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NEET • PHYSICS • CURRENT ELECTRICITY

Current electricity practice · Mixed difficulty

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Showing 91-120 of 198 questions

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91 Medium
91 of 198
Analyzing +4 | -1
Each side of regular polygon of nn sides has a resistance R.R. The equivalent resistance between any two adjacent vertices is
View answer and explanation
Correct option: C
(n−1)Rn\frac{{(n - 1)R}}{n}
The correct answer is C ((n−1)Rn\frac{{(n - 1)R}}{n}). The equivalent resistance between two adjacent vertices of a regular polygon with n sides, each having resistance R, can be found by considering the parallel combination of the remaining (n-1) resistors.
92 Medium
92 of 198
Understanding +4 | -1
Two bulbs are working in parallel order. Bulb AA is brighter than bulb BB. If RA{R_A} and RB{R_B} are their resistance respectively then
View answer and explanation
Correct option: B
RA<  RB{R_A} < \,\,{R_B}
Option B (RA< RB{R_A} < \,{R_B}) is correct because brighter bulbs have higher power consumption, and in parallel, higher power implies lower resistance.
93 Hard
93 of 198
Analyzing +4 | -1
Statement-1: If the radius of copper wire carrying a current is doubled, then the drift velocity of the electrons will become one fourth.
Statement-2: Drift velocity will change according to the relation, I=neAvdI=n e A v_{{d}}.
View answer and explanation
Correct option: A
Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1
Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1 because drift velocity is inversely proportional to the cross-sectional area, which depends on the radius squared.
94 Medium
94 of 198
Analyzing +4 | -1
An ammeter and a voltmeter of resistance RR are connected in series to an electric cell of negligible internal resistance. Their readings are AA and VV respectively. If another resistance RR is connected in parallel with the voltmeter
View answer and explanation
Correct option: D
AA will increase and VV will decrease
Option D (AA will increase and VV will decrease) is correct because adding a parallel resistance to the voltmeter decreases the overall resistance, increasing the current and decreasing the voltage reading.
95 Medium
95 of 198
Application +4 | -1
An electric current passes through a circuit containing two wires of the same material connected in parallel. If the lengths of the wires are in the ratio of 4/3\mathrm{4/3} and radius of the wires are in the ratio of 2/3\mathrm{2/3}, then the ratio of the current passing through the wires will be
View answer and explanation
Correct option: B
1/3\mathrm{1/3}
Option B (1/3\mathrm{1/3}) is correct because the ratio of currents is inversely proportional to the ratio of resistances, which depends on length and radius.
96 Medium
96 of 198
Understanding +4 | -1
When current is passed in antimony-bismuth couple, then
View answer and explanation
Correct option: B
The junction becomes hot when current flows from antimony to bismuth
Option B (The junction becomes hot when current flows from antimony to bismuth) is correct because this describes the Peltier effect, where heat is absorbed or released at the junction of two dissimilar metals depending on the direction of current flow.
97 Medium
97 of 198
Remembering +4 | -1
To deposit one gm equivalent of an element at an electrode, the quantity of electricity needed is
View answer and explanation
Correct option: D
96500  coulombs96500\,\,coulombs
The correct answer is 96500  coulombs96500\,\,coulombs because this is the definition of the Faraday constant, which represents the charge required to deposit one gram equivalent of an element.
98 Medium
98 of 198
Remembering +4 | -1
Kirchhoff’s first law i.e.  ∑i=0i.e.\,\,\sum i = 0 at a junction is based on the law of conservation of

