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JEE • CHEMISTRY • CHEMICAL BONDING & MOLECULAR STRUCTURE

Chemical bonding & molecular structure practice · Easy

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Practice format and chapter quiz

These sets use single-correct-answer MCQs. They do not cover every JEE Main or JEE Advanced question format and are not full-length mock papers.

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Showing 1-30 of 124 questions
1 Easy
1 of 124
Understanding +4 | -1
Which statement is correct?
View answer and explanation
Correct option: A
Pi-bond always exists with sigma-bond
Option A (Pi-bond always exists with sigma-bond) is correct because a pi-bond forms only after a sigma-bond has already formed between the two atoms.
2 Easy
2 of 124
Understanding +4 | -1
Bond energy of C-C bond is highest in
View answer and explanation
Correct option: C
CH≡CHCH \equiv CH
Option C (CH≡CHCH \equiv CH) is correct because the triple bond has the highest bond energy due to the presence of three bonds between the carbon atoms.
3 Easy
3 of 124
Analyzing +4 | -1
Which of the following contains atleast one lone pair of electrons in all of its halides?
View answer and explanation
Correct option: A
Xe{Xe}
Option A (Xe{Xe}) is correct because Xenon (Xe) has a noble gas configuration and can form halides with at least one lone pair of electrons.
4 Easy
4 of 124
Understanding +4 | -1
Which compound among the following has more covalent character?
View answer and explanation
Correct option: B
AlI3\mathrm{Al}{\mathrm{I}_3}
Option B is correct because, according to Fajan's rule, larger anions and smaller cations with higher charges favor covalent character. AlI3AlI_3 fits this description better than the other options.
5 Easy
5 of 124
Analyzing +4 | -1
Which has the least bond angle
View answer and explanation
Correct option: C
H2O{H}_2 {O}
Option C (H2O{H}_2 {O}) is correct because the lone pair-lone pair repulsions in water are greater than lone pair-bond pair repulsions in ammonia and bond pair-bond pair repulsions in methane, leading to the smallest bond angle.
6 Easy
6 of 124
Understanding +4 | -1
When two atoms of chlorine combine to form one molecule of chlorine gas, the energy of the molecule
View answer and explanation
Correct option: C
Lower than that of separate atoms
Option C (Lower than that of separate atoms) is correct because when atoms combine to form a molecule, energy is released, resulting in a lower energy state for the molecule compared to the separate atoms.
7 Easy
7 of 124
Analyzing +4 | -1
Species having same bond order are
View answer and explanation
Correct option: C
F2+,   O2−1F_2^ + ,\,\,\,O_2^{ - 1}
Option C (F2+,O2−1F_2^+ , O_2^{-1}) is correct because both species have the same bond order of 1.5.
8 Easy
8 of 124
Remembering +4 | -1
sp hybridisation is also called :
View answer and explanation
Correct option: A
Diagonal hybridisation
Option A (Diagonal hybridisation) is correct because sp hybridization results in a linear geometry, which can be visualized as a diagonal arrangement of electron density.
9 Easy
9 of 124
Application +4 | -1
Which of the following species is paramagnetic?
View answer and explanation
Correct option: A
NO−\mathrm{NO}^{-}
The correct answer is A (NO−\mathrm{NO}^{-}) because it has unpaired electrons, making it paramagnetic.
10 Easy
10 of 124
Application +4 | -1
Which has sp2s{p^2}-hybridisation?
View answer and explanation
Correct option: B
SO2\mathrm{S}{\mathrm{O}_2}
The correct answer is SO2\mathrm{S}{\mathrm{O}_2} because it has a central sulfur atom with one lone pair and two bonding pairs, resulting in sp2s{p^2} hybridization.
11 Easy
11 of 124
Understanding +4 | -1
Electricity do not pass through ionic compounds
View answer and explanation
Correct option: B
In solid state
Option B (In solid state) is correct because ionic compounds in the solid state do not have mobile ions to conduct electricity.
12 Easy
12 of 124
Understanding +4 | -1
Linear shape molecule is
View answer and explanation
Correct option: D
BeCl2{BeCl}_2
Option D (BeCl2{BeCl}_2) is correct because Beryllium has two bond pairs and no lone pairs, resulting in a linear geometry.
13 Easy
13 of 124
Understanding +4 | -1
The molecule not having π\pi-bond is
View answer and explanation
Correct option: A
Cl2{Cl}_2
Option A (Cl2{Cl}_2) is correct because it has a single sigma bond and no pi bonds, while the other options have pi bonds.
14 Easy
14 of 124
Understanding +4 | -1
Electrovalent compounds do not have
View answer and explanation
Correct option: A
High M.P. and Low B.P.
Option A (High M.P. and Low B.P.) is correct because electrovalent (ionic) compounds typically have high melting points and high boiling points due to strong electrostatic forces between ions, requiring significant energy to overcome.
15 Easy
15 of 124
Understanding +4 | -1
Which of the following is not stable
View answer and explanation
Correct option: C
He2H{e_2}
Option C is correct because He2 does not exist as a stable molecule due to its bond order being zero.

