JEE CHEMISTRY MCQ: CHEMICAL BONDING & MOLECULAR STRUCTURE

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Analyzing +4 | -1

Polar molecule among the following is

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Correct option: A

Xe{O_3}

Option A (

Xe{O_3}

) is correct because it has a non-zero dipole moment due to its pyramidal shape.

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\mathrm{C}{\mathrm{O}_2}

\left( A \right)\mathrm{HgC}{\mathrm{l}_2},\left( B \right)\mathrm{N}{\mathrm{O}_2},\left( C \right)\mathrm{SnC}{\mathrm{l}_4},\left( D \right){\mathrm{C}_2}{\mathrm{H}_2}

{BF}_3

{BCl}_3

{BF}_3

{BCl}_3

{B}-X \pi