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NEET • CHEMISTRY • SOME BASIC CONCEPTS OF CHEMISTRY

Some basic concepts of chemistry practice · Mixed difficulty

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Showing 211-240 of 313 questions

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211 Medium
211 of 313
Understanding +4 | -1
The stoichiometry of the following reaction is
K2S2O8(aq)+2KI(aq)→2K2SO4(aq)+I2(aq){\mathrm{K}_2}{\mathrm{S}_2}{\mathrm{O}_8}\left( {aq} \right) + 2\mathrm{KI}\left( {aq} \right) \to 2{\mathrm{K}_2}\mathrm{S}{\mathrm{O}_4}\left( {aq} \right) + {\mathrm{I}_2}\left( {aq} \right)
View answer and explanation
Correct option: C
1:21\mathrm{ }:\mathrm{ }2
Option C is correct because the stoichiometry of K2S2O8K_2S_2O_8 to KI is 1:2 as indicated by the balanced chemical equation.
212 Medium
212 of 313
Understanding +4 | -1
The electrochemical equivalent of a metal is ′x′'x' g coulomb−1.\mathrm{coulom}{\mathrm{b}^{ - 1}}\mathrm{.} The equivalent weight of metal is
View answer and explanation
Correct option: B
x×96500x \times 96500
Option B (x×96500x \times 96500) is correct because the equivalent weight is the product of the electrochemical equivalent and Faraday's constant (96500 C/mol).
213 Medium
213 of 313
Understanding +4 | -1
A: Ratio of empirical formula mass and molecular formula mass may be a whole number.

R: Molecular formula mass =n×=\mathrm{n} \times empirical formula mass, where n\mathrm{n} is the simplest whole number.
View answer and explanation
Correct option: B
Both A and R are correct, but R is not the correct explanation of A.
Option B (Both A and R are correct, but R is not the correct explanation of A) is correct because both the assertion and the reason are correct statements, but the reason doesn't directly explain why the ratio in the assertion is a whole number.
214 Easy
214 of 313
Application +4 | -1
Which gas contains larger number of molecules?
View answer and explanation
Correct option: A
4g  of   H2O4\mathrm{g}\;\mathrm{of}{\mkern 1mu} \;{\mathrm{H}_2}\mathrm{O}
Option A (4g  of   H2O4\mathrm{g}\;\mathrm{of}{\mkern 1mu} \;{\mathrm{H}_2}\mathrm{O}) is correct because it has the highest number of moles compared to the other options, and therefore the largest number of molecules.
215 Medium
215 of 313
Understanding +4 | -1
Mole and millimole of reactants react in the ……….as represented by balanced stoichiometric equation.
View answer and explanation
Correct option: A
Molar ratio
Option A (Molar ratio) is correct because reactants react in the molar ratio as represented by the balanced stoichiometric equation.
216 Medium
216 of 313
Application +4 | -1
Which has maximum number of atoms ?
View answer and explanation
Correct option: B
44gofCO244\mathrm{ }g\mathrm{ }of\mathrm{ }C{O_2}
Option B (44gofCO244\mathrm{ }g\mathrm{ }of\mathrm{ }C{O_2}) is correct because it contains the highest number of moles of molecules and the highest number of atoms per molecule compared to the other options after correcting the calculation.
217 Hard
217 of 313
Analyzing +4 | -1
Analysis show that nickel oxide consists of nickel ion with 96%96 \% ions having d8{d}^8 configuration and 4%4 \% having of d7{d}^7 configuration. Which amongst the following best represents the formula of the oxide.
View answer and explanation
Correct option: D
Ni0.98O1.00{Ni}_{0.98} {O}_{1.00}
Option D is correct because it represents the formula where the ratio of Ni to O is 0.98:1, accounting for the presence of Ni2+ and Ni3+ ions to maintain charge neutrality.
218 Medium
218 of 313
Application +4 | -1
What volume of 0.40 MM Na2S2O3\mathrm{N}{\mathrm{a}_2}{\mathrm{S}_2}{\mathrm{O}_3} would be required to react with the I2{\mathrm{I}_2} liberated by adding excess of KI to 50 mL of 0.20 MM CuSO4\mathrm{CuS}{\mathrm{O}_4} solution?
View answer and explanation
Correct option: B
25 mL
Option B (25 mL) is correct because it calculates the volume of Na2S2O3 required based on the stoichiometry of the reactions.
219 Hard
219 of 313
Analyzing +4 | -1
0.1 M solution of KI reacts with excess of H2SO4\mathrm{H}_2 \mathrm{SO}_4 and KIO3\mathrm{KIO}_3 solution. According to equation

