NEET UG CHEMISTRY MCQ: REDOX REACTIONS

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Turn bull’s blue is :

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Correct option: A

\mathrm{F}{\mathrm{e}_3}{\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_6}} \right]_2}

Option A (

\mathrm{F}{\mathrm{e}_3}{\left[ {\mathrm{Fe}{{\left( {\mathrm{CN}} \right)}_6}} \right]_2}

) is correct because Turnbull's blue is ferric ferrocyanide, formed by the reaction of ferric ions with ferrocyanide ions.

More Questions from REDOX REACTIONS

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{I_2}

\mathrm{MnO}_4^ - + {\mathrm{C}_2}\mathrm{O}_4^{2 - } + {\mathrm{H}^ + } \to \mathrm{M}{\mathrm{n}^{2 + }} + \mathrm{C}{\mathrm{O}_2} + {\mathrm{H}_2}\mathrm{O}

\mathrm{MnO}_4^ -

{\mathrm{C}_2}\mathrm{O}_4^{2 - }

{\mathrm{H}^ + }