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NEET • PHYSICS • UNITS & MEASUREMENTS

Units & measurements practice · Mixed difficulty

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Showing 361-384 of 384 questions
361 Hard
361 of 384
Application +4 | -1
Taking frequency ff, velocity vv and density ρ\rho to be the fundamental quantities, then the dimensional formula for momentum will be
View answer and explanation
Correct option: A
[ρv4f−3]\left[ {\rho {v^4}{f^{ - 3}}} \right]
Option A ([ρv4f−3\rho {v^4}{f^{ - 3}}]) is correct because dimensional analysis, using frequency, velocity, and density as fundamental quantities, yields the dimensions of momentum.
362 Medium
362 of 384
Analyzing +4 | -1
Given that :y=Asin⁡[(2πλ)  (ct−x)]:y = A\sin \left[ {\left( {\frac{{2\pi }}{\lambda }} \right)\;\left( {ct - x} \right)} \right] where, y and x are measured in metre. Which of the following statements is true?
View answer and explanation
Correct option: A
The unit of λ\lambda is same as that of x and A
Option A (The unit of λ\lambda is same as that of x and A) is correct because in the given equation, y, x, and λ\lambda all represent lengths and thus have the same unit.
363 Medium
363 of 384
Application +4 | -1
The concorde is the fastest airlines used for commercial service. It can cruise at 1450 mile per hour (about two times the speed of sound or in other words mach 2). What is it in m/s?
View answer and explanation
Correct option: A
644.4m/s
Option A (644.4m/s) is correct because 1 mile is approximately 1609.34 meters and 1 hour is 3600 seconds. Converting 1450 miles per hour to meters per second yields approximately 644.4 m/s.
364 Medium
364 of 384
Analyzing +4 | -1
S=A(1−e−Bxt)S = A(1 - {e^{ - Bxt}}) where S is speed and x is displacement. Then unit of B is
View answer and explanation
Correct option: A
m−1s−1{m^{ - 1}}{s^{ - 1}}
Option A (m−1s−1{m^{ - 1}}{s^{ - 1}}) is correct because the exponent must be dimensionless, making the units of B the inverse of x and t.
365 Medium
365 of 384
Analyzing +4 | -1
If C,R,L and I denote capacity, resistance, inductance and electric current respectively, the quantities having the same dimensions of time are (1) CR,  (2) LR ,  (3) LC  (4) LI2\left( 1 \right)\,CR,\,\,\left( 2 \right)\,\frac{L}{R}\,,\,\,\left( 3 \right)\,\sqrt {LC} \,\,\left( 4 \right)\,L{I^2}
View answer and explanation
Correct option: D
(1), (2) and (3) only
Option D ((1), (2) and (3) only) is correct because CR, L/R, and √(LC) all have the dimensions of time.
366 Medium
366 of 384
Application +4 | -1
In a new system of units, unit f mass is 10 kg, unit of length is 1 km and unit of time is 1 min. The value of 1 joule in this new hypothertical system is
View answer and explanation
Correct option: A
3.6×10−4 3.6\mathrm{ } \times {10^{ - 4}}\, new units
Option A (3.6×10−4 3.6\mathrm{ } \times {10^{ - 4}}\,) is correct because it represents the conversion of 1 Joule into the new system of units.
367 Medium
367 of 384
Remembering +4 | -1
The dimensional formula for impulse is
View answer and explanation
Correct option: B
MLT−1ML{T^{ - 1}}
Option B (MLT−1ML{T^{ - 1}}) is correct because impulse is the change in momentum, and momentum's dimensional formula is [MLT-1].
368 Medium
368 of 384
Remembering +4 | -1
Unit of magnetic moment is
View answer and explanation
Correct option: A
Ampere−metre  2Ampere - metre{\;^2}
Option A (Ampere−metre  2Ampere - metre{\;^2}) is correct because magnetic moment is defined as current times area, hence Ampere-meter².
