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JEE • PHYSICS • SEMI CONDUCTOR DEVICES

Semi conductor devices practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 301-330 of 370 questions

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301 Medium
301 of 370
Remembering +4 | -1
In CECE mode, the input characteristics of a transistor is the variation of
View answer and explanation
Correct option: A
IB{I_B} against VBE{V_{BE}} at constant VCE{V_{CE}}
Option A (IB{I_B} against VBE{V_{BE}} at constant VCE{V_{CE}}) is correct because the input characteristics in CE mode show the relationship between base current and base-emitter voltage at a fixed collector-emitter voltage.
302 Medium
302 of 370
Understanding +4 | -1
In a diode, when there is a saturation current, the plate resistance will be
View answer and explanation
Correct option: D
Infinite quantity
Option D is correct because at saturation, the current is constant regardless of voltage changes, implying infinite plate resistance.
303 Medium
303 of 370
Remembering +4 | -1
In a common base amplifier, the phase difference between the input signal voltage and output voltage is
View answer and explanation
Correct option: C
Zero
Option C (Zero) is correct because in a common base amplifier, the input and output voltages are in phase.
304 Medium
304 of 370
Understanding +4 | -1
Given below are two statements: One is labelled as Assertion A and the other is labelled as Reason R.
Assertion A: n-p-n transistor permits more current than a p-n-p transistor.
Reason R: Electrons have greater mobility as a charge carrier.
Choose the correct answer from the options given below:
View answer and explanation
Correct option: A
Both A and R are true, and R is correct explanation of A.
The correct answer is A (Both A and R are true, and R is correct explanation of A) because n-p-n transistors allow more current due to the higher mobility of electrons, which is the majority carrier.
305 Medium
305 of 370
Remembering +4 | -1
Which of the following gates are called universal gates?
View answer and explanation
Correct option: C
Both 1 and 2
Option C (Both 1 and 2) is correct because both NAND and NOR gates can be used to implement any other logic gate, making them universal gates.
306 Medium
306 of 370
Remembering +4 | -1
Zenor diode works on the principle of
View answer and explanation
Correct option: A
Reverse bias
Option A (Reverse bias) is correct because Zener diodes are designed to operate in the reverse breakdown region, maintaining a constant voltage across them when reverse biased.
307 Medium
307 of 370
Application +4 | -1
When the reverse bias in a junction diode is changed from 5V to 15V, the value of current changes from 38 μA38\,\mu A to 88 μA88\,\mu A. The reverse resistance of the junction diode will be
View answer and explanation
Correct option: B
2×105 Ω2 \times {10^5}\,\Omega
Option B (2×105 Ω2 \times {10^5}\,\Omega) is correct because it is calculated using Ohm's law for the change in voltage and current in the reverse bias.
308 Easy
308 of 370
Understanding +4 | -1
If a LED forward biased, then
View answer and explanation
Correct option: A
electrons from the nn - type side cross the p−np-n junction and recombine with holes in the pp - type side
Option A (electrons from the nn - type side cross the p−np-n junction and recombine with holes in the pp - type side) is correct because in forward bias, electrons move from the n-side to the p-side and recombine with holes, leading to light emission in an LED.
309 Medium
309 of 370
Understanding +4 | -1
A piece of copper and another of germanium are cooled from room temperature to 77 K, the resistance of
View answer and explanation
Correct option: C
Copper decreases and germanium increases
Option B is correct because both the assertion and the reason are true, but the reason is not the correct explanation of the assertion. Vibrational degrees of freedom become significant at high temperatures, and diatomic gases do have vibrational degrees of freedom.
310 Medium
310 of 370
Remembering +4 | -1
If a transistor, the emitter, base and collector are respectively
View answer and explanation
Correct option: A
Heavily doped, lightly doped, moderately doped
Option A (Heavily doped, lightly doped, moderately doped) is correct because the emitter needs a high carrier concentration, the base needs minimal recombination, and the collector handles a significant current.
