Assertion (A): $\mathrm{CO}_2$ is resonance stabilized molecule. Reason (R): Bond length of $\mathrm{C}-\mathrm{O}$ in $\mathrm{CO}_2$ is intermediate of single and double bond length.

Both (A) & (R) are true and the (R) is the correct explanation of the (A)

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JEE • CHEMISTRY • CHEMICAL BONDING & MOLECULAR STRUCTURE

Chemical bonding & molecular structure practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 91-120 of 124 questions

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91 Easy

91 of 124

Understanding +4 | -1

s p^3

hybridized orbital contains

View answer and explanation

Correct option: A

\frac{1}{4} s

- character

Option A is correct because in sp3 hybridization, one s orbital and three p orbitals mix, resulting in 25% s character (1/4).

92 Easy

92 of 124

Analyzing +4 | -1

Assertion (A):

\mathrm{CO}_2

is resonance stabilized molecule.

Reason (R): Bond length of

\mathrm{C}-\mathrm{O}

\mathrm{CO}_2

is intermediate of single and double bond length.

View answer and explanation

Correct option: C

(A) is true but (R) is false

Option C ((A) is true but (R) is false) is correct because CO2 is resonance stabilized, but the C-O bond length is intermediate between a double and triple bond, not a single and double bond.

93 Easy

93 of 124

Analyzing +4 | -1

Assertion(A)

{N}_2

and

{NO}^{+}

both are diamagnetic substances.
Reason(R)

{NO}^{+}

is isoelectronic with

{N}_2

View answer and explanation

Correct option: B

If both (A) and (R) are correct but (R) is not the correct explanation of the (A).

Option B is correct because both the assertion and the reason are correct, but the reason is not the correct explanation of the assertion. Both

{N}_2

and

{NO}^+

are diamagnetic, but this is due to their electronic configurations, not just because they are isoelectronic.

94 Easy

94 of 124

Remembering +4 | -1

According to Pauling, the atomic orbitals combine to form new set of equivalent atomic orbitals known as

View answer and explanation

Correct option: B

Hybrid orbitals

Option B (Hybrid orbitals) is correct because, according to Pauling, atomic orbitals combine to form hybrid orbitals.

95 Easy

95 of 124

Analyzing +4 | -1

Assertion (A) : Dipole moment of o-dichloro benzene is larger than the theoretical value.

Reason (R): Due to dipole-dipole repulsion of two

{Cl}

-atoms in ortho position bond angle is greater than

60^{\circ}

View answer and explanation

Correct option: D

\mathbf{A}

is false but

\mathbf{R}

is true.

The correct answer is D (

\mathbf{A}

is false but

\mathbf{R}

is true) because the dipole moment of o-dichlorobenzene is *smaller* than the theoretical value due to the vector addition of the bond dipoles, and the reason is correct that the bond angle is greater than 60 degrees due to repulsion.

96 Easy

96 of 124

Remembering +4 | -1

The electrons in an incomplete outershell are known as:

View answer and explanation

Correct option: B

Valency electrons

Option B (Valency electrons) is correct because electrons in the outermost shell of an atom are specifically referred to as valence electrons.

97 Easy

97 of 124

Application +4 | -1

Which is expected to show paramagnetism?

View answer and explanation

Correct option: A

\mathrm{Cl}{\mathrm{O}_2}

Option A (

\mathrm{Cl}{\mathrm{O}_2}

) is correct because it has an odd number of electrons (33), resulting in at least one unpaired electron and thus paramagnetism.

98 Easy

98 of 124

Analyzing +4 | -1

The bond angle in

\mathrm{As}{\mathrm{H}_3}

is greater than that in

View answer and explanation

Correct option: D

None of these

The correct answer is D (None of these) because the bond angle in AsH3 is smaller than in NH3, H2O, and BCl3.

99 Easy

99 of 124

Analyzing +4 | -1

Assertion (A): All

P-Cl

bond lengths are equal in

{PCl}_3

but different in

{PCl}_5.

Reason (R): Hybrid state of central atom is different in Both molecules.

