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JEE • CHEMISTRY • REDOX REACTIONS

Redox reactions practice · Mixed difficulty

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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151 Easy
151 of 264
Understanding +4 | -1
Fluorine is a strong oxidising agent because :
View answer and explanation
Correct option: B
It is very small and has 7 electrons in valency shell
Option B is correct because fluorine's small size and high electronegativity due to its 7 valence electrons make it a strong oxidizing agent, readily accepting electrons.
152 Medium
152 of 264
Analyzing +4 | -1
In the reaction, NaH+H2O→NaOH+H2\mathrm{NaH} + {\mathrm{H}_2}\mathrm{O} \to \mathrm{NaOH} + {\mathrm{H}_2}:
View answer and explanation
Correct option: A
H−{H^ - } is oxidised
The correct answer is A. In the reaction NaH + H2O -> NaOH + H2, H- in NaH is oxidized to H2.
153 Medium
153 of 264
Analyzing +4 | -1
Statement-I: H2SO4\mathrm{H}_2 \mathrm{SO}_4 can act as reducing agent and oxidising agent.

Statement-II: Sulphur can not increase its oxidation number beyond +6.
View answer and explanation
Correct option: D
Statement-I is incorrect but statement-II is correct
Option D is correct because H2SO4 can only act as an oxidizing agent, and sulfur cannot increase its oxidation number beyond +6.
154 Medium
154 of 264
Understanding +4 | -1
Which of the following is not a redox reaction?
View answer and explanation
Correct option: B
NaOH+HCl⟶NaCl+H2O{NaOH}+{HCl} \longrightarrow {NaCl}+{H}_2 {O}
Option B (NaOH+HCl⟶NaCl+H2O\mathrm{NaOH}+{HCl} \longrightarrow {NaCl}+{H}_2 {O}) is correct because it is a neutralization reaction, which involves the combination of an acid and a base to form salt and water, without any change in oxidation states.
155 Medium
155 of 264
Application +4 | -1
Number of moles of MnO4−\mathrm{MnO}_4^ - required to oxidise one mole of ferrous oxalate completely in acidic medium will be :
View answer and explanation
Correct option: D
0.6 mole
Option D (0.6 mole) is correct because 3 moles of MnO4- are required to oxidize 5 moles of ferrous oxalate, thus 0.6 moles are needed for 1 mole.
156 Hard
156 of 264
Analyzing +4 | -1
Identify the substance oxidised, reduced, oxidising agent and reducing agent respectively from the following reaction.

2AgBr(s)+C6H6O2(aq)⟶2Ag(s)+2HBr(aq)+C6H4O2(aq)2 \mathrm{AgBr}(s)+\mathrm{C}_6 \mathrm{H}_6 \mathrm{O}_2(a q) \longrightarrow 2 \mathrm{Ag}(s)+2 \mathrm{HBr}(a q)+\mathrm{C}_6 \mathrm{H}_4 \mathrm{O}_2(a q)
View answer and explanation
Correct option: B
C6H6O2,AgBr,AgBr,C6H6O2\mathrm{C}_6 \mathrm{H}_6 \mathrm{O}_2, \mathrm{AgBr}, \mathrm{AgBr}, \mathrm{C}_6 \mathrm{H}_6 \mathrm{O}_2
Option B (C6H6O2, AgBr, AgBr, C6H6O2) is correct because C6H6O2 is oxidized (reducing agent) and AgBr is reduced (oxidizing agent).
157 Medium
157 of 264
Understanding +4 | -1
For reducing one mole of Fe2+\mathrm{F}{\mathrm{e}^{2 + }}ion to FeFe, the number of faraday of electricity is :
View answer and explanation
Correct option: A
2
Option A (2) is correct because reducing one mole of Fe2+\mathrm{F}{\mathrm{e}^{2 + }} to FeFe requires 2 moles of electrons, which corresponds to 2 Faradays of electricity.
158 Medium
158 of 264
Analyzing +4 | -1
Assertion: Among Br−,O22−,H−\mathrm{Br}^-, \mathrm{O}_2^{2-}, \mathrm{H}^- and NO3−,\mathrm{NO}_3^-, the ions that could not act as oxidising agents are Br−\mathrm{Br}^{-}and H−.\mathrm{H}^{-}.

