4 | -1
An ideal monoatomic gas given mass is heated at constant pressure. In this process, the fraction supplied heat energy used for the increase of the internal energy of the gas is
View answer and explanation
Correct option: B
45780
The correct answer is B (03-May) because the fraction of heat energy used to increase internal energy is the ratio of specific heat at constant volume to specific heat at constant pressure, which is 3/5 for a monoatomic gas.
227 Easy
227 of 384
Understanding +4 | -1
A thermodynamical system is changed from state(p1V1)to(p2,V2)\left( {{p_1}{V_1}} \right)\mathrm{to}\left( {{p_2},{V_2}} \right) by two different processes, the quantity which will remain same will be
View answer and explanation
Correct option: D
ΔQ−ΔW\mathrm{\Delta }Q - \mathrm{\Delta }W
Option D (ΔQ−ΔW{\Delta }Q - {\Delta }W) is correct because the change in internal energy (ΔU{\Delta }U) is path-independent and equals ΔQ−ΔW{\Delta }Q - {\Delta }W.
228 Medium
228 of 384
Understanding +4 | -1
Choose the incorrect statement from the following S1 : The efficiency of a heat engine can be 1, but the coefficient of performance of a refrigerator can never be infinity S2 : The first law of thermodynamics is basically the principle of conservation of energy S3 : The second law of thermodynamics does not allow several phenomena consistent with the first law S4 : A process, whose sole result is the transfer of heat from a colder object to a hotter object is impossible
View answer and explanation
Correct option: A
S1
Option S1 is incorrect because the coefficient of performance of a refrigerator can be greater than 1, even approaching infinity under ideal conditions, while the efficiency of a heat engine is always less than 1.
229 Medium
229 of 384
Remembering +4 | -1
In an isothermal change, an ideal gas obeys
View answer and explanation
Correct option: A
Boyle’s law
Option A (Boyle’s law) is correct because Boyle's law states that for an ideal gas at constant temperature, the pressure and volume are inversely proportional.
230 Medium
230 of 384
Understanding +4 | -1
(A): The internal energy of an ideal gas does not change during an isothermal process.
(R): In isothermal process product of pressure and volume is constant.
View answer and explanation
Correct option: A
Both (A) and (R) are true and (R) is the correct explanation of (A)
Option A is correct because in an isothermal process, the temperature remains constant, and for an ideal gas, internal energy depends only on temperature; also, Boyle's law states that for a fixed mass of gas at constant temperature, the product of pressure and volume is constant.
231 Medium
231 of 384
Application +4 | -1
In a thermodynamic process, helium gas obeys the law TP2/5=\frac{{T}}{{P}^{2 / 5}}= constant. The heat given to the gas when temperature of 2 moles of gas is raised from TT to 2T2 T
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because the process described is adiabatic, meaning no heat is exchanged with the surroundings.
232 Medium
232 of 384
Understanding +4 | -1
A gas is being compressed adiabatically. The specific heat of the gas during compression is
View answer and explanation
Correct option: A
Zero
Option A is correct because in an adiabatic process, there is no heat exchange with the surroundings, meaning the specific heat is zero.
233 Medium
233 of 384
Remembering +4 | -1
The ideal gas equation for an adiabatic process is:
View answer and explanation
Correct option: A
PVγ=P V^\gamma= constant
Option A (PVγ=P V^\gamma= constant) is correct because this is the standard equation for an adiabatic process.
234 Medium
234 of 384
Understanding +4 | -1
(A): A refrigerator transfers heat from lower temperature to higher temperature.
(R): Heat cannot be transferred from lower temperature to higher temperature without doing any external work.
View answer and explanation
Correct option: B
Both (A) and (R) are true and (R) is not the correct explanation of (A)
Option B is correct because a refrigerator does transfer heat from a lower to a higher temperature, and this requires external work, as stated by the second law of thermodynamics.
235 Medium
235 of 384
Application +4 | -1
A vessel containing 5 litres of a gas at 0.8 M pressure, is connected to an evacuated vessel of volume 3 litres. The resultant pressure inside will be assuming whole system to the isolated.
View answer and explanation
Correct option: B
0.5 m
Option B (0.5 m) is correct because it is calculated using Boyle's Law, where the product of pressure and volume remains constant in an isolated system.
236 Medium
236 of 384
Understanding +4 | -1
In a cyclic process
View answer and explanation
Correct option: C
Change in internal energy is always zero
Option C (Change in internal energy is always zero) is correct because in a cyclic process, the system returns to its initial state, meaning the initial and final internal energies are the same.
237 Medium
237 of 384
Understanding +4 | -1
Statement I: The internal energy of a perfect gas is entirely kinetic and depends only on absolute temperature of the gas and not on its pressure or volume.

Statement II: A perfect gas is heated keeping pressure constant and later at constant volume. For the same amount of heat the temperature of the gas at constant pressure is lower than that at constant volume.
View answer and explanation
Correct option: B
Statement I is true, Statement II is true; Statement II is not the correct explanation for Statement I
Option B (Statement I is true, Statement II is true; Statement II is not the correct explanation for Statement I) is correct because both statements are true, but they are independent of each other.
238 Medium
238 of 384
Application +4 | -1
One mole of an ideal mono atomic gas is compressed isothermally in a rigid vessel to double its pressure at room temperature, 270C{27^0}C. The work done on the gas will be
View answer and explanation
Correct option: D
300 R ln 2
Option D (300 R ln 2) is correct because the work done in an isothermal compression is calculated using W=nRTln⁡(P1P2)W = nRT \ln(\frac{{P_1}}{{P_2}}).
239 Medium
239 of 384
Understanding +4 | -1
In an isothermal expansion of an ideal gas, select the wrong statement.
View answer and explanation
Correct option: D
The work done by the gas is equal to the change in its internal energy
Option D (The work done by the gas is equal to the change in its internal energy) is the wrong statement because in an isothermal process, the change in internal energy is zero, and the work done is equal to the heat supplied.
240 Medium
240 of 384
Remembering +4 | -1
The specific heat relation for ideal gas is
View answer and explanation
Correct option: B
CP−CV=R{C_P} - {C_V} = R
Option B (CP−CV=R{C_P} - {C_V} = R) is correct because this is the Mayer's relation for ideal gases, relating specific heat at constant pressure and volume to the universal gas constant.
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