The average oxidation number of ${I}$ in ${KI}_3$ and ${Fe}$ in ${Fe}_3 {O}_4$ are respectively :-

JEE CHEMISTRY MCQ: REDOX REACTIONS

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Application +4 | -1

The average oxidation number of

{I}

{KI}_3

and

{Fe}

{Fe}_3 {O}_4

are respectively :-

View answer and explanation

Correct option: A

-1 / 3,+8 / 3

Option A (

-1 / 3,+8 / 3

) is correct because it represents the average oxidation states calculated for I in KI3 and Fe in Fe3O4 respectively.

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\mathrm{H}

2 \mathrm{KClO}_3 \longrightarrow 2 \mathrm{KCl}+3 \mathrm{O}_2

\mathrm{HNO}_3

\mathrm{HNO}_3

\mathrm{MnO}_4^{-}(\mathrm{aq})+\mathrm{Br}^{-}(\mathrm{aq})+\mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{MnO}_2(\mathrm{aq})+\mathrm{BrO}_3^{-}(\mathrm{aq})+2 \mathrm{OH}^{-}(\mathrm{aq})

\mathrm{Br}

-1

+5.