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NEET • PHYSICS • UNITS & MEASUREMENTS

Units & measurements practice · Mixed difficulty

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331 Easy
331 of 384
Application +4 | -1
The position of the particle moving along YY-axis is given as y=At2−Bt3y=A t^2-B t^3, where yy is measured in metre and tt in second. Then, the dimensions of BB are
View answer and explanation
Correct option: C
[LT−3]\left[\mathrm{LT}^{-3}\right]
Option C [LT−3]\left[\mathrm{LT}^{-3}\right] is correct because in the equation y=At2−Bt3y=A t^2-B t^3, each term must have the same dimensions as yy, which is length [L].
332 Medium
332 of 384
Application +4 | -1
The work done by a battery is W=εΔqW = \varepsilon \Delta q , where Δq\Delta q charge transferred by battery, ε\varepsilon = emf of the battery. What are dimensions of emf of battery?
View answer and explanation
Correct option: D
[ML2T−3A−1]\left[ {\mathrm{M}{\mathrm{L}^2}{\mathrm{T}^{ - 3}}{\mathrm{A}^{ - 1}}} \right]
Option D [ML2T−3A−1]\left[ {\mathrm{M}{\mathrm{L}^2}{\mathrm{T}^{ - 3}}{\mathrm{A}^{ - 1}}} \right] is correct because emf is work done per unit charge, and its dimensions can be derived from the dimensions of work and charge.
333 Easy
333 of 384
Application +4 | -1
A geometry ruler has 20 divisions between 5 cm. Its least count is
View answer and explanation
Correct option: A
0.25 cm
Option A (0.25 cm) is correct because the least count is calculated by dividing the length between the divisions by the number of divisions.
334 Hard
334 of 384
Analyzing +4 | -1
The focal length of a mirror is given by 1f=1u+1  v\frac{1}{f} = \frac{1}{u} + \frac{{1\;}}{v} where u and vv represent object and image distances respectively. The maximum relative error in ff is
View answer and explanation
Correct option: D
Δff=Δuu+Δvv+Δuu+v+Δvu+v\frac{{\Delta f}}{f} = \frac{{\Delta u}}{u} + \frac{{\Delta v}}{v} + \frac{{\Delta u}}{{u + v}} + \frac{{\Delta v}}{{u + v}}
Option D (Δff=Δuu+Δvv+Δuu+v+Δvu+v\frac{{\Delta f}}{f} = \frac{{\Delta u}}{u} + \frac{{\Delta v}}{v} + \frac{{\Delta u}}{{u + v}} + \frac{{\Delta v}}{{u + v}}) is correct because it correctly represents the maximum relative error in f, derived using error propagation techniques.
335 Hard
335 of 384
Analyzing +4 | -1
A student performs an experiment for determination of g(=4π2lT2),  l≈1m,\mathrm{g}\left( { = \frac{{4{\mathrm{\pi }^2}l}}{{{T^2}}}} \right),\mathrm{\;}l \approx 1\mathrm{m},, and he commits an error of Δl.\Delta l.. For T he takes the time of n oscillations with the stop watch of least count ∆T and he commits a human error of 0.1 s. For which of the following data, the measurement of g will be most accurate?
View answer and explanation
Correct option: D
ΔL=0.5,  ΔT=0.05,  n=50\Delta L = 0.5,\;\Delta T = 0.05,\;n = 50
Option D (ΔL=0.5,  ΔT=0.05,  n=50\Delta L = 0.5,\;\Delta T = 0.05,\;n = 50) is correct because it minimizes the percentage error in g by having a smaller error in time measurement and a larger number of oscillations.
336 Medium
336 of 384
Remembering +4 | -1
The SI unit of electrochemical equivalent is
View answer and explanation
Correct option: C
Kg C−1\mathrm{Kg}\,{\mathrm{C}^{ - 1}}
Option C (Kg C−1\mathrm{Kg}\,{\mathrm{C}^{ - 1}}) is correct because electrochemical equivalent is mass per unit charge, hence Kg/C.
337 Easy
337 of 384
Application +4 | -1
The value of (17.5)2{(17.5)^2} is
View answer and explanation
Correct option: A
306
Option A (306) is correct because the result should be rounded to the least precise value, which has no decimal places.
338 Medium
338 of 384
Application +4 | -1
