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JEE • PHYSICS • GRAVITATION

Gravitation practice · Medium

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 392 questions

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91 Medium
91 of 392
Understanding +4 | -1
Which of the following is/are correct.

I. An object moving the earth under the influence of Earth's gravitational force is in a state of "free-fall".

II. The dominant effect causing a slowdown in the rotation of the earth is the gravitational pull of other planets in the solar system.

III. Generally the path of a projectile from the earth is parabolic but it is elliptical for projectiles going to a very large height.

IV. The path of a projectile is independent of the gravitational force of earth.
View answer and explanation
Correct option: C
I and III
Option C is correct because an object moving under Earth's gravity is in free-fall, and projectile paths are generally parabolic but become elliptical at very large heights.
92 Medium
92 of 392
Analyzing +4 | -1
The earth is an approximate sphere. If the interior contained matter which is not of the same density everywhere, then on the surface of the earth, the acceleration due to gravity
View answer and explanation
Correct option: D
cannot be zero at any point.
The correct answer is D because even with varying densities, the acceleration due to gravity cannot be zero at any point on the Earth's surface.
93 Medium
93 of 392
Application +4 | -1
If the radius of the earth decreases by 10%, the mass remaining unchanged, then the acceleration due to gravity.
View answer and explanation
Correct option: D
increases by more than 19%
Option D (increases by more than 19%) is correct because the acceleration due to gravity increases by more than 19% when the radius decreases by 10%, keeping mass constant.
94 Medium
94 of 392
Application +4 | -1
The ratio of the radii of the planets P1 and P2{P_1}\,and\,{P_2} is a. The ratio of their acceleration due to gravity is b. The ratio of the escape velocities from them will be
View answer and explanation
Correct option: B
ab\sqrt {ab}
Option B (ab\sqrt {ab}) is correct because the escape velocity depends on both the radius and the acceleration due to gravity of the planet.
95 Medium
95 of 392
Analyzing +4 | -1
Observers on the 10th, 5th and ground floor of a tall building measure the velocity of a certain raindrop by some accurate method. Surprisingly the velocity of the raindrop measured by the three observers was found to be the same. This is because
View answer and explanation
Correct option: A
there is no gravitational force acting on the drop
Option B (gravitational force on the raindrop is balanced by the force produced by the surrounding air) is correct because the raindrop reaches terminal velocity where the net force is zero, resulting in constant velocity.
96 Medium
96 of 392
Remembering +4 | -1
The orbital velocity of a body close to the earth's surface is
View answer and explanation
Correct option: A
8 kms−18 \mathrm{~kms}^{-1}
Option A (8 kms−18 \mathrm{~kms}^{-1}) is correct because the orbital velocity close to the Earth's surface is approximately 8 km/s.
97 Medium
97 of 392
Analyzing +4 | -1
Assertion: Gravitational force between two particles is negligibly small compared to the electrical force.
Reason: The electrical force is experienced by charged particles only.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not the correct explanation of assertion
Option B (If both assertion and reason are true but reason is not the correct explanation of assertion) is correct because gravitational force is much weaker than electrical force, and electrical force acts only on charged particles.
98 Medium
98 of 392
Understanding +4 | -1
When earth moves around the sun, the quantity which remains constant is
View answer and explanation
Correct option: D
Areal velocity
Option D (Areal velocity) is correct because according to Kepler's second law, the areal velocity of a planet orbiting the sun remains constant.
99 Medium
99 of 392
Application +4 | -1
Abody weighed 250 N250 \mathrm{~N} on the surface assuming the earth to be a sphere of uniform mass density, how much would it weigh half way down to the centre of the earth?
View answer and explanation
Correct option: C
125 N125 \mathrm{~N}
Option C (125 N125 \mathrm{~N}) is correct because the weight decreases linearly with depth inside the Earth, assuming uniform density.
100 Medium
100 of 392
Application +4 | -1
The mass of a planet that has a moon whose time period and orbital radius are TT and RR respectively can be written as
View answer and explanation
Correct option: A
4π2R3G−1T−24{\pi ^2}{R^3}{G^{ - 1}}{T^{ - 2}}
Option A (4π2R3G−1T−24{\pi ^2}{R^3}{G^{ - 1}}{T^{ - 2}}) is correct because it is derived from equating gravitational force and centripetal force.
101 Medium
101 of 392
Analyzing +4 | -1
Statement I: At height hh from ground and at depth hh below ground, where hh is approximately equal to 0.62R0.62 \mathrm{R}, the value of g\mathrm{g} acceleration due to gravity is same.