View answer and explanation
Correct option: A
Charge
Option A is correct because Kirchhoff's first law is based on the principle of conservation of charge, stating that the total current entering a junction must equal the total current leaving it.
99 Medium
99 of 198
Application +4 | -1
A battery of 24  cells\mathrm{24}\,\,\mathrm{cells}, each of emf 1.5  V1.5\,\,V and internal resistance 2  Ω2\,\,\mathrm{\Omega } is to be connected in order to send the maximum current through a 12  Ω12\,\,\mathrm{\Omega } resistor. The correct arrangement of cells will be
View answer and explanation
Correct option: A
2  rows\mathrm{2}\,\,\mathrm{rows} of 12  cells\mathrm{12}\,\,\mathrm{cells} connected in parallel
The correct answer is A (2 rows of 12 cells connected in parallel) because this arrangement minimizes the internal resistance relative to the external resistance, maximizing current.
100 Hard
100 of 198
Application +4 | -1
A resistor RR has power of dissipation PP with cell voltage EE. The resistor is cut in nn equal parts and all parts are connected in parallel with same cell. The new power dissipation is
View answer and explanation
Correct option: C
n2Pn^2 P
Option C (n2Pn^2 P) is correct because cutting the resistor into n parts reduces the resistance of each part by a factor of n, and connecting them in parallel reduces the equivalent resistance by a factor of n2n^2.
101 Easy
101 of 198
Application +4 | -1
A current of 10 amp10 \mathrm{~amp} is passing through a metallic wire of cross sectional area 4×10−6 m24 \times 10^{-6} \mathrm{~m}^2. If the density of the aluminum conductor is 2.7 gm/cc2.7 \,\mathrm{gm/cc} considering aluminum gives 1 electrons per atom for conduction find the drift speed of the electrons if molecular weight of aluminum is 27 gm27 \mathrm{~gm}.
View answer and explanation
Correct option: C
2.6×10−4 m/s2.6 \times 10^{-4} \mathrm{~m} / \mathrm{s}
Option C (2.6×10−4 m/s2.6 \times 10^{-4} \mathrm{~m} / \mathrm{s}) is correct because it is the drift speed calculated using the formula I=neAvdI = n e A v_d and the given parameters.
102 Medium
102 of 198
Remembering +4 | -1
Kirchoff’s second law for the analysis of circuit is based on
View answer and explanation
Correct option: B
Conversion of energy
Option B is correct because Kirchhoff's second law is based on the principle of conservation of energy.
103 Medium
103 of 198
Application +4 | -1
A wire has a resistance of 3  Ω\mathrm{3}\,\,\mathrm{\Omega }. It is cut into two parts and both half values are connected in parallel. The new resistance is
View answer and explanation
Correct option: D
1.5   Ω1.5\,\,\,\mathrm{\Omega }
Option D (1.5   Ω1.5 \,\,\,\mathrm{\Omega }) is correct because cutting the wire in half doubles the resistance of each part, and connecting them in parallel halves the combined resistance.
104 Medium
104 of 198
Understanding +4 | -1
On passing the current in water voltmeter, hydrogen
View answer and explanation
Correct option: B
Is liberated at cathode
Option B (Is liberated at cathode) is correct because in the electrolysis of water, hydrogen ions (H+H^+) are reduced at the cathode to form hydrogen gas.
105 Easy
105 of 198
Application +4 | -1
A wire X\mathrm{X} is half the diameter and half the length of a wire Y\mathrm{Y} of similar material. The ratio of resistance of XX to that of YY is
View answer and explanation
Correct option: C
2:12: 1
Option C (2:12: 1) is correct because resistance is inversely proportional to the area and directly proportional to the length, so halving the length and halving the diameter (which quarters the area) results in a ratio of 2:1.
106 Medium
106 of 198
Application +4 | -1
Four wires AB,  BC,  CD,  DAAB,\,\,BC,\,\,CD,\,\,DA of resistance 4  ohm4\,\,ohm each and a fifth wire BDBD of resistance 8  ohm8\,\,ohm are joined to form a rectangle A B C DA\,B\,C\,D of which BDBD is a diagonal. The effective resistance between the points AA and BB is
View answer and explanation
Correct option: D
83  ohm\frac{8}{3}\,\,ohm
Option D (83  ohm\frac{8}{3}\,\,ohm) is correct because the effective resistance is calculated by simplifying the circuit using series and parallel combinations.
107 Easy
107 of 198
Application +4 | -1
A uniform wire of length ll and radius rr has a resistance of 100 Ω100\,\Omega . It is recast into a wire of radius r2\frac{r}{2}. The resistance of new wire will be
View answer and explanation
Correct option: A
1600Ω1600\Omega
Option A (1600Ω1600\Omega) is correct because when the radius is halved, the area is quartered, and since the volume remains constant, the length becomes four times the original, resulting in a 16-fold increase in resistance.
108 Medium
108 of 198
Application +4 | -1
An AC generator of 220  V220\,\,V having internal resistance r=10  Ωr = 10\,\,\mathrm{\Omega } and external resistance R=100  ΩR = 100\,\,\mathrm{\Omega }. What is the power developed in the external circuit
View answer and explanation
Correct option: B
400  W400\,\,W
Option B (400 W) is correct because it is the power calculated using the voltage across the external resistor and its resistance, considering the total resistance in the circuit.
109 Medium
109 of 198
Understanding +4 | -1
Which statement is true?
(i) Kirchoff’s law is equally applicable to both AC\mathrm{AC} and DC\mathrm{DC}.

(ii) Semiconductors have a positive temperature coefficient of resistance.

(iii) Meter bridge is greater sensitive when the resistance of all four arms of the bridge is of the same order.

