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JEE PHYSICS MCQ: GRAVITATION

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A body placed at a distance

R_0

from the centre of earth, starts moving from rest. The velocity of the body on reaching at the earth's surface will be

\left(\mathrm{R}_{\mathrm{e}}=\right.

radius of earth and

\mathrm{M}_{\mathrm{e}}=

mass of earth)

View answer and explanation

Correct option: D

\sqrt{2 G M_e\left(\frac{1}{R_e}-\frac{1}{R_0}\right)}

Option D (

\sqrt{2 G M_e\left(\frac{1}{R_e}-\frac{1}{R_0}\right)}

) is correct because it is derived from the conservation of energy principle, equating initial and final energies.

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