Statement II: Value of g\mathrm{g} decreases both sides, in going up and down.
View answer and explanation
Correct option: B
If both Statement - I and Statement - II are true but Statement - II is not the correct explanation of Statement - I.
Option B (If both Statement - I and Statement - II are true but Statement - II is not the correct explanation of Statement - I) is correct because both statements are true, but the general decrease of 'g' doesn't explain the specific height/depth where 'g' is the same.
102 Medium
102 of 392
Application +4 | -1
A point P(R3,0,0)P\left( {R\sqrt 3 ,0,0} \right) lies on the axis of a ring of mass MM and radius RR. The ring is located in y−zy - z plane with its centre at origin OO. A small particle of mass m starts from P and reaches OO under gravitational attraction only. Its speed at OO will be
View answer and explanation
Correct option: A
GMR\sqrt {\frac{{GM}}{R}}
Option A (GMR\sqrt {\frac{{GM}}{R}}) is correct because the speed at O is calculated using conservation of energy.
103 Medium
103 of 392
Application +4 | -1
The radius of the earth is 6.37×106 m6.37 \times 10^6 \mathrm{~m}, its mean density is 5.5×103 kg m−35.5 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3} and G=6.66×10−11 Nm2 kg−2G=6.66 \times 10^{-11}\mathrm{~Nm}^2 \mathrm{~kg}^{-2}. Determine the gravitational potential on the surface of the earth.
View answer and explanation
Correct option: A
−6.22×107 J kg−1-6.22 \times 10^7 \mathrm{~J} \mathrm{~kg}^{-1}
Option A (21\frac{2}{1}) is correct because using the ideal gas law, the ratio of the number of gas molecules in A to B is 2:1.
104 Medium
104 of 392
Application +4 | -1
The time period of a satellite of earth is 24 hours. If the separation between the earth and the satellite is decreased to one fourth of the previous value, then its new time period will become.
View answer and explanation
Correct option: C
3 hours
Option C (3 hours) is correct because the time period is proportional to R(3/2), so reducing the radius to one-fourth reduces the time period to one-eighth of the original, resulting in 3 hours.
105 Medium
105 of 392
Application +4 | -1
A body attains a height equal to the radius of the earth. The velocity of the body with which it was projected is
View answer and explanation
Correct option: A
GMR\sqrt{\frac{G M}{R}}
Option A (GMR\sqrt{\frac{G M}{R}}) is correct because it is the velocity required for a body to reach a height equal to the radius of the Earth, derived from conservation of energy.
106 Medium
106 of 392
Understanding +4 | -1
Consider the following statements and select the correct statement(s).
(i) Gravitational force may be attractive or repulsive.
(ii) Gravitational force between two particles is independent of presence of other particles.
(iii) Gravitational force is a short-range force.
View answer and explanation
Correct option: B
(ii) only
Option B (ii) only is correct because gravitational force is always attractive, is a long-range force, and is independent of the presence of other particles.
107 Medium
107 of 392
Application +4 | -1
At a point above the surface of the earth, the gravitational potential is −5.12×107 J kg−1-5.12 \times 10^7 \mathrm{~J} \mathrm{~kg}^{-1} and the acceleration due to gravity is 6.4 ms−26.4 \mathrm{~ms}^{-2}. Assuming the mean radius of the earth to be 6400 km6400 \mathrm{~km}, calculate the height of this point above the earth's surface.
View answer and explanation
Correct option: A
1600 km1600 \mathrm{~km}
Option A (1600 km) is correct because it is the height calculated by using the gravitational potential and acceleration due to gravity.
108 Medium
108 of 392
Understanding +4 | -1
In a satellite orbiting the earth, a coin is immersed in a jar of
water and released. It will:
View answer and explanation
Correct option: C
remain where left
Option C (remain where left) is correct because in a satellite orbiting the Earth, objects experience weightlessness, so the coin will not sink or rise.
109 Medium
109 of 392
Application +4 | -1
Suppose there existed a planet that went around the sun twice as fast as the earth. What would be its orbital size as compared to that of the earth?
View answer and explanation
Correct option: A
0.63 AU{0 . 6 3} \mathrm{~AU}
Option A (0.63 AU{0 . 6 3} \mathrm{~AU}) is correct because it is calculated using Kepler's Third Law, relating the orbital period and orbital size.
110 Medium
110 of 392
Analyzing +4 | -1
A satellite is in an orbit around the Earth; if its kinetic energy is doubled, then
View answer and explanation
Correct option: D
it will escape out of Earth's gravitational field
Option D is correct. Doubling the kinetic energy increases the satellite's velocity to the escape velocity, causing it to escape Earth's gravitational field.
111 Medium
111 of 392
Application +4 | -1
An object is taken to a height above the surface of earth at a distance 54R\frac{5}{4} R from the centre of the earth. Where radius of earth, R=6400 kmR=6400 \mathrm{~km}. The percentage decrease in the weight of the object will be
View answer and explanation
Correct option: A
{\text{36% }}{\text{36% }}
Option A (36%) is correct because the percentage decrease in weight is calculated by comparing the weight at height 54R\frac{5}{4}R from the center of the Earth to the weight on the surface.
112 Medium
112 of 392
Understanding +4 | -1
Statement I: Escape velocity of a tennis ball from the surface of earth is the same as the escape velocity of a cricket ball from the surface of earth.

