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NEET • CHEMISTRY • SOME BASIC CONCEPTS OF CHEMISTRY

Some basic concepts of chemistry practice · Mixed difficulty

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Showing 181-210 of 313 questions

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181 Easy
181 of 313
Understanding +4 | -1
The number of significant figures for the three numbers 161 cm, 0.161 cm, 0.0161 cm are
View answer and explanation
Correct option: D
3,3 and 3 respectively
Option D is correct because leading zeros are not significant, and trailing zeros after a decimal point are significant.
182 Easy
182 of 313
Analyzing +4 | -1
Which contains greatest number of oxygen atoms?
View answer and explanation
Correct option: D
All have the same number of atoms
Option D (All have the same number of atoms) is correct because 1 g of each substance contains the same number of oxygen atoms.
183 Easy
183 of 313
Application +4 | -1
From the equation, 3C2H2→C6H6,3{\mathrm{C}_2}{\mathrm{H}_2} \to {\mathrm{C}_6}{\mathrm{H}_6}, find the volume of acetylene (NTP) for the manufacture of 3 mole of benzene:
View answer and explanation
Correct option: C
201.6 litre
Option C (201.6 litre) is correct because 3 moles of benzene require 9 moles of acetylene, which occupies 201.6 L at NTP.
184 Easy
184 of 313
Remembering +4 | -1
The numerical value of Nn\frac{\mathrm{N}}{n} (where, Nis the number of molecules in a given sample of gas and n is the number of moles of the gas) is
View answer and explanation
Correct option: B
6.02×10236.02 \times {10^{23}}
Option B (6.02×10236.02 \times {10^{23}}) is correct because it represents Avogadro's number, which is the number of molecules per mole.
185 Medium
185 of 313
Understanding +4 | -1
The weights of two elements which combine with one another are in the ratio of their:
View answer and explanation
Correct option: C
Eq. wt.
The correct answer is C (Eq. wt.) because the weights of two elements that combine with each other are in the ratio of their equivalent weights.
186 Easy
186 of 313
Analyzing +4 | -1
Which of the following samples contain the least number of atoms
View answer and explanation
Correct option: A
1g  of CO2(g)1g\,\,of\,C{O_2}\left( g \right)
Option A (1g  of CO2(g)1g\,\,of\,C{O_2}\left( g \right)) is correct because it has the smallest number of atoms compared to the other options, considering their respective molar masses and number of atoms per molecule.
187 Easy
187 of 313
Application +4 | -1
Maximum no. of atoms are present in
View answer and explanation
Correct option: A
8g CH48g\,C{H_4}
Option A (8g CH48g\,C{H_4}) is correct because it contains the highest number of moles of molecules, and each molecule has a significant number of atoms.
188 Medium
188 of 313
Application +4 | -1
Which among the following has maximum number of atoms among the following?
View answer and explanation
Correct option: A
22gCO222\mathrm{ }g\mathrm{ }C{O_2}
Option A (22 g CO2) is correct because it contains the highest number of moles of molecules, and each molecule has 3 atoms.
189 Easy
189 of 313
Remembering +4 | -1
The apparatus in which standard solution is prepared is known as :
View answer and explanation
Correct option: A
Measuring flask
Option A (Measuring flask) is correct because a measuring flask is specifically designed for preparing standard solutions with accurate volumes.
190 Hard
190 of 313
Application +4 | -1
How much time (in hours) would it take to distribute one Avogadro number of wheat grains if 102010^{20} grains are distributed each second ?
View answer and explanation
Correct option: B
1.673
Option B (1.673) is correct because it involves converting Avogadro's number of grains distributed per second to hours.
191 Easy
191 of 313
Understanding +4 | -1
Which one of the following set of units represents the smallest and largest amount of energy respectively?
View answer and explanation
Correct option: D
eV and L-atm
Option D (eV and L-atm) is correct because eV (electron volt) is a very small unit of energy, while L-atm (litre-atmosphere) is a larger unit of energy.
