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NEET • PHYSICS • CURRENT ELECTRICITY

Current electricity practice · Mixed difficulty

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Showing 181-198 of 198 questions

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181 Medium
181 of 198
Remembering +4 | -1
Material that is widely used to make wire bound standard resistors is
View answer and explanation
Correct option: A
Manganin
Option A (Manganin) is correct because Manganin is widely used to make wire-wound standard resistors due to its low temperature coefficient of resistance and high resistivity.
182 Medium
182 of 198
Application +4 | -1
Masses of the three wires of same material are in the ratio of 1:2:31:2:3 and their lengths in the ratio of 3:2:13:2:1. Electrical resistance of these wires will be in the ratio of
View answer and explanation
Correct option: D
27:6:127:6:1
Option D (27:6:127:6:1) is correct because the resistance is proportional to the square of the length and inversely proportional to the mass.
183 Medium
183 of 198
Analyzing +4 | -1
Assertion: When Wheatstone bridge is balanced, the current through the cell depends on the resistance of galvanometer.
Reason: In the balanced condition, current through the galvanometer is very high.
View answer and explanation
Correct option: D
If both Assertion & Reason are False
Option D (If both Assertion & Reason are False) is correct because in a balanced Wheatstone bridge, the current through the galvanometer is zero, and the current through the cell depends on the overall resistance of the bridge, not the galvanometer's resistance.
184 Medium
184 of 198
Remembering +4 | -1
The length of a conductor is doubled and its radius is halved, its specific resistance is
View answer and explanation
Correct option: A
Unchanged
Option A (Unchanged) is correct because specific resistance (resistivity) is a material property and does not depend on the dimensions of the conductor.
185 Medium
185 of 198
Application +4 | -1
For a thermocouple, the inversion temperature is 600 ∘C600\,^\circ C  and the neutral temperature is 320 ∘C320\,^\circ C. Find the temperature of the cold junction?
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Correct option: A
40 ∘C40\,^\circ C
Option A (40 °C) is correct because the temperature of the cold junction is calculated using the formula relating inversion temperature, neutral temperature, and cold junction temperature.
186 Medium
186 of 198
Analyzing +4 | -1
Twelve wires of equal resistance RR are connected to form a cube. The effective resistance between two opposite diagonal ends will be
View answer and explanation
Correct option: A
(5/6)R\left( {5/6} \right)R
The correct answer is A ((5/6)R\left( {5/6} \right)R). The effective resistance between two opposite diagonal ends of a cube formed by 12 equal resistors can be calculated using symmetry and Kirchhoff's laws.
187 Easy
187 of 198
Application +4 | -1
The heat Produced in a given resistor in a given time by the sinusoidal current I0sin⁡I_0 \sin ωt\omega \mathrm{t} will be the same as that by a steady current of magnitude
View answer and explanation
Correct option: D
I02\frac{I_0}{\sqrt{2}}
Option D (I02\frac{I_0}{\sqrt{2}}) is correct because the RMS value of a sinusoidal current is I0/2I_0/\sqrt{2}, and the heat produced is proportional to the square of the RMS current.
188 Hard
188 of 198
Application +4 | -1
Five cells each of emf EE and internal resistance rr send the same amount of current through an external resistance RR whether the cells are connected in parallel or in series. Then the ratio (Rr)\left(\frac{R}{r}\right) is
View answer and explanation
Correct option: D
1
Option D (1) is correct because the condition for the same current in series and parallel configurations leads to the external resistance being equal to the internal resistance.
189 Medium
189 of 198
Understanding +4 | -1
Thermoelectric constant of a thermocouple are α\alpha and β.\beta .. Thermoelectric power at inversion temperature is
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Correct option: B
−α- \alpha
Option B (−α- \alpha) is correct because at the inversion temperature, the thermoelectric power is the negative of the thermoelectric constant α\alpha.
190 Hard
190 of 198
Application +4 | -1
In a simple metre-bridge circuit, the gaps are bridge by coils PP and QQ having the smaller resistance. A balance is obtained when the jockey key makes contact at a point of the bridge wire 40 cm from the PP end. On shunting the coil QQ with a resistance of 50Ω,50 \Omega, the balance point is moved through 10 cm. The resistance PP and QQ are
View answer and explanation
Correct option: B
503Ω,502Ω\frac{50}{3} \Omega, \frac{50}{2} \Omega respectively
Option B (503Ω,502Ω\frac{50}{3} \Omega, \frac{50}{2} \Omega respectively) is correct because it satisfies the conditions of the meter bridge circuit before and after shunting the coil Q.
191 Medium
191 of 198
Analyzing +4 | -1
Assertion (A) : If potential difference across two points is zero, current between these two points should be zero.

