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NEET • CHEMISTRY • SOME BASIC CONCEPTS OF CHEMISTRY

Some basic concepts of chemistry practice · Mixed difficulty

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Showing 241-270 of 313 questions

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241 Medium
241 of 313
Remembering +4 | -1
To prepare a standard solution of a substance, we use:
View answer and explanation
Correct option: C
Measuring flask
Option C is correct because a measuring flask is used to prepare a standard solution, ensuring accurate volume measurement.
242 Hard
242 of 313
Application +4 | -1
For a reaction, N2(g)+3H2(g)→ 2NH3(g){N_2}(g) + 3{H_2}(g)\xrightarrow{\,}2N{H_3}(g), identify dihydrogen (H2)({H_2}) as a limiting reagent in the following reaction mixtures.
View answer and explanation
Correct option: A
56 g  of  N2+10 g  of  H256\,g\,\,\mathrm{of}\,\,{N_2} + 10\,g\,\,\mathrm{of}\,\,{H_2}
Option A (56 g  of  N2+10 g  of  H256\,g\,\,\mathrm{of}\,\,{N_2} + 10\,g\,\,\mathrm{of}\,\,{H_2}) is correct because dihydrogen is the limiting reagent when the mole ratio of H2H_2 to N2N_2 is less than 3:1.
243 Easy
243 of 313
Analyzing +4 | -1
In the reaction

Br2+Na2CO3→NaBr+NaBrO3+CO2\mathrm{Br}_2+\mathrm{Na}_2 \mathrm{CO}_3 \rightarrow \mathrm{NaBr}+\mathrm{NaBrO}_3+\mathrm{CO}_2

The equivalent weight of NaBrO3\mathrm{NaBrO}_3 is
View answer and explanation
Correct option: C
Molecular weight5\frac{\text {Molecular weight}}{5}
Option C (Molecular weight/5) is correct because the change in oxidation state of Br in NaBrO3 is 5.
244 Easy
244 of 313
Understanding +4 | -1
Millimole of a solute in a solution can be given by :
View answer and explanation
Correct option: D
Both (b) and (c)
Option D is correct because millimoles can be calculated using both M×VinmLM \times V_{in mL} and wt.mol.wt.×1000\frac{wt.}{mol.wt.} \times 1000.
245 Medium
245 of 313
Analyzing +4 | -1
Statement - I: All the members of any class of hydrocarbon (alkane, alkene, alkyne or
arene) have the same, empirical formula.

Statement - II: Compounds having the same general formula may have different empirical
formula.
View answer and explanation
Correct option: D
If Statement-I is false but Statement-II is true
Option D (If Statement-I is false but Statement-II is true) is correct. Statement I is false because members of different classes of hydrocarbons have different empirical formulas. Statement II is true because compounds with the same general formula can have different empirical formulas.
246 Hard
246 of 313
Understanding +4 | -1
Two Flasks A and B of equal capacity of volume
contain NH3NH_3 and SO2SO_2 gas respectively under
similar condition which flask has more number
of moles.
View answer and explanation
Correct option: C
Both have same moles
Option C (Both have same moles) is correct because, under similar conditions of temperature and pressure, equal volumes of gases contain the same number of moles (Avogadro's Law).
247 Easy
247 of 313
Understanding +4 | -1
In the relationship molecular formula = empirical formula ×  n.  The  ′n′    may  have:\times \;n.\;\mathrm{The}\;'n'\;\;\mathrm{may}\;\mathrm{ have}:
View answer and explanation
Correct option: C
Only positive integer value
Option C (Only positive integer value) is correct because 'n' in the formula must be a positive integer, representing the multiple of the empirical formula that makes up the molecular formula.
248 Easy
248 of 313
Understanding +4 | -1
On dissolving 1 mole each of the following acids in 1 litre water, the acid which do not give a solution of 1 N strength is:
View answer and explanation
Correct option: D
H3PO4{\mathrm{H}_3}\mathrm{P}{\mathrm{O}_4}
Option D (H3PO4{\mathrm{H}_3}\mathrm{P}{\mathrm{O}_4}) is correct because H3PO4 is a triprotic acid, meaning 1 mole of it will not produce a 1 N solution.
249 Easy
249 of 313
Remembering +4 | -1
The net charge on ferrous ion is:
View answer and explanation
Correct option: A
+2+ 2
Option A (+2) is correct because the ferrous ion (Fe2+) has a charge of +2.
250 Easy
250 of 313
Application +4 | -1
Two elements XX (atomic weight = 75) and YY (atomic weight =16) combine to give a compound having 75.8% of XX. The formula of the compound is:
View answer and explanation
Correct option: D
X2Y3{X_2}{Y_3}
Option D (X2Y3{X_2}{Y_3}) is correct because the ratio of moles of X and Y calculated from the given percentage and atomic weights is approximately 2:3.
251 Easy
251 of 313
Understanding +4 | -1
Number of g-atoms of an element in one atom are:
View answer and explanation
Correct option: B
1.66×10−241.66 \times {10^{ - 24}}
Option B (1.66×10−241.66 \times {10^{ - 24}}) is correct because one gram-atom is equal to Avogadro's number of atoms, and the mass of one atom in grams is the reciprocal of Avogadro's number.
252 Hard
252 of 313
Application +4 | -1
100 tons of Fe2O3\mathrm{F}{\mathrm{e}_2}{\mathrm{O}_3} containing 20% impurities will give iron by reduction with H2{\mathrm{H}_2} equal to
View answer and explanation
Correct option: D
56 tons
Option D (56 tons) is correct because it is the mass of iron produced from 100 tons of Fe2O3 containing 20% impurities after reduction with H2.
253 Medium
253 of 313
Understanding +4 | -1
Choose the correct statement.
View answer and explanation
Correct option: C
The particles of gases are far apart as compared to
solids and liquids and their movement is easy and
fast.
The correct answer is C (The particles of gases are far apart as compared to solids and liquids and their movement is easy and fast) because it accurately describes the arrangement and movement of particles in gases.
254 Hard
254 of 313
Analyzing +4 | -1
In the reaction,

