JEE PHYSICS MCQ: GRAVITATION

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A body is projected vertically upwards from the surface of planet of mass

\mathrm{M}

and radius

\mathrm{R}

with upward speed

\sqrt{\frac{\mathrm{GM}}{\mathrm{R}}}

. The maximum height attained by body is:

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Correct option: B

\mathrm{R}

Option B (R) is correct because it's derived by equating the change in kinetic energy to the change in potential energy, considering the gravitational potential energy formula.

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The escape velocity for a body projected vertically upwards from the surface of the earth is

11.2\mathrm{\;\;km}{\mathrm{s}^{ - 1}}

. If the body is projected in a direction making an angle of

{45^0}

with the vertical, the escape velocity will be The escape velocity of a body projected from the surface of earth is

v_e

. If the body is projected at an angle

\theta

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