Reason (R): Current passing from a resistor I=VRI=\frac{V}{R}
View answer and explanation
Correct option: D
If Assertion is false but the Reason is true.
Option D is correct because a potential difference of zero does not necessarily mean zero current if there is no resistance, and Ohm's law is correctly stated.
192 Medium
192 of 198
Application +4 | -1
A certain electrical conductor has a square cross-section, 2.0  mm\mathrm{2}\mathrm{.0}\,\,\mathrm{mm} on side, and is 12m\mathrm{12 m} long. The resistance between its ends is 0.072  Ω0.072\,\,\mathrm{\Omega }. The resistivity of its material is equal to
View answer and explanation
Correct option: D
2.4  ×  10−8  Ω m2.4\,\, \times \,\,{10^{ - 8}}\,\,\mathrm{\Omega }\,\mathrm{m}
Option D (160Ω,0.09Ω160 \Omega, 0.09 \Omega) is correct because it calculates the primary and secondary load resistances based on the given voltages, power, and efficiency.
193 Easy
193 of 198
Analyzing +4 | -1
Statement-1: If a wire is stretched to increase its length nn times then its resistance also become nn time.
Statement-2: Resistance of the wire is directly proportional to its length.
View answer and explanation
Correct option: D
Statement-1 is false, Statement-2 is true
Statement-1 is false, and Statement-2 is true. When a wire is stretched, its volume remains constant, so increasing length affects the area, changing the resistance non-linearly. Resistance is directly proportional to length.
194 Medium
194 of 198
Application +4 | -1
A battery of emf 2  V\mathrm{2}\,\,\mathrm{V} and internal resistance 0.1  Ω0.1\,\,\Omega is being charged by a current of 5  A\mathrm{5}\,\,\mathrm{A}. the potential difference between the terminals of the battery is
View answer and explanation
Correct option: A
2.5  Ω2.5\,\,\Omega
Option A (2.5  Ω2.5\,\,\Omega) is correct because the potential difference is calculated by adding the product of current and internal resistance to the emf when charging.
195 Medium
195 of 198
Application +4 | -1
In a Wheatstone bridge, P=90  Ω,  Q=110  Ω,  R=40  Ω  and  S=60  ΩP = 90\,\,\mathrm{\Omega },\,\,Q = 110\,\,\mathrm{\Omega },\,\,R = 40\,\,\mathrm{\Omega }\,\,\mathrm{and}\,\,S = 60\,\,\mathrm{\Omega } and a cell of 4  V\mathrm{4}\,\,\mathrm{V} emf. Then the potential difference between the diagonal along which a galvanometer is connected is
View answer and explanation
Correct option: A
−0.2  V- 0.2\,\,\mathrm{V}
Option A (-0.2 V) is correct because it is the potential difference calculated using the Wheatstone bridge formula and given resistor values.
196 Medium
196 of 198
Analyzing +4 | -1
A wire is cut into 4 pieces, which are put together by sides to obtain one conductor. If the original resistance of wire was RR, the resistance of the buridle will be
View answer and explanation
Correct option: D
R/32R/32.
The correct answer is C (R16\frac{{R}}{{16}}). When a wire is cut into 4 pieces and bundled together, the length is reduced to 1/4 and the area is increased 4 times, resulting in a resistance of R/16.
197 Medium
197 of 198
Remembering +4 | -1
Watt−hourWatt - hour meter measures
View answer and explanation
Correct option: A
Electric energy
The Watt-hour meter measures electric energy. It integrates power consumption over time to determine the total energy used.
198 Easy
198 of 198
Analyzing +4 | -1
Statement-1: When a wire is stretched so that its diameter is halved then its resistance become 16 times.
Statement-2: Resistance of wire decrease with increase in length.
View answer and explanation
Correct option: C
Statement-1 is true, Statement-2 is false
Statement-1 is true, and Statement-2 is false. When the diameter is halved, the area becomes one-fourth, and since the volume is constant, the length becomes 4 times its initial length. Therefore, the resistance becomes 16 times. Resistance increases with length.
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