369 Easy
369 of 384
Analyzing +4 | -1
Statement-I: Surface tension and spring constant have the same dimensions.
Statement-II: Both are equivalent to force per unit length
View answer and explanation
Correct option: A
Statement-I is true and statement-II is true
Statement-I is true and statement-II is true because both surface tension and spring constant have dimensions of force per unit length.
370 Easy
370 of 384
Analyzing +4 | -1
You may not know integration. But using dimensional analysis you can check or prove results. In the integral ∫dx(2ax−x2)1/2=ansin⁡−1(xa−1)\int \frac{d x}{\left(2 {ax}-x^2\right)^{1 / 2}}=a^n \sin ^{-1}\left(\frac{x}{a}-1\right) the value of nn should be-
View answer and explanation
Correct option: A
0
Option A (0) is correct because the argument of the inverse sine function must be dimensionless, and dimensional analysis shows that n must be zero.
371 Medium
371 of 384
Analyzing +4 | -1
The equation which is dimensionally correct among the following is
View answer and explanation
Correct option: C
s=ut+at2s = ut + a{t^2}
Option C (s=ut+at2s = ut + a{t^2}) is dimensionally correct because each term has the dimension of length [L].
372 Medium
372 of 384
Understanding +4 | -1
Dimension of R is
View answer and explanation
Correct option: B
ML2T−3A−2M{L^2}{T^{ - 3}}{A^{ - 2}}
Option B (ML2T−3A−2M{L^2}{T^{ - 3}}{A^{ - 2}}) is correct because it represents the dimensions of resistance derived from Ohm's law and the definition of power.
373 Medium
373 of 384
Analyzing +4 | -1
A quantity X is given by ε0LΔVΔt,  {\varepsilon _0}L\frac{{\Delta V}}{{\Delta t}},\;, where ε0{\varepsilon _0} is the permittivity of free space, L is a length, ΔV{\Delta V} is a potential difference and Δt{\Delta t} is a time interval. The dimensional formula for X is the same as that of
View answer and explanation
Correct option: D
Electric current
Option D (Electric current) is correct because the given expression is dimensionally equivalent to current, as it represents the displacement current in a capacitor.
374 Medium
374 of 384
Understanding +4 | -1
The unit of physical quantity obtained by the line intergral of electric field is
View answer and explanation
Correct option: C
JC−1\mathrm{J}{\mathrm{C}^{ - 1}}
Option C (JC−1\mathrm{J}{\mathrm{C}^{ - 1}}) is correct because the line integral of the electric field represents the electric potential difference, which is measured in Volts (J/C).
375 Medium
375 of 384
Understanding +4 | -1
The respective number of significant figures for the numbers 23.023, 0.0003 and 2.1×10−32.1 \times {10^{ - 3}} are
View answer and explanation
Correct option: A
5, 1, 2
Option A (5, 1, 2) is correct because 23.023 has 5 significant figures, 0.0003 has 1, and 2.1×10−32.1 \times 10^{-3} has 2.
376 Medium
376 of 384
Analyzing +4 | -1
The quantities x=1μ0ε0,  y=EBx = \frac{1}{{\sqrt {{\mu _0}{\varepsilon _0}} }},\,\,y = \frac{E}{B} and z=lCRz = \frac{l}{{CR}} are defined, where CC is capacitance, RR is resistance, ll is length, EE is electric field, BB is magnetic field, ε0{\varepsilon _0} is free space permittivity and μ0{\mu _0} is permeability, respectively. Then,
View answer and explanation
Correct option: A
x, y and z have the same dimension
x, y and z have the same dimension because all three represent velocity.
377 Medium
377 of 384
Understanding +4 | -1
In   S=a+bt+ct2\mathrm{\;S} = a + bt + c{t^2}. S is measured in metre and t in second. The unit of c is
View answer and explanation
Correct option: D
ms−2m{s^{ - 2}}
Option D (ms−2m{s^{ - 2}}) is correct because in the equation S=a+bt+ct2S = a + bt + ct^2, each term must have the same dimensions as S (which is in meters). Therefore, ct2ct^2 must have dimensions of meters, implying c has units of m/s2m/s^2.