Let L denote the self-inductance of coil which is in series with a capacitor of capacitance C. Which of the following has the unit second?
View answer and explanation
Correct option: A
LC\sqrt {LC}
Option A (LC\sqrt {LC}) is correct because the time period of an LC circuit is given by T=2πLCT = 2\pi \sqrt{LC}, so LC\sqrt{LC} has the unit of time (second).
339 Hard
339 of 384
Analyzing +4 | -1
If velocity of light c, acceleration due to gravity g and density d are the fundamental quantities in a system of measurement then mass has
View answer and explanation
Correct option: D
dimensions 6 in c
Option D (dimensions 6 in c) is correct because the mass can be expressed as M=c6g−2d−1M = c^6 g^{-2} d^{-1} using dimensional analysis.
340 Medium
340 of 384
Understanding +4 | -1
The SI unit of gravitational potential is
View answer and explanation
Correct option: B
Jkg−1\mathrm{Jk}{\mathrm{g}^{ - 1}}
Option B (Jkg⁻¹) is correct because gravitational potential is defined as gravitational potential energy per unit mass.
341 Medium
341 of 384
Analyzing +4 | -1
If a book with many printing errors contains four different formulae for the displacement yy of a particle undergoing a certain periodic motion.
(1) y=asin⁡2πtTy=a \sin \frac{2 \pi t}{T}
(2) y=asin⁡vTy=a \sin v T
(3) y=aTsin⁡tay=\frac{a}{T} \sin \frac{t}{a}
(4) y=(a2)(sin⁡2πtT+cos⁡2πtT)y=(a \sqrt{2})\left(\sin \frac{2 \pi t}{T}+\cos \frac{2 \pi t}{T}\right)
where aa is the maximum displacement of the particle, vv is the speed of particle, TT is the time period of motion. Then dimensionally
View answer and explanation
Correct option: B
(2) and (3) are wrong
Option B ((2) and (3) are wrong) is correct because these options are dimensionally incorrect, meaning the dimensions on both sides of the equation do not match.
342 Medium
342 of 384
Understanding +4 | -1
SI unit of permittivity is
View answer and explanation
Correct option: B
C2m−2N−1{\mathrm{C}^2}{\mathrm{m}^{ - 2}}{\mathrm{N}^{ - 1}}
Option B (C2m−2N−1{\mathrm{C}^2}{\mathrm{m}^{ - 2}}{\mathrm{N}^{ - 1}}) is correct because permittivity (ϵ\epsilon) appears in Coulomb's law: F=14πϵq1q2r2F = \frac{1}{{4\pi \epsilon}} \frac{{q_1 q_2}}{{r^2}}.
343 Medium
343 of 384
Application +4 | -1
If 1 g cm s−1=x{\mathrm{s}^{ - 1}} = x newton-second, then the number x is equal to
View answer and explanation
Correct option: C
1×10−51 \times {10^{ - 5}}
Option C (1×10−51 \times {10^{ - 5}}) is correct because it involves converting 1 g cm s−1{\mathrm{s}^{ - 1}} to newton-seconds using the conversion factors 1 g = 10-3 kg and 1 cm = 10-2 m.
344 Hard
344 of 384
Application +4 | -1
E, m, L and G denote energy, mass, angular momentum and gravitational constant respectively, EL2m5G2\frac{{E{L^2}}}{{{m^5}{G^2}}} has the dimensions of
View answer and explanation
Correct option: D
angle
Option D (angle) is correct because it involves finding the dimensions of EL2m5G2\frac{{E{L^2}}}{{{m^5}{G^2}}}, where E is energy, L is angular momentum, m is mass, and G is the gravitational constant. After substituting the dimensions of each quantity and simplifying, the result is dimensionless, which corresponds to an angle.
345 Medium
345 of 384
Understanding +4 | -1
The dimensional formula for impulse is same as the dimensional formula for
View answer and explanation
Correct option: A
Momentum
Option A (Momentum) is correct because impulse is the change in momentum, hence having the same dimensions as momentum.
346 Easy
346 of 384
Remembering +4 | -1
The number 0.004 has significant figures equal to
View answer and explanation
Correct option: A
1
Option A (1) is correct because leading zeros are not significant figures.
347 Easy
347 of 384
Application +4 | -1
A physical quantity QQ is calculated according to the expression