311 Medium
311 of 370
Understanding +4 | -1
Statement-I: A p−n\mathrm{p-n} junction with reverse bias can be used as a photodiode to measure light intensity.

Statement-II: In a reverse bias condition the current is small but it is more sensitive to changes in incident light intensity.
View answer and explanation
Correct option: A
If both statements are correct.
Option A is correct because a reverse-biased p-n junction can be used as a photodiode to measure light intensity, and the current in reverse bias is small but highly sensitive to changes in incident light intensity.
312 Medium
312 of 370
Understanding +4 | -1
A piece of copper and another of germanium are cooled from temperature to 80∘ K.80^\circ \,K. The resistance of
View answer and explanation
Correct option: D
Copper decreases and germanium increases
Option D (Copper decreases and germanium increases) is correct because copper is a metal and its resistance decreases with decreasing temperature, while germanium is a semiconductor and its resistance increases with decreasing temperature.
313 Medium
313 of 370
Remembering +4 | -1
Bonding in a germanium crystal (semi-conductor) is
View answer and explanation
Correct option: D
Covalent
Option D (Covalent) is correct because germanium, like silicon, forms a crystal lattice through covalent bonds.
314 Medium
314 of 370
Understanding +4 | -1
Electric conduction in semi-conductor takes place due to
View answer and explanation
Correct option: C
Both electrons and holes
Option C (Both electrons and holes) is correct because both electrons and holes contribute to the electric current in a semiconductor.
315 Medium
315 of 370
Remembering +4 | -1
Let np  and ne{n_p}\,\,{\text{and }}{n_e} be the number of holes and conduction electrons in an intrinsic semiconductor. Then
View answer and explanation
Correct option: B
np=ne{n_p} = {n_e}
Option B (np=ne{n_p} = {n_e}) is correct because, in an intrinsic semiconductor, the number of holes is equal to the number of conduction electrons.
316 Medium
316 of 370
Understanding +4 | -1
In order to forward bias a PNPN junction, the negative terminal of battery is connected to
View answer and explanation
Correct option: C
NN-side
Option C is correct because to forward bias a PN junction, the negative terminal of the battery is connected to the N-side, and the positive terminal to the P-side.
317 Medium
317 of 370
Understanding +4 | -1
In an nn-type semiconductor, the fermi energy level lies
View answer and explanation
Correct option: A
In the forbidden energy gap nearer to the conduction band
Option A (In the forbidden energy gap nearer to the conduction band) is correct because in an n-type semiconductor, the Fermi level is close to the conduction band due to the presence of excess electrons.
318 Medium
318 of 370
Understanding +4 | -1
A LED (light emitting diode) in its proper Operation is
View answer and explanation
Correct option: B
A heavily doped p-n junction in forward biased
Option B (A heavily doped p-n junction in forward biased) is correct because LEDs require heavy doping and forward bias to emit light efficiently.
319 Medium
319 of 370
Understanding +4 | -1
If ne{n_e} and vd{v_d} be the number of electrons and drift velocity in a semiconductor. When the temperature is increased
View answer and explanation
Correct option: A
ne{n_e} increases and vd{v_d} decreases
Option A is correct because in a semiconductor, increasing the temperature increases the number of free electrons (nen_e), but the increased scattering reduces the drift velocity (vdv_d).
320 Medium
320 of 370
Understanding +4 | -1
CC and SiSi both have same lattice structure, having 4 bonding electrons in each. However, CC is insulator where as Si is intrinsic semiconductor. This is because
View answer and explanation
Correct option: C
The four bonding electrons in the case of CC lie in the second orbit, whereas in the case of SiSi they lie in the third
The difference in conductivity between C and Si is due to the energy band gap, which is influenced by the orbital location of bonding electrons. Carbon's electrons are closer to the nucleus, resulting in a larger energy gap.
