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JEE • PHYSICS • SEMI CONDUCTOR DEVICES

Semi conductor devices practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 370 questions

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91 Medium
91 of 370
Understanding +4 | -1
Using Boolean algebra, the value of (A⋅B)+A(A \cdot B)+A is equal to
View answer and explanation
Correct option: D
(A⋅Aˉ)+A(A \cdot \bar{A})+A
Option D ((A⋅Aˉ)+A(A \cdot \bar{A})+A) is correct because using Boolean algebra, (A⋅B)+A(A \cdot B)+A simplifies to A, which is equivalent to (A⋅Aˉ)+A(A \cdot \bar{A})+A.
92 Medium
92 of 370
Analyzing +4 | -1
Assertion : Absorption factor for GaAs\mathrm{GaAs} is larger as compared to Si\mathrm{Si} for sunlight.

Reason : ΔEg\Delta \mathrm{E}_{\mathrm{g}} is more for GaAs\mathrm{GaAs}.
View answer and explanation
Correct option: B
If both Assertion and Reason are true but Reason is not a correct explanation of the Assertion
Option B is correct because while both the assertion and reason are true, the band gap energy difference doesn't directly explain the absorption factor difference.
93 Medium
93 of 370
Remembering +4 | -1
For an insulator the forbidden energy gap is
View answer and explanation
Correct option: C
5 eV
Option C (5 eV) is correct because insulators have a large forbidden energy gap, typically greater than 3 eV, which prevents electrons from easily moving to the conduction band.
94 Medium
94 of 370
Remembering +4 | -1
Which one of the following is the weakest kind of bonding in solids
View answer and explanation
Correct option: C
Vander Waals
Option C (Vander Waals) is correct because Vander Waals forces are weak intermolecular forces arising from temporary dipoles.
95 Medium
95 of 370
Remembering +4 | -1
Zener breakdown in a semi-conductor diode occurs when
View answer and explanation
Correct option: B
Reverse bias exceeds certain value
Option B (Reverse bias exceeds certain value) is correct because Zener breakdown occurs when a high reverse voltage creates a strong electric field in the depletion region.
96 Medium
96 of 370
Understanding +4 | -1
The addition of antimony atoms to a sample of intrinsic germanium transforms it to a material which is
View answer and explanation
Correct option: C
NN-type semiconductor
Option C (NN-type semiconductor) is correct because antimony is a pentavalent impurity, which donates extra electrons to the germanium lattice, creating an N-type semiconductor.
97 Medium
97 of 370
Application +4 | -1
In a common base transistor amplifier, the input and the output resistance are 500 Ω500 ~\Omega and 40 Ω40 ~\Omega, and the emitter current is 1.0 mA1.0 \mathrm{~mA}. Find the input and the output voltages. Given α=0.95\alpha=0.95
View answer and explanation
Correct option: C
38V38 V
The correct answer is C (38V38 V) because the output voltage is calculated by multiplying the collector current (αiE\alpha i_E) by the output resistance.
98 Medium
98 of 370
Understanding +4 | -1
Platinum and silicon are heated upto 250∘C{250^ \circ }C and after that cooled. In the process of cooling
View answer and explanation
Correct option: B
Resistance of silicon will increase and that of platinum will decrease
Option B (Resistance of silicon will increase and that of platinum will decrease) is correct because silicon has a negative temperature coefficient and platinum has a positive temperature coefficient.
99 Medium
99 of 370
Remembering +4 | -1
The barrier potential of a p-n junction does not depends on:

