JEE PHYSICS MCQ: THERMODYNAMICS

1 Medium

1 of 1

Understanding +4 | -1

c_p

and

c_v

denote the specific heats (per unit mass of an ideal gas of molecular weight

M

), then

View answer and explanation

Correct option: C

c_p-c_v=R/M

Option C is correct because the relationship between specific heats and the gas constant is cp - cv = R/M.

More Questions from THERMODYNAMICS

Practice All Chapter MCQs →

0.25\,\,{m^3}

{10^3}N/{m^2},

T

P

V

\left( {\gamma = \frac{{{C_p}}}{{{C_v}}}} \right)