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JEE • CHEMISTRY • CHEMICAL BONDING & MOLECULAR STRUCTURE

Chemical bonding & molecular structure practice · Easy

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These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 61-90 of 124 questions

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61 Easy

61 of 124

Application +4 | -1

The hybridization of phosphorus in

\mathrm{POC}{\mathrm{l}_3}

is same as in:

View answer and explanation

Correct option: A

\mathrm{P in PC}{\mathrm{l}_3}

Option A (P in

PCl_3

) is correct because both

POCl_3

and

PCl_3

have a central phosphorus atom with

sp^3

hybridization.

62 Easy

62 of 124

Application +4 | -1

Two hybrid orbitals have a bond angle of

120^\circ

. The percentage ofs character in the hybrid orbital is nearly

View answer and explanation

Correct option: B

33\%

Option B (33%) is correct because a bond angle of 120° corresponds to sp² hybridization, which has 33% s character.

63 Easy

63 of 124

Understanding +4 | -1

The bond in the formation of fluorine molecule is

View answer and explanation

Correct option: C

Due to p - p overlapping

The correct answer is C (Due to p - p overlapping) because fluorine forms a single bond through the overlap of its p-orbitals.

64 Easy

64 of 124

Application +4 | -1

Which is not paramagnetic

View answer and explanation

Correct option: C

{O}_2^{2-}

Option C (

{O}_2^{2-}

) is correct because it has all its electrons paired and is therefore diamagnetic, while the others have unpaired electrons.

65 Easy

65 of 124

Understanding +4 | -1

The geometry of the molecule with

s p^3 d^2

hybridised central atom is

View answer and explanation

Correct option: C

Octahedral

Option C (Octahedral) is correct because

sp^3d^2

hybridization results in six hybrid orbitals directed towards the corners of an octahedron.

66 Easy

66 of 124

Understanding +4 | -1

Strongest hydrogen bonding is present in

View answer and explanation

Correct option: A

HF

Option A (HF) is correct because fluorine is the most electronegative element, leading to the strongest hydrogen bonding.

67 Easy

67 of 124

Understanding +4 | -1

Formation of

\pi

-bond:

View answer and explanation

Correct option: B

Decreases bond length

Option B is correct because the formation of a

\pi

-bond results in increased electron density between the atoms, leading to a shorter bond length.

68 Easy

68 of 124

Understanding +4 | -1

Among the bonds formed by a chlorine atom with atoms of hydrogen, chlorine, sodium and carbon, the strongest bond is formed between

View answer and explanation

Correct option: C

{Na}-{Cl}

Option C (

{Na}-{Cl}

) is correct because ionic bonds are generally stronger than covalent bonds, and

{Na}-{Cl}

is an ionic bond.

69 Easy

69 of 124

Understanding +4 | -1

Which shows the least dipole moment?

View answer and explanation

Correct option: D

\mathrm{CC}{\mathrm{l}_4}

Option D (

\mathrm{CC}{\mathrm{l}_4}

) is correct because due to its symmetrical tetrahedral geometry, the bond dipoles cancel out, resulting in a zero dipole moment.

70 Easy

70 of 124

Understanding +4 | -1

According to MO theory

View answer and explanation

Correct option: A

{O_2}^{^ + }

is paramagnetic and B.O is greater than

{O_2}

Option A (

{O_2}^{^ + }

is paramagnetic and B.O is greater than

{O_2}

) is correct because

{O_2}^+

has an unpaired electron making it paramagnetic, and its bond order is 2.5, which is greater than the bond order of

{O_2}

(which is 2).

71 Easy

71 of 124

Analyzing +4 | -1

In which of the following processes, the bond order is decreased?

View answer and explanation

Correct option: A

\mathrm{CO}^{+} \longrightarrow \mathrm{CO}

Option A is correct. The bond order decreases when CO+ is converted to CO.

72 Easy

72 of 124

Understanding +4 | -1

In the transition of

{Zn}

atoms to

{Zn}^{++}

ions there is a decrease in the

View answer and explanation

Correct option: A

Number of valency electrons

Option A (Number of valency electrons) is correct because when Zn atoms transform to Zn++ ions, they lose two valence electrons.

73 Easy

73 of 124

Analyzing +4 | -1

Which species does not exhibit paramagnetism?

View answer and explanation

Correct option: C

{CO}

The correct answer is C (

{CO}

) because it has an even number of electrons and all molecular orbitals are filled, resulting in no unpaired electrons.

74 Easy

74 of 124

Analyzing +4 | -1

Which of the following molecules has the maximum dipole moment

View answer and explanation

Correct option: C

N{H_3}

Option C is correct because NH3 has the maximum dipole moment due to the additive nature of bond moments and the lone pair's contribution.

75 Easy

75 of 124

Remembering +4 | -1

The hybridisation state of carbon in fullerene is

View answer and explanation

Correct option: B

s p^2

Option B (

s p^2

) is correct because each carbon atom in fullerene is bonded to three other carbon atoms, resulting in

s p^2

hybridization.

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76 Easy

76 of 124

Understanding +4 | -1

Which of the following statement is not true

View answer and explanation

Correct option: C

HF

is less polar than

HBr

Option C (

HF

is less polar than

HBr

) is correct because the polarity of a bond increases with the electronegativity difference between the atoms, and F is more electronegative than Br.