5I−+IO3−+6H+→3I2+3H2O5 \mathrm{I}^{-}+\mathrm{IO}_3^{-}+6 \mathrm{H}^{+} \rightarrow 3 \mathrm{I}_2+3 \mathrm{H}_2 \mathrm{O}

Identify the correct statements:

(A) 200 mL of KI solution reacts with 0.004 mol of KIO3\mathrm{KIO}_3

(B) 200 mL of KI solution reacts with 0.006 mol of H2SO4\mathrm{H}_2 \mathrm{SO}_4

(3) 0.5 L of KI solution produced 0.005 mol of I2\mathrm{I}_2

(4) Equivalent weight of KIO3\mathrm{KIO}_3 is equal to (Molecular weight5)\left(\frac{\text {Molecular weight}}{5}\right)

Choose the correct answer from the options given below:
View answer and explanation
Correct option: A
(A) and (D) only
Option A is correct because 200 mL of 0.1 M KI reacts with 0.004 mol of KIO3 and the equivalent weight of KIO3 is Molecular weight/5.
220 Medium
220 of 313
Understanding +4 | -1
A mixture contains two or more substances in ________ which are called its ________.
View answer and explanation
Correct option: C
any ratio, components
Option C (any ratio, components) is correct because mixtures can have variable composition, and the substances within are called components.
221 Easy
221 of 313
Analyzing +4 | -1
A: Number of ions in 9 gram of NH4+{NH}_4^{+}is equal to Avogadro's number (NA)\left({N}_{{A}}\right).

