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NEET • CHEMISTRY • SOLID STATE

Solid state practice · Mixed difficulty

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Showing 91-120 of 238 questions
91 Easy
91 of 238
Analyzing +4 | -1
Among the following which one has the highest cation to anion size ratio?
View answer and explanation
Correct option: C
CsF\mathrm{CsF}
Option C (CsF) is correct because Cs has the largest cation size and F has the smallest anion size among the given options, leading to the highest cation to anion size ratio.
92 Easy
92 of 238
Understanding +4 | -1
The radius ratio of CsCl\mathrm{CsCl} is 0.93. The expected lattice structure is
View answer and explanation
Correct option: D
Body centred cubic
Option D (Body centred cubic) is correct because a radius ratio of 0.93 falls within the range (0.732 - 1.000) that corresponds to a body-centered cubic structure.
93 Easy
93 of 238
Remembering +4 | -1
The crystalline structure of NaCl\mathrm{NaCl} is
View answer and explanation
Correct option: B
Face centred cubic
Option B (Face centred cubic) is correct because the crystalline structure of NaCl is a face-centered cubic (FCC) lattice.
94 Medium
94 of 238
Understanding +4 | -1
Crystalline metal can be transformed into metallic glass by:
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Correct option: D
Very rapid cooling of a spray of the molten metal
Option D (Very rapid cooling of a spray of the molten metal) is correct because rapid cooling prevents the formation of a crystalline structure, resulting in a metallic glass.
95 Medium
95 of 238
Understanding +4 | -1
Amorphous substances show (i) Short and long range order (ii) Short range order (iii) Long range order (iv) Have no sharp melting point
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Correct option: D
(ii)and (iv) are correct
Option D ((ii)and (iv) are correct) is correct because amorphous substances exhibit short-range order and lack a sharp melting point.
96 Easy
96 of 238
Understanding +4 | -1
For AXAX ionic crystal to exist in bcc structure, the ratio of radii (rcationranions)\left( {\frac{{{r_{\mathrm{cation}}}}}{{{r_{\mathrm{anions}}}}}} \right) should be
View answer and explanation
Correct option: B
Greater then 0.73
Option B (Greater then 0.73) is correct because for an AX ionic crystal to exist in a bcc structure, the radius ratio must be greater than 0.73.
97 Easy
97 of 238
Understanding +4 | -1
The oxide which shows transition from metal to insulation, i.e., semiconductors are :
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Correct option: D
All of these
Option D (All of these) is correct because V2O3{\mathrm{V}_2}{\mathrm{O}_3}, VO2\mathrm{V}{\mathrm{O}_2}, and Ti2O3\mathrm{T}{\mathrm{i}_2}{\mathrm{O}_3} all exhibit metal-insulator transitions, behaving as semiconductors.
98 Medium
98 of 238
Remembering +4 | -1
Solid CO2{CO}_2 is an example of the crystal type -
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Correct option: D
molecular
Option D (molecular) is correct because solid CO2 (dry ice) consists of CO2 molecules held together by weak van der Waals forces, characteristic of molecular crystals.
99 Hard
99 of 238
Application +4 | -1
Sodium metal crystallizes as a body centred cubic lattice with the cell edge 4.29A∘4.29{A^{^{^ \circ }}} What is the radius sodium atom?
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Correct option: A
1.857×10(−8)cm1.857\mathrm{ \times }{10^{( - 8)}}cm
Option A (1.857×10(−8)cm1.857\mathrm{ \times }{10^{( - 8)}}cm) is correct because it's the calculated radius of the sodium atom in a BCC lattice.
100 Medium
100 of 238
Application +4 | -1
X- ray analysis shows that the unit cell length in NaCl\mathrm{NaCl} is 562.8 pm. Calculate the density you would expect on this basis, NA=6.023x1023mol−1{N_A} = 6.023\mathrm{x}{10^{23}}\mathrm{mo}{\mathrm{l}^{ - 1}}
View answer and explanation
Correct option: B
2.179 g cm−32.179\,g\,c{m^{ - 3}}
Option B (2.179 g cm−32.179\,g\,c{m^{ - 3}}) is correct because it's the calculated density based on the given unit cell length.
101 Easy
101 of 238
Remembering +4 | -1
A match box exhibits :
View answer and explanation
Correct option: C
Orthorhombic geometry
Option C is correct because a matchbox has three unequal sides (length, width, and height) and all angles are 90 degrees, which corresponds to orthorhombic geometry.
102 Easy
102 of 238
Application +4 | -1
The distance between an octahedral and tetrahedral void in fcc lattice would be :-
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Correct option: D
3a4\frac{\sqrt{3} a}{4}
Option D (3a4\frac{{\sqrt 3 a}}{4}) is correct because it represents half the distance between the body center (octahedral void) and a corner (tetrahedral void) in an FCC lattice.
103 Easy
103 of 238
Remembering +4 | -1
Schottky defect is observed in the crystal of
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Correct option: A
NaClNaCl
Option A (NaClNaCl) is correct because Schottky defects are commonly observed in highly ionic compounds with a small difference in cation and anion size.
104 Hard
104 of 238
Understanding +4 | -1
If the radius of an octahedral void and that of atom in close packing is r & R{r} \,\&\,{R} respectively then relation between r & R{r} \,\&\, {R} is:
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Correct option: C
r=0.414R{r}=0.414 {R}
Option C is correct because the relationship between the radius of an octahedral void (r) and the radius of the atom in close packing (R) is given by r = 0.414R.
105 Medium
105 of 238
Remembering +4 | -1
The closest distance between the centres of two molecules of a gas taking part in collision is called
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Correct option: C
Both (1) and (2)
Option C (Both (1) and (2)) is correct because both "Effective molecular diameter" and "Collision diameter" refer to the closest distance between the centers of two colliding gas molecules.
106 Medium
106 of 238
Analyzing +4 | -1
Statement I: Frenkel defect involving the migration of ions to interstitial sites is more likely for covalent compounds and for large (and highly polarisable) anions.