192 Easy
192 of 313
Application +4 | -1
The equivalent weight of Zn(OH)2\mathrm{Zn}{\left( {\mathrm{OH}} \right)_2} in the following reaction is equal to its,
Zn(OH)2+HNO3→Zn(OH)(NO3)+H2O\mathrm{Zn}{\left( {\mathrm{OH}} \right)_2} + \mathrm{HN}{\mathrm{O}_3} \to \mathrm{Zn}\left( {\mathrm{OH}} \right)\left( {\mathrm{N}{\mathrm{O}_3}} \right) + {\mathrm{H}_2}\mathrm{O}:
View answer and explanation
Correct option: A
Formula  wt.1\frac{{\mathrm{Formula}\;\mathrm{wt}\mathrm{.}}}{1}
Option A (Formula wt./1) is correct because in this reaction, Zn(OH)2Zn(OH)_2 reacts with one equivalent of HNO3HNO_3, so its equivalent weight is its formula weight divided by 1.
193 Easy
193 of 313
Remembering +4 | -1
Difference in density is the basis of
View answer and explanation
Correct option: D
gravity separation
Option D is correct because gravity separation is a technique that relies on differences in density to separate components of a mixture.
194 Medium
194 of 313
Analyzing +4 | -1
Which is correct for Na2HPO3\mathrm{N}{\mathrm{a}_2}\mathrm{HP}{\mathrm{O}_3}?
View answer and explanation
Correct option: D
All of these
Option D (All of these) is correct because Na2HPO3 is an acid salt, has an equivalent weight of M/2, and the oxidation number of P is +3.
195 Easy
195 of 313
Understanding +4 | -1
Which statement is correct?
View answer and explanation
Correct option: C
Equivalent weight changes with valence
Option C (Equivalent weight changes with valence) is correct because the equivalent weight of an element is calculated by dividing its atomic weight by its valence; therefore, a change in valence directly affects the equivalent weight.
196 Hard
196 of 313
Understanding +4 | -1
Consider the following statements.
(i) Atoms of H, O, NH, \, O, \, N and CC have identical properties but different mass.
(ii) Matter is divisible into atoms which are further indivisible.
(iii) The ratio of N:HN: H in NH3NH_3 is 1 : 3 and N:ON : O in nitric oxide is 2 : 1.
(iv) Dalton’s atomic theory support law of conservation of mass.
Which of the following pairs of statements is true according to Dalton’s atomic theory ?
View answer and explanation
Correct option: C
(ii) and (iv)
Option C ((ii) and (iv)) is correct because Dalton's atomic theory states that matter is divisible into indivisible atoms and supports the law of conservation of mass.
197 Medium
197 of 313
Analyzing +4 | -1
0.75 moles of a solid A4{A_4} and 2 moles of O2(g){O_2}(g) are heated in a sealed vessel, completely using up the reactants and produces only one compound. It is found that when the temperature is used to initial temperature, the contents of the vessel exhibit a pressure equal to 12\frac{1}{2} of the original pressure. The formula of the product will be
View answer and explanation
Correct option: C
A3O4{A_3}{O_4}
Option C (A3O4{A_3}{O_4}) is correct because the stoichiometry of the reaction and the pressure change indicate that 3 moles of A4{A_4} react with 8 moles of O2{O_2} to produce 4 moles of A3O4{A_3}{O_4}.
198 Easy
198 of 313
Application +4 | -1
510 mg of a liquid on vaporization in Victor meyer’s apparatus displaces 67.2  cm3\mathrm{67}\mathrm{.2}\;\mathrm{c}{\mathrm{m}^3} of air at (STP). The molecular weight of the liquid is:
View answer and explanation
Correct option: C
170
Option C (170) is correct because it is calculated using the ideal gas law and the given mass and volume.
199 Easy
199 of 313
Application +4 | -1
The number of atoms in 0.1 mol of a triatomic gas is
View answer and explanation
Correct option: B
1.806×10231.806 \times {10^{23}}
Option B (1.806×10231.806 \times {10^{23}}) is correct because it calculates the total number of atoms by multiplying the number of moles by Avogadro's number and the number of atoms per molecule.
200 Medium
200 of 313
Understanding +4 | -1
In the reaction 3Mg+N2→Mg3N23Mg + {N_2} \to M{g_3}{N_2}
View answer and explanation
Correct option: B
MgMg is oxidised
Option B (MgMg is oxidised) is correct because Magnesium loses electrons (oxidation) to form Mg3N2Mg_3N_2.
201 Hard
201 of 313
Understanding +4 | -1
Choose the correct statements.