2Al(s)+6HCl(aq)→2Al3+(aq)+6Cl−(aq)+3H2(g)2\mathrm{Al}\left( s \right) + 6\mathrm{HCl}\left( {aq} \right) \to 2\mathrm{A}{\mathrm{l}^{3 + }}\left( {aq} \right) + 6\mathrm{C}{\mathrm{l}^ - }\left( {aq} \right) + 3{\mathrm{H}_2}\left( \mathrm{g} \right)
View answer and explanation
Correct option: D
11.2LH2(g)11.2\mathrm{L}{\mathrm{H}_2}\left( \mathrm{g} \right) at STP is produced for every mole HCl(aq) consumed
Option D (11.2LH2(g)11.2\mathrm{L}{\mathrm{H}_2}\left( \mathrm{g} \right) at STP is produced for every mole HCl(aq) consumed) is correct because the stoichiometry of the reaction shows that 6 moles of HCl produce 3 moles of H₂, meaning 1 mole of HCl produces 0.5 moles of H₂.
255 Hard
255 of 313
Application +4 | -1
112ml112 \mathrm{ml} of a gas is produced at S.T.P. by the action of 4.12 mg\mathrm{mg} of alcohol ROH\mathrm{ROH} with CH3Mg\mathrm{CH}_3 \mathrm{Mg}. The molecular mass of alcohol is
View answer and explanation
Correct option: C
82.4 g82.4 \mathrm{~g}
Option C (82.4 g82.4 \mathrm{~g}) is correct. The molecular mass of the alcohol is calculated based on the volume of gas produced and the reaction with Grignard reagent.
256 Hard
256 of 313
Application +4 | -1
The crystalline salt Na2SO4⋅xH2O{Na}_2{SO}_4 \cdot {xH}_2{O} on heating loses 55.9%55.9 \% of its mass ad becomes anhydrous. The formula of crystalline salt is
View answer and explanation
Correct option: D
Na2SO4⋅10H2O{Na}_2 {SO}_4 \cdot 10 {H}_2{O}
Option D (Na2SO4⋅10H2O{Na}_2 {SO}_4 \cdot 10 {H}_2{O}) is correct because the mass loss corresponds to 10 water molecules per formula unit of sodium sulfate.
257 Hard
257 of 313
Remembering +4 | -1
Which of the following is not described in Charaka Samhita?
View answer and explanation
Correct option: C
Preparation of perfumes and cosmetics
Option C (Preparation of perfumes and cosmetics) is correct because Charaka Samhita primarily deals with medicine and treatment, not cosmetics.
258 Easy
258 of 313
Understanding +4 | -1
Molar concentration of a solution in water is:
View answer and explanation
Correct option: B
More than molality of the solution
Option D is correct because molarity is less than molality when the density of the solution is less than 1 g/mL, which is common for aqueous solutions.
259 Easy
259 of 313
Analyzing +4 | -1
Moon takes 27.3 days to complete one orbit around the Earth. Now read the following statements and choose the correct code. Here T is for true statement and F is for ‘False statement’.
(i) Moon takes 655.2 hours to complete one orbit around the Earth.
(ii) Moon takes 39312 seconds to complete one orbit around the earth.
(iii) Moon takes 1638 minutes to complete one orbit around the Earth.
View answer and explanation
Correct option: C
T F F
Option C (T F F) is correct because statement (i) is true, while statements (ii) and (iii) are false based on the conversion of days to hours, seconds, and minutes.
260 Easy
260 of 313
Analyzing +4 | -1
Suppose 60%w/w60 \% \mathrm{w} / \mathrm{w} aqueous solution of glucose (C6H12O6)\left({C}_6 {H}_{12} {O}_6\right) and 20%w/w20 \% \mathrm{w} / \mathrm{w} aqueous solution of urea (NH2CONH2)\left({NH}_2 {CONH}_2\right) have equal molarity, then which solution has higher density:
View answer and explanation
Correct option: A
Both have equal density
Option B (Glucose solution) is correct because for equal molarity, the glucose solution, having a higher weight percentage, must have a higher density.
261 Easy
261 of 313
Understanding +4 | -1
The oxidation of SO2S{O_2} to SO3S{O_3} is an exothermic reaction. The yield of SO3S{O_3} will be maximum if:
View answer and explanation
Correct option: B
Temperature is reduced and pressure is increased
The correct answer is B (Temperature is reduced and pressure is increased) because the reaction is exothermic and involves a decrease in the number of moles of gas, favoring low temperature and high pressure.
262 Easy
262 of 313
Understanding +4 | -1
1 mol of CH4C{H_4} contains
View answer and explanation
Correct option: B
4 g.atom of Hydrogen
Option B (4 g.atom of Hydrogen) is correct because 1 mole of CH4CH_4 contains 4 moles of hydrogen atoms, which is equivalent to 4 g.atom of Hydrogen.
263 Hard
263 of 313
Analyzing +4 | -1
For the reaction,