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16 Easy
16 of 124
Understanding +4 | -1
Which is least soluble in water?
View answer and explanation
Correct option: C
Benzene
Option C (Benzene) is correct because it is a nonpolar hydrocarbon and lacks the ability to form hydrogen bonds with water, making it the least soluble.
17 Easy
17 of 124
Application +4 | -1
Which of the following species would be expected paramagnetic
View answer and explanation
Correct option: C
Cu++{Cu}^{++}
Option C (Cu++{Cu}^{++}) is correct because it has an unpaired electron, making it paramagnetic.
18 Easy
18 of 124
Understanding +4 | -1
Among NaF,    NaCl,    NaBr    and    NaI,\mathrm{NaF,\;}\,\,\mathrm{NaCl,\;}\,\,\mathrm{NaBr\;}\,\,\mathrm{and\;}\,\,\mathrm{NaI,} the NaF has highest melting point because:
View answer and explanation
Correct option: A
It has maximum ionic character
Option A (It has maximum ionic character) is correct because, according to Fajan's rule, smaller anions have less polarization and therefore higher ionic character and melting point.
19 Easy
19 of 124
Remembering +4 | -1
The bond angle in ethylene is
View answer and explanation
Correct option: B
120∘120^{\circ}
Option B (120∘120^{\circ}) is correct because ethylene has a trigonal planar geometry around each carbon atom due to sp2sp^2 hybridization.
20 Easy
20 of 124
Remembering +4 | -1
In a triple bond there is a sharing of
View answer and explanation
Correct option: D
6 electrons
The correct answer is D (6 electrons) because a triple bond involves the sharing of three pairs of electrons, totaling six electrons.
21 Easy
21 of 124
Understanding +4 | -1
As the pp-character increases, the bond angle in hybrid orbitals formed by ss and atomic orbitals
View answer and explanation
Correct option: A
Decreases
Option A (Decreases) is correct because as the p-character increases in hybrid orbitals, the s-character decreases, leading to smaller bond angles.
22 Easy
22 of 124
Application +4 | -1
Species having highest number of antibonding electrons
View answer and explanation
Correct option: C
O22−{O}_2^{2-}
Option C (O22−{O}_2^{2-}) is correct because it has the highest number of antibonding electrons among the given species, with 8 antibonding electrons.
23 Easy
23 of 124
Analyzing +4 | -1
Which does not have pyramidal geometry?
View answer and explanation
Correct option: B
NO3−\mathrm{NO}_3^ -
Option B (NO3−\mathrm{NO}_3^ -) is correct because it has a trigonal planar geometry, not a pyramidal geometry.
24 Easy
24 of 124
Application +4 | -1
An element XX with the electronic configuration 1s2,2s22p6,3s21 s^2, 2 s^2 2 p^6, 3 s^2 would be expected to form the chloride with the formula
View answer and explanation
Correct option: B
XCl2{XCl}_2
Option B (XCl2{XCl}_2) is correct because element X has 2 valence electrons, so it will form a chloride with the formula XCl2.
25 Easy
25 of 124
Understanding +4 | -1
Bond polarity is least in
View answer and explanation
Correct option: D
C–HC – H
Option D (C–HC – H) is correct because the electronegativity difference between carbon and hydrogen is the smallest among the given options, leading to the least bond polarity.
26 Easy
26 of 124
Understanding +4 | -1
Which of the following phenomenon will occur when two atoms of an element with same spin of electron in orbitals approach each other?
View answer and explanation
Correct option: B
Orbitals will not overlap
Option B (Orbitals will not overlap) is correct because, according to valence bond theory, orbitals with electrons of the same spin will not overlap to form a bond.
27 Easy
27 of 124
Analyzing +4 | -1
Among the following molecules which one have smallest bond angle
View answer and explanation
Correct option: D
H2Sc{H}_2 {Sc}
Option D (H2Sc{H}_2 {Sc}) is likely to have the smallest bond angle due to the large size and low electronegativity of Selenium, leading to less repulsion between the bond pairs.
28 Easy
28 of 124
Remembering +4 | -1
The value of one debye unit is equal to :
View answer and explanation
Correct option: C
3.33×10−30 Cm3.33 \times 10^{-30} \mathrm{~Cm}
Option C (3.33×10−30 Cm3.33 \times 10^{-30} \mathrm{~Cm}) is correct because this is the standard conversion factor between Debye units and Coulomb-meters.
29 Easy
29 of 124
Analyzing +4 | -1
The smallest bond angle is found in
View answer and explanation
Correct option: A
IF7{IF}_7
Option A (IF7{IF}_7) is correct because it has a pentagonal bipyramidal geometry, resulting in bond angles of approximately 90° and 72°, which are the smallest among the given options.
30 Easy
30 of 124
Analyzing +4 | -1
Assertion : lonic reactions are not instantaneous.

Reason : Oppositely charged ions exert strong forces.
View answer and explanation
Correct option: D
If assertion is false but reason is true
Option D (If assertion is false but reason is true) is correct because ionic reactions are generally very fast, and the strong forces between oppositely charged ions are the reason for this speed.
Revision notes and key takeaways

Review CHEMICAL BONDING & MOLECULAR STRUCTURE in your textbook or class notes, then use this set to check your understanding.

Key Takeaways

  • ✓ This set contains 124 single-correct-answer MCQs on CHEMICAL BONDING & MOLECULAR STRUCTURE.
  • ✓ Try each question before opening its answer. Read the explanation where one is available.
  • ✓ Sign in to save submitted answers. Revisit incorrect answers alongside your textbook or class notes.
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