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JEE • PHYSICS • SEMI CONDUCTOR DEVICES

Semi conductor devices practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 271-300 of 370 questions

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271 Medium
271 of 370
Understanding +4 | -1
Avalanche breakdown of p-n junction diode is due to
View answer and explanation
Correct option: A
Collision of electrons with atoms
Option A (Collision of electrons with atoms) is correct because avalanche breakdown occurs due to the impact ionization caused by colliding electrons.
272 Medium
272 of 370
Understanding +4 | -1
In a PP-type semiconductor
View answer and explanation
Correct option: A
Current is mainly carried by holes
Option A (Current is mainly carried by holes) is correct because P-type semiconductors are doped with trivalent impurities, creating an excess of holes.
273 Medium
273 of 370
Understanding +4 | -1
Which of the following statements are CORRECT?

Statement I: When a battery is connected across the junction diode with its negative terminal connected to the p-side and the positive terminal connected to the n\mathrm{n}-side, the diode is said to be forward biased.

Statement II: In forward bias condition, if the bias voltage is greater than the barrier potential, the majority carries move towards the junction and cross it.

Statement III: In reverse biasing of a diode, the majority carriers are pulled away from the junction, making the depletion layer wider.
View answer and explanation
Correct option: B
II and III
Option B (II and III) is correct. Statement I is incorrect because forward bias requires the positive terminal to be connected to the p-side and the negative terminal to the n-side.
274 Medium
274 of 370
Understanding +4 | -1
Assertion: Positive feedback is essential for converting a transistor into an oscillator.
Reason: Positive feedback works between cut-off and saturation region.
View answer and explanation
Correct option: B
If both Assertion and Reason are true, but Reason is not the correct explanation of Assertion
Option B is correct because while both the assertion and reason are true, the reason doesn't directly explain why positive feedback is essential for an oscillator. Positive feedback is needed to sustain oscillations, but the cut-off and saturation region is not the primary reason.
275 Medium
275 of 370
Remembering +4 | -1
The saturation current in a diode valve is governed by
View answer and explanation
Correct option: C
Richardson’s law
Option C (Richardson’s law) is correct because Richardson's law describes the relationship between the saturation current and the temperature of the cathode in a diode valve.
276 Medium
276 of 370
Application +4 | -1
The conductivity of an intrinsic semiconductor depends on temperature as σ=σ0e−ΔE/2kT\sigma=\sigma_0 e^{-\Delta E / 2 k T}, where σ0\sigma_0 is a constant. Find the temperature at which the conductivity of an intrinsic germanium semiconductor will be double of its value at T=300 KT=300 \mathrm{~K}. Assume that the gap for germanium is 0.650 eV0.650 \mathrm{~eV} and remains constant as the temperature is increased.
View answer and explanation
Correct option: A
318 K318 \mathrm{~K}
Option A (318 K318 \mathrm{~K}) is correct because it is the temperature at which the conductivity of the germanium semiconductor doubles, calculated using the given formula.
277 Medium
277 of 370
Understanding +4 | -1
In semiconductor diode, the barrier potential offers opposition to flow of
View answer and explanation
Correct option: A
Majority charge carriers in both regions
Option A is correct because the barrier potential in a semiconductor diode opposes the flow of majority charge carriers in both regions.
278 Medium
278 of 370
Analyzing +4 | -1
Assertion : When the temperature of a semiconductor is increased, then its resistance decreases

Reason : The energy gap between conduction band and valence band is very small
View answer and explanation
Correct option: A
If both Assertion & reason are True & the reason is a correct explanation of the assertion
Option A (If both Assertion & reason are True & the reason is a correct explanation of the assertion) is correct because increasing temperature increases conductivity in semiconductors due to their small energy gap.
279 Medium
279 of 370
Analyzing +4 | -1
Assertion: A P-N photodiode is made from a semiconductor for which Eg=2.8eV\mathrm{Eg}=2.8 \mathrm{eV}. This photodiode will not detect the wavelength of 6000 nm6000 \mathrm{~nm}.

