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NEET • PHYSICS • WORK-ENERGY-POWER

Work-energy-power practice · Mixed difficulty

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Showing 91-120 of 347 questions

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91 Medium
91 of 347
Analyzing +4 | -1
Two students are sitting face to face, at two ends of a long compartment of a train, running at a constant acceleration. They toss a ball to each other, with the same muzzle velocity and at the same inclination to the vertical.
Statement-1: The time intervals for the free fall in either direction are equal.
Statement-2: In the frame of compartment velocity is changing but the vertical velocity remains unaffected by the horizontal acceleration of the cart.
View answer and explanation
Correct option: A
Statement-1 and Statement-2 are true, Statement-2 is the correct explanation for Statement-1
Option A (Statement-1 and Statement-2 are true, Statement-2 is the correct explanation for Statement-1) is correct because the time intervals are equal due to the vertical motion being unaffected by the horizontal acceleration of the train compartment.
92 Medium
92 of 347
Application +4 | -1
A particle is released from a height H. At certain height its kinetic energy is two times its potential energy. Height and speed of particle at that instant are
View answer and explanation
Correct option: A
H3,2gH3\frac{H}{3},2\sqrt {\frac{{gH}}{3}}
Option A (H3,2gH3\frac{H}{3},2\sqrt {\frac{{gH}}{3}}) is correct because at height H/3, the kinetic energy is twice the potential energy, and the speed is calculated accordingly.
93 Medium
93 of 347
Analyzing +4 | -1
The slope of the kinetic energy displacement curve of a particle in motion is
View answer and explanation
Correct option: C
Directly proportional to the acceleration
Option C is correct because the slope of the kinetic energy-displacement curve is equal to the force, which is directly proportional to the acceleration.
94 Medium
94 of 347
Application +4 | -1
A particle moves with constant angular velocity in circular path of certain radius and is acted upon by a certain centripetal force F. If the angular velocity is doubled keeping radius the same, the new force will be
View answer and explanation
Correct option: C
4F
Option C (4F) is correct because the centripetal force is proportional to the square of the angular velocity, so doubling the angular velocity quadruples the force.
95 Medium
95 of 347
Application +4 | -1
Force of 4 N is applied on a body of mass 20 kg. The work done in 3rd second is
View answer and explanation
Correct option: A
2 J
Option D (1.2 J) is correct because the work done is calculated using the distance traveled in the third second and the applied force.
96 Medium
96 of 347
Understanding +4 | -1
Which of the following is not a perfectly inelastic collision
View answer and explanation
Correct option: A
Striking of two glass balls
Option A (Striking of two glass balls) is correct because in a perfectly inelastic collision, objects stick together, which doesn't happen with glass balls.
97 Medium
97 of 347
Application +4 | -1
A particle of mass m is moving in a circular path of constant radius r such that its centripetal acceleration ac{a_c}  is varying with time as ac=k2rt4,{a_c} = {k^2}r{t^4},, where k is a constant. The power delivered to the particle by the forces acting on its is
View answer and explanation
Correct option: D
2mk2r2t32m{k^2}{r^2}{t^3}
Option D (2mk2r2t32m{k^2}{r^2}{t^3}) is correct because it is derived from calculating the tangential force and then the power delivered to the particle.
98 Medium
98 of 347
Application +4 | -1
The mass of ship is 2×107  kg2 \times {10^7}\;kg. On applying a force of 25×105  N25 \times {10^5}\;N , it is displaced through 25 m. After the displacement, the velocity acquired by the ship will be
View answer and explanation
Correct option: D
2.5 m/s
Option D (2.5 m/s) is correct because the velocity is calculated using the work-energy theorem, where the work done by the force equals the change in kinetic energy.
99 Easy
99 of 347
Application +4 | -1
The kinetic energy of a body is KK. If one – fourth of its mass is removed and velocity is doubled, its new kinetic energy is,
View answer and explanation
Correct option: B
3K3K
Option B (3K) is correct because the new kinetic energy is calculated by adjusting the mass and velocity in the kinetic energy formula.
100 Easy
100 of 347
Application +4 | -1
A bus of mass 6 metric tons is pulled at a speed of 18 kmpH on a smooth incline of inclination 1in 20. Power of the engine is [g=10 ms−2]\left[ {g = 10\,m{s^{ - 2}}} \right]
View answer and explanation
Correct option: A
15 kW
Option A is correct because the power is calculated by finding the component of weight along the incline and multiplying it by the velocity.