View answer and explanation

Correct option: B

Both (A) & (R) are true but the (R) is not the correct explanation of the (A)

Option B (Both (A) & (R) are true but the (R) is not the correct explanation of the (A)) is correct because both the assertion and the reason are true, but the reason does not explain the assertion. The difference in bond lengths in

{PCl}_5

is due to axial and equatorial positions, not just the hybridization.

100 Easy

100 of 124

Remembering +4 | -1

Atoms or group of atoms which are electrically charged are known as:

View answer and explanation

Correct option: C

Ions

Option C (Ions) is correct because ions are atoms or groups of atoms that carry an electrical charge, either positive (cations) or negative (anions).

101 Easy

101 of 124

Understanding +4 | -1

What is the hybridisation of

{Be}

{BeF}_2

molecule?

View answer and explanation

Correct option: C

{sp}

Option C (sp) is correct because Beryllium in BeF2 has two bond pairs and no lone pairs, resulting in sp hybridization.

102 Easy

102 of 124

Remembering +4 | -1

Hybridisation involves

View answer and explanation

Correct option: B

Mixing up of atomic orbitals

Option B (Mixing up of atomic orbitals) is correct because hybridization is the process of mixing atomic orbitals to form new hybrid orbitals with different energies, shapes, etc.

103 Easy

103 of 124

Understanding +4 | -1

Among the given species identify the isostructural pairs

View answer and explanation

Correct option: B

BF_4^ - \,\,{\text{and}}\,\,NH_4^ +

Option B (

BF_4^ - \,\,{\text{and}}\,\,NH_4^ +

) is correct because both ions have tetrahedral geometry and sp3 hybridization.

104 Easy

104 of 124

Understanding +4 | -1

The compound containing co-ordinate bond is

View answer and explanation

Correct option: D

All of these

Option D (All of these) is correct because

O_3

SO_3

, and

H_2SO_4

all contain coordinate bonds.

105 Easy

105 of 124

Understanding +4 | -1

Which of the following is most stable?

View answer and explanation

Correct option: A

H_2

Option A (

H_2

) is correct because it has the highest bond order and no antibonding electrons, making it the most stable.

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P-BLOCK ELEMENTS 736 MCQs Equilibrium 696 MCQs STRUCTURE OF ATOM 634 MCQs THERMODYNAMICS 536 MCQs SOLUTIONS 480 MCQs CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES 455 MCQs

106 Easy

106 of 124

Remembering +4 | -1

Debye an unit of dipole moment is of the order of:

View answer and explanation

Correct option: B

{10^{ - 18}}

esu cm

Option B (

{10^{ - 18}}

esu cm) is correct because the Debye unit is defined as approximately

{10^{ - 18}}

electrostatic units times centimeters (esu cm).

107 Easy

107 of 124

Remembering +4 | -1

One Debye is equal to how many coulomb meter?

View answer and explanation

Correct option: A

3.33 \times 10^{-30}

Option A (

3.33 \times 10^{-30}

) is correct because 1 Debye is defined as

3.33 \times 10^{-30}

Coulomb meter.

108 Easy

108 of 124

Application +4 | -1

Chloride of metal is

{MCl}_2

. The formula of its phosphate will be

View answer and explanation

Correct option: B

{M}_3\left({PO}_4\right)_2

Option B (

{M}_3\left({PO}_4\right)_2

) is correct because if the metal chloride is

{MCl}_2

, the metal has a +2 charge, and phosphate has a -3 charge, leading to the formula

{M}_3\left({PO}_4\right)_2

109 Easy

109 of 124

Analyzing +4 | -1

Which of the following has the highest dipole moment

View answer and explanation

Correct option: C

{H_2}O

Option C (

{H_2}O

) is correct because water has a bent structure and a significant difference in electronegativity between oxygen and hydrogen, resulting in a high dipole moment due to the two lone pairs of electrons on oxygen.

110 Easy

110 of 124

Analyzing +4 | -1

In which of the following bond angle is maximum

View answer and explanation

Correct option: C

PC{l_5}

Option C (

PC{l_5}

) is correct because it has a bond angle of 120° due to sp3d hybridization, which is the largest among the given options.