(iv) The emf of a cell depends upon the size and area of electrodes.
View answer and explanation
Correct option: C
(iii) and (iv)
Option C ((iii) and (iv)) is correct because a meter bridge is most sensitive when the resistances are of the same order, and the emf of a cell depends on the size and area of the electrodes.
110 Medium
110 of 198
Analyzing +4 | -1
Choose the incorrect statement out of the following
View answer and explanation
Correct option: B
Resistivity of all materials increases with increase in temperature
The incorrect statement is B. Resistivity generally increases with temperature for metals but can decrease for semiconductors.
111 Medium
111 of 198
Application +4 | -1
The chemical equivalent of silver is 108\mathrm{108}. If the current in a silver voltmeter is 2  amp2\,\,amp, the time required to deposit 27  grams27\,\,grams of silver will be
View answer and explanation
Correct option: C
3.35  hrs3.35\,\,hrs
Option C (3.35 hrs) is correct because it is calculated using Faraday's laws of electrolysis, relating mass deposited to current and time.
112 Medium
112 of 198
Application +4 | -1
The length of the wire is doubled. Its conductance will be
View answer and explanation
Correct option: B
Halved
Option B (Halved) is correct because conductance is inversely proportional to the length of the wire. Doubling the length halves the conductance.
113 Medium
113 of 198
Analyzing +4 | -1
Assertion: The drift velocity of electrons in a metallic wire will decrease, if the temperature of the wire is increased.

Reason: On increasing temperature, conductivity of metallic wire decreases.
View answer and explanation
Correct option: B
If both Assertion and Reason are true but Reason is not correct explanation of Assertion.
Option B is correct because increasing temperature decreases conductivity, which reduces drift velocity, but the reason isn't a direct explanation.
114 Medium
114 of 198
Understanding +4 | -1
To draw maximum current from a combination of cells, how should the cells be grouped?
View answer and explanation
Correct option: D
Depends upon the relative values of internal and external resistances
Option D is correct because the optimal grouping depends on matching the total internal resistance of the cells to the external resistance for maximum power transfer.
115 Hard
115 of 198
Application +4 | -1
To measure the internal resistance of a battery, potentiometer is used. For R=10Ω\mathrm{R}=10 \Omega, the balance point is observed at ℓ=500 cm\ell=500 \mathrm{~cm} and for R=1Ω\mathrm{R}=1 \Omega the balance point is observed at ℓ=400 cm\ell=400 \mathrm{~cm}. The internal resistance of the battery is approximately:
View answer and explanation
Correct option: D
0.3Ω0.3 \Omega
Option D (If both Assertion & Reason are False) is correct because the terminal potential difference can be greater than the emf during charging, and the potential drop due to internal resistance decreases the terminal potential difference.
116 Medium
116 of 198
Application +4 | -1
Two cells when connected in series are balanced on 8 m on a potentiometer. If the cells are connected with polarities of one of the cells reversed, they balance on 2 m. The ratio of e.m.f.&#39;s of the two cells is
View answer and explanation
Correct option: B
5:35\mathrm{ }:\mathrm{ }3
Option B (5:35\mathrm{ }:\mathrm{ }3) is correct because the ratio of emfs can be found by setting up two equations based on series and reversed polarities.
117 Medium
117 of 198
Understanding +4 | -1
Drift velocity vd{v_d} varies with the intensity of electric field as per the relation
View answer and explanation
Correct option: A
vd∝E{v_d} \propto E
Option A (vd∝E{v_d} \propto E) is correct because drift velocity is directly proportional to the electric field intensity.
118 Medium
118 of 198
Remembering +4 | -1
The reciprocal of resistance is
View answer and explanation
Correct option: A
Conductance
Option A (Conductance) is correct because conductance is defined as the reciprocal of resistance.
119 Medium
119 of 198
Application +4 | -1
The temperature of cold junction of thermocouple is 0 ∘C0\,^\circ C. If the neutral temperature is 270 ∘C270\,^\circ C, then the inversion temperature is
View answer and explanation
Correct option: A
540 ∘C540\,^\circ C
Option A (540 ∘C540\,^\circ C) is correct because the inversion temperature is twice the neutral temperature when the cold junction is at 0°C.
120 Medium
120 of 198
Application +4 | -1
A cell can be balanced against 110  cm\mathrm{110}\,\,\mathrm{cm} and 100  cm\mathrm{100}\,\,\mathrm{cm} of potentiometer wire, respectively with and without being short circuited through a resistance of 10  Ω\mathrm{10}\,\,\mathrm{\Omega }. Its internal resistance is
View answer and explanation
Correct option: A
1.0  Ω\mathrm{1}\mathrm{.0}\,\,\mathrm{\Omega }
Option C (>25W> 25\mathrm{ }W) is correct because the resistance decreases less than expected at lower voltage, leading to higher power dissipation.
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