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NEET • PHYSICS • CURRENT ELECTRICITY

Current electricity practice · Easy

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1 Easy
1 of 34
Application +4 | -1
The e.m.f. of a cell is 6 volt. When 2 ampere current is drawn from it then the potential difference across its terminals remains 3 volt. Its internal resistance wil be:
View answer and explanation
Correct option: A
1.5Ω1.5 \Omega
Option A (1.5Ω1.5 \Omega) is correct because the internal resistance can be calculated using the formula r = (E-V)/I.
2 Easy
2 of 34
Application +4 | -1
The emf of a battery A is balanced by a length of 80 cm on a potentiometer wire. The emf of a standard cell 1 V is balanced by 50 cm. The emf of A is
View answer and explanation
Correct option: D
1.6 V
Option D (1.6 V) is correct because the emf is directly proportional to the balancing length in a potentiometer experiment.
3 Easy
3 of 34
Application +4 | -1
When a current II is set up in a wire of radius rr, the drift velocity is vd\mathrm{v}_{\mathrm{d}}. If the same current is set up through a wire of radius 2r2 \mathrm{r}, the drift velocity will be
View answer and explanation
Correct option: D
vd/4\mathrm{v}_{\mathrm{d}} / 4
Option D (vd/4\mathrm{v}_{\mathrm{d}} / 4) is correct because the drift velocity is inversely proportional to the cross-sectional area of the wire, which is proportional to the square of the radius.
4 Easy
4 of 34
Application +4 | -1
The radius (r)(r), length (l)(l) and resistance (R)(R) of a metal wire was measured in the laboratory as
r=(0.35±0.05)cmr=(0.35 \pm 0.05) \mathrm{cm}
R=(100±10)ohmR=(100 \pm 10) \mathrm{ohm}
l=(15±0.2)cml=(15 \pm 0.2) \mathrm{cm}
The percentage error in resistivity of the material of the wire is:
View answer and explanation
Correct option: B
39.9%39.9 \%
Option B (39.9%39.9 \%) is correct because it is the percentage error in resistivity calculated using the given errors in radius, length, and resistance.
5 Easy
5 of 34
Understanding +4 | -1
A piece of copper and the other of germanium are cooled from the room temperature to 80 K80 \mathrm{~K}, then which of the following would be wrong statements?
(a) Resistance of each increases
(b) Resistance of each decreases
(c) Resistance of copper increases while that of germanium decreases
(d) Resistance of copper decreases while that of germanium increases
View answer and explanation
Correct option: A
(a), (b) and (c)
Option A ((a), (b) and (c)) is correct because the resistance of copper decreases with decreasing temperature, while the resistance of germanium increases with decreasing temperature. Therefore, (a), (b), and (c) are wrong statements.
6 Easy
6 of 34
Application +4 | -1
The number of electrons flowing per second in the filament of a 110 W110 \mathrm{~W} bulb operating at 220 V220 \mathrm{~V} is :

(Given e=1.6×10−19C\mathrm{e}=1.6 \times 10^{-19} \mathrm{C})
View answer and explanation
Correct option: A
31.25×101731.25 \times 10^{17}
Option A (31.25×101731.25 \times 10^{17}) is correct because it is calculated by dividing the power by the voltage to find the current, then dividing the current by the elementary charge to find the number of electrons per second.
7 Easy
7 of 34
Understanding +4 | -1
Statement-1: Current flows in a conductor only when there is an electric field within the conductor.
Statement-2: The drift velocity of electrons in the presence of electric field decreases.
View answer and explanation
Correct option: C
Statement-1 is true, Statement-2 is false
Option C is correct because current flow requires an electric field, but drift velocity increases with the electric field, not decreases.
8 Easy
8 of 34
Understanding +4 | -1
Statement-1: Two unequal resistances are connected in series across a cell, then potential drop across the larger resistance is more.
Statement-2: The current will be same in both unequal resistances.
View answer and explanation
Correct option: A
Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1
Option A (Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1) is correct because in a series circuit, the current is the same through all resistors, and the potential drop is proportional to the resistance.
9 Easy
9 of 34
Analyzing +4 | -1
If 12 resistors of 12 Ω12\, \Omega each are connected in each edge of a cubical circuit then effective resistance across any of its edge is :-
View answer and explanation
Correct option: C
7 Ω7\, \Omega
The correct answer is C (7 Ω7 \, \Omega). The effective resistance across an edge of a cube with resistors on each edge can be calculated using symmetry and Kirchhoff's laws.
10 Easy
10 of 34
Application +4 | -1
A potentiometer consist of a wire of length 2m and resistance . It is connected to an ideal cell of e.m.f 4V. The potential difference per unit length of the wire will be
View answer and explanation
Correct option: D
2 V/m
Option D (2 V/m) is correct because the potential difference per unit length is the total potential difference divided by the length of the wire.