321 Medium
321 of 370
Understanding +4 | -1
In semiconductors at room temperature: -
View answer and explanation
Correct option: A
The valence band is partially empty and conduction band is partially filled
Option A is correct because, at room temperature, some electrons in semiconductors gain enough energy to move from the valence band to the conduction band, resulting in both bands being partially filled.
322 Medium
322 of 370
Analyzing +4 | -1
A⋅Bˉ+Aˉ⋅B‾\overline{A \cdot \bar{B}+\bar{A} \cdot B} is equivalent to
View answer and explanation
Correct option: B
(A+Bˉ)+(Aˉ+B)(A+\bar{B})+(\bar{A}+B)
Option D ((A+B)⋅(Aˉ+Bˉ)(A+B) \cdot(\bar{A}+\bar{B})) is correct because it represents the simplified form of the given Boolean expression after applying De Morgan's law and simplification.
323 Medium
323 of 370
Understanding +4 | -1
Zener diodes have higher dopant densities as compared to ordinary p-n junction diodes. This
View answer and explanation
Correct option: C
decreases the width of depletion layer but increases the electric field
Option C is correct because higher dopant densities in Zener diodes decrease the depletion layer width and increase the electric field.
324 Medium
324 of 370
Understanding +4 | -1
Statement A: In intrinsic semiconductors, conductivity is mainly due to the breakage of covalent bonds.
Statement B: In extrinsic semiconductors, the conductivity is mainly due to the addition of impurities.
View answer and explanation
Correct option: C
Both A and B are true
Option C is correct because both statements are true: intrinsic semiconductors conduct due to broken covalent bonds, and extrinsic semiconductors conduct due to added impurities.
325 Medium
325 of 370
Understanding +4 | -1
When a P-N junction is forward biased, the flow of current across the junction is mainly due to
View answer and explanation
Correct option: B
Diffusion of charges
Option B (Diffusion of charges) is correct because in forward bias, the majority carriers diffuse across the junction, contributing significantly to the current.
326 Medium
326 of 370
Remembering +4 | -1
For germanium crystal, the forbidden energy gap in joules is
View answer and explanation
Correct option: A
1.12×10−191.12 \times {10^{ - 19}}
Option A (1.12×10−191.12 \times {10^{ - 19}}) is correct because the forbidden energy gap for germanium is approximately 0.7 eV, which is equal to 1.12×10−191.12 \times {10^{ - 19}} joules.
327 Medium
327 of 370
Remembering +4 | -1
For LED’s to emit light in visible region of electromagnetic light, it should have energy band gap in the range of:
View answer and explanation
Correct option: D
1.7 eV to 3.0 eV
Option D (1.7 eV to 3.0 eV) is correct because this range corresponds to the energy of photons in the visible light spectrum.
328 Medium
328 of 370
Understanding +4 | -1
Which of the following statements is not correct when a junction diode is in forward bias?
View answer and explanation
Correct option: D
Electrons on nn-side and holes on pp-side will move away from junction.
Option D is correct because in forward bias, electrons from the n-side and holes from the p-side move towards the junction, not away from it.
329 Medium
329 of 370
Understanding +4 | -1
For a transistor α\alpha and β\beta are given as α=ICIE\alpha = \frac{{{I_C}}}{{{I_E}}} and β=ICIE\beta = \frac{{{I_C}}}{{{I_E}}}. Then, the correct relation between α\alpha and β\beta will be
View answer and explanation
Correct option: B
β=α1−α\beta = \frac{\alpha }{{1 - \alpha }}
Option B is correct because the correct relation between α\alpha and β\beta is β=α1−α\beta = \frac{\alpha}{1 - \alpha}.
330 Medium
330 of 370
Understanding +4 | -1
In forward bias, the width of potential barrier in a PP-NN junction diode
View answer and explanation
Correct option: B
Decreases
Option B (Decreases) is correct because forward bias reduces the potential barrier width by reducing the depletion region.
Revision notes and key takeaways

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