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JEE • PHYSICS • GRAVITATION

Gravitation practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 151-180 of 450 questions

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151 Medium
151 of 450
Application +4 | -1
Two identical solid copper spheres of radius R are placed in contact with each other. The gravitational attraction between them is proportional to
View answer and explanation
Correct option: C
R4{R^4}
Option C (R4{R^4}) is correct because the gravitational force is proportional to the product of masses divided by the square of the distance between them.
152 Medium
152 of 450
Application +4 | -1
The height above surface of earth where the value of gravitational acceleration is the value of
gravitational acceleration is one fourth of that at surface, will be
View answer and explanation
Correct option: D
Re{{R_e}}
Option D (ReR_e) is correct because it satisfies the condition where the gravitational acceleration is one-fourth of its value at the surface of the Earth.
153 Medium
153 of 450
Understanding +4 | -1
If the mass of a body on the earth surface is MM, then its mass on the moon surface, is
View answer and explanation
Correct option: C
MM
Option C (MM) is correct because mass is an intrinsic property of an object and does not change with location.
154 Medium
154 of 450
Application +4 | -1
The acceleration of a train travelling with speed of 400 m/s as it goes round a curve of radius 160 m, is
View answer and explanation
Correct option: A
1  km/s21\;km/{s^2}
Option A (1;km/s21\\;km/{s^2}) is correct because the centripetal acceleration is calculated using the formula a=v2ra = \frac{{{v^2}}}{r}.
155 Medium
155 of 450
Understanding +4 | -1
What does not change in the field of central force
View answer and explanation
Correct option: D
Angular momentum
Option D (Angular momentum) is correct because in a central force field, the torque is zero, leading to the conservation of angular momentum.
156 Hard
156 of 450
Analyzing +4 | -1
Pertaining to two planets, the ratio of escape velocities from respective surfaces is 1:21: 2, the ratio of the time period of the same simple pendulum at their respective surfaces is 2:12: 1 (in same order). Then the ratio of their average densities is
View answer and explanation
Correct option: C
1:41: 4
Option C is correct because the ratio of average densities is calculated using the ratios of escape velocities and time periods of a simple pendulum.
157 Medium
157 of 450
Application +4 | -1
A satellite which is geostationary in a particular orbit is taken to another orbit. Its distance from the centre of earth in new orbit is 2 times that of the earlier orbit. The time period in the second orbit is
View answer and explanation
Correct option: B
482  hours48\sqrt 2 \;hours
The correct answer is 48248\sqrt{2} hours because the time period is proportional to r3/2r^{3/2} according to Kepler's third law.
158 Medium
158 of 450
Understanding +4 | -1
Given below are two statements:

Statement I : Rotation of the earth shows effect on the value of acceleration due to gravity (g)(\mathrm{g}).

Statement II : The effect of rotation of the earth on the value of ' gg ' at the equator is minimum and that at the pole is maximum.