Reason: Br⊖\mathrm{Br}^{\ominus} and H−\mathrm{H}^{-} could not be reduced.
View answer and explanation
Correct option: A
Assertion is true, Reason is true and Reason is correct explanation for Assertion
Option A (Assertion is true, Reason is true and Reason is correct explanation for Assertion) is correct because Br- and H- are in their lowest oxidation states and cannot be further reduced, thus cannot act as oxidizing agents.
159 Medium
159 of 264
Analyzing +4 | -1
The reaction; H2S+H2O2→2H2O+S{\mathrm{H}_2}\mathrm{S} + {\mathrm{H}_2}{\mathrm{O}_2} \to 2{\mathrm{H}_2}\mathrm{O} + \mathrm{S} shows :
View answer and explanation
Correct option: C
Oxidising action of H2O2{\mathrm{H}_2}{\mathrm{O}_2}
Option C (Oxidising action of H2O2{\mathrm{H}_2}{\mathrm{O}_2}) is correct because hydrogen peroxide oxidizes H2SH_2S to sulfur.
160 Easy
160 of 264
Understanding +4 | -1
Which does not form two or more chlorides?
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Correct option: A
NA
Option A (NA) is correct because Sodium (Na) typically exhibits only one oxidation state (+1) and thus does not form multiple chlorides.
161 Medium
161 of 264
Analyzing +4 | -1
Statement-I: KClO3→KClO4+KCl{KClO}_3 \rightarrow {KClO}_4+{KCl}. This is a disproportionation reaction.
Statement-II: The reaction in which one substance gets oxidised and reduced is known as disproportionation reaction.
View answer and explanation
Correct option: A
Both the statements are correct
Option A (Both the statements are correct) is correct because in the given reaction, chlorine undergoes both oxidation and reduction, which defines a disproportionation reaction.
162 Medium
162 of 264
Application +4 | -1
Oxidation number of carbon in carbon sub oxide (C3O2)\left( {{\mathbf{C}_\mathbf{3}}{\mathbf{O}_\mathbf{2}}} \right)
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Correct option: B
+43+ \frac{4}{3}
Option B (+43+ \frac{4}{3}) is correct because the average oxidation number of carbon in carbon suboxide is calculated to be +4/3.
163 Easy
163 of 264
Understanding +4 | -1
Which of the following statement(s) is/are correct ?

(i) Oxidation state of carbon in C3H4\mathrm{C}_3 \mathrm{H}_4 is −(4/3)-(4 / 3).

(ii) Electrons are never shared in fraction.
View answer and explanation
Correct option: A
(i) and (ii)
Option A ((i) and (ii)) is correct because the oxidation state of carbon in C3H4\mathrm{C}_3 \mathrm{H}_4 is indeed −(4/3)-(4 / 3), and electrons are never shared in fractions.
164 Medium
164 of 264
Understanding +4 | -1
Cr2O72−\mathrm{Cr}_2 \mathrm{O}_7^{2-} is not a self indicator but
View answer and explanation
Correct option: B
oxidises the indicator substance
Option B (oxidises the indicator substance) is correct because Cr2O72−\mathrm{Cr}_2 \mathrm{O}_7^{2-} acts as an oxidizing agent and oxidizes the indicator substance.
165 Easy
165 of 264
Remembering +4 | -1
Oxidation is a process which involves :
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Correct option: A
de-electronation
Option A (de-electronation) is correct because oxidation involves the loss of electrons, which is also known as de-electronation.
166 Medium
166 of 264
Remembering +4 | -1
The maximum oxidation state of oxygen is
View answer and explanation
Correct option: C
+2+2
Option C (+2) is correct because the maximum oxidation state of oxygen is +2, which occurs when it is bonded to fluorine in OF2OF_2.
167 Medium
167 of 264
Understanding +4 | -1
A solution of sulphur dioxide in water reacts with H2S{H}_2 {S} precipitating sulphur. Here sulphur dioxide acts as
View answer and explanation
Correct option: A
As oxidising agent
The correct answer is A (As oxidising agent) because sulphur dioxide gains electrons from hydrogen sulfide, thus reducing itself and oxidizing hydrogen sulfide to sulphur.
168 Medium
168 of 264
Analyzing +4 | -1
Assertion: KCl/NaCl/NH4Cl{KCl} / {NaCl} / {NH}_4 {Cl} etc. cannot be used in the salt bridge of a cell containing silver.