101 Hard
101 of 347
Application +4 | -1
A particle experiences a variable force F⃗=(2x2i^+2yj^)N\vec{F}=\left(2 x^2 \hat{i}+2 y \hat{j}\right) N in a horizontal X−YX-Y plane. where xx and yy are in meters. If the particle moves from point (0,1)(0,1) to point (1,2)(1,2) in the X−YX-Y plane, then kinetic energy charges by
View answer and explanation
Correct option: A
113 J\frac{11}{3} \mathrm{~J}
Option A (113 J\frac{11}{3} \mathrm{~J}) is correct because the change in kinetic energy is equal to the work done by the force, which is calculated by integrating the force along the path.
102 Hard
102 of 347
Application +4 | -1
The potential energy U=3ax3−2bx2U=3 a x^3-2 b x^2. The force constant is represented by
View answer and explanation
Correct option: C
4b4 b
Option C (4 b) is correct because the force constant is the second derivative of the potential energy with respect to x, evaluated at equilibrium.
103 Medium
103 of 347
Application +4 | -1
A bucket filled with water is tied to a rope of length 0.5 m and is rotated in a circular path in vertical plane. The least velocity it should have at the lowest point of circle so that water dose not spill is (g=10  ms−2)\left( {g = 10\;\mathrm{m}{\mathrm{s}^{ - 2}}} \right)
View answer and explanation
Correct option: C
5  ms−15\;\mathrm{m}{\mathrm{s}^{ - 1}}
Option C (5  ms−15\;\mathrm{m}{\mathrm{s}^{ - 1}}) is correct because it represents the minimum velocity required at the lowest point to prevent water spillage, calculated using the condition for circular motion at the highest point.
104 Hard
104 of 347
Application +4 | -1
In a conservative field, if the potential energy UU as a function of position xx is given as U=x3+2x+3,U=x^3+2 x+3, then the corresponding conservative force is given by:
View answer and explanation
Correct option: C
−3x2−2-3 x^2-2
Option C (−3x2−2-3 x^2-2) is correct because the conservative force is the negative gradient of the potential energy function, which means taking the negative derivative of UU with respect to xx.
105 Medium
105 of 347
Application +4 | -1
A can filled with water is revolved in a vertical circle of radius 4 m and the water does not fall down. The time period of  revaluation will be
View answer and explanation
Correct option: B
4 s
Option B (4 s) is correct because the minimum speed at the top of the circle is gr\sqrt{gr}, and the time period is related to this speed and the radius.
106 Medium
106 of 347
Analyzing +4 | -1
Assertion: A truck and a car moving with the same kinetic energy are brought to rest by the application of breaks which provide equal retarding forces. Both come to rest in equal distance.
Reason: It is possible that the speed of a body is zero but velocity is not zero.
View answer and explanation
Correct option: C
If assertion is True but the Reason is False
Option C is correct because the assertion is true, and the reason is false. The assertion follows from the work-energy theorem, while the reason is incorrect because speed and velocity can be zero simultaneously.
107 Medium
107 of 347
Analyzing +4 | -1
Which of the following statements is wrong?
View answer and explanation
Correct option: C
If two protons are brought towards each other the PE of the system decreases.
Option C (If two protons are brought towards each other the PE of the system decreases.) is wrong because the potential energy of the system increases as two protons are brought closer due to electrostatic repulsion.
108 Medium
108 of 347
Application +4 | -1
A body of mass m starts moving from rest along x-axis so that its velocity varies as v=asv = a\sqrt s where a is a constant and s is the distance covered by the body. The total work done by all the forces acting on the body in the first t second after the start of the motion is:
View answer and explanation
Correct option: A
18ma4t2\frac{1}{8}m{a^4}{t^2}
Option A (18ma4t2\frac{1}{8}m{a^4}{t^2}) is correct because it is derived from calculating the work done using the work-energy theorem, considering the velocity's dependence on distance and time.
109 Medium
109 of 347
Understanding +4 | -1
A body of mass 1 kg1 \mathrm{~kg} is rotated in a horizontal circle of radius 1 m1 \mathrm{~m} and moves with velocity 2 m/sec2 \mathrm{~m} / \mathrm{sec}. The work done in 10 revolutions is
View answer and explanation
Correct option: D
Zero
The correct answer is D (Zero) because the work done in uniform circular motion is zero as the force is always perpendicular to the displacement.
110 Medium
110 of 347
Application +4 | -1
A circular road of radius 1000 m has banking angle 450{45^0}. The maximum safe speed of a car having mass 2000 kg will be, if the coefficient of friction between tyre and road is 0.5
View answer and explanation
Correct option: A
172 m/s
Option A (172 m/s) is correct because the maximum safe speed on a banked road is calculated using the formula v=rg(tan⁡θ+μ)/(1−μtan⁡θ)v = \sqrt{rg(\tan\theta + \mu)/(1 - \mu\tan\theta)}.
111 Easy
111 of 347
Application +4 | -1
A body of mass 8 kg8 \mathrm{~kg} and another of mass 2 kg2 \mathrm{~kg} are moving with equal kinetic energy. The ratio of their respective momenta will be
View answer and explanation
Correct option: B
2:12: 1
Option B (2:12: 1) is correct because the ratio of their momenta is calculated using the relationship between kinetic energy and momentum.