(a) types of semi conductor material

(b) physical shape or size of the diode

(c) design of the diode

Which one of the following is correct:
View answer and explanation
Correct option: C
b and c only
Option C (b and c only) is correct because the barrier potential of a p-n junction depends on the type of semiconductor material and the amount of doping, but not on the physical shape or size, or the design of the diode.
100 Medium
100 of 370
Understanding +4 | -1
An intrinsic semiconductor at 0 K temperature behaves like
View answer and explanation
Correct option: D
Insulator
Option D (Insulator) is correct because at 0 K, there are no free electrons or holes available for conduction in an intrinsic semiconductor.
101 Medium
101 of 370
Understanding +4 | -1
The density for simple cubic lattice is (where AA is atomic weight, NN is Avogadro’s number and aa is a lattice parameter)
View answer and explanation
Correct option: C
ANa3\frac{A}{{N{a^3}}}
Option C (ANa3\frac{A}{{N{a^3}}}) is correct because the density of a simple cubic lattice is calculated by dividing the mass of the unit cell (A/N) by the volume of the unit cell (a3a^3).
102 Hard
102 of 370
Understanding +4 | -1
Consider the following statements I and II and
identify the correct answer from the given options.

Statement-I: A zener diode should be connected
in reverse bias for proper functioning.

Statement-II: The potential barrier of a silicon
p-n junction lies between 2 V and 5 V.

Choose the correct answer from the options given
below.
View answer and explanation
Correct option: C
Statement-I is true but Statement-II is false
Option C is correct because a Zener diode operates in reverse bias, and the potential barrier of a silicon p-n junction is typically around 0.7V, not between 2V and 5V.
103 Medium
103 of 370
Remembering +4 | -1
Which of the following materials in non crystalline
View answer and explanation
Correct option: C
Wood
Option C (Wood) is correct because wood lacks a long-range ordered structure, which is characteristic of crystalline materials.
104 Medium
104 of 370
Analyzing +4 | -1
The Boolean equation x=[(A+B‾)⋅(B+C)]⋅B\mathrm{x}=[(\mathrm{A}+\overline{\mathrm{B}}) \cdot(\mathrm{B}+\mathrm{C})] \cdot \mathrm{B} can be simplified to
View answer and explanation
Correct option: C
x=A⋅B\mathrm{x}=\mathrm{A} \cdot \mathrm{B}
Option C (x=A⋅B) is correct because the Boolean expression simplifies to A AND B using Boolean algebra rules.
105 Medium
105 of 370
Application +4 | -1
A diode is connected to a forward bias to a battery of emf 5V and a series resistance R. In its V-I characteristics it is found that a minimum current of 1 mA flows at the knee point. The maximum value of R will be
View answer and explanation
Correct option: B
4.3 K Ω4.3\,K\,\Omega
Option B (4.3 KΩ4.3\,K\Omega) is correct because it is the maximum resistance value calculated using Ohm's law and the given voltage and current values at the knee point of the diode.
106 Medium
106 of 370
Understanding +4 | -1
Intrinsic semiconductor is electrically neutral. Extrinsic semiconductor having large number of current carriers would be
View answer and explanation
Correct option: D
Electrically neutral
Option D (Electrically neutral) is correct because extrinsic semiconductors, whether N-type or P-type, maintain overall electrical neutrality.
107 Medium
107 of 370
Understanding +4 | -1
Assertion : During everse biasing a diode does not Conduct current

Reason : It narrows the depletion layer
View answer and explanation
Correct option: C
If Assertion is True but the reason is false
Option C (If Assertion is True but the reason is false) is correct because a diode does not conduct current during reverse biasing, but the depletion layer widens, not narrows.
108 Medium
108 of 370
Understanding +4 | -1
Statement-I: In common base configuration, the current gain of the transistor is less than unity.

