JEE PHYSICS MCQ: GRAVITATION

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The height from the surface of earth at which the gravitational potential energy of a ball of mass

m

is half of that at the centre of earth is (where

R

is the radius of earth)

View answer and explanation

Correct option: B

\frac{R}{3}

Option B (

\frac{R}{3}

) is correct because it is calculated by equating half the gravitational potential energy at the center of the Earth to the gravitational potential energy at a height h from the surface.

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11.2\mathrm{\;\;km}{\mathrm{s}^{ - 1}}

. If the body is projected in a direction making an angle of

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with the vertical, the escape velocity will be The escape velocity of a body projected from the surface of earth is

v_e

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