11 Easy
11 of 34
Application +4 | -1
An electron beam has an aperture 1.0 mm21.0 \mathrm{~mm}^2. A total of 6×10166 \times 10^{16} electrons go through any perpendicular cross section per second. Find the current density in the beam. (in A/m2\mathrm{A} / \mathrm{m}^2 )
View answer and explanation
Correct option: B
9.6×1039.6 \times 10^3
Option B (9.6×103A/m29.6 \times 10^3 \mathrm{A} / \mathrm{m}^2) is correct because it is calculated by dividing the total current by the area of the aperture.
12 Easy
12 of 34
Application +4 | -1
A direct current of 4 A4 \mathrm{~A} and an alternating current of peak value 4 A flow through resistance of 3Ω3 \Omega and 2Ω2 \Omega respectively. The ratio of heat produced in the two resistances in same interval of time will be :
View answer and explanation
Correct option: B
3:13: 1
Option B (3:13: 1) is correct because the heat produced is proportional to the square of the current, and the RMS value of the AC current is used for heat calculations.
13 Easy
13 of 34
Remembering +4 | -1
The Kirchhoff's second law (ΣiR=ΣE),(\Sigma i R=\Sigma E), where the symbols have their usual meanings, is based on
View answer and explanation
Correct option: D
conservation of energy
Option D is correct because Kirchhoff's second law is based on the conservation of energy, stating that the sum of potential differences around a closed loop is zero.
14 Easy
14 of 34
Analyzing +4 | -1
Statement-1: Potential difference across the terminals of a battery can be greater than its emf.
Statement-2: When current is taken from battery, V=ε−IrV={\varepsilon}- Ir (Symbols have their usual meaning).
View answer and explanation
Correct option: B
Statement-1 is true, Statement-2 is true, Statement-2 is not the correct explanation for Statement-1
Option B (Statement-1 is true, Statement-2 is true, Statement-2 is not the correct explanation for Statement-1) is correct because the potential difference can be greater than the emf when the battery is being charged, and Statement-2 describes the voltage when the battery is discharging.
15 Easy
15 of 34
Application +4 | -1
The colour code of a resistor is brown, black and brown. Then the value of resistance is
View answer and explanation
Correct option: C
0.1 kΩ0.1 \,{k} \Omega
Option C (0.1 kΩ) is correct because the color code brown, black, brown corresponds to 1, 0, and a multiplier of 101, resulting in 10 × 101 = 100 ohms = 0.1 kΩ.
16 Easy
16 of 34
Application +4 | -1
A technician has only two resistance coils. By using
them singly in series or in parallel, he is able to obtain
the resistance 1.5, 2, 6 and 8 ohms. The resistance
of two coils are
View answer and explanation
Correct option: C
2 ohm and 6 ohm
Option C (2 ohm and 6 ohm) is correct because these values satisfy the given conditions for series and parallel combinations.
17 Easy
17 of 34
Understanding +4 | -1
Statement-1: Two unequal resistances are connected in parallel across a cell, then current through the smaller resistor is more.
Statement-2: More current will flow through a larger resistor.
View answer and explanation
Correct option: C
Statement-1 is true, Statement-2 is false
Option C (Statement-1 is true, Statement-2 is false) is correct because in a parallel circuit, the voltage is the same across all resistors, and the current is inversely proportional to the resistance.
18 Easy
18 of 34
Application +4 | -1
A block of metal is heated directly by dissipating power in the internal resistance of block. Because of temperature rise, the resistance increases exponentially with time and is given by R(t)=0.5 e2t\mathrm{R}(\mathrm{t})=0.5 \, \mathrm{e}^{2 \mathrm{t}}, where t\mathrm{t} is in second. The block is connected across a 110 V110 \mathrm{~V} source and dissipates 7644 J7644 \mathrm{~J} heat energy over a certain period of time. This period of time is ______ ×10−1\times 10^{-1} sec.
View answer and explanation
Correct option: A
5
Option A (5) is correct. The heat energy dissipated is given by the integral of power over time. Solving the integral yields a time of 0.5 seconds, which is 5 × 10-1 seconds.
19 Easy
19 of 34
Application +4 | -1
Two heaters AA and BB have power rating of 1 kW1 \mathrm{~kW} and 2 kW,2 \mathrm{~kW}, respectively. Those two are first connected in series and then in parallel to a fixed power source. The ratio of power outputs for these two cases is:
View answer and explanation
Correct option: A
2:92: 9
Option A (2:9) is correct because the ratio of power outputs in series and parallel configurations depends on the resistances, which are inversely proportional to the power ratings given a fixed voltage.
20 Easy
20 of 34
Application +4 | -1
If negligibly small current is passed though a wire of length 15 m15 \mathrm{~m} and resistance of 5Ω5 \Omega, having uniform cross section of 6×10−7 m26 \times 10^{-7} \mathrm{~m}^2, then coefficient of resistivity of material is
View answer and explanation
Correct option: B
2×10−7Ω−m2 \times 10^{-7} \Omega-\mathrm{m}
Option B (2×10−7Ω−m2 \times 10^{-7} \Omega-\mathrm{m}) is correct because it is calculated using the formula for resistivity: R=ρLAR = \rho \frac{L}{A}.