112 Hard
112 of 347
Application +4 | -1
A bomb of mass 10 kg explodes into two pieces of mass 5 kg and 5 kg. The velocity of mass 5 kg is 16 m/s. The K.E of mass 5 kg is
View answer and explanation
Correct option: B
640 J
Option B is correct because the kinetic energy is calculated directly from the mass and velocity of the 5 kg piece.
113 Medium
113 of 347
Understanding +4 | -1
Statement-I: A quick collision between two bodies is more violent than slow collision, even when initial and final velocities are identical.
Statement-II: The rate of change of momentum determines that the force is small or large.
View answer and explanation
Correct option: A
Statement-I &\& II are true.
Option A (Statement-I & II are true) is correct because a quick collision involves a larger force due to a greater rate of change of momentum, making it more violent, and the rate of change of momentum indeed determines the force.
114 Medium
114 of 347
Understanding +4 | -1
In which of the following cases, can the work done increase the potential energy?
View answer and explanation
Correct option: B
Conservative force only
Option B (Conservative force only) is correct because work done by a conservative force decreases potential energy, and the negative of that work increases potential energy.
115 Medium
115 of 347
Application +4 | -1
Power supplied to a particle of mass 2 kg varies with time as P=3t22P = \frac{{3{t^2}}}{2} watt. Here t is in second. If the velocity of particle at t=0 is v=0, the velocity of particle at time t=2 s will be
View answer and explanation
Correct option: C
2ms−12\mathrm{m}{\mathrm{s}^{ - 1}}
Option C (2  ms−12\mathrm{\;m}{\mathrm{s}^{ - 1}}) is correct because it is derived from the relationship between power, work, kinetic energy, and velocity.
116 Easy
116 of 347
Application +4 | -1
Two masses of 1 kg and 4 kg are moving with equal kinetic energy. The ratio of their linear momentum is
View answer and explanation
Correct option: A
0.043055556
Option A (0.043055556) is incorrect. The correct ratio of their linear momentum is 0.5, not 0.043055556. The kinetic energy is equal, so 1/2∗m1∗v12=1/2∗m2∗v221/2 * m1 * v1^2 = 1/2 * m2 * v2^2. Therefore, v1/v2=sqrt(m2/m1)=sqrt(4/1)=2v1/v2 = sqrt(m2/m1) = sqrt(4/1) = 2. The ratio of momentum is $m1*v1 / (m2*v2) = 1*v1 / (4*v2) = 1/4 * v1/v2 = 1/4 * 2 = 1/2 = 0.5
117 Medium
117 of 347
Analyzing +4 | -1
Motion of a particle in x−yx - y plane is described by a set of following equations x=4sin⁡(π2−ωt)mx = 4\sin \left( {\frac{\pi }{2} - \omega t} \right)m and y=4sin⁡(ωt)m.y = 4\sin \left( {\omega t} \right)m. The path of the particle will be
View answer and explanation
Correct option: A
Circular
Option A (Circular) is correct because the equations describe a parametric representation of a circle, where x and y components are sinusoidal functions with a phase difference of π/2\pi/2.
118 Medium
118 of 347
Analyzing +4 | -1
This question has statement I and statement II. Of the four choices given after the statements, choose the one that best describes the two statements. If two springs S1S_1 and S2S_2 of the force constants k1k_1 and k2k_2, respectively, are stretched by the same force, it is found that more work is done on spring S1S_1 than on spring S2S_2.
Statement-I: If stretched by the same amount, work done on S1S_1, will be more than that of S2S_2
Statement-II : k1<k2k_1 < k_2
View answer and explanation
Correct option: C
Statement-I is false, Statement-II is true
Option C (Statement-I is false, Statement-II is true) is correct because if S1 requires more work for the same force, it's less stiff (smaller k), and if stretched by the same amount, more work would be done on the stiffer spring (S2).
119 Medium
119 of 347
Understanding +4 | -1
A particle is moving along a circular path with a uniform speed. How does its angular velocity change when it completes half of the circular path?
View answer and explanation
Correct option: A
No change
The correct answer is A. Angular velocity is defined as the rate of change of angular displacement. If the particle moves with uniform speed, the angular velocity remains constant.
120 Easy
120 of 347
Application +4 | -1
Two bodies of masses 4 kg4 \mathrm{~kg} and 5 kg5 \mathrm{~kg} are moving with equal momentum. Then the ratio of their respective kinetic energies is
View answer and explanation
Correct option: D
5:45: 4
Option D (5:45: 4) is correct because kinetic energy is inversely proportional to mass when momentum is constant, so the ratio of KE is the inverse ratio of masses.
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