Q=A3B3CDQ=\frac{A^3 B^3}{C \sqrt{D}}

If percentage errors in A,B,C,DA, B, C, D are 2%,1%,3%2 \%, 1 \%, 3 \% and 4%4 \%, respectively. What is the percentage error in QQ ?
View answer and explanation
Correct option: C
±14%\pm 14 \%
Option C (±14\pm 14 \\% ) is correct because the percentage error in Q is calculated by summing the percentage errors in A, B, C, and D, each multiplied by its respective power.
348 Medium
348 of 384
Analyzing +4 | -1
Which of the following is the most accurate instrument for measuring length?
View answer and explanation
Correct option: D
A screw gauge of least count 0.001 mm0.001 {~mm}
Option D (A screw gauge of least count 0.001 mm) is the most accurate because it has the smallest least count, allowing for the most precise measurement.
349 Easy
349 of 384
Understanding +4 | -1
Dimensions of frequency are
View answer and explanation
Correct option: B
M0L0T−1{M^0}{L^0}{T^{ - 1}}
Option B (M0L0T−1{M^0}{L^0}{T^{ - 1}}) is correct because frequency is inverse of time period, hence only time dimension is involved.
350 Medium
350 of 384
Application +4 | -1
In an experiment the angles are required to be measured using an instrument. 29 divisions of the main scale exactly coincide with the 30 divisions of the vernier scale. If the smallest division of the main scale is half-a-degree (=0.5∘),\left( { = 0.5^\circ } \right), then the least count of the instrument is
View answer and explanation
Correct option: A
One minute
Option A (One minute) is correct because the least count is calculated by dividing the smallest division of the main scale by the total number of divisions on the vernier scale.
351 Medium
351 of 384
Application +4 | -1
If v=At+Bt2+Ct3v = \frac{A}{t} + B{t^2} + C{t^3} , where vv is velocity, t is time and A,B and C are constants, then the dimensional formula of B is
View answer and explanation
Correct option: D
[M0LT−3]\left[ {{\mathrm{M}^0}\mathrm{L}{\mathrm{T}^{ - 3}}} \right]
Option D ([M0LT−3]\left[ {{\mathrm{M}^0}\mathrm{L}{\mathrm{T}^{ - 3}}} \right]) is correct because each term in the equation must have the same dimensions as velocity (LT⁻¹). Therefore, Bt2Bt^2 must have dimensions of LT⁻¹, implying B has dimensions of LT−3LT^{-3}.
352 Medium
352 of 384
Remembering +4 | -1
One shake is equal to
View answer and explanation
Correct option: B
10−810^{-8} seconds
Option B (10−810^{-8} seconds) is correct because one shake is defined as 10−810^{-8} seconds, a unit often used in nuclear physics.
353 Easy
353 of 384
Analyzing +4 | -1
Statement-I: If error in measurement of mass is 2%2 \% and that in measurement of velocity is 5%5 \% than error in measurement of kinetic energy is 6%6 \%.
Statement-II: Error in kinetic energy is ΔKK=(Δmm+2Δvv)\frac{\Delta K}{K}=\left(\frac{\Delta m}{m}+2 \frac{\Delta v}{v}\right)
View answer and explanation
Correct option: C
Statement-I is false and statement-II is true
Option D (h0c5G−1A−1{h^{0}}{c^{5}}{G^{-1}}{A^{ - 1}}) is correct because it provides the correct dimensions for stopping potential in terms of h, c, G, and A.
354 Medium
354 of 384
Understanding +4 | -1
Dimensions of coefficient of viscosity are
View answer and explanation
Correct option: C
ML−1T−1M{L^{ - 1}}{T^{ - 1}}
Option C (ML−1T−1M{L^{ - 1}}{T^{ - 1}}) is correct because it is derived from the formula for viscous force.
355 Medium
355 of 384
Understanding +4 | -1
A spherometer has 100 equal divisions marked along the periphery of its disc and one full rotation of the disc advances on the main scale by 0.01 cm0.01 \mathrm{~cm}. The least count of this system is
View answer and explanation
Correct option: B
10−4 cm10^{-4} \mathrm{~cm}
Option B (10−4 cm10^{-4} \mathrm{~cm}) is correct because the least count is calculated by dividing the main scale division by the number of divisions on the circular scale.
356 Easy
356 of 384
Application +4 | -1
In a simple pendulum experiment for determination of acceleration due to gravity (g)(\mathrm{g}), time taken for 20 oscillations is measured by using a watch of 1 second least count. The mean value of time taken comes out to be 30 s30 \mathrm{~s}. The length of pendulum is measured by using a meter scale of least count 1 mm1 \mathrm{~mm} and the value obtained is 55.0 cm55.0 \mathrm{~cm}. The percentage (%)(\%) error in the determination of gg is close to
View answer and explanation
Correct option: A
6.8
Option A (6.8) is correct because the percentage error in g is calculated using the formula involving the errors in time period and length.
357 Easy
357 of 384
Understanding +4 | -1
Energy per unit volume represents
View answer and explanation
Correct option: A
Pressure
Option A (Pressure) is correct because pressure is defined as force per unit area, and energy per unit volume has the same dimensions as pressure.
358 Easy
358 of 384
Application +4 | -1
A physical quantity XX is given by X=2k3l2mnX=\frac{2 k^3 l^2}{m \sqrt{n}}

The percentage error in the measurements of k,l,mk, l, m and nn are 1%,2%,3%1 \%, 2 \%, 3 \% and 4%4 \%, respectively. The value of XX is uncertain by
View answer and explanation
Correct option: C
12%12 \%
Option C (12%) is correct because the percentage error in X is calculated by summing the percentage errors in k, l, m, and n, each multiplied by their respective powers in the formula.
359 Medium
359 of 384
Analyzing +4 | -1
From the dimensional consideration, which of the following equation is correct
View answer and explanation
Correct option: A
T=2πrR3GM  T = 2\pi r\sqrt {\begin{array}{cccccccccccccccccccc} {\frac{{{R^3}}}{{GM}}}\\ \; \end{array}}
Option A (T=2πrR3GMT = 2\pi r\sqrt {\begin{array}{cccccccccccccccccccc} {\frac{{{{{R^3}}}}}{{{{GM}}}}}\\ \\ \end{array}}) is correct because it is dimensionally incorrect. The correct equation should be T=2πR3GMT = 2\pi \sqrt {\frac{{{R^3}}}{{GM}}}
360 Medium
360 of 384
Remembering +4 | -1
To measure the distance of a planet from the Earth, ______ method is used.
View answer and explanation
Correct option: C
Parallax
Option C (Parallax) is correct because the parallax method is specifically designed for measuring distances to stars and planets.
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