(A) Weight of a substance is the amount of matter present in it.

(B) Mass is the force exerted by gravity on an object.

(C) Volume is the amount of space occupied by a substance.

(D) Temperatures below 0∘C0^\circ C are possible in Celsius scale, but in Kelvin scale negative
temperature is not possible.

(E) Precision refers to the closeness of various measurements for the same quantity.
View answer and explanation
Correct option: D
(C), (D) and (E) Only
The correct answer is D ((C), (D) and (E) Only) because statements C, D, and E are correct definitions and properties in chemistry.
202 Easy
202 of 313
Analyzing +4 | -1
In the reaction, VO+Fe2O3→FeO+V2O5.\mathrm{VO} + \mathrm{F}{\mathrm{e}_2}{\mathrm{O}_3} \to \mathrm{FeO} + {\mathrm{V}_2}{\mathrm{O}_5}\mathrm{.}. The eq.wt. of V2O5{\mathrm{V}_2}{\mathrm{O}_5} is equal to its :
View answer and explanation
Correct option: C
mol.wt./6mol.\mathrm{ }wt./6
Option C (mol.wt./6mol.\mathrm{ }wt./6) is correct because the equivalent weight is the molecular weight divided by the change in oxidation state of Vanadium, which is 6.
203 Easy
203 of 313
Application +4 | -1
If H2SO4{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4} ionises as H2SO4+2H2O→2H3O++SO42{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4} + 2{\mathrm{H}_2}\mathrm{O} \to 2{\mathrm{H}_3}{\mathrm{O}^ + } + \mathrm{SO}_4^2, then total number of ions produced by 0.1  M  H2SO4\mathrm{0}\mathrm{.1}\;\mathrm{M}\;{\mathrm{H}_2}\mathrm{S}{\mathrm{O}_4} will be
View answer and explanation
Correct option: D
1.8×10231.8 \times {10^{23}}
Option D (1.8×10231.8 \times {10^{23}}) is correct because each H2SO4 molecule produces 3 ions, and we have 0.1 moles of H2SO4.
204 Medium
204 of 313
Analyzing +4 | -1
Which of the following has the smallest number of molecules?
View answer and explanation
Correct option: A
0.1 mole of CO2\mathrm{C}{\mathrm{O}_2} gas
Option A (0.1 mole of CO2\mathrm{C}{\mathrm{O}_2} gas) is correct because it represents the smallest number of molecules compared to the other options when converted to moles.
205 Hard
205 of 313
Analyzing +4 | -1
Assertion: The H-bonding of NH3\mathrm{NH}_3 and H2O\mathrm{H}_2 \mathrm{O} is represented as:
H−O∣H−−−H−N∣H−H{\text{H}} - \mathop {\text{O}}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {\text{H}} \end{array}} - - - {\text{H}} - \mathop {\text{N}}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {\text{H}} \end{array}} - {\text{H}}
Reason: H2O\mathrm{H}_2 \mathrm{O} is more acidic than NH3\mathrm{NH}_3 and thus, H2O\mathrm{H}_2 \mathrm{O} is a proton donor.
View answer and explanation
Correct option: B
Assertion is wrong but Reason is correct
Option A (Assertion is correct but Reason is wrong) is correct because the H-bonding representation is incorrect, and while water is more acidic than ammonia, it's not the primary reason for the specific H-bonding structure.
206 Medium
206 of 313
Understanding +4 | -1
Reactants react in the equal number of …….. to give products.
View answer and explanation
Correct option: C
Equivalent
Option C (Equivalent) is correct because reactants react in equal numbers of equivalents to give products, based on the concept of equivalent weight.
207 Medium
207 of 313
Understanding +4 | -1
What products are expected from the disproportionation reaction of hypochlorous acid
View answer and explanation
Correct option: B
HClO2 and  HClO4HCl{O_2}\,and\,\,HCl{O_4}
Option D is correct because hypochlorous acid (HClO) disproportionates into hydrochloric acid (HCl) and chloric acid (HClO3).
208 Easy
208 of 313
Remembering +4 | -1
The relation between molecular weight (M)\left( M \right) and vapour density (VD)\left( VD \right) is:
View answer and explanation
Correct option: B
M=2×VDM = 2 \times \mathrm{VD}
Option B (M=2×VDM = 2 \times \mathrm{VD}) is correct because the molecular weight is twice the vapor density.
209 Medium
209 of 313
Understanding +4 | -1
Molecular weight of tribasic acid is W. Its equivalent weight will be:
View answer and explanation
Correct option: B
W3\frac{W}{3}
Option B (W/3) is correct because equivalent weight of an acid is its molecular weight divided by its basicity, which is 3 for a tribasic acid.
210 Easy
210 of 313
Remembering +4 | -1
The prefix 10−24{10^{ - 24}} is
View answer and explanation
Correct option: C
yocto
Option C is correct because the prefix yocto represents 10-24.
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