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JEE • CHEMISTRY • REDOX REACTIONS

Redox reactions practice · Mixed difficulty

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121 Medium
121 of 264
Application +4 | -1
If rod of a metal (x) is put in a metal ion solution which is blue in colour, solution turn colourless. The metal rod and solution respectively are?
View answer and explanation
Correct option: D
Both (1) and (3)
The correct answer is D (Both (1) and (3)) because both Zinc and Aluminium are more reactive than Copper and can displace Cu(II) ions from the solution, causing the blue color to disappear.
122 Hard
122 of 264
Understanding +4 | -1
Co(s)+Cu2+(aq)⟶Co2+(aq)+Cu(s){Co}({s})+{Cu}^{2+}({aq}) \longrightarrow {Co}^{2+}({aq})+{Cu}({s})

The above reaction is
View answer and explanation
Correct option: C
Redox reaction
Option A (Displacement of metal by some other metal from complex ion) is correct because gold and silver are recovered by displacing them from their cyanide complexes using a more reactive metal like zinc.
123 Easy
123 of 264
Analyzing +4 | -1
In the reaction ; 2Ag+2H2SO4→Ag2SO4+2H2O+SO2,H2SO42\mathrm{Ag} + 2{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4} \to \mathrm{A}{\mathrm{g}_2}\mathrm{S}{\mathrm{O}_4} + 2{\mathrm{H}_2}\mathrm{O} + \mathrm{S}{\mathrm{O}_2},{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}act as :
View answer and explanation
Correct option: A
Oxidising agent
Option A (Oxidising agent) is correct because H2SO4 acts as an oxidizing agent by accepting electrons and getting reduced.
124 Medium
124 of 264
Analyzing +4 | -1
Given below the two statements:
Statement I: The Eo{E^\mathrm{o}} value for Ce4+/Ce3+C{e^{4 + }}/C{e^{3 + }} is + 1.74 V.
Statement II: CeCe is more stable in Ce4+C{e^{4 + }} state than Ce3+C{e^{3 + }} state.
In the light of the above statement, choose the correct answer from the options given below:
View answer and explanation
Correct option: D
Statement I is correct but statement II is incorrect
Option D is correct because Statement I is correct (E° value for Ce4+/Ce3+ is +1.74 V), but Statement II is incorrect (Ce3+ is more stable than Ce4+).
125 Medium
125 of 264
Application +4 | -1
The value of n inMnO4−+8H++ne−→Mn2++4H2O\mathrm{MnO}_4^ - + 8{\mathrm{H}^ + } + n{e^ - } \to \mathrm{M}{\mathrm{n}^{2 + }} + 4{\mathrm{H}_2}\mathrm{O} is
View answer and explanation
Correct option: A
5
Option A (5) is correct because the manganese oxidation state changes from +7 to +2, requiring 5 electrons to be added to the left side of the equation.
126 Medium
126 of 264
Analyzing +4 | -1
Assertion: Reaction of SO2\mathrm{SO}_2 and H2S\mathrm{H}_2 \mathrm{S} in the presence of Fe2O3\mathrm{Fe}_2 \mathrm{O}_3 catalyst gives element sulphur.

Reason: SO2\mathrm{SO}_2 is a reducing agent.
View answer and explanation
Correct option: B
Assertion is true, Reason is true and Reason is not correct explanation for Assertion
The correct answer is B (Assertion is true, Reason is true and Reason is not correct explanation for Assertion) because SO2 acts as an oxidizing agent in the reaction, not a reducing agent.
127 Easy
127 of 264
Analyzing +4 | -1
Statement-I: Oxidation state of nitrogen in N2H2\mathrm{N}_2 \mathrm{H}_2 is −1.-1.