Reason: A salt bridge contains concentrated solution of an inert electrolyte like KCl,KNO3,NH4NO3{KCl}, {KNO}_3, {NH}_4 {NO}_3 etc. or solidified solution of such as electrolyte in agar-agar and gelatine.
View answer and explanation
Correct option: B
If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion.
The correct answer is B (If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion) because while the reason correctly describes the composition of a salt bridge, it doesn't explain why certain salts cannot be used with silver.
169 Medium
169 of 264
Application +4 | -1
Consider the following reaction, xMnO4−+yC2O42−+zH+→xMn2++2yCO2+z2H2OxMnO_4^ - + y{C_2}O_4^{2 - } + z{H^ + } \to xM{n^{2 + }} + 2yC{O_2} + \frac{z}{2}{H_2}O The values of xx, yy and zz in the reaction are respectively
View answer and explanation
Correct option: C
2, 5 and 16
Option C (2, 5 and 16) is correct because balancing the redox reaction using the half-reaction method yields these stoichiometric coefficients.
170 Easy
170 of 264
Application +4 | -1
Select the compound in which the oxidation state of oxygen is -1
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Correct option: D
BaO2Ba{O_2}
Option D (BaO2Ba{O_2}) is correct because in peroxides like barium peroxide, oxygen exhibits an oxidation state of -1.
171 Medium
171 of 264
Understanding +4 | -1
In which reaction is hydrogen acting as an oxidising agent?
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Correct option: B
With lithium to give lithium hydride
Option B (With lithium to give lithium hydride) is correct because hydrogen gains an electron (reduction) to form H−1H^{-1}, thus acting as an oxidizing agent.
172 Medium
172 of 264
Analyzing +4 | -1
Which of the following involves transfer of five electrons?
View answer and explanation
Correct option: A
MnO4−→Mn2+{MnO}_4^{-} \rightarrow {Mn}^{2+}
Option A (MnO4−→Mn2+{MnO}_4^{-} \rightarrow {Mn}^{2+}) is correct because the oxidation state of Mn changes from +7 to +2, involving a transfer of 5 electrons.
173 Medium
173 of 264
Understanding +4 | -1
Given below are two statements.
One is labelled as Assertion (A) and the other is labelled as Reason (R).
Assertion (A) Aluminium is extracted from bauxite by the electrolysis of molten mixture of Al2O3A{l_2}{O_3} with cryolite.
Reason (R) The oxidation state of AlAl in cryolite is +3.
In the light of the above statements, choose the most appropriate answer from the options given below.
View answer and explanation
Correct option: D
Both (A) and (R) are true but (R) is not the correct explanation of (A)
The correct answer is D (Both (A) and (R) are true but (R) is not the correct explanation of (A)) because both the assertion and reason are true, but the reason doesn't explain the assertion.
174 Easy
174 of 264
Application +4 | -1
What is the oxidation number of chlorine in ClO3−\mathrm{ClO}_3^ -?
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Correct option: A
+5+ 5
Option A (+5) is correct because the oxidation number of Cl in ClO3−ClO_3^- is calculated by setting the sum of oxidation numbers to the overall charge.
175 Medium
175 of 264
Analyzing +4 | -1
Which of the following is not a redox reaction?
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Correct option: B
CaCO3(s)→ heat CaO(s)+CO2(g)\mathrm{CaCO}_3\text{(s)}\xrightarrow{\text { heat }} \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g})
Option B (CaCO3(s)→ heat CaO(s)+CO2(g)\mathrm{CaCO}_3\text{(s)}\xrightarrow{\text { heat }} \mathrm{CaO}(\mathrm{s})+\mathrm{CO}_2(\mathrm{g})) is the correct answer because there is no change in oxidation states of any element during the reaction, indicating it is not a redox reaction.
176 Easy
176 of 264
Understanding +4 | -1
Which of the following elements does not show disproportionation tendency?
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Correct option: C
F\mathrm{F}
Option F (Fluorine) is correct because it is the most electronegative element and has a fixed oxidation state of -1, thus it cannot undergo disproportionation.
177 Medium
177 of 264
Analyzing +4 | -1
Which of the following is not an intramolecular redox reaction?
View answer and explanation
Correct option: D
2H2O2+2H2O+O22 \mathrm{H}_2 \mathrm{O}_2+2 \mathrm{H}_2 \mathrm{O}+\mathrm{O}_2
Option D (2H2O2+2H2O+O22 \mathrm{H}_2 \mathrm{O}_2+2 \mathrm{H}_2 \mathrm{O}+\mathrm{O}_2) is correct because it is an intermolecular redox reaction, not intramolecular.
178 Easy
178 of 264
Remembering +4 | -1
An increase in the oxidation number of the element is termed as
View answer and explanation
Correct option: B
oxidation
Option B (oxidation) is correct because an increase in the oxidation number of an element is defined as oxidation.
179 Medium
179 of 264
Understanding +4 | -1
Oxalic acid on reacting with acidified KMnO4\mathrm{KMn}{\mathrm{O}_4} is oxidised to :
View answer and explanation
Correct option: C
CO2 and H2O\mathrm{C}{\mathrm{O}_2}\,and\,{\mathrm{H}_2}\mathrm{O}
Option C (CO2 and H2O\mathrm{C}{\mathrm{O}_2}\,and\,{\mathrm{H}_2}\mathrm{O}) is correct because oxalic acid is oxidized to carbon dioxide and water by acidified potassium permanganate.
180 Easy
180 of 264
Understanding +4 | -1
The oxide, which cannot act as a reducing agent, is
View answer and explanation
Correct option: A
CO2{CO}_2
Option A (CO2{CO}_2) is correct because carbon is already in its highest oxidation state and cannot be further oxidized to act as a reducing agent.
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