111 Easy

111 of 124

Analyzing +4 | -1

Which of the following pairs of species have identical shapes

View answer and explanation

Correct option: C

Xe{F_4}

and

ICl_4^ -

The correct answer is C (

Xe{F_4}

and

ICl_4^ -

) because both species have a square planar shape due to the same number of bond pairs and lone pairs.

112 Easy

112 of 124

Analyzing +4 | -1

Given below are two statements: one is labeled as Assertion (A) and the other is labeled as Reason (R).
Assertion (A) Dipole –dipole interactions are the only non-covalent interactions, resulting in hydrogen bond formation.
Reason (R) Fluorine is the most electronegative element and hydrogen bonds in

HF

are symmetrical.
In the light of the above statements, choose the most appropriate answer from the options given below.

View answer and explanation

Correct option: A

A is false but R is true.

Option A is correct because the assertion is false as dipole-dipole interactions are not the ONLY non-covalent interactions, and the reason is true.

113 Easy

113 of 124

Analyzing +4 | -1

Asser tion : Fluorine molecule has bond order one.

Reason : The number of electrons in the anti-bonding molecular orbitals is two less than that in bonding molecular orbitals.

View answer and explanation

Correct option: A

If both Assertion and Reason are correct and the Reason is the correct explanation of Assertion.

Option A is correct because both the assertion and the reason are correct, and the reason correctly explains why the fluorine molecule has a bond order of one.

114 Easy

114 of 124

Understanding +4 | -1

Which of the following species assumes planar structure

View answer and explanation

Correct option: B

CH_3^ +

Option B (

CH_3^ +

) is correct because

CH_3^+

has a planar structure with the carbon atom being

sp^2

hybridized.

115 Easy

115 of 124

Understanding +4 | -1

Which one of the following is the correct set of hybridisation and shape with respect to molecule?

View answer and explanation

Correct option: C

\mathrm{BCl}_3 \mathrm{~Asp}^2,

triangular planar

Option C (

\mathrm{BCl}_3 \mathrm{~Asp}^2,

triangular planar) is correct because Boron in BCl3 has sp2 hybridization and a trigonal planar shape.

116 Easy

116 of 124

Analyzing +4 | -1

In which of the following molecules, the type of hybridisation changes when

View answer and explanation

Correct option: B

Al{H_3}

combines with

{H^ - }

Option B (

Al{H_3}

combines with

{H^ - }

) is correct because the hybridization of Al changes from sp2 in AlH3 to sp3 in AlH4-.

117 Easy

117 of 124

Remembering +4 | -1

Who introduced the term covalent bond ?

View answer and explanation

Correct option: B

Langmuir

Option B (Langmuir) is correct because Langmuir introduced the term covalent bond.

118 Easy

118 of 124

Analyzing +4 | -1

Assertion : The bond between two identical nonmetal atoms has a pair of electrons with identical spin.

Reason : Electrons are transferred fully from one atom to another.

View answer and explanation

Correct option: D

If the assertion and reason both are false.

Option D (If the assertion and reason both are false) is correct because the bond between two identical nonmetal atoms has electrons with opposite spins, and electrons are equally shared, not transferred.

119 Easy

119 of 124

Understanding +4 | -1

Hybridization of

P

PCl_5

View answer and explanation

Correct option: A

sp^3d

Option A (

sp^3d

) is correct because in

PCl_5

, the phosphorus atom is

sp^3d

hybridized, resulting in a trigonal bipyramidal geometry.

120 Easy

120 of 124

Analyzing +4 | -1

s{p^3}{d^2}

hybridization is not displayed by

View answer and explanation

Correct option: D

P{F_5}

Option B is correct because the equilibrium constant for the reaction D ⇌ 4A is found by manipulating the given equilibrium constants: K = Z / (X² * Y).

Revision notes and key takeaways

Review CHEMICAL BONDING & MOLECULAR STRUCTURE in your textbook or class notes, then use this set to check your understanding.

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