378 Medium
378 of 384
Application +4 | -1
In an experiment, the following observation’s were recorded: L=2.820  mL = 2.820\;m, M=3.00 kg,l=0.087 cm, diameter D=0.041 cm. Taking g=9.81 m/s2m/{s^2} using the formula,
Y=4MgLπD2lY = \frac{{4MgL}}{{\pi {D^2}l}}, the maximum permissible error in Y is
View answer and explanation
Correct option: C
0.065
Option C (0.065) is correct because the maximum permissible error in Y is calculated by summing the percentage errors of each component, weighted by their exponents in the formula.
379 Hard
379 of 384
Application +4 | -1
The external and internal diameters of a hallow cylinder are measured to be (4.23±0.01) cm(4.23 \pm 0.01)\,cm and (3.89±0.01) cm(3.89 \pm 0.01)\,cm. The thickness of the wall of the cylinder is
View answer and explanation
Correct option: C
(0.17±0.01) cm(0.17 \pm 0.01)\,cm
Option C ((0.17±0.01) cm(0.17 \pm 0.01)\,cm) is correct because it accurately calculates the thickness and its associated error.
380 Medium
380 of 384
Analyzing +4 | -1
The Vander Waal’s equation of state for real gases is given as (P+aV2)(V−b)=nRT\left( {P + \frac{a}{{{V^2}}}} \right)\left( {V - b} \right) = nRT which of the following terms has dimensions different from that of energy
View answer and explanation
Correct option: B
aV2\frac{a}{{{V^2}}}
Option B (aV2\frac{a}{{{V^2}}}) is correct because it has dimensions of pressure, not energy. The other options have dimensions of energy.
381 Medium
381 of 384
Analyzing +4 | -1
Assertion A: If in five complete rotations of the circular scale, the distance travelled on main scale of the screw gauge in 5 mm and there are 50 total divisions on circular scale, then least count of screw gauge is 0.002 cm.
Reason R: Least count = Pitch  Total divisions on circular scale =\frac{\text { Pitch }}{\text { Total divisions on circular scale }}
View answer and explanation
Correct option: C
Both A and R are true and R is the correct explanation of A
Option C (Both A and R are true and R is the correct explanation of A) is correct because the assertion's least count calculation is accurate and the reason correctly states the formula for least count.
382 Medium
382 of 384
Analyzing +4 | -1
A student performs an experiment for determination of g=4π2lT2g = \frac{{4{\pi ^2}l}}{{{T^2}}} and he commits an error of ∆l. For that he takes the time of n oscillations with the stop watch of least count Δ\DeltaT and he commits a human error of 0.1 sec. For which of the following data, the measurement of g will be most accurate Δl  ΔT  n  Ampli.of oscill\Delta l\,\,\Delta T\,\,n\,\,Ampli.of\,oscill
View answer and explanation
Correct option: D
1 mm 0.1sec 50 1mm
Option D (1 mm 0.1sec 50 1mm) is correct because it minimizes the errors in length and time measurements by having a smaller least count and a larger number of oscillations.
383 Medium
383 of 384
Remembering +4 | -1
1 Parsec is equal to
View answer and explanation
Correct option: B
3.26 ly
Option B (3.26 ly) is correct because 1 parsec is approximately equal to 3.26 light-years.
384 Medium
384 of 384
Understanding +4 | -1
[ML2T−2]\left[ {\mathrm{M}{\mathrm{L}^2}{\mathrm{T}^{ - 2}}} \right] are dimensions of
View answer and explanation
Correct option: B
Moment of force
Option B (Moment of force) is correct because the moment of force (torque) is calculated as force times distance, which has the given dimensions.
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