77 Easy

77 of 124

Analyzing +4 | -1

Assertion: Hydrogen bonding is responsible for the unique properties of water, such as its high boiling point and density.

Reason: Hydrogen bonding is a type of intermolecular force that occurs between molecules containing polar covalent bonds, resulting in strong attractive forces.

View answer and explanation

Correct option: B

Both Assertion and Reason are true, but Reason is not the correct explanation for Assertion

Option A is correct because both statements are correct, and Statement II correctly explains Statement I. Exothermic reactions can become spontaneous at low temperatures due to the decrease in entropy's influence.

78 Easy

78 of 124

Analyzing +4 | -1

Which of the following has the highest dipole moment

View answer and explanation

Correct option: C

{H_2}O

The correct answer is C (H2O) because water has a bent structure and two lone pairs, resulting in a significant dipole moment.

79 Easy

79 of 124

Understanding +4 | -1

\mathrm{HCl}

molecule in the vapour state is an example of:

View answer and explanation

Correct option: C

Polar covalent bond

Option C (Polar covalent bond) is correct because chlorine is more electronegative than hydrogen, resulting in an unequal sharing of electrons and a dipole moment.

80 Easy

80 of 124

Understanding +4 | -1

The lowest bond order present in :

View answer and explanation

Correct option: B

\mathrm{He}_2

Option B (

\mathrm{He}_2

) is correct because it has a bond order of 0, which is the lowest among the given options.

81 Easy

81 of 124

Analyzing +4 | -1

Which of the following sets of species does not follow octet rule?

View answer and explanation

Correct option: C

\mathrm{AlCl}_3, \mathrm{BF}_3, \mathrm{PCl}_5, \mathrm{SF}_6

Option C is correct because

\mathrm{AlCl}_3, \mathrm{BF}_3

are electron deficient, and

\mathrm{PCl}_5, \mathrm{SF}_6

have expanded octets.

82 Easy

82 of 124

Analyzing +4 | -1

Which of the following has least bond energy?

View answer and explanation

Correct option: A

Xe{F_2}

Option A (

Xe{F_2}

) is correct because it has the least bond energy due to the weak interaction between Xenon and Fluorine.

83 Easy

83 of 124

Understanding +4 | -1

Among the

LiCl,\,BeC{l_2},\,BC{l_3}

and

CC{l_4}

, the covalent bond character varies as

View answer and explanation

Correct option: C

LiCl < BeC{l_2} < BC{l_3} < CC{l_4}

The correct answer is C (

LiCl < BeCl_2 < BCl_3 < CCl_4

) because covalent character increases with the polarizing power of the cation, which increases with decreasing size and increasing charge.

84 Easy

84 of 124

Application +4 | -1

Covalency of chlorine atom after the excitation of two electrons will be

View answer and explanation

Correct option: B

Option B (5) is correct because after the excitation of two electrons, the chlorine atom can form 5 covalent bonds.

85 Easy

85 of 124

Analyzing +4 | -1

In which of the following processes, the bond order increases and paramagnetic character changes to diamagnetic one?

View answer and explanation

Correct option: C

\mathrm{NO} \rightarrow \mathrm{NO}^{+}

Option C (

NO \rightarrow NO^+

) is correct because the bond order increases from 2.5 to 3, and the paramagnetic NO becomes diamagnetic

NO^+

by losing an electron from an antibonding orbital.

86 Easy

86 of 124

Analyzing +4 | -1

The increasing order of bond angle among

\mathrm{BeCl}_2(\mathrm{I})

\mathrm{NH}_3(\mathrm{II}), \mathrm{CH}_4(\mathrm{III}), \mathrm{BF}_3 \mathrm{(IV})

will be:

View answer and explanation

Correct option: B

<

III

<

<

Option B (II < III < IV < I) is correct because it accurately reflects the increasing order of bond angles based on VSEPR theory and hybridization.

87 Easy

87 of 124

Analyzing +4 | -1

Which of the following pairs will from the most stable ionic bond?

View answer and explanation

Correct option: B

Mg\mathrm{ }\, and \mathrm{ }\,F

Option B is correct because Mg and F will form the most stable ionic bond due to the higher charge on Mg (+2) leading to a greater lattice energy.

88 Easy

88 of 124

Remembering +4 | -1

The bond angle in carbon tetrachloride is approximately

View answer and explanation

Correct option: B

109^{\circ}

Option B (

109^{\circ}

) is correct because carbon tetrachloride (

CCl_4

) has a tetrahedral geometry due to

sp^3

hybridization, resulting in a bond angle of approximately 109.5 degrees.

89 Easy

89 of 124

Remembering +4 | -1

The carbon atoms of graphite are

View answer and explanation

Correct option: A

sp^2

hybridised

Option A (

sp^2

hybridised) is correct because each carbon atom in graphite is bonded to three other carbon atoms in a planar arrangement, resulting in

sp^2

hybridization.

90 Easy

90 of 124

Analyzing +4 | -1

The dipole moment is highest for

View answer and explanation

Correct option: C

Acetophenone

Option C (Acetophenone) is correct because it has a significant difference in electronegativity between the carbonyl carbon and oxygen, leading to a substantial dipole moment, and the geometry allows for a net dipole moment.

Revision notes and key takeaways

Review CHEMICAL BONDING & MOLECULAR STRUCTURE in your textbook or class notes, then use this set to check your understanding.

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