Statement-II: Nitogen has fractional oxidation state in N3H.\mathrm{N}_3 \mathrm{H}.
View answer and explanation
Correct option: D
Statement-I is incorrect but statement-II is correct
Statement-I is incorrect, and Statement-II is correct; the oxidation state of nitrogen in N2H2 is -1, while in N3H, it's fractional (-1/3). Therefore, option D is the correct answer.
128 Hard
128 of 264
Application +4 | -1
What volume of 3 molar HNO3\mathrm{HN}{\mathrm{O}_3} is needed to oxidise 8 g of Fe2+\mathrm{F}{\mathrm{e}^{2 + }} to Fe3+\mathrm{F}{\mathrm{e}^{3 + }} HNO3\mathrm{HN}{\mathrm{O}_3}, gets converted to NO :
View answer and explanation
Correct option: B
16 m L
Option B (16 mL) is correct because it is calculated using the stoichiometry of the redox reaction between HNO3 and Fe²⁺, considering the change in oxidation states.
129 Medium
129 of 264
Analyzing +4 | -1
Assertion (A): 3ClO−→ClO3−+2Cl−3 {ClO}^{-} \rightarrow {ClO}_3^{-}+2 Cl^{-} is an example of dissociation reaction.

Reason (R): ClO−{ClO}^{-} gets oxidised as well as reduced.
View answer and explanation
Correct option: D
Both (A) and (R) are false
Option D (Both (A) and (R) are false) is correct because the reaction is a disproportionation reaction, not a dissociation reaction, and ClO−{}^{-} gets both oxidized and reduced.
130 Medium
130 of 264
Application +4 | -1
The eq. wt. of Fe3O4\mathrm{F}{\mathrm{e}_3}{\mathrm{O}_4} in , Fe3O4+KMnO4→Fe2O3+MnO2\mathrm{F}{\mathrm{e}_3}{\mathrm{O}_4} + \mathrm{KMn}{\mathrm{O}_4} \to \mathrm{F}{\mathrm{e}_2}{\mathrm{O}_3} + \mathrm{Mn}{\mathrm{O}_2} is:
View answer and explanation
Correct option: B
MM
Option B (MM) is correct because the equivalent weight is calculated based on the change in oxidation state of iron in the reaction.
131 Hard
131 of 264
Application +4 | -1
For combustion of one mole acetone into CO2\mathrm{CO}_2 and H2O\mathrm{H}_2 \mathrm{O}, moles of electron transferred during redox reaction :-
View answer and explanation
Correct option: B
16
Option B (16) is correct because the combustion of one mole of acetone requires 4 moles of oxygen, and each mole of oxygen involves the transfer of 4 moles of electrons.
132 Medium
132 of 264
Analyzing +4 | -1
Which is not a redox reaction?
View answer and explanation
Correct option: A
BaO2+H2SO4\mathrm{Ba}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4}→BaSO4+H2O2\to \mathrm{BaS}{\mathrm{O}_4} + {\mathrm{H}_2}{\mathrm{O}_2}
The correct answer is A because in the reaction BaO2+H2SO4→BaSO4+H2O2\mathrm{Ba}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4} \to \mathrm{BaS}{\mathrm{O}_4} + {\mathrm{H}_2}{\mathrm{O}_2}, the oxidation numbers of all elements remain unchanged, indicating no redox reaction.
133 Medium
133 of 264
Application +4 | -1
How many electrons are involved in oxidation of KMnO4\mathrm{KMn}{\mathrm{O}_4} in basic medium?
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Correct option: A
1
Option A (1) is correct because in a basic medium, KMnO4 is reduced to K2MnO4, involving a change of +7 to +6 in oxidation state, which means only 1 electron is involved.
134 Medium
134 of 264
Analyzing +4 | -1
Statement-I: In the reaction, 12O2+F2→OF2, F2\frac{1}{2} \mathrm{O}_2+\mathrm{F}_2 \rightarrow \mathrm{OF}_2, \mathrm{~F}_2 is oxidant.