21 Easy
21 of 34
Application +4 | -1
A current of 10 amp10 \mathrm{~amp} is passing through a metallic wire of cross sectional area 4×10−6 m24 \times 10^{-6} \mathrm{~m}^2. If the density of the aluminum conductor is 2.7 gm/cc2.7 \,\mathrm{gm/cc} considering aluminum gives 1 electrons per atom for conduction find the drift speed of the electrons if molecular weight of aluminum is 27 gm27 \mathrm{~gm}.
View answer and explanation
Correct option: C
2.6×10−4 m/s2.6 \times 10^{-4} \mathrm{~m} / \mathrm{s}
Option C (2.6×10−4 m/s2.6 \times 10^{-4} \mathrm{~m} / \mathrm{s}) is correct because it is the drift speed calculated using the formula I=neAvdI = n e A v_d and the given parameters.
22 Easy
22 of 34
Application +4 | -1
A wire X\mathrm{X} is half the diameter and half the length of a wire Y\mathrm{Y} of similar material. The ratio of resistance of XX to that of YY is
View answer and explanation
Correct option: C
2:12: 1
Option C (2:12: 1) is correct because resistance is inversely proportional to the area and directly proportional to the length, so halving the length and halving the diameter (which quarters the area) results in a ratio of 2:1.
23 Easy
23 of 34
Application +4 | -1
A uniform wire of length ll and radius rr has a resistance of 100 Ω100\,\Omega . It is recast into a wire of radius r2\frac{r}{2}. The resistance of new wire will be
View answer and explanation
Correct option: A
1600Ω1600\Omega
Option A (1600Ω1600\Omega) is correct because when the radius is halved, the area is quartered, and since the volume remains constant, the length becomes four times the original, resulting in a 16-fold increase in resistance.
24 Easy
24 of 34
Application +4 | -1
Resistance of conductor is doubled keeping the potential difference across it constant. The rate of generation of heat will
View answer and explanation
Correct option: B
be halved
Option B (be halved) is correct because the rate of heat generation is inversely proportional to the resistance when the potential difference is constant.
25 Easy
25 of 34
Application +4 | -1
The resistance of a 240 V240 \mathrm{~V} and 200 W200 \mathrm{~W} electric bulb when hot is 10 times the resistance when cold. Find its resistance at room temperature. If the working temperature of the filament is 2000∘C2000^{\circ} \mathrm{C}, find the temperature coefficient of the filament.
View answer and explanation
Correct option: B
4.5×10−3∘C−14.5 \times 10^{-3}{ }^{\circ} \mathrm{C}^{-1}
Option B (4.5×10−3∘C−14.5 \times 10^{-3}{ }^{\circ} \mathrm{C}^{-1}) is correct because it is the temperature coefficient calculated using the change in resistance with temperature.
26 Easy
26 of 34
Analyzing +4 | -1
Five hundred cells of same emf EE and same internal resistance rr are connected in series to form a loop in same order (without external resistance). The potential drop across 199 cells is found to be
View answer and explanation
Correct option: D
Zero
Option D (Zero) is correct because the cells are connected in a closed loop in the same order, resulting in zero net emf and thus zero potential drop across any number of cells.
27 Easy
27 of 34
Understanding +4 | -1
The electrical conductivity of earth's atmosphere
View answer and explanation
Correct option: B
Increases with altitude.
Option B (Increases with altitude) is correct because the electrical conductivity of the Earth's atmosphere increases with altitude due to increased ionization from cosmic rays and solar radiation.
28 Easy
28 of 34
Understanding +4 | -1
Ohm's law is valid if
View answer and explanation
Correct option: D
II depends on VV linearly
Option D (II depends on VV linearly) is correct because Ohm's law states that current is directly proportional to voltage, implying a linear relationship.
29 Easy
29 of 34
Understanding +4 | -1
Statement-1: A piece of copper and other of germanium are cooled from room temperature to 100 K100 \,\mathrm{K} conductivity of copper increases and that of germanium decreases.
Statement-2: Copper has positive temperature coefficient where as germanium has negative temperature coefficient.
View answer and explanation
Correct option: A
Statement-1 is true, Statement-2 is true, Statement-2 is the correct explanation for Statement-1
Option A is correct because copper's conductivity increases with decreasing temperature (positive temperature coefficient), while germanium's conductivity decreases (negative temperature coefficient).
30 Easy
30 of 34
Application +4 | -1
An inductance of 0.1 henry is connected with D.C. source of 120 volt. If the current flowing in the inductive coil is 0.5 amp0.5\, \mathrm{amp}, then resistance of the coil is:
View answer and explanation
Correct option: B
240 Ω240\, \Omega
Option B (240 Ω240\, \Omega) is correct because the resistance is calculated using Ohm's law with the given voltage and current in a DC circuit.
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