Statement II: Escape velocity of a body is independent of the mass of the body
View answer and explanation
Correct option: A
If both Statement- I and Statement- II are true, and Statement - II is the correct explanation of Statement-I.
Option A (If both Statement- I and Statement- II are true, and Statement - II is the correct explanation of Statement-I.) is correct because escape velocity is independent of the mass of the object, making both statements true and related.
113 Medium
113 of 392
Understanding +4 | -1
Two masses 2 kg and 4 kg are separated in air by 10 cm. Now air is replaced by water of density 1000 kg/m31000\,kg/{m^3}, then the percentage change in force is
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because the gravitational force between two masses is independent of the surrounding medium.
114 Medium
114 of 392
Application +4 | -1
A man is standing on an international space station, which is orbiting earth at an altitude 520 Km with a constant speed 7.6 km/s. If the man’s weight is 50 kg, his acceleration is [in m/s2m/{s^2}]
View answer and explanation
Correct option: C
8.4
Option C (8.4) is correct because the acceleration is the gravitational acceleration at the altitude of the space station.
115 Medium
115 of 392
Application +4 | -1
To what height the body is to be raised so that acceleration due to gravity on it is 1% of the value on the surface of earth? (Radius of earth is 6400km)
View answer and explanation
Correct option: A
12800 km
Option A (12800 km) is correct because the height is calculated by setting the acceleration due to gravity to 1% of its surface value and solving for the height using the formula g′=g(RR+h)2g' = g(\frac{R}{R+h})^2.
116 Medium
116 of 392
Application +4 | -1
At what depth below the surface of the earth, the value of gg is the same as that at a height of 5 km?
View answer and explanation
Correct option: D
10 km
Option D (10 km) is correct because the depth at which g is the same as at a height of 5 km is twice the height.
117 Medium
117 of 392
Understanding +4 | -1
Orbital velocity of an artificial does not depend upon
View answer and explanation
Correct option: B
Mass of the satellite
Option B is correct because the orbital velocity depends on the mass of the Earth, the radius of the orbit, and the gravitational constant, but not the mass of the satellite.
118 Medium
118 of 392
Understanding +4 | -1
Given below are two statements:
Statement I: Acceleration due to gravity is different
at different places on the surface of earth.
Statement II: Acceleration due to gravity increases
as we go down below the earth’s surface.
In the light of the above statements, choose the correct answer from the options given below
View answer and explanation
Correct option: B
Statement I is true but Statement II is false
Option B (Statement I is true but Statement II is false) is correct because the acceleration due to gravity varies on the Earth's surface, but decreases as we go deeper.
119 Medium
119 of 392
Understanding +4 | -1
The international space station is maintained in a nearly circular orbit with a mean altitude of 330 km330 \mathrm{~km} and a maximum of 410 km410 \mathrm{~km}. An astronaut is floating in the space station's cabin. The acceleration of astronaut as measured from the earth is
View answer and explanation
Correct option: D
Nearly gg and directed towards the earth
Option D is correct because at the altitude of the space station, the acceleration due to gravity is still nearly g and directed towards the Earth.
120 Medium
120 of 392
Application +4 | -1
If the radius of earth reduces by 4%4 \% and density remains same then escape velocity will
View answer and explanation
Correct option: C
Reduce by 4%4 \%
Option C (Reduce by 4 %) is correct because the escape velocity is directly proportional to the radius when the density remains constant, ve∝Rv_e \propto R.
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