Assertion: The oxidation number of $\mathrm{S}$ is $+6$ in $\mathrm{H}_2 \mathrm{SO}_4$. Reason: $\mathrm{H}_2 \mathrm{SO}_4$ has one peroxide linkage.

If both Assertion and Reason are correct and Reason is the correct explanation of Assertion

If both Assertion and Reason are correct, but Reason is not the correct explanation of Assertion

If both Assertion and Reason are incorrect

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JEE • CHEMISTRY • REDOX REACTIONS

Redox reactions practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 73 questions

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1 Easy

1 of 73

Remembering +4 | -1

The oxidation number of

\mathrm{H}

in sodium hydride is

View answer and explanation

Correct option: C

-1

Option C (-1) is correct because hydrogen has an oxidation number of -1 when bonded to a more electropositive element like sodium.

2 Easy

2 of 73

Remembering +4 | -1

A substance, that by its sharp colour change indicates the completion of reaction is known as :

View answer and explanation

Correct option: C

Indicator

Option A (Square of the orbital wave function i.e.,

\psi^2

) is correct because the probability of finding an electron at a point within an atom is proportional to the square of the orbital wave function,

\psi^2

3 Easy

3 of 73

Analyzing +4 | -1

Statement-I: In the reaction between potassium permanganate and potassium iodide, permanganate ions act as oxidising agent.

Statement-II: Oxidation state of manganese changes from +2 to +7 during the above reaction.

View answer and explanation

Correct option: C

Statement-I is correct but statement-II is incorrect

Option C is correct. Statement-I is correct because potassium permanganate acts as an oxidizing agent. Statement-II is incorrect because the oxidation state of manganese changes from +7 to +2 (in acidic medium) or +4 (in neutral or basic medium).

4 Easy

4 of 73

Application +4 | -1

The oxidation number of hydrogen in hydrolith

\left( {\mathbf{Ca}{\mathbf{H}_\mathbf{2}}} \right)

View answer and explanation

Correct option: B

- 1

Option B (-1) is correct because in metal hydrides like CaH₂, hydrogen has an oxidation state of -1.

5 Easy

5 of 73

Analyzing +4 | -1

when

{\mathbf{K}_\mathbf{2}}\mathbf{C}{\mathbf{r}_\mathbf{2}}{\mathbf{O}_\mathbf{7}}

is converted to

{\mathbf{K}_\mathbf{2}}\mathbf{Cr}{\mathbf{O}_\mathbf{4}}

, the change in the oxidation of chromium is

View answer and explanation

Correct option: A

Option A is correct because the oxidation state of chromium remains +6 in both

{\mathbf{K}_\mathbf{2}}\mathbf{C}{\mathbf{r}_\mathbf{2}}{\mathbf{O}_\mathbf{7}}

and

{\mathbf{K}_\mathbf{2}}\mathbf{Cr}{\mathbf{O}_\mathbf{4}}

, hence the change is 0.

6 Easy

6 of 73

Understanding +4 | -1

The highest oxidation state of Mn is shown by

View answer and explanation

Correct option: B

KMn{o_4}

Option B (

KMn{o_4}

) is correct because in

KMn{O_4}

, manganese has an oxidation state of +7, which is its highest possible oxidation state.

7 Easy

7 of 73

Application +4 | -1

The oxidation number of N in

{\mathrm{N}_2}\mathrm{H}_5^ +

is :

View answer and explanation

Correct option: A

- 2

Option A (-2) is correct because it accurately calculates the oxidation number of N in N2H5+.

8 Easy

8 of 73

Application +4 | -1

Maximum oxidation state is present in :

View answer and explanation

Correct option: A

\mathrm{Cr}{\mathrm{O}_2}\mathrm{C}{\mathrm{l}_2}\mathrm{ and MnO}_4^ -

Option A (

\mathrm{Cr}{\mathrm{O}_2}\mathrm{C}{\mathrm{l}_2}\mathrm{ and MnO}_4^ -

) is correct because Cr in CrO2Cl2 has +6 and Mn in MnO4- has +7 oxidation states, which are the maximum for these elements.

9 Easy

9 of 73

Application +4 | -1

The oxidation number of carbon in

\mathrm{CH}_2 \mathrm{O}

is:

View answer and explanation

Correct option: C

Option C (0) is correct because the oxidation number of carbon in CH2O is calculated by setting the sum of oxidation numbers of all atoms to zero.

