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JEE • CHEMISTRY • P-BLOCK ELEMENTS

P-block elements practice · Mixed difficulty

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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421 Easy
421 of 705
Understanding +4 | -1
Which are hydrolysed by water?
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because XeF2XeF_2, XeF4XeF_4, and XeF6XeF_6 all react with water to form various products including HFHF, XeO3XeO_3 and XeO64−XeO_6^{4-}.
422 Easy
422 of 705
Remembering +4 | -1
Nitric acid may be kept in a bottle of:
View answer and explanation
Correct option: D
AlAl
Option D (AlAl) is correct because aluminum forms a passive layer of aluminum oxide (Al2O3Al_2O_3) which protects it from further reaction with nitric acid.
423 Easy
423 of 705
Understanding +4 | -1
Iron is dropped in dil HNO3HN{O_3} it gives
View answer and explanation
Correct option: C
Ferrous nitrate and ammonium nitrate
The correct answer is C (Ferrous nitrate and ammonium nitrate) because dilute nitric acid reacts with iron to produce ferrous nitrate and ammonium nitrate.
424 Medium
424 of 705
Remembering +4 | -1
Which of the silver salts are soluble in water?
View answer and explanation
Correct option: C
AgFAgF
Option C (AgFAgF) is correct because silver fluoride is soluble in water due to the high hydration enthalpy of the fluoride ion.
425 Medium
425 of 705
Remembering +4 | -1
Which of the following is used to provide smoke screens :
View answer and explanation
Correct option: A
Calcium phosphide
Option A (Calcium phosphide) is correct because calcium phosphide reacts with water to produce phosphine gas, which spontaneously ignites and creates smoke.
426 Easy
426 of 705
Remembering +4 | -1
The most abundant inert gas in air is:
View answer and explanation
Correct option: C
Ar
Option C (Ar) is correct because Argon constitutes approximately 1% of the Earth's atmosphere, making it the most abundant inert gas in air.
427 Medium
427 of 705
Analyzing +4 | -1
Assertion : Dinegative anion of oxygen (O2−)\left({O}^{2-}\right) is quite common but dinegative anion of sulphur (S2−)\left({S}^{2-}\right) is less common.

Reason : Covalency of oxygen is two.
View answer and explanation
Correct option: C
If the Assertion is correct but Reason is incorrect.
The correct answer is C (If the Assertion is correct but Reason is incorrect) because while the dinegative oxygen anion is common, the reason given (covalency of oxygen is two) is not the primary explanation. The stability of O2- is due to oxygen's high electron gain enthalpy.
428 Medium
428 of 705
Analyzing +4 | -1
The gaseous decomposition of ozone 2O3→3O22 \mathrm{O}_3 \rightarrow 3 \mathrm{O}_2 follows the mechanism

O3⇌keqO2+O (Fast), O+O3→k12O2 (Slow) \mathrm{O}_3 \stackrel{\mathrm{k}_{\mathrm{eq}}}{\rightleftharpoons} \mathrm{O}_2+\mathrm{O} \text { (Fast), } \mathrm{O}+\mathrm{O}_3 \xrightarrow{\mathrm{k}_1} 2 \mathrm{O}_2 \text { (Slow) }

Determine the order of reaction with respect to O2\mathrm{O}_2 :
View answer and explanation
Correct option: A
-1
Option A (-1) is correct because the rate law derived from the given mechanism shows that the reaction order with respect to O2 is -1.
429 Easy
429 of 705
Remembering +4 | -1
The principal source of helium is:
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Correct option: B
Monazite sand
Option B (Monazite sand) is correct because monazite sand is a significant source of helium, as it contains radioactive elements that decay to produce helium.
430 Medium
430 of 705
Analyzing +4 | -1
A mixture of which pair of species react with water to produce a pure colourless gas that gives white fumes with HClHCl?
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Correct option: C
Magnesium nitride and calcium nitride
Option C (Magnesium nitride and calcium nitride) is correct because both react with water to produce ammonia gas, which forms white fumes with HCl.
431 Medium
431 of 705
Analyzing +4 | -1
Assertion (A) : Cl2{Cl}_2 or Br2{Br}_2 changes KI{KI} into I2{I}_2 (violet in CCl4{CCl}_4 layer), Cl2{Cl}_2 changes KBr{KBr} into Br2{Br}_2 (orange-yellow in CCl4{CCl}_4 layer). Thus, Cl2{Cl}_2 would change mixture of KI{KI} and KBr{KBr} into violet layer in CCl4{CCl}_4.