In the light of the above statements, choose the correct answer from the options given below
View answer and explanation
Correct option: D
Statement I is true but statement II is false
Option D (Statement I is true but statement II is false) is correct because the effect of Earth's rotation on 'g' is maximum at the equator and minimum at the poles.
159 Medium
159 of 450
Application +4 | -1
Two spherical balls of mass 1 kg and 4 kg are separated by a distance of 12 cm. The distance from 1 kg at which the gravitational force on any mass becomes zero.
View answer and explanation
Correct option: A
4 cm
Option A (4 cm) is correct because the distance from the 1 kg mass where the gravitational force is zero is calculated using the formula for the neutral point between two masses.
160 Medium
160 of 450
Application +4 | -1
The escape velocity from the earth is 11.2  kms  −111.2\;\mathrm{kms}{\;^{ - 1}}. The escape velocity from a planet having twice the radius and the same mean density is (in  kms−1)(\mathrm{in\;km}{\mathrm{s}^{ - 1}})
View answer and explanation
Correct option: D
22.4
Option D (22.4) is correct because the escape velocity is directly proportional to the radius when the mean density is the same, thus doubling the radius doubles the escape velocity.
161 Easy
161 of 450
Understanding +4 | -1
According to Newton's law of gravitation, the magnitude of the force FF on point masses m1m_1 and m2m_2 (say) is given by ∣F∣=Gm1m2r2|F|=\frac{G m_1 m_2}{r^2}.
I. This equation is not directly applicable for the gravitational force between extended object (like the earth) and a point mass.
II. This equation can be applied to find the gravitational force between an extended object and a point mass provided rr is the distance of the point mass from the geometric centre of the extended objects.
Which of the following statement(s) about this equation is/are correct?
View answer and explanation
Correct option: A
Only I
Option A is correct because Newton's law of gravitation in its simple form applies directly only to point masses, not extended objects without further calculation.
162 Medium
162 of 450
Understanding +4 | -1
If W1,W2  and  W3{W_1},{W_2}\,\,\mathrm{and}\,\,{W_3} represent the work done in moving a particle from A to B along three different paths 1, 2, and 3 respectively, (as shown in the figure) in the gravitational field of a point mass mm, find the correct relation between W1,W2  and  W3{W_1},{W_2}\,\,\mathrm{and}\,\,{W_3} .
View answer and explanation
Correct option: B
W1=W2=W3{W_1} = {W_2} = {W_3}
Option B (W1=W2=W3{W_1} = {W_2} = {W_3}) is correct because the gravitational force is conservative, and the work done is path-independent.
163 Medium
163 of 450
Understanding +4 | -1
Time period of a simple pendulum inside a satellite orbiting Earth is:
View answer and explanation
Correct option: B
Infinite
Option B is correct. Inside a satellite orbiting Earth, the effective gravitational acceleration is zero, leading to an infinite time period for a simple pendulum.
164 Easy
164 of 450
Remembering +4 | -1
Period of revolution of a geostationary satellite around the earth is
View answer and explanation
Correct option: B
24 hours
Option B (24 hours) is correct because a geostationary satellite has the same period as the Earth's rotation, which is 24 hours.
165 Medium
165 of 450
Understanding +4 | -1
Where will it be profitable to purchase 1 kilogram sugar
View answer and explanation
Correct option: B
At equator
Option B (At equator) is correct because the weight of an object is least at the equator due to the Earth's rotation and shape.
166 Medium
166 of 450
Application +4 | -1
With what velocity should a particle be projected so that its height becomes equal to radius of earth?
View answer and explanation
Correct option: A
(GMR)1/2\left(\frac{G M}{R}\right)^{1 / 2}
Option A ((GMR)1/2\left(\frac{G M}{R}\right)^{1 / 2}) is correct because it is the velocity required for the particle to reach a height equal to the radius of the Earth.
167 Medium
167 of 450
Understanding +4 | -1
Select the incorrect statements from the following.
(i) The orbital velocity of a satellite increases with the radius of the orbit.
(ii) Escape velocity of a particle from the surface of the Earth depends on the speed with which it is fired.
(iii) The time period of a satellite does not depend on the radius of the orbit.
(iv) The orbital velocity is inversely proportional to the square root of the radius of the orbit.
View answer and explanation
Correct option: D
(i), (ii), and (iii)
Option D ((i), (ii), and (iii)) is correct because statements (i), (ii), and (iii) are all incorrect regarding satellite motion and escape velocity.
168 Medium
168 of 450
Understanding +4 | -1
When does the object in a satellite escapes to infinity?
View answer and explanation
Correct option: C
Both (1) and (2)
Option C (Both (1) and (2)) is correct because an object escapes to infinity when its total energy (kinetic + potential) is zero or positive.
169 Medium
169 of 450
Application +4 | -1
A rocket is launched vertical from the surface of the earth of radius RR with an initial speed vv. If atmospheric resistance is neglected, then maximum height attained by the rocket is
View answer and explanation
Correct option: A
h=R(2gRv2−1)h=\frac{R}{\left(\frac{2 g R}{v^2}-1\right)}
Option A (h=R(2gRv2−1)h=\frac{R}{(\frac{2 g R}{v^2}-1)}) is correct because it correctly applies the conservation of energy principle to find the maximum height.
170 Medium
170 of 450
Application +4 | -1