10 Easy

10 of 73

Application +4 | -1

The number of oxygen atoms having -2 oxidation state in

\mathbf{Cr}{\mathbf{O}_\mathbf{5}}

View answer and explanation

Correct option: B

Option B (1) is correct because in

CrO_5

, there is one oxygen atom with a -2 oxidation state and four oxygen atoms involved in peroxide linkages.

11 Easy

11 of 73

Application +4 | -1

The number of oxygen atoms having -2 oxidation state in

\mathbf{Cr}{\mathbf{O}_\mathbf{5}}

View answer and explanation

Correct option: B

Option B (1) is correct because in

CrO_5

, there is one oxygen atom with a -2 oxidation state and four oxygen atoms involved in peroxide linkages.

12 Easy

12 of 73

Application +4 | -1

A metal ion

\mathrm{M}^{3+}

loses 3 electrons, its oxidation number will be:

View answer and explanation

Correct option: B

Option B (6) is correct because when a metal ion M³⁺ loses 3 electrons, its oxidation state increases by 3, resulting in +6.

13 Easy

13 of 73

Analyzing +4 | -1

Which reaction involves neither oxidation nor reduction?

View answer and explanation

Correct option: A

\mathrm{CrO}_4^{2 - } \to \mathrm{C}{\mathrm{r}_2}\mathrm{O}_7^{2 - }

Option A (

\mathrm{CrO}_4^{2 - } \to \mathrm{C}{\mathrm{r}_2}\mathrm{O}_7^{2 - }

) is correct because the oxidation state of Cr remains +6 on both sides of the reaction.

14 Easy

14 of 73

Analyzing +4 | -1

Assertion: The oxidation number of

\mathrm{S}

+6

\mathrm{H}_2 \mathrm{SO}_4

.
Reason:

\mathrm{H}_2 \mathrm{SO}_4

has one peroxide linkage.

View answer and explanation

Correct option: C

If Assertion is correct but Reason is incorrect

The correct answer is A (1) because, based on the stoichiometry and equilibrium calculations, the Kp for the reaction is found to be 1.

15 Easy

15 of 73

Analyzing +4 | -1

In which reaction there is no change in valency and the oxidation state?

View answer and explanation

Correct option: C

N{a_2}{O_2} + {H_2}S{O_4} \to N{a_2}S{O_4} + {H_2}{O_2}

Option C is correct. In the reaction Na₂O₂ + H₂SO₄ → Na₂SO₄ + H₂O₂, the oxidation states of all elements remain unchanged.

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16 Easy

16 of 73

Understanding +4 | -1

Nitrogen shows different oxidation states in the range

View answer and explanation

Correct option: B

–3 to +5

Option B (–3 to +5) is correct because nitrogen can exhibit oxidation states ranging from -3 (e.g., in NH3) to +5 (e.g., in N2O5).

17 Easy

17 of 73

Analyzing +4 | -1

Which of the following has the highest oxidation number

View answer and explanation

Correct option: D

KI{O_4}

Option D (

KIO_4

) is correct because iodine has the highest oxidation number (+7) in this compound.

18 Easy

18 of 73

Remembering +4 | -1

The process in which oxidation number increases is

View answer and explanation

Correct option: C

Oxidation

Option C (Oxidation) is correct because oxidation is defined as the process where the oxidation number of an atom, ion, or molecule increases.

19 Easy

19 of 73

Remembering +4 | -1

What is the net charge on ferrous ion ?

View answer and explanation

Correct option: A

+2

Option A (+2) is correct because the ferrous ion (

Fe^{2+}

) has a +2 charge, indicating that it has lost two electrons.

20 Easy

20 of 73

Understanding +4 | -1

In Nickel-cadmium battery, the change in oxidatioin state at anode and cathode is

View answer and explanation

Correct option: A

0 \rightarrow+2 ;+3 \rightarrow+2

Option A (

0 \rightarrow+2 ;+3 \rightarrow+2

) is correct because in a Nickel-cadmium battery, Cadmium (Cd) is oxidized from 0 to +2 at the anode, and Nickel (Ni) is reduced from +3 to +2 at the cathode.