Reason (R) : Oxidising power is in order I2<Br2<Cl2<F2{I}_2 < {Br}_2 < {Cl}_2 < {F}_2.
View answer and explanation
Correct option: A
Both A\mathbf{A} and R\mathbf{R} are true and R\mathbf{R} is the correct explanation of A\mathbf{A}.
Option A (Both A and R are true and R is the correct explanation of A) is correct because chlorine is a stronger oxidizing agent than bromine, which is stronger than iodine, thus chlorine will oxidize both iodide and bromide to their respective halogens.
432 Medium
432 of 705
Analyzing +4 | -1
Assertion (A): Conc. Sulphuric acid can be used to prepare HClHCl on reaction with NaCl.NaCl.

Reason (R): Conc. H2SO4\mathrm{H}_2 \mathrm{SO}_4 is a moderately strong reducing agent.
View answer and explanation
Correct option: C
(A) is true but (R) is false
Option C is correct because concentrated sulfuric acid can be used to prepare HCl, but it acts as an oxidizing agent, not a reducing agent.
433 Easy
433 of 705
Analyzing +4 | -1
In which reaction does SO2S{O_2} act as oxidizing agent?
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Correct option: D
H2S{H_2}S
The correct answer is D (H2S{H_2}S) because in this reaction, SO2SO_2 oxidizes H2S{H_2}S by accepting electrons, causing sulfur to be deposited.
434 Easy
434 of 705
Remembering +4 | -1
Liquor ammonia is
View answer and explanation
Correct option: C
Concentrated solution of NH3N{H_3} in water
Option C (Concentrated solution of NH3N{H_3} in water) is correct because liquor ammonia is a concentrated aqueous solution of ammonia.
435 Easy
435 of 705
Understanding +4 | -1
Which element shows polymorphism?
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because Sulfur, Selenium, and Oxygen, all members of group 16, exhibit polymorphism.
436 Medium
436 of 705
Remembering +4 | -1
Which of the following pairs is obtained on heating ammonium dichromate?
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Correct option: A
N2 and H2O{\mathrm{N}_\mathrm{2}}\,\mathrm{and}\,\mathrm{ }{\mathrm{H}_\mathrm{2}}\mathrm{O}
Option A (N2 and H2O{\mathrm{N}_{\mathrm{2}}}\,\mathrm{and}\,\mathrm{ }{\mathrm{H}_{\mathrm{2}}}\mathrm{O}) is correct because ammonium dichromate on heating decomposes to give nitrogen gas and water as products.
437 Easy
437 of 705
Understanding +4 | -1
Phosphine is not collected in air because:
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Correct option: C
It catches fire spontaneously in air
The correct answer is C (It catches fire spontaneously in air) because phosphine is highly reactive and ignites spontaneously in the presence of air due to the presence of P2H4 impurities.
438 Easy
438 of 705
Remembering +4 | -1
The noble gas forming maximum number of compound is
View answer and explanation
Correct option: A
Xe
Option A (Xe) is correct because Xenon has the lowest ionization energy among the stable noble gases, allowing it to form the most compounds.
439 Medium
439 of 705
Understanding +4 | -1
On reaction with water,

I. fluorine oxidises water to oxygen.

II. chlorine and bromine react with water to form corresponding hydrohalic and hypohalous acids.

III. reaction of iodine with water is spontaneous.

Which of the above mentioned statements is/are correct?
View answer and explanation
Correct option: C
I and II
Option C (I and II) is correct because fluorine oxidizes water to oxygen, and chlorine and bromine react with water to form corresponding hydrohalic and hypohalous acids. Iodine's reaction with water is non-spontaneous.
440 Medium
440 of 705
Analyzing +4 | -1
Read the following statements regarding chemical reactivity of group 15 elements.

(i) Only compound of Bi{Bi} with +5 oxidation state is BiF5{BiF}_5.

(ii) Intermediate oxidation states for both nitrogen and phosphorus disproportionate in both acid and alkali.

(iii) Nitrogen due to absence of d-orbitals in its valence shell cannot form dπ{d} \pi-p π\pi bond as the heavier elements thus R3P=O{R}_3 {P}={O} exists but R3 N=O{R}_3 {~N}={O} does not exists.

(iv) BiH3{BiH}_3 is the strongest reducing agent amongst the hydrides of nitrogen family.

(v) P2O3{P}_2 {O}_3 is more acidic than P2O5{P}_2 {O}_5.