If the escape velocity on the earth is 11.2 Km/s, its value for a planet having double the radius and 8 times the mass of the earth is …… (in km/s)
View answer and explanation
Correct option: B
22.4
Option B (22.4) is correct because the escape velocity is calculated using the relationship between escape velocity, mass, and radius, considering the changes in mass and radius of the planet.
171 Medium
171 of 450
Understanding +4 | -1
Assertion: Gravitational forces do not depend on the medium between the masses.
Reason: Mediating particle responsible for gravitational force is graviton.
View answer and explanation
Correct option: B
If both Assertion & Reason are True but Reason is not a correct explanation of the Assertion
Option B is correct because both the Assertion and Reason are true, but the Reason does not explain the Assertion; gravitational forces are independent of the medium because the gravitational interaction is fundamental, and gravitons (hypothetical) are the mediating particles.
172 Medium
172 of 450
Understanding +4 | -1
Two spheres of mass mm and M are situated in air and the gravitational force between them is FF. The space around the masses is now filled with a liquid of specific gravity 3. The gravitational force will now be
View answer and explanation
Correct option: A
FF
Option A (F) is correct because the gravitational force between two masses is independent of the surrounding medium.
173 Medium
173 of 450
Analyzing +4 | -1
Assertion: The difference in the value of acceleration due to gravity at pole and equator is proportional to square of angular velocity of earth.
Reason: The value of acceleration due to gravity is minimum at the equator and maximum at the pole.
View answer and explanation
Correct option: B
If both assertion and reason are true but reason is not correct explanation of the assertion.
Option B is correct because both the assertion and the reason are true, but the reason doesn't directly explain why the difference in acceleration due to gravity is proportional to the square of the angular velocity.
174 Medium
174 of 450
Application +4 | -1
A body of mass 5 kg is moving in a circle of radius 1 m with an angular velocity of 2 rad  s−1\mathrm{rad\;}{\mathrm{s}^{ - 1}}. The centripetal force, is
View answer and explanation
Correct option: B
20 N
Option B (20 N) is correct because the centripetal force is calculated using the formula F=mrω2F = mr\omega^2, where m is the mass, r is the radius, and ω\omega is the angular velocity.
175 Medium
175 of 450
Application +4 | -1
The maximum and minimum distances of a comet from the sun are 8×1012m8 \times {10^{12}}m and 1.6×1012m1.6 \times {10^{12}}m . If its velocity when nearest to the sun is 60  m/s60\,\,m/s . What will be its velocity in m/sm/s , when it is farthest?
View answer and explanation
Correct option: A
12
Option A (12) is correct because it is derived from the conservation of angular momentum, where the product of velocity and distance remains constant.
176 Easy
176 of 450
Understanding +4 | -1
Assertion: Smaller the orbit of a planet around the sun, shorter is the time it takes to complete.
Reason: According to Kepler's third law of planetary motion, square of time period is proportional to cube of mean distance from the sun.
View answer and explanation
Correct option: A
Assertion is True, Reason is True; Reason is a correct explanation for Assertion
Option A is correct because both the assertion and reason are true, and the reason (Kepler's third law) correctly explains why planets closer to the sun have shorter orbital periods.
177 Medium
177 of 450
Understanding +4 | -1
The value of gg on the surface of earth is smallest at the equator because
View answer and explanation
Correct option: C
The angular speed of earth is maximum at equator
The correct answer is A (The centripetal force is maximum at equator) because the effective gravity is reduced most at the equator due to the Earth's rotation.
178 Easy
178 of 450
Understanding +4 | -1
Assertion: Earth does not retain hydrogen molecules and helium atoms in its atmosphere, but does retain much heavier molecules, such as oxygen and nitrogen.
Reason: Lighter molecules in the atmosphere have translational speed that is greater or closer to escape speed of earth.
View answer and explanation
Correct option: A
Assertion is True, Reason is True; Reason is a correct explanation for Assertion
Option A (Assertion is True, Reason is True; Reason is a correct explanation for Assertion) is correct because lighter molecules have higher average speeds, making it easier for them to reach escape velocity and leave the atmosphere.
179 Medium
179 of 450
Application +4 | -1
The escape velocity from the earth is 11  km/s11\,\,km/s . The escape velocity from a planet having twice the radius and same density as that of the earth is (in km/skm/s )
View answer and explanation
Correct option: A
22
Option A (22) is correct because escape velocity is proportional to radius times the square root of density, and with twice the radius and same density, it doubles.
180 Medium
180 of 450
Remembering +4 | -1
Kepler's law states that, square of the time period of any planet moving around the sun in an elliptical orbit of semi-major axis (R)(R) is directly proportional to
View answer and explanation
Correct option: C
R3{R}^3
Option C (R3{R}^3) is correct because Kepler's third law states that the square of the period is proportional to the cube of the semi-major axis.
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