R: Number of ions is equal to number of atoms.
View answer and explanation
Correct option: D
Both the A and R are incorrect.
Option D is correct because both the assertion and the reason are incorrect. 9g of NH4+ is not equal to Avogadro's number of ions, and the number of ions is not always equal to the number of atoms.
222 Hard
222 of 313
Understanding +4 | -1
Which of the following is chemically inert and cannot undergo disproportionation
View answer and explanation
Correct option: B
SF6\mathrm{SF}_6
Option B (SF6\mathrm{SF}_6) is correct because sulfur hexafluoride is sterically crowded and kinetically inert, preventing disproportionation.
223 Medium
223 of 313
Application +4 | -1
Oxidation number of carbon in carbon suboxide is :
View answer and explanation
Correct option: B
+43+ \frac{4}{3}
Option B (+43+ \frac{4}{3}) is correct because the oxidation number of carbon in carbon suboxide (C3O2C_3O_2) is calculated based on the oxidation state of oxygen being -2.
224 Medium
224 of 313
Remembering +4 | -1
The gram molecular weight of hydrogen peroxide is 34. What is the unit of gram molecular weight?
View answer and explanation
Correct option: C
g  mol−1g\;\mathrm{mo}{\mathrm{l}^{ - 1}}
Option C (g  mol−1g\;\mathrm{mo}{\mathrm{l}^{ - 1}}) is correct because gram molecular weight is expressed as grams per mole.
225 Hard
225 of 313
Application +4 | -1
The number of moles of KMnO4KMn{O_4} that will be needed to react completely with one mole of oxalate ion in acidic solution is
View answer and explanation
Correct option: C
25\frac{2}{5}
Option C (25\frac{2}{5}) is correct because the stoichiometry of the redox reaction between KMnO4KMnO_4 and oxalate in acidic solution requires 2 moles of KMnO4KMnO_4 for every 5 moles of oxalate.
226 Hard
226 of 313
Application +4 | -1
A molecule of organic compound contains atoms of Carbon, Hydrogen, Nitrogen and oxygen in the ratio 9:15:1:3.9:15:1:3. If there are 18 oxygen atoms per molecule then the molecular formula of the organic compound is
View answer and explanation
Correct option: C
C54H90N6O18\mathrm{C}_{54} \mathrm{H}_{90} \mathrm{N}_6 \mathrm{O}_{18}
Option C (C54H90N6O18\mathrm{C}_{54} \mathrm{H}_{90} \mathrm{N}_6 \mathrm{O}_{18}) is correct. The molecular formula is determined by scaling the given ratio of atoms until the number of oxygen atoms matches the given value.
227 Easy
227 of 313
Application +4 | -1
What is the mass percent of carbon in CO2C{O_2}
View answer and explanation
Correct option: B
27.27%27.27\mathrm{ }\%
Option B (27.27%27.27\mathrm{ }\%) is correct because it is the mass percentage of carbon calculated from the molar masses of carbon and carbon dioxide.
228 Easy
228 of 313
Analyzing +4 | -1
Equivalent weight of FeS2\mathrm{FeS}_2 in the half reaction, FeS2⟶Fe2O3+SO2\mathrm{FeS}_2 \longrightarrow \mathrm{Fe}_2 \mathrm{O}_3+\mathrm{SO}_2 is :
View answer and explanation
Correct option: B
M/11M / 11
Option B (M / 11) is correct because the change in oxidation state of Fe and S in the given half-reaction leads to a total of 11 electrons transferred per molecule of FeS2.
229 Easy
229 of 313
Application +4 | -1
The empirical formula of an organic compound is CH2O\mathbf{C}{\mathbf{H}_\mathbf{2}}\mathbf{O} , its vapour density is 45, The molecular formula of the compound is
View answer and explanation
Correct option: C
C3H6O3{C_3}{H_6}{O_3}
Option C (C3H6O3{C_3}{H_6}{O_3}) is correct because the molecular formula is a multiple of the empirical formula, and the molar mass calculated from the vapor density matches the molar mass of C3H6O3.
230 Medium
230 of 313
Application +4 | -1
If 30 mL30 \mathrm{~mL} of H2\mathrm{H}_2 and 20 mL20 \mathrm{~mL} of O2\mathrm{O}_2 react to form water, what is left at the end of the reaction?
View answer and explanation
Correct option: D
5 mL5 \mathrm{~mL} of O2\mathrm{O}_2
Option D (5 mL5 \mathrm{~mL} of O2\mathrm{O}_2) is correct because the reaction consumes twice the volume of H2 compared to O2, leaving excess O2.
231 Medium
231 of 313
Analyzing +4 | -1
Choose the correct option based on following statements. Here ‘T’ stands for true and ‘F’ stands for false statement.
(i) Molecular mass of cane sugar (C12H22O11)(C_{12}H_{22}O_{11}) is 182 amu.
(ii) 1 mole of cane sugar contains 6.022×10236.022 \times 10^{23} molecules of cane sugar.
(iii) 34.20 g of cane sugar contains 6.022×10216.022 \times 10^{21} molecules of cane sugar.
