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JEE PHYSICS MCQ: GRAVITATION

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The ratio of the escape velocity to the orbital velocity of a surface satellite of the earth

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Correct option: A

\sqrt 2

Option A (

\sqrt 2

) is correct because the escape velocity is

\sqrt{2}

times the orbital velocity for a satellite orbiting close to the Earth's surface.

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The escape velocity for a body projected vertically upwards from the surface of the earth is

11.2\mathrm{\;\;km}{\mathrm{s}^{ - 1}}

. If the body is projected in a direction making an angle of

{45^0}

with the vertical, the escape velocity will be The escape velocity of a body projected from the surface of earth is

v_e

. If the body is projected at an angle

\theta

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