21 Easy

21 of 73

Analyzing +4 | -1

The most powerful oxidizing agent from the following is

View answer and explanation

Correct option: D

\mathrm{H}_2 \mathrm{SO}_4

Option D (H2SO4) is correct because sulfur is in its highest oxidation state (+6), making it a strong oxidizing agent as it can readily accept electrons.

22 Easy

22 of 73

Understanding +4 | -1

The oxidation state of the underlined elements in the given compound is:

\mathrm{\underline{Ba}Cl}_2

View answer and explanation

Correct option: A

The correct answer is 2 because in

\mathrm{BaCl}_2

, barium (Ba) is an alkaline earth metal and has an oxidation state of +2.

23 Easy

23 of 73

Analyzing +4 | -1

Which of the following is not a redox reaction?

View answer and explanation

Correct option: C

\mathrm{AgN}{\mathrm{O}_3} + \mathrm{NaCl} \to \mathrm{AgCl} + \mathrm{NaN}{\mathrm{O}_3}

The correct answer is C (

\mathrm{AgN}{\mathrm{O}_3} + \mathrm{NaCl} \to \mathrm{AgCl} + \mathrm{NaN}{\mathrm{O}_3}

) because it is a double displacement reaction where oxidation states of all elements remain unchanged.

24 Easy

24 of 73

Analyzing +4 | -1

Which of the following compounds can act as both oxidising and reducing agent w.r.t central atom?

View answer and explanation

Correct option: B

{NO}_2

Option B (NO₂) is correct because nitrogen in NO₂ can be both oxidized (to +5) and reduced (to lower oxidation states).

25 Easy

25 of 73

Application +4 | -1

The oxidation state of phosphorous in cyclo- trimetaphosphoric acid is:

View answer and explanation

Correct option: B

+5

Option B (+5) is correct because the sum of oxidation states in the cyclotrimetaphosphoric acid molecule must equal zero, leading to a +5 oxidation state for phosphorus.

26 Easy

26 of 73

Application +4 | -1

Chlorine is in

+3

oxidation number in

View answer and explanation

Correct option: D

{ClF}_3

Option D (

{ClF}_3

) is correct because the oxidation number of Cl in

{ClF}_3

is +3, calculated by setting the sum of oxidation numbers to zero.

27 Easy

27 of 73

Analyzing +4 | -1

Among the following, the number of elements showing only one non-zero oxidation state is

\mathrm{O},\mathrm{\;Cl},\mathrm{\;F},\mathrm{\;N},\mathrm{\;P},\mathrm{\;Sn},\mathrm{\;Tl},\mathrm{\;Na},\mathrm{\;Ti}

View answer and explanation

Correct option: B

Option B (2) is correct because only F and Na exhibit only one non-zero oxidation state.

28 Easy

28 of 73

Understanding +4 | -1

Oxidation number of iodine varies from

View answer and explanation

Correct option: B

-1

+7

Option B (

-1

+7

) is correct because iodine, having 7 valence electrons, can exhibit oxidation states ranging from -1 to +7.

29 Easy

29 of 73

Analyzing +4 | -1

Which one of the following can act as an oxidizing agent but not as a reducing agent?

View answer and explanation

Correct option: D

\mathrm{MnO}_4^{-}

Option D (

\mathrm{MnO}_4^{-}

) is correct because manganese is in its highest oxidation state (+7) and can only be reduced, thus acting as an oxidizing agent.

30 Easy

30 of 73

Analyzing +4 | -1

Which of the following decomposition reaction is not a redox reaction?

View answer and explanation

Correct option: D

\mathrm{CaCO}_3

(s)

\stackrel{\Delta}{\longrightarrow} \mathrm{CaO}

(s)

+\mathrm{CO}_2(\mathrm{g})

Option D (

\mathrm{CaCO}_3

(s)

\stackrel{\Delta}{\longrightarrow} \mathrm{CaO}

(s)

+\mathrm{CO}_2(\mathrm{g})

) is correct because there is no change in oxidation state for any of the elements in this decomposition reaction.

Revision notes and key takeaways

Review REDOX REACTIONS in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

✓ This set contains 73 single-correct-answer MCQs on REDOX REACTIONS.
✓ Try each question before opening its answer. Read the explanation where one is available.
✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.

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