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JEE PHYSICS MCQ: GRAVITATION

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A chain of 125 links is 1.25 m long and has mass of 2 kg with the ends fastened together. It is set for rotating at 50 revs−1\mathrm{rev}{\mathrm{s}^{ - 1}}, centripetal force on each links is
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Correct option: C
314 N
Option D (None of these) is incorrect. Option A (3.14 N) is incorrect. Option B (0.314 N) is incorrect. Option C (314 N) is correct because it is the centripetal force on each link, calculated using the formula F=mrω2F = mr\omega^2.

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