Statement-II: Fluorine cannot show positive oxidation state.
View answer and explanation
Correct option: A
Both the statements are correct
The correct answer is A (Both the statements are correct) because fluorine is indeed the oxidant in the reaction, and it cannot exhibit a positive oxidation state.
135 Medium
135 of 264
Application +4 | -1
When KMnO4\mathrm{KMn}{\mathrm{O}_4} as oxidising agent and ultimately forms MnO42−, MnO2, Mn2O3 andMn2+,\mathrm{MnO}_4^{2 - }, \, {\text{MnO}}_{2}, \, \mathrm{M}{\mathrm{n}_2}{\mathrm{O}_3} \, \mathrm{and M}{\mathrm{n}^{2 + }}, the number of electrons transferred per mole of KMnO4\mathrm{KMn}{\mathrm{O}_4} each case respectively is:
View answer and explanation
Correct option: C
1, 3, 4, 5
Option C (1, 3, 4, 5) is correct because it represents the number of electrons transferred per mole of KMnO4 in each reduction to MnO42-, MnO2, Mn2O3, and Mn2+ respectively.
136 Medium
136 of 264
Analyzing +4 | -1
Which of the following is redox reaction
View answer and explanation
Correct option: D
Nitrogen oxides form nitrogen and oxygen by lightning
The correct answer is D because a redox reaction involves a change in oxidation states, which occurs when nitrogen oxides form nitrogen and oxygen by lightning.
137 Easy
137 of 264
Analyzing +4 | -1
Sulphur Containing species that cannot be a reducing agent is
View answer and explanation
Correct option: C
H2SO4{H_2}S{O_4}
Option C (H2SO4) is correct because sulfur in H2SO4 is in its highest oxidation state (+6) and cannot be further oxidized, thus it cannot act as a reducing agent.
138 Medium
138 of 264
Analyzing +4 | -1
Assertion: HNO2\mathrm{HNO}_2 acts as reducing agent only.
Reason: HNO2\mathrm{HNO}_2 oxidises to HNO3\mathrm{HNO}_3 only but not reduce by any reducing agent.
View answer and explanation
Correct option: D
If both Assertion and Reason are incorrect
Option D (If both Assertion and Reason are incorrect) is correct because HNO2\mathrm{HNO}_2 can act as both a reducing and oxidizing agent due to the nitrogen's oxidation state of +3.
139 Medium
139 of 264
Understanding +4 | -1
Oxidation number of sodium in sodium amalgam is
View answer and explanation
Correct option: B
0
Option B (0) is correct because in an amalgam, sodium exists in its elemental form, and the oxidation number of an element in its elemental form is zero.
140 Easy
140 of 264
Application +4 | -1
The equivalent weight of element is 5.33. If it forms oxychloride which is isomorphous with CrO2Cl2{CrO}_2 {Cl}_2 the atomic weight of element is
View answer and explanation
Correct option: B
32
Option B (32) is correct because the atomic weight of the element is calculated by multiplying its equivalent weight by its valency, which is determined by the isomorphous oxychloride formula.
141 Medium
141 of 264
Analyzing +4 | -1
Identify the set from the following sets in which all species can exhibit disproportionation reactions.
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Correct option: A
Cl2,ClO2−,ClO3−,S8\mathrm{Cl}_2, \mathrm{ClO}_2^{-}, \mathrm{ClO}_3^{-}, \mathrm{S}_8
The correct answer is A (Cl2,ClO2−,ClO3−,S8\mathrm{Cl}_2, \mathrm{ClO}_2^{-}, \mathrm{ClO}_3^{-}, \mathrm{S}_8) because each of these species can be both oxidized and reduced in a disproportionation reaction.
142 Medium
142 of 264
Application +4 | -1
C2H6(g)+NO2(g)→CO2(g)+H2O(l){C}_2 {H}_6(g)+{NO}_2(g) \rightarrow {CO}_2(g)+{H}_2 {O}(l)

