Skip to main content
Back to GRAVITATION

Your Progress

0 / 392 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • PHYSICS • GRAVITATION

Gravitation practice · Medium

Choose an answer to check it, or open “View answer” to study the explanation. Sign in to save progress to your account.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 121-150 of 392 questions

Preparing practice and saved progress…

121 Medium
121 of 392
Application +4 | -1
Halley’s comet has a period of 76, had distance of closest approach to the sun equal to 8.9×1010m8.9 \times {10^{10}}\mathrm{m}. the comet’s farthest distance from the sun if the mass of sun is 2×1030kg and G=6.67×10112 \times {10^{30}}kg\,and\,G = 6.67 \times {10^{11}} in MKS units is
View answer and explanation
Correct option: C
5.3×1012m5.3 \times {10^{12}}\mathrm{m}
Option C (5.3×1012m5.3 \times {10^{12}}\mathrm{m}) is correct because it is calculated using Kepler's third law and the properties of an ellipse.
122 Medium
122 of 392
Understanding +4 | -1
Find the sum of given series

F=GMmr2[1+12+14+…∞∣ ]F=\frac{G M m}{r^2}\left[\left.1+\frac{1}{2}+\frac{1}{4}+\ldots \infty \right\rvert\,\right]
View answer and explanation
Correct option: A
F=2GMmr2F=\frac{2 G M m}{r^2}
Option A is correct because the given series is a geometric progression with a sum to infinity of 2, resulting in the force being 2GMm/r².
123 Medium
123 of 392
Understanding +4 | -1
If the angular speed of the earth is doubled, the value of acceleration due to gravity (g) at the north pole
View answer and explanation
Correct option: C
Remains same
Option C (Remains same) is correct because the acceleration due to gravity at the North Pole is independent of the Earth's angular speed.
124 Medium
124 of 392
Understanding +4 | -1
The value of G{G} varies with
View answer and explanation
Correct option: D
None of these
Option D (None of these) is correct because G, the universal gravitational constant, is a fundamental constant and does not vary with height, depth, or the radius of the planet.
125 Medium
125 of 392
Application +4 | -1
What is the maximum height attained by a body projected with a velocity equal to one-third of the escape velocity from the surface of the earth? (Radius of the earth =R=R )
View answer and explanation
Correct option: D
R/8R / 8
Option D (R/8R / 8) is correct because it is derived from the conservation of energy principle, considering the initial velocity as one-third of the escape velocity.
126 Medium
126 of 392
Understanding +4 | -1
Assertion: Gravitational potential is maximum at infinite.
Reason: Gravitational potential is the amount of work done to shifting a unit mass from infinity to a given point in gravitational attraction force field.
View answer and explanation
Correct option: A
If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion
Option A (If both Assertion & Reason are True & the Reason is a correct explanation of the Assertion) is correct because gravitational potential is defined as the work done in bringing a unit mass from infinity, and it's maximum (zero) at infinity.
127 Medium
127 of 392
Application +4 | -1
Two identical solid copper spheres of radius R are placed in contact with each other. The gravitational attraction between them is proportional to
View answer and explanation
Correct option: C
R4{R^4}
Option C (R4{R^4}) is correct because the gravitational force is proportional to the product of masses divided by the square of the distance between them.
128 Medium
128 of 392
Application +4 | -1
The height above surface of earth where the value of gravitational acceleration is the value of
gravitational acceleration is one fourth of that at surface, will be
View answer and explanation
Correct option: D
Re{{R_e}}
Option D (ReR_e) is correct because it satisfies the condition where the gravitational acceleration is one-fourth of its value at the surface of the Earth.
129 Medium
129 of 392
Understanding +4 | -1
If the mass of a body on the earth surface is MM, then its mass on the moon surface, is
View answer and explanation
Correct option: C
MM
Option C (MM) is correct because mass is an intrinsic property of an object and does not change with location.
130 Medium
130 of 392
Application +4 | -1
The acceleration of a train travelling with speed of 400 m/s as it goes round a curve of radius 160 m, is
View answer and explanation
Correct option: A
1  km/s21\;km/{s^2}
Option A (1;km/s21\\;km/{s^2}) is correct because the centripetal acceleration is calculated using the formula a=v2ra = \frac{{{v^2}}}{r}.
131 Medium
131 of 392
Understanding +4 | -1
What does not change in the field of central force
View answer and explanation
Correct option: D
Angular momentum
Option D (Angular momentum) is correct because in a central force field, the torque is zero, leading to the conservation of angular momentum.
132 Medium
132 of 392
Application +4 | -1
A satellite which is geostationary in a particular orbit is taken to another orbit. Its distance from the centre of earth in new orbit is 2 times that of the earlier orbit. The time period in the second orbit is
View answer and explanation
Correct option: B
482  hours48\sqrt 2 \;hours
The correct answer is 48248\sqrt{2} hours because the time period is proportional to r3/2r^{3/2} according to Kepler's third law.
133 Medium
133 of 392
Understanding +4 | -1
Given below are two statements:

Statement I : Rotation of the earth shows effect on the value of acceleration due to gravity (g)(\mathrm{g}).

Statement II : The effect of rotation of the earth on the value of ' gg ' at the equator is minimum and that at the pole is maximum.

In the light of the above statements, choose the correct answer from the options given below
View answer and explanation
Correct option: D
Statement I is true but statement II is false
Option D (Statement I is true but statement II is false) is correct because the effect of Earth's rotation on 'g' is maximum at the equator and minimum at the poles.
134 Medium
134 of 392
Application +4 | -1
Two spherical balls of mass 1 kg and 4 kg are separated by a distance of 12 cm. The distance from 1 kg at which the gravitational force on any mass becomes zero.
View answer and explanation
Correct option: A
4 cm
Option A (4 cm) is correct because the distance from the 1 kg mass where the gravitational force is zero is calculated using the formula for the neutral point between two masses.
135 Medium
135 of 392
Application +4 | -1
The escape velocity from the earth is 11.2  kms  −111.2\;\mathrm{kms}{\;^{ - 1}}. The escape velocity from a planet having twice the radius and the same mean density is (in  kms−1)(\mathrm{in\;km}{\mathrm{s}^{ - 1}})
View answer and explanation
Correct option: D
22.4
Option D (22.4) is correct because the escape velocity is directly proportional to the radius when the mean density is the same, thus doubling the radius doubles the escape velocity.
136 Medium
136 of 392
Understanding +4 | -1
If W1,W2  and  W3{W_1},{W_2}\,\,\mathrm{and}\,\,{W_3} represent the work done in moving a particle from A to B along three different paths 1, 2, and 3 respectively, (as shown in the figure) in the gravitational field of a point mass mm, find the correct relation between W1,W2  and  W3{W_1},{W_2}\,\,\mathrm{and}\,\,{W_3} .
View answer and explanation
Correct option: B
W1=W2=W3{W_1} = {W_2} = {W_3}
Option B (W1=W2=W3{W_1} = {W_2} = {W_3}) is correct because the gravitational force is conservative, and the work done is path-independent.
137 Medium
137 of 392
Understanding +4 | -1
Time period of a simple pendulum inside a satellite orbiting Earth is:
View answer and explanation
Correct option: B
Infinite
Option B is correct. Inside a satellite orbiting Earth, the effective gravitational acceleration is zero, leading to an infinite time period for a simple pendulum.
138 Medium
138 of 392
Understanding +4 | -1
Where will it be profitable to purchase 1 kilogram sugar
View answer and explanation
Correct option: B
At equator
Option B (At equator) is correct because the weight of an object is least at the equator due to the Earth's rotation and shape.
139 Medium
139 of 392
Application +4 | -1
With what velocity should a particle be projected so that its height becomes equal to radius of earth?
View answer and explanation
Correct option: A
(GMR)1/2\left(\frac{G M}{R}\right)^{1 / 2}
Option A ((GMR)1/2\left(\frac{G M}{R}\right)^{1 / 2}) is correct because it is the velocity required for the particle to reach a height equal to the radius of the Earth.
140 Medium
140 of 392
Understanding +4 | -1
Select the incorrect statements from the following.
(i) The orbital velocity of a satellite increases with the radius of the orbit.
(ii) Escape velocity of a particle from the surface of the Earth depends on the speed with which it is fired.
(iii) The time period of a satellite does not depend on the radius of the orbit.
(iv) The orbital velocity is inversely proportional to the square root of the radius of the orbit.
View answer and explanation
Correct option: D
(i), (ii), and (iii)
Option D ((i), (ii), and (iii)) is correct because statements (i), (ii), and (iii) are all incorrect regarding satellite motion and escape velocity.
141 Medium
141 of 392
Understanding +4 | -1
When does the object in a satellite escapes to infinity?
View answer and explanation
Correct option: C
Both (1) and (2)
Option C (Both (1) and (2)) is correct because an object escapes to infinity when its total energy (kinetic + potential) is zero or positive.
142 Medium
142 of 392
Application +4 | -1
A rocket is launched vertical from the surface of the earth of radius RR with an initial speed vv. If atmospheric resistance is neglected, then maximum height attained by the rocket is
View answer and explanation
