Skip to main content
Back to REDOX REACTIONS

Your Progress

0 / 171 Answered
0
Correct
0
Incorrect
0%
Accuracy
JEE • CHEMISTRY • REDOX REACTIONS

Redox reactions practice · Medium

Try a question, then open “View answer” to check it. Sign in to submit answers and save progress.

Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

Take a chapter quiz →
Showing 1-30 of 171 questions
1 Medium
1 of 171
Remembering +4 | -1
A reagent, which can decrease the oxidation number of an element, is called
View answer and explanation
Correct option: C
reducing agent
Option C (reducing agent) is correct because a reducing agent donates electrons, causing another substance to have its oxidation number decreased.
2 Medium
2 of 171
Analyzing +4 | -1
Consider the following decomposition reaction

2KClO3⟶2KCl+3O22 \mathrm{KClO}_3 \longrightarrow 2 \mathrm{KCl}+3 \mathrm{O}_2

In the above reaction,
View answer and explanation
Correct option: B
chlorine is undergoing reduction
Option B is correct because chlorine's oxidation state decreases from +5 to -1, indicating reduction.
3 Medium
3 of 171
Analyzing +4 | -1
Assertion (A): HNO3\mathrm{HNO}_3 acts as oxidizing agent.

Reason (R): Oxidation no. of nitrogen is +5, no increase in oxidation no. beyond +5 can occur. The oxidation no. of HNO3\mathrm{HNO}_3 can only decrease.
View answer and explanation
Correct option: A
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
The correct answer is A because HNO3 acts as an oxidizing agent due to the nitrogen atom's ability to decrease its oxidation number from +5, and the reason correctly explains this.
4 Medium
4 of 171
Application +4 | -1
The number of mole of ferrous oxalate oxidised by one mole of KMnO4\mathrm{KMn}{\mathrm{O}_4} is:
View answer and explanation
Correct option: D
5/35/3
Option D (5/35/3) is correct because the balanced redox reaction between ferrous oxalate and KMnO4 requires 5/3 moles of ferrous oxalate per mole of KMnO4.
5 Medium
5 of 171
Analyzing +4 | -1
Which one is not a redox titration?
View answer and explanation
Correct option: D
AgNO3vs.KCl\mathrm{AgN}{\mathrm{O}_3}vs.\mathrm{KCl}
The correct answer is D (AgNO₃ vs. KCl) because this is a precipitation reaction, not a redox reaction involving electron transfer.
6 Medium
6 of 171
Application +4 | -1
The average oxidation number of I{I} in KI3{KI}_3 and Fe{Fe} in Fe3O4{Fe}_3 {O}_4 are respectively :-
View answer and explanation
Correct option: A
−1/3,+8/3-1 / 3,+8 / 3
Option A (−1/3,+8/3-1 / 3,+8 / 3) is correct because it represents the average oxidation states calculated for I in KI3 and Fe in Fe3O4 respectively.
7 Medium
7 of 171
Application +4 | -1
In compound HN3H{N_3} (Hydrozoic acid), oxidation state of N atoms are
View answer and explanation
Correct option: B
0,−2,+10,-2,+1
Option B (0,-2,+1) is correct because the oxidation states of the three nitrogen atoms in HN3HN_3 are 0, -2, and +1, respectively, based on resonance structures.
8 Medium
8 of 171
Analyzing +4 | -1
Which of the following involves the reduction of copper?
View answer and explanation
Correct option: B
Cu2+(aq)+2I−(aq)→2CuI(aq){Cu}^{2+}(\mathrm{aq})+2 {I^-}(\mathrm{aq}) \rightarrow 2 {CuI}(\mathrm{aq})
The correct answer is B because in the reaction Cu2+(aq) + 2I-(aq) → 2CuI(aq), copper's oxidation state decreases from +2 to +1, indicating reduction.
9 Medium
9 of 171
Application +4 | -1
Fe shows an oxidation state of +1 in:
View answer and explanation
Correct option: B
[Fe(H2O)5NO]SO4\left[\mathrm{Fe}\left(\mathrm{H}_2 \mathrm{O}\right)_5 \mathrm{NO}\right] \mathrm{SO}_4
Option B ([Fe(H₂O)₅NO]SO₄) is correct because the iron in this complex has an oxidation state of +1, considering NO as NO⁺.
10 Medium
10 of 171
Remembering +4 | -1
The redox reactions are called combustion reactions which make use of
View answer and explanation
Correct option: A
elemental dioxygen
Option A (elemental dioxygen) is correct because combustion reactions are redox reactions that involve the rapid reaction of a substance with oxygen.
11 Medium
11 of 171
Understanding +4 | -1
During a redox change, the oxidant K2Cr2O7{\mathrm{K}_2}\mathrm{C}{\mathrm{r}_2}{\mathrm{O}_7} is always reduced to :
View answer and explanation
Correct option: C
Cr3+\mathrm{C}{\mathrm{r}^{3 + }}
Option C is correct. During a redox reaction, dichromate (K2Cr2O7) acts as an oxidizing agent and is reduced to Cr3+.
12 Medium
12 of 171
Analyzing +4 | -1
Assuming complete ionization, same moles of which of the following compounds will require the least
Amount of acidified KMnO4\mathrm{KMn}{\mathrm{O}_\mathrm{4}} for complete oxidation?
View answer and explanation
Correct option: C
FeSO4\mathrm{FeS}{\mathrm{O}_\mathrm{4}}
Option C (FeSO4) is correct because FeSO4 requires the least amount of KMnO4 for complete oxidation as it involves the smallest change in oxidation state.
13 Medium
13 of 171
Understanding +4 | -1
Which one of the following is the correct match?
View answer and explanation
Correct option: D
SO2\mathrm{SO}_2 - both oxidising and reducing agent
Option D (SO2 - both oxidising and reducing agent) is correct because sulfur in SO2 has an intermediate oxidation state (+4) and can either gain or lose electrons.
14 Medium
14 of 171
Application +4 | -1
In the following redox reactions
Cr2O72−+Fe2+ →  Fe3++Cr3+C{r_2}O_7^{2 - } + F{e^{2 + }}\,\xrightarrow{\,}\,F{e^{3 + }} + C{r^{3 + }}
1 mole of Cr2O72−C{r_2}O_7^{2 - } oxidises
View answer and explanation
Correct option: D
6  moles  of  Fe2+\mathrm{6\,\,moles\,\,of }\,\,F{e^{2 + }}
Option D (6  moles  of Fe2+\mathrm{6\,\,moles\,\,of }\,F{e^{2 + }}) is correct because 1 mole of Cr2O72−C{r_2}O_7^{2 - } requires 6 moles of Fe2+F{e^{2 + }} for complete oxidation based on the balanced redox reaction.
15 Medium
15 of 171
Understanding +4 | -1
Which of the following acts as an oxidising as well as reducing agent?
View answer and explanation
Correct option: D
NaNO2\mathrm{NaN}{\mathrm{O}_2}
The correct answer is D (NaNO2\mathrm{NaN}{\mathrm{O}_2}) because it can both accept and donate electrons, acting as both an oxidizing and reducing agent due to nitrogen's intermediate oxidation state.
16 Medium
16 of 171
Application +4 | -1
For the balanced redox reaction.
aMnO4−+bH2O2+cH+→dMn2++eO2+fH2O{aMnO}_4^{-}+{bH}_2 {O}_2+{cH}^{+} \rightarrow {dMn}^{2 +}+{eO}_2+{fH}_2 {O} the value of a,b,ca, b, c and ee respectively are
View answer and explanation
Correct option: B
2,5,6,52,5,6,5
The correct answer is 2,5,6,52, 5, 6, 5. Balancing the redox reaction requires determining the correct stoichiometric coefficients to ensure both mass and charge are conserved.
17 Medium
17 of 171
Analyzing +4 | -1
Assertion: SO2\mathrm{SO}_2 and Cl2\mathrm{Cl}_2 both are bleaching agents.