Which of the following is the correct code for the statements above?
View answer and explanation
Correct option: C
TFTTF
Option C (TFTTF) is correct because statements (i), (iii), and (iv) are true, while (ii) and (v) are false based on the chemical reactivity of group 15 elements.
441 Medium
441 of 705
Remembering +4 | -1
NH3  N{H_3}\; gas is dried over:
View answer and explanation
Correct option: C
Quick lime
Option C (Quick lime) is correct because ammonia gas can be dried over quick lime (CaO) as it doesn't react with it.
442 Medium
442 of 705
Understanding +4 | -1
The reaction in the Kipp’s apparatus stops on closing the outlet, because:
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Correct option: D
The contact between sulphide and the acid is broken by the presence of gas collected in the free surface of the middle chamber
Option D (The contact between sulphide and the acid is broken by the presence of gas collected in the free surface of the middle chamber) is correct because the pressure of the gas produced builds up and pushes the acid away from the solid reactant, stopping the reaction.
443 Easy
443 of 705
Understanding +4 | -1
The hydride of group 16 elements showing maximum tendency for complex formation is
View answer and explanation
Correct option: B
H2O{H_2}O
Option B is correct because water (H2O{H_2}O) has the highest tendency for complex formation due to the small size and high electronegativity of oxygen, leading to a higher electron density and better donation ability.
444 Easy
444 of 705
Remembering +4 | -1
S-I: OgO g has been synthetically produced by collision of 98249Cf{ }_{98}^{249} {Cf} atoms 2048Ca{ }_{20}^{48} {Ca} ions.

S-II: Its (Og)({Og}) half life period is 7 sec7 \, \mathrm{sec}.
View answer and explanation
Correct option: C
S-I is true, S-II is false
Option C (S-I is true, S-II is false) is correct because Oganesson (Og) was indeed synthesized by colliding Californium and Calcium ions, but its half-life is much shorter than 7 seconds.
445 Medium
445 of 705
Analyzing +4 | -1
Statement-I: P2O3{P}_2 {O}_3 is more basic than N2O3{N}_2 {O}_3

Statement-II: Metallic nature of the central atom increases down the group
View answer and explanation
Correct option: A
Statement I and II are correct
The correct answer is A because the basicity of oxides decreases down the group, and the metallic nature of the central atom increases down the group.
446 Medium
446 of 705
Remembering +4 | -1
The gas which is absorbed by ferrous sulphate solution giving blackish brown colour is:
View answer and explanation
Correct option: D
NO
Option D (NO) is correct because ferrous sulphate solution absorbs nitric oxide (NO) to form a blackish-brown colored complex.
447 Easy
447 of 705
Remembering +4 | -1
A person working with phosphorus suffers from a disease in which bones decay. It is known as
View answer and explanation
Correct option: B
Phossay jaw
Option B (Phossay jaw) is correct because it is a disease caused by exposure to phosphorus, leading to bone decay in the jaw.
448 Easy
448 of 705
Understanding +4 | -1
The acidity of hydrides of O, S, Se, Te varies in the order
View answer and explanation
Correct option: B
H2O<H2S<H2Se<H2Te{H_2}O < {H_2}S < {H_2}Se < {H_2}Te
Option B (H2O<H2S<H2Se<H2Te{H_2}O < {H_2}S < {H_2}Se < {H_2}Te) is correct because the acidity of hydrides increases down the group due to decreasing bond strength.
449 Easy
449 of 705
Analyzing +4 | -1
In which of the following reactions chlorine is both reduced and oxidized?
View answer and explanation
Correct option: B
6NaOH+3Cl2⟶5NaCl+NaClO3+3H2O6 {NaOH}+3 {Cl}_2 \longrightarrow 5 {NaCl}+{NaClO}_3+3 {H}_2 {O}
Option B (6NaOH+3Cl2⟶5NaCl+NaClO3+3H2O6 {NaOH}+3 {Cl}_2 \longrightarrow 5 {NaCl}+{NaClO}_3+3 {H}_2 {O}) is correct because chlorine undergoes both oxidation (to NaClO3NaClO_3) and reduction (to NaClNaCl) in the same reaction.
450 Easy
450 of 705
Remembering +4 | -1
Nitrogen forms …. Oxides.
View answer and explanation
Correct option: C
5
Option C (5) is correct because Nitrogen forms five stable oxides: N2ON_2O, NONO, N2O3N_2O_3, N2O4N_2O_4, and N2O5N_2O_5.
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