Statement-II: The collector terminal is reverse biased for amplification.
View answer and explanation
Correct option: A
If both statements are correct.
Option A (If both statements are correct) is correct because in a common base configuration, the current gain is less than unity, and the collector terminal is reverse biased for amplification.
109 Medium
109 of 370
Remembering +4 | -1
What is the coordination number of sodium ions in the case of sodium chloride structure
View answer and explanation
Correct option: A
6
Option A (6) is correct because in the NaCl structure, each sodium ion is surrounded by six chloride ions.
110 Medium
110 of 370
Remembering +4 | -1
The temperature coefficient of a zener mechanism is
View answer and explanation
Correct option: A
Negative
Option A (Negative) is correct because the temperature coefficient of a Zener diode is typically negative, meaning its breakdown voltage decreases with increasing temperature.
111 Medium
111 of 370
Understanding +4 | -1
If a PN junction diode of depletion layer width WW and barrier height V0{V_0} is forward biased, then
View answer and explanation
Correct option: D
both WW and V0{V_0} decrease
Option D (both WW and V0{V_0} decrease) is correct because in forward bias, the applied voltage opposes the barrier potential, reducing the depletion width and barrier height.
112 Medium
112 of 370
Analyzing +4 | -1
Assertion: Silicon is preferred over germanium for making semiconductor devices.

Reason: The energy gap for germanium is more than the energy gap of silicon.
View answer and explanation
Correct option: C
Assertion is true but reason is false
The correct answer is C because while the assertion that silicon is preferred is true, the reason stating germanium has a larger energy gap is false.
113 Medium
113 of 370
Application +4 | -1
Calculate the current amplification factor β\beta (beta) when change in collector current is 3 mA and change in base current is 10  μA10\,\,\mu A
View answer and explanation
Correct option: B
300
Option B (300) is correct because the current amplification factor beta is the ratio of change in collector current to change in base current.
114 Medium
114 of 370
Remembering +4 | -1
Pentavalent impurity is called
View answer and explanation
Correct option: B
Donor
Option B (Donor) is correct because pentavalent impurities donate extra electrons to the semiconductor, hence they are called donors.
115 Medium
115 of 370
Remembering +4 | -1
Zener diode is a heavily doped P-N junction and
operated in
View answer and explanation
Correct option: A
reverse bias
Option A (reverse bias) is correct because Zener diodes are designed to operate in the reverse breakdown region to regulate voltage.
116 Medium
116 of 370
Remembering +4 | -1
In a P-N junction, there is no appreciable current
if
View answer and explanation
Correct option: B
P section negative and N-section positive
Option B (P section negative and N-section positive) is correct because a P-N junction does not conduct appreciable current when reverse biased, which occurs when the P-side is negative and the N-side is positive.
117 Medium
117 of 370
Understanding +4 | -1
The visible LED are made of a material having energy gap:
View answer and explanation
Correct option: A
Larger than 1.8 eV1.8 \mathrm{~eV}
Option A is correct because visible LEDs emit light in the visible region, which corresponds to energy gaps larger than 1.8 eV.
118 Medium
118 of 370
Understanding +4 | -1
The effect of increase in temperature on the number of electrons in conduction band (ne)\left(n_{\mathrm{e}}\right) and resistance of a semiconductor will be as
View answer and explanation
Correct option: B
nen_{\mathrm{e}} increases, resistance decreases
Option B (nen_e increases, resistance decreases) is correct because in semiconductors, increasing temperature leads to more electrons in the conduction band and a decrease in resistance.
119 Medium
119 of 370
Understanding +4 | -1
For a junction diode the ratio of forward current (IF)\left( {{I_F}} \right) and reverse current (Ir)\left( {{I_r}} \right) is

[Ie={I_e} =electronic charge, V=V =voltage applied across junction, k=k = Boltzmann constant, T=T =temperature in kelvin]
View answer and explanation
Correct option: D
(eV/kT−1)\left( {{e^{V/kT}} - 1} \right)
Option D ((eV/kT−1)\left( {{e^{V/kT}} - 1} \right)) is correct because it represents the ratio of forward current to reverse current in a p-n junction diode.
120 Medium
120 of 370
Application +4 | -1
A transistor is operated in common – emitter configuration at VC=2 V{V_C} = 2\,V such that a change in the base current from 100 μA100\,\mu A to 200 μA200\,\mu A produces a change in the collector current is 5 mA to 10 mA then current gain is
View answer and explanation
Correct option: D
50
Option D (50) is correct because the current gain is calculated as the change in collector current divided by the change in base current.
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