Reason: Both are reducing agents.
View answer and explanation
Correct option: C
Assertion is true, Reason is false
Option C (Assertion is true, Reason is false) is correct because both SO2 and Cl2 are bleaching agents, but their mechanisms differ; SO2 acts as a reducing agent, while Cl2 acts as an oxidizing agent.
18 Medium
18 of 171
Analyzing +4 | -1
Which of the following would not give disproportionation reaction on hydrolysis?
View answer and explanation
Correct option: B
N2O5\mathrm{N}_2 \mathrm{O}_5
Option B is correct because N2O5, upon hydrolysis, only forms HNO3, where nitrogen remains in the +5 oxidation state, thus not undergoing disproportionation.
19 Medium
19 of 171
Analyzing +4 | -1
White phosphorus reacts with caustic soda, the products are PH3 and NaH2PO2.\mathrm{P}{\mathrm{H}_3}\,\mathrm{and}\,\mathrm{Na}{\mathrm{H}_2}\mathrm{P}{\mathrm{O}_2}.This reaction is an example of
View answer and explanation
Correct option: C
Disproportionation
Option C is correct because phosphorus undergoes both oxidation and reduction in this reaction, which is the definition of a disproportionation reaction.
20 Medium
20 of 171
Application +4 | -1
In which of the following pairs, there is greatest difference in the oxidation number of the underlined elements?
View answer and explanation
Correct option: D
S‾O2{\underline{\mathrm{S}}{O}_2} and S‾O3{\underline{\mathrm{S}}{O}_3}
Option D (SO2 and SO3) is correct because the difference in oxidation numbers of S in SO2 and SO3 is 2, which is the greatest among the given pairs.
21 Medium
21 of 171
Application +4 | -1
The number of mole of potassium salt,i.e,KHC2O4.H2C2O4.2H2Oi.e,\mathrm{KH}{\mathrm{C}_2}{\mathrm{O}_4}\mathrm{.}{\mathrm{H}_2}{\mathrm{C}_2}{\mathrm{O}_4}.2{\mathrm{H}_2}\mathrm{O} oxidised by one mole of permanganate ion is :
View answer and explanation
Correct option: D
5/45/4
Option D (5/45/4) is correct because it represents the number of moles of the potassium salt oxidized by one mole of permanganate ion based on the balanced redox reaction.
22 Medium
22 of 171
Analyzing +4 | -1
Which is the best description of the behaviour of bromine in the reaction given below ?