Correct option: A
h=R(2gRv2−1)h=\frac{R}{\left(\frac{2 g R}{v^2}-1\right)}
Option A (h=R(2gRv2−1)h=\frac{R}{(\frac{2 g R}{v^2}-1)}) is correct because it correctly applies the conservation of energy principle to find the maximum height.
143 Medium
143 of 392
Application +4 | -1
If the escape velocity on the earth is 11.2 Km/s, its value for a planet having double the radius and 8 times the mass of the earth is …… (in km/s)
View answer and explanation
Correct option: B
22.4
Option B (22.4) is correct because the escape velocity is calculated using the relationship between escape velocity, mass, and radius, considering the changes in mass and radius of the planet.
144 Medium
144 of 392
Understanding +4 | -1
Assertion: Gravitational forces do not depend on the medium between the masses.
Reason: Mediating particle responsible for gravitational force is graviton.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B is correct because both the Assertion and Reason are true, but the Reason does not explain the Assertion; gravitational forces are independent of the medium because the gravitational interaction is fundamental, and gravitons (hypothetical) are the mediating particles.
145 Medium
145 of 392
Understanding +4 | -1
Two spheres of mass mm and M are situated in air and the gravitational force between them is FF. The space around the masses is now filled with a liquid of specific gravity 3. The gravitational force will now be
View answer and explanation
Correct option: A
FF
Option A (F) is correct because the gravitational force between two masses is independent of the surrounding medium.
146 Medium
146 of 392
Analyzing +4 | -1
Assertion: The difference in the value of acceleration due to gravity at pole and equator is proportional to square of angular velocity of earth.
Reason: The value of acceleration due to gravity is minimum at the equator and maximum at the pole.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not correct explanation of the assertion.
Option B is correct because both the assertion and the reason are true, but the reason doesn't directly explain why the difference in acceleration due to gravity is proportional to the square of the angular velocity.
147 Medium
147 of 392
Application +4 | -1
A body of mass 5 kg is moving in a circle of radius 1 m with an angular velocity of 2 rad  s−1\mathrm{rad\;}{\mathrm{s}^{ - 1}}. The centripetal force, is
View answer and explanation
Correct option: B
20 N
Option B (20 N) is correct because the centripetal force is calculated using the formula F=mrω2F = mr\omega^2, where m is the mass, r is the radius, and ω\omega is the angular velocity.
148 Medium
148 of 392
Application +4 | -1
The maximum and minimum distances of a comet from the sun are 8×1012m8 \times {10^{12}}m and 1.6×1012m1.6 \times {10^{12}}m . If its velocity when nearest to the sun is 60  m/s60\,\,m/s . What will be its velocity in m/sm/s , when it is farthest?
View answer and explanation
Correct option: A
12
Option A (12) is correct because it is derived from the conservation of angular momentum, where the product of velocity and distance remains constant.
149 Medium
149 of 392
Understanding +4 | -1
The value of gg on the surface of earth is smallest at the equator because
View answer and explanation
Correct option: C
The angular speed of earth is maximum at equator
The correct answer is A (The centripetal force is maximum at equator) because the effective gravity is reduced most at the equator due to the Earth's rotation.
150 Medium
150 of 392
Application +4 | -1
The escape velocity from the earth is 11  km/s11\,\,km/s . The escape velocity from a planet having twice the radius and same density as that of the earth is (in km/skm/s )
View answer and explanation
Correct option: A
22
Option A (22) is correct because escape velocity is proportional to radius times the square root of density, and with twice the radius and same density, it doubles.
Revision notes and key takeaways

Review GRAVITATION in your textbook or class notes, then use this set to check your understanding.

Showing 121-150 of 392 questions

Your practice

0 / 392 answered · 392 remaining · 0% accuracy

Progress is stored on this device. Sign in to save to your account.

✓ Correct · ✗ Incorrect · ○ Unanswered

Practice settings

Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.