Reason: A PN photodiode detects wavelength I if hcλ>Eg\frac{h c}{\lambda} > E_g
View answer and explanation
Correct option: B
Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion
Option B (Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion) is correct because both statements are correct, but the reason doesn't explain the assertion.
280 Medium
280 of 370
Remembering +4 | -1
In a cubic unit cell of bcc structure, the lattice points (ieie, number of atoms) are
View answer and explanation
Correct option: A
2
Option A (2) is correct because a body-centered cubic (bcc) unit cell has atoms at each of the 8 corners (each contributing 1/8) and one atom at the center, totaling 2 atoms per unit cell.
281 Medium
281 of 370
Understanding +4 | -1
In an unbiased p-n junction, holes diffuse from the p-region to n-region because of
View answer and explanation
Correct option: C
the higher hole concentration in p-region than that in n-region
Option C is correct because holes diffuse from the p-region to the n-region due to the higher concentration of holes in the p-region compared to the n-region.
282 Medium
282 of 370
Understanding +4 | -1
Consider the following statements (A) and (B) and identify the correct answer.
(A) Zener diode can be used as voltage regulator.
(B) In unbiased p-n junction, at thermal equilibrium, drift current is equal to diffusion current.
View answer and explanation
Correct option: B
Both A and B are correct
Option B (Both A and B are correct) is correct because a Zener diode maintains a constant voltage in reverse breakdown and in an unbiased p-n junction, the drift and diffusion currents are equal at thermal equilibrium.
283 Medium
283 of 370
Remembering +4 | -1
The energy band gap is maximum in
View answer and explanation
Correct option: C
Insulators
Option C (Insulators) is correct because insulators have the largest energy band gap, preventing electrons from easily moving to the conduction band and thus inhibiting electrical conductivity.
284 Medium
284 of 370
Understanding +4 | -1
Assertion : Generally semiconductors do not obey Ohm’ law.

Reason : Electric current is determined by the rate of flow of charge carriers.
View answer and explanation
Correct option: B
If both Assertion and Reason are true but Reason is not a correct explanation of the Assertion
Option B (If both Assertion and Reason are true but Reason is not a correct explanation of the Assertion) is correct because both statements are true, but the reason doesn't explain why semiconductors don't obey Ohm's law.
285 Medium
285 of 370
Understanding +4 | -1
Why do we prefer indirectly heated cathode to the directly heated cathode?
View answer and explanation
Correct option: A
Equality of potential throughout the cathode
Option A (Equality of potential throughout the cathode) is correct because indirectly heated cathodes provide a more uniform potential, leading to consistent electron emission.
286 Medium
286 of 370
Remembering +4 | -1
In PP-type semiconductor the majority and minority charge carriers are respectively
View answer and explanation
Correct option: D
Holes and electrons
Option D (Holes and electrons) is correct because P-type semiconductors have holes as majority carriers and electrons as minority carriers.
287 Medium
287 of 370
Remembering +4 | -1
Radiowaves of constant amplitude can be generated with
View answer and explanation
Correct option: D
Oscillator
Option B (Transistor) is correct because a transistor, when properly biased, can act as an oscillator to generate a sine wave of constant amplitude.
288 Medium
288 of 370
Application +4 | -1
A common emitter amplifier has a voltage gain of 50, an input impedance of 100 Ω\Omega and an output impedance of 200Ω\Omega . The power gain of the amplifier is
View answer and explanation
Correct option: C
1250
Option C (1250) is correct because the power gain is calculated using the formula: Power gain = (Voltage gain)2 / (Impedance gain).
289 Medium
289 of 370
Application +4 | -1
Calculate the current amplification factor β\beta (beta) when change in collector current is 1 mA and change in base current is 20 μA.20\,\mu A.
View answer and explanation
Correct option: B
50
Option B (50) is correct because the current amplification factor (beta) is the ratio of the change in collector current to the change in base current.
290 Medium
290 of 370
Remembering +4 | -1
The coordination number of hexagonal close packing (hcp) is
View answer and explanation
Correct option: C
12
Option C is correct because in hexagonal close packing (hcp), each atom is surrounded by 12 nearest neighbors.
291 Medium
291 of 370
Remembering +4 | -1
The majority charge carriers in PP-type semiconductor are
View answer and explanation
Correct option: C
Holes
Option C (Holes) is correct because P-type semiconductors are doped with acceptor impurities, which create an excess of holes (positive charge carriers).
292 Medium
292 of 370
Remembering +4 | -1
The typical ionisation energy of a donar in silicon is
View answer and explanation
Correct option: C
0.1 eV
Option C (0.1 eV) is correct because the typical ionization energy of a donor in silicon is around 0.04 to 0.1 eV.
293 Medium
293 of 370
Application +4 | -1
The energy gap of silicon is 1.14 eV. The maximum wavelength at which silicon starts energy absorption, will be(h=6.62×10−34  Js;c=3×108ms−1h = 6.62 \times {10^{ - 34}}\mathrm{\;Js};\mathrm{c} = 3 \times {10^8}\mathrm{m}{\mathrm{s}^{ - 1}})
View answer and explanation
Correct option: D
10888  A∘10888\;\mathop A\limits^ \circ
Option D (10888  A∘10888\;\mathop A\limits^ \circ) is correct because it is calculated using the formula λ=hcE\lambda = \frac{{hc}}{E} with the given energy gap.
294 Medium
294 of 370
Understanding +4 | -1
The output from a NAND gate is 0 when the inputs A, B and C are such that.
View answer and explanation
Correct option: D
A = B = C = 1
The correct answer is D (A = B = C = 1) because a NAND gate outputs 0 only when all inputs are 1.
295 Medium
295 of 370
Analyzing +4 | -1
Given below are two statements : one is labelled as Assertion A and the other is labelled as Reason R.

