JEE PHYSICS MCQ: THERMODYNAMICS

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Application +4 | -1

A cylinder of mass

1kg

is given heat of

20000J

at atmospheric pressure. If initially temperature of cylinder is

{20^ \circ }C

, then work done by the cylinder will be (Given that Specific heat of cylinder

= 400J k{g^{ - 1}}

), Coefficient of volume expansion

= 9 \times {10^{ - 5}}^ \circ {C^{ - 1}}

, Atmospheric pressure

= {10^5}N/{m^2}

and density of cylinder

9000kg/{m^3}

)

View answer and explanation

Correct option: B

0.05J

Option B (0.05J) is correct because it is calculated using the formula for work done by a gas at constant pressure.

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