In this equation, the ratio of the coefficients of CO2{CO}_2 and H2O{H}_2 {O} is
View answer and explanation
Correct option: B
2:32: 3
Option B (2:32: 3) is correct because the balanced equation is 2C2H6+7O2→4CO2+6H2O2 {C}_2 {H}_6+7 {O}_2 \rightarrow 4 {CO}_2+6 {H}_2 {O}, and the ratio of the coefficients of CO2{CO}_2 and H2O{H}_2 {O} is 4:64: 6 or 2:32: 3.
143 Hard
143 of 264
Remembering +4 | -1
Solution of potassium chloride or ammonium nitrate in salt-bridge usually solidified by boiling with
View answer and explanation
Correct option: A
agar-agar
Option A (agar-agar) is correct because agar-agar is used to solidify the electrolyte solution in a salt bridge.
144 Medium
144 of 264
Application +4 | -1
The oxidation number of Ni\mathrm{Ni} in K4[Ni(CN)4]{\mathrm{K}_4}\left[ {\mathrm{Ni}{{\left( {\mathrm{CN}} \right)}_4}} \right] is :
View answer and explanation
Correct option: D
0
Option D (0) is correct because the overall charge of the complex ion is -4, and considering the charges of K and CN, the oxidation number of Ni must be 0.
145 Medium
145 of 264
Application +4 | -1
Chlorine undergoes disproportionation in alkaline medium as shown below :
aCl2(g)+bOH(aq)−→cClO(aq)−+dCl(aq)−+eH2O(l)a \mathrm{Cl}_{2(g)}+b O H_{(a q)}^{-} \rightarrow \mathrm{cClO}_{(a q)}^{-}+d \mathrm{Cl}_{(a q)}^{-}+\mathrm{eH}_2 \mathrm{O}_{(l)}

The values of a,b,c\mathrm{a}, \mathrm{b}, \mathrm{c} and d\mathrm{d} in a balanced redox reaction are respectively:
View answer and explanation
Correct option: B
1, 2, 1 and 1
Option B (1, 2, 1 and 1) is correct because it represents the coefficients that balance the disproportionation reaction of chlorine in an alkaline medium.
146 Medium
146 of 264
Analyzing +4 | -1
In the reactions;As2S3+HNO3→H3AsO4+H2SO4+NO\mathrm{A}{\mathrm{s}_2}{\mathrm{S}_3} + \mathrm{HN}{\mathrm{O}_3} \to {\mathrm{H}_3}\mathrm{As}{\mathrm{O}_4} + {\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4} + \mathrm{NO}, the element oxidized is/ are :
View answer and explanation
Correct option: D
As and S both
Option D is correct. In the given reaction, both Arsenic (As) and Sulfur (S) are oxidized.
147 Medium
147 of 264
Application +4 | -1
In which compound, oxygen has an oxidation state of +2+ 2 ?
View answer and explanation
Correct option: C
OF2\mathrm{O}{\mathrm{F}_2}
Option C (OF2OF_2) is correct because fluorine is more electronegative than oxygen, giving oxygen a +2 oxidation state.
148 Medium
148 of 264
Application +4 | -1
Oxidation state of P\mathrm{P} in H4P2O5,H4P2O6\mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_5, \mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_6 and H4P2O7\mathrm{H}_4 \mathrm{P}_2 \mathrm{O}_7 are respectively :
View answer and explanation
Correct option: A
+3,+4,+5+3,+4,+5
Option A (+3,+4,+5) is correct because it represents the correct oxidation states of P in the given compounds.
149 Medium
149 of 264
Understanding +4 | -1
Among the properties given below, the set of properties shown by CN−\mathrm{C}{\mathrm{N}^ - } ion towards metal species is :1. Reducing; 2. Oxidising ; 3. Complexation
View answer and explanation
Correct option: A
1,3
Option A (1,3) is correct because cyanide ions can act as reducing agents and form complexes with metal species.
150 Easy
150 of 264
Remembering +4 | -1
The half-reactions that involve gain of electrons are known as
View answer and explanation
Correct option: A
reduction reactions
Option A (reduction reactions) is correct because reduction reactions involve the gain of electrons.
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