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JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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Analyzing +4 | -1
The hybrid orbital having only 20% dd – character
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Correct option: C
SF4S{F_4}
Option B (SF6S{F_6}) is incorrect, Option A (CCl4CC{l_4}) is incorrect, Option D (Cl2OC{l_2}O) is incorrect and Option C (SF4S{F_4}) is correct because SF4S{F_4} has sp3ds{p^3}d hybridization, which means it has 20% d-character.

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