Assertion A: Photodiodes are preferably operated in reverse bias condition for light intensity measurement.

Reason R: The current in the forward bias is more than the current in the reverse bias for a p−np-n junction diode.

In the light of the above statements, choose the correct answer from the options given below:
View answer and explanation
Correct option: D
Both A and R are true but R is NOT the correct explanation of A
Option D is correct because both the assertion and reason are true, but the reason doesn't explain why photodiodes are operated in reverse bias.
296 Medium
296 of 370
Remembering +4 | -1
In a fcc lattice structure, what is the effective number of atoms?
View answer and explanation
Correct option: A
4
Option A (4) is correct because in a face-centered cubic (fcc) lattice, there are 4 effective atoms per unit cell.
297 Medium
297 of 370
Understanding +4 | -1
During regulation action of a Zener diode correct statement is :-

(a) the current and voltage across the Zener remains fixed.

(b) the current through the series resistance (RS)\left(\mathrm{R}_{\mathrm{S}}\right) changes.

(c) the Zener resistance is constant.

(d) the resistance offered by the Zener diode changes.
View answer and explanation
Correct option: D
b and d
Option D (b and d) is correct because during Zener diode regulation, the current through the series resistance changes, and the resistance offered by the Zener diode changes to maintain a constant voltage.
298 Medium
298 of 370
Application +4 | -1
The voltage gain of an amplifier with 9% negative feedback is 10. The voltage gain without feedback will be
View answer and explanation
Correct option: B
100
Option B (100) is correct because the voltage gain without feedback can be calculated using the formula for amplification with negative feedback.
299 Medium
299 of 370
Understanding +4 | -1
The forbidden energy band gap in conductors, semiconductors and insulators are EG1,  EG2E{G_1},\;E{G_2} and EG3E{G_3} respectively. The relation them is
View answer and explanation
Correct option: B
EG1<EG2<EG3E{G_1} < E{G_2} < E{G_3}
Option D is correct because Planck's constant has the dimensions of energy divided by frequency, which is equivalent to angular momentum.
300 Medium
300 of 370
Understanding +4 | -1
A transistor oscillator is

(i) An amplifier with positive feedback

(ii) An amplifier with reduced gain

(iii) The one in which DC supply energy is converted into AC output energy. Then
View answer and explanation
Correct option: C
(i) and (iii) are correct
Option C is correct because a transistor oscillator is an amplifier with positive feedback and converts DC supply energy into AC output energy.
Revision notes and key takeaways

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