View answer and explanation
Correct option: C
FTF
Option C (FTF) is correct because statement (i) is false (molecular mass is 342 amu), statement (ii) is true, and statement (iii) is false (34.20 g contains 6.022×10226.022 \times 10^{22} molecules).
232 Medium
232 of 313
Analyzing +4 | -1
The highest mass corresponds to which of the following?
View answer and explanation
Correct option: D
1  mole  of  O21\;\mathrm{mole }\;\mathrm{of}\;{\mathrm{O}_2}
Option D (1  mole  of  O21\;\mathrm{mole }\;\mathrm{of}\;{\mathrm{O}_2}) is correct because 1 mole of O2 has a mass of 32g, which is the highest among the given options.
233 Medium
233 of 313
Application +4 | -1
The average atomic mass of neon based on following data is:
IsotopeRelatives  abundance20Ne0.905121Ne0.002722Ne0.0922\begin{array}{cccccccccccccccccccc} {{\text{Isotope}}}&{{\text{Relatives}}\,\,{\text{abundance}}} \\ {{}^{20}Ne}&{0.9051} \\ {{}^{21}Ne}&{0.0027} \\ {{}^{22}Ne}&{0.0922} \end{array}
View answer and explanation
Correct option: B
20.187 u
Option B (20.187 u) is correct because it involves calculating the weighted average of the isotopic masses based on their relative abundances.
234 Hard
234 of 313
Understanding +4 | -1
Statement I : Volume occupied by 1 equivalent of H2{H_2} at NTP is 11.2 L
Statement II : 1 equivalent of H2=1 g=0.5  mol{H_2} = 1\,g = 0.5\,\,mol and volume occupied by 1 mol of any gas at NTP = 22.4 L
Which statement(s) is/are correct?
View answer and explanation
Correct option: B
Only II
Option B (Only II) is correct because 1 equivalent of H2 is 1g, which is 0.5 mol, and 1 mol of any gas at NTP occupies 22.4 L, so 0.5 mol occupies 11.2 L.
235 Medium
235 of 313
Application +4 | -1
Which of the following pair of gases contain the same number of molecules?
View answer and explanation
Correct option: A
16gO2,14gN216\mathrm{g}{\mathrm{O}_2},14\mathrm{g}{\mathrm{N}_2}
Option A (16gO2,14gN216\mathrm{g}{\mathrm{O}_2},14\mathrm{g}{\mathrm{N}_2}) is correct because both gases have the same number of moles, and therefore the same number of molecules.
236 Medium
236 of 313
Application +4 | -1
In an experiment during the analysis of a carbon compound, 145  mLof  H2145\,\,\mathrm{mL of}\,\,{\mathrm{H}_2} was collected at 760  mmHg760\,\,\mathrm{mm Hg} pressure and 270C{27^0}C. The weight of H2{H_2} is nearly :
View answer and explanation
Correct option: B
12  mg12\,\,\mathrm{mg}
Option B (12 mg) is correct because it is calculated using the ideal gas law to find the moles of H2 and then converting to mass.
237 Medium
237 of 313
Understanding +4 | -1
The weight of 11.2 litre of any gas at STP represents its:
View answer and explanation
Correct option: D
Vapour density
Option D (Vapour density) is correct because the weight of 11.2 liters of any gas at STP represents half of its gram molecular weight, which is related to vapor density.
238 Hard
238 of 313
Analyzing +4 | -1
Assertion: Analytical molarity of 1 M HCl1 \mathrm{~M~HCl} is zero.
Reason: Equilibrium molarity of 1 M HCl1 \mathrm{~M~HCl} is zero.
View answer and explanation
Correct option: B
Assertion is wrong but Reason is correct
Option B (Assertion is wrong but Reason is correct) is correct because analytical molarity considers the initial concentration, while equilibrium molarity considers the concentration after dissociation, which is zero for HCl.
239 Hard
239 of 313
Analyzing +4 | -1
The first and second ionisation enthalpies of a metal are 496 and 4560 kJ mol−1\mathrm{kJ}\,\mathrm{ mo}{\mathrm{l}^{ - \mathrm{1}}}, respectively. How many moles of HClHCl and H2SO4,{H_2}S{O_4}, respectively, will be needed to react completely with 1 mole of the metal hydroxide?
View answer and explanation
Correct option: D
1 and 0.5
Option D (1 and 0.5) is correct because the metal likely forms MOHMOH and M2SO4M_2SO_4 due to its low first ionization enthalpy and high second ionization enthalpy, indicating it forms a +1 ion.
240 Easy
240 of 313
Application +4 | -1
The total number of electrons in 18 ml of water (density = 1/gml
View answer and explanation
Correct option: B
6.023  ×  10246.023\,\, \times \,\,{10^{^{24}}}
Option B (6.023×10246.023 \times {10^{^{24}}}) is correct because it calculates the total number of electrons based on the number of water molecules and electrons per molecule.
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