FeS2+KMnO4+H∗⟶Fe3++H2SO4+Mn2++H2O\mathrm{FeS}_2+\mathrm{KMnO}_4+\mathrm{H}^* \longrightarrow \mathrm{Fe}^{3+}+\mathrm{H}_2 \mathrm{SO}_4+\mathrm{Mn}^{2+}+\mathrm{H}_2 \mathrm{O}

if the molar mass of FeS2\mathrm{FeS}_2 is M\mathrm{M}, then equivalent mass of FeS2\mathrm{FeS}_2 would be equal to
View answer and explanation
Correct option: D
M15\frac{M}{15}
Option D (M/15) is correct because the equivalent mass is the molar mass divided by the change in oxidation state of FeS2, which is 15.
264 Medium
264 of 313
Application +4 | -1
The volume of air needed for complete combustion of 1 kg carbon at STP is:
View answer and explanation
Correct option: A
9333.33 litre
Option A (9333.33 litre) is correct because it involves calculating the moles of carbon, then the moles of oxygen required, and finally the volume of air needed, considering air is approximately 21% oxygen.
265 Easy
265 of 313
Application +4 | -1
Equivalent mass of Na2S2O3\mathrm{N}{\mathrm{a}_2}{\mathrm{S}_2}{\mathrm{O}_3} in its reaction with I2{\mathrm{I}_2} is equal to :
View answer and explanation
Correct option: A
MolarmassMolar\mathrm{ }mass
Option A (MolarmassMolar\mathrm{ }mass) is correct because in the reaction of sodium thiosulfate with iodine, each mole of Na2S2O3 reacts with one mole of I2, so the equivalent mass is equal to the molar mass.
266 Hard
266 of 313
Application +4 | -1
26 mL26\,\mathrm{mL} of CO2\mathrm{C}{\mathrm{O}_2} are passed over hot coke. The maximum volume of CO formed is :
View answer and explanation
Correct option: D
52 mL52\,\mathrm{mL}
Option D (52 mL52\,\mathrm{mL}) is correct because the volume of CO formed is calculated based on the stoichiometry of the reaction.
267 Hard
267 of 313
Understanding +4 | -1
Which of the following statements about a compound is/are incorrect?

I. A molecule of a compound has atoms of different elements.

II. A compound cannot be separated into its constituent elements by physical methods of separation.
III. A compound retains the physical properties of its constituent elements.

IV. The ratio of atoms of different elements in a compound is fixed.
View answer and explanation
Correct option: A
Only III
The correct answer is A (Only III) because a compound does not retain the physical properties of its constituent elements.
268 Medium
268 of 313
Understanding +4 | -1
H3BO3{\mathrm{H}_3}\mathrm{B}{\mathrm{O}_3} is:
View answer and explanation
Correct option: A
Monobasic and weak Lewis acid
Option A (Monobasic and weak Lewis acid) is correct because boric acid accepts a hydroxide ion from water, acting as a Lewis acid, and it only accepts one, making it monobasic.
269 Medium
269 of 313
Analyzing +4 | -1
Statement-I: Equivalent weight of NH3,{NH}_3, in the reaction N2→NH3N_2 \rightarrow N H_3 is 17/317 / 3 while that of N2N_2 is 28/6.28 / 6.

Statement-II: Equivalent weight = Molecular weight  number of e− lost or gained/mole =\frac{\text { Molecular weight }}{\text { number of } e^- \text{ lost or gained/mole }}
View answer and explanation
Correct option: A
Both the statements are correct
Option A (Both the statements are correct) is correct because the equivalent weight is calculated correctly in statement I, and statement II provides the correct definition of equivalent weight.
270 Easy
270 of 313
Remembering +4 | -1
The hardness of water is usually expressed in:
View answer and explanation
Correct option: A
ppm
Option A (ppm) is correct because the hardness of water is commonly expressed in parts per million (ppm).
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