Statement II: Large polarisable anions make it easier to accommodate the displaced cations and minimise repulsive effect.
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Correct option: A
Both Statement I and Statement II are correct and Statement II is the correct explanation of Statement I
Option A is correct because Frenkel defects are more likely in covalent compounds with large, polarizable anions, as these conditions facilitate cation displacement and minimize repulsion.
107 Medium
107 of 238
Analyzing +4 | -1
Oxygen atom forms FCC unit cell with 'A' atoms occupying all tetrahedral voids and 'B' atoms occupying all octahedral voids. If atoms are removed from two of the body diagonals then determine the formula of resultant compound formed.
View answer and explanation
Correct option: B
A8B6O7\mathrm{A}_8 \mathrm{B}_6 \mathrm{O}_7
Option B (A8B6O7\mathrm{A}_8 \mathrm{B}_6 \mathrm{O}_7) is correct because after removing atoms from the body diagonals, the remaining ratio of A, B, and O atoms corresponds to this formula.
108 Medium
108 of 238
Remembering +4 | -1
This one is amorphous –
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Correct option: B
fused quartz
Option B (fused quartz) is correct because fused quartz is an amorphous form of silicon dioxide, lacking long-range order.
109 Easy
109 of 238
Application +4 | -1
The fraction of total volume occupies by the atoms present in a simple cube is :
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Correct option: D
π6\frac{\pi }{6}
Option D (π6\frac{\pi }{6}) is correct because the packing fraction for a simple cubic cell is calculated as the volume occupied by the atoms divided by the total volume of the unit cell, which simplifies to π6\frac{\pi }{6}.
110 Medium
110 of 238
Remembering +4 | -1
Structure similar to zinc blende is found in
View answer and explanation
Correct option: C
CuCl\mathrm{CuCl}
Option C (CuCl\mathrm{CuCl}) is correct because CuCl has a zinc blende (ZnS) structure.
111 Easy
111 of 238
Remembering +4 | -1
Amorphous solids:
View answer and explanation
Correct option: C
Do not undergo clean cleavage when cut with knife
Option C (Do not undergo clean cleavage when cut with knife) is correct because amorphous solids lack long-range order, resulting in irregular fracture patterns when cut.
112 Easy
112 of 238
Remembering +4 | -1
Iodine crystals are :
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Correct option: C
Molecular solid
Option C is correct because iodine crystals are formed by weak van der Waals forces between I2I_2 molecules, making them molecular solids.
113 Easy
113 of 238
Understanding +4 | -1
In which of the following crystals alternate tetrahedral voids are occupied?
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Correct option: B
Zns\mathrm{Zns}
Option B (Zns\mathrm{Zns}) is correct because in ZnS, sulfide ions form a face-centered cubic lattice, and zinc ions occupy alternate tetrahedral voids.
114 Medium
114 of 238
Remembering +4 | -1
Which of the following is an example of ferrimagnetic substance?
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Correct option: D
Fe3O4F{e_3}{O_4}
Option D (Fe3O4F{e_3}{O_4}) is correct because it is a well-known example of a ferrimagnetic material due to its unequal alignment of magnetic moments.
115 Easy
115 of 238
Understanding +4 | -1
The parameters of the unit cell of a substance are a=2.5,b=3.0,c=4.0,α=900,β=1200,γ=800a = 2.5,b = 3.0,c = 4.0,\alpha = {90^0},\beta = {120^0},\gamma = {80^0}. The crystal system of the substance is :
View answer and explanation
Correct option: D
Triclinic
Option D (Triclinic) is correct because the triclinic crystal system has unequal axes (a≠b≠ca \neq b \neq c) and unequal angles (α≠β≠γ≠900\alpha \neq \beta \neq \gamma \neq 90^0).
116 Hard
116 of 238
Application +4 | -1
An fcc lattice has a lattice parameter aa = 400 pm. Calculate the molar volume of the lattice including all the empty space
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Correct option: D
9.6  mL9.6\,\,mL
Option D (9.6  mL9.6\,\,mL) is correct because it's the calculated molar volume of the FCC lattice.
117 Medium
117 of 238
Remembering +4 | -1
Which of the following is ferroelectric compound?
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Correct option: A
BaTiO3\mathrm{BaTi}{\mathrm{O}_3}
Option A (BaTiO3\mathrm{BaTi}{\mathrm{O}_3}) is correct because Barium Titanate is a well-known ferroelectric material, exhibiting spontaneous electric polarization.
118 Medium
118 of 238
Analyzing +4 | -1
Distance between nearest cation and anion in an ionic solid is 3a4\frac{\sqrt{3} a}{4} then ionic solid may be:
View answer and explanation
Correct option: D
All
Option D (All) is correct because the given distance between the nearest cation and anion corresponds to the tetrahedral void, which can be found in all the mentioned structures.
119 Easy
119 of 238
Analyzing +4 | -1
A mineral having the formula AB2\mathrm{AB}_2 crystallizes in ccp lattice with A\mathrm{A} atoms occupying the lattice points. Pick out the correct statements of the following
View answer and explanation
Correct option: A
100%100 \% occupancy of tetrahedral voids, C.N. of B=4\mathrm{B}=4
Option A is correct because in a ccp lattice, A atoms occupy the lattice points, and with the formula AB2AB_2, B must