H2O+Br2⟶HOBr+HBr\mathrm{H}_2 \mathrm{O}+\mathrm{Br}_2 \longrightarrow \mathrm{HOBr}+\mathrm{HBr}
View answer and explanation
Correct option: D
Both oxidised and reduced
The correct answer is D because bromine undergoes both oxidation and reduction in the reaction, acting as both an oxidizing and reducing agent (disproportionation).
23 Medium
23 of 171
Analyzing +4 | -1
In the following chemical reaction:

Ag2O+H2O+2e−→2Ag+2OH−{Ag}_2 {O}+{H}_2 {O}+2 e^{-} \rightarrow 2 {Ag}+2 {OH}^{-}
View answer and explanation
Correct option: C
Water is oxidised
Option C is correct because in the reaction, water gains oxygen, indicating it is being oxidized.
24 Medium
24 of 171
Application +4 | -1
The value of n inMnO4−+8H++ne−→Mn2++4H2O\mathrm{MnO}_4^ - + 8{\mathrm{H}^ + } + n{e^ - } \to \mathrm{M}{\mathrm{n}^{2 + }} + 4{\mathrm{H}_2}\mathrm{O} is
View answer and explanation
Correct option: A
5
Option A (5) is correct because the manganese oxidation state changes from +7 to +2, requiring 5 electrons to be added to the left side of the equation.
25 Medium
25 of 171
Analyzing +4 | -1
Which one of the following is an example of disproportionation reaction?
View answer and explanation
Correct option: A
3MnO42−+4H+→2MnO4−+MnO2+2H2O3MnO_4^{2 - } + 4{H^ + } \to 2MnO_4^ - + Mn{O_2} + 2{H_2}O
Option A is correct because in the given reaction, MnO42- undergoes both oxidation and reduction, thus it is a disproportionation reaction.
26 Medium
26 of 171
Remembering +4 | -1
Which metal exhibits more than one oxidation states?
View answer and explanation
Correct option: D
Fe\mathrm{Fe}
Option D (Fe\mathrm{Fe}) is correct because iron (Fe) is a transition metal that commonly exhibits multiple oxidation states, such as +2 and +3.
27 Medium
27 of 171
Understanding +4 | -1
Statement-I: Oxidation number of Ni\mathrm{Ni} in [Ni(CO)4]\left[\mathrm{Ni}(\mathrm{CO})_4\right] is +2.+2.

Statement-II: Nickel is bonded to neutral ligand, carbonyl.
View answer and explanation
Correct option: D
Statement-I is incorrect but statement-II is correct
The correct answer is D (Statement-I is incorrect but statement-II is correct) because the oxidation number of Ni in [Ni(CO)4] is 0, not +2, and CO is a neutral ligand.
28 Medium
28 of 171
Analyzing +4 | -1
In which transfer of five electrons takes place?
View answer and explanation
Correct option: A
MnO4−→Mn2+\mathrm{MnO}_4^ - \to \mathrm{M}{\mathrm{n}^{2 + }}
Option A (MnO4−→Mn2+\mathrm{MnO}_4^ - \to \mathrm{M}{\mathrm{n}^{2 + }}) is correct because the oxidation state of Mn changes from +7 to +2, involving a transfer of 5 electrons.
29 Medium
29 of 171
Application +4 | -1
Oxidation number of P in P2O74−{P_2}O_7^{4 - } is :
View answer and explanation
Correct option: C
+5+ 5
Option C (+5+ 5) is correct because the oxidation number of P is calculated by setting up an equation based on the overall charge of the ion.
30 Medium
30 of 171
Analyzing +4 | -1
Assertion: Oxidation number of carbon in HCHO\mathrm{HCHO} is zero.

Reason: HCHO\text{HCHO} formaldehyde, is a covalent compound.
View answer and explanation
Correct option: B
Assertion is true, Reason is true and Reason is not correct explanation for Assertion
Option B is correct because both the assertion and reason are true, but the reason is not the correct explanation for the assertion. The oxidation number of carbon in HCHO is zero, and HCHO is a covalent compound, but the latter doesn't explain the former.
Revision notes and key takeaways

Review REDOX REACTIONS in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

  • ✓ This set contains 171 single-correct-answer MCQs on REDOX REACTIONS.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
  • ✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.
Showing 1-30 of 171 questions
0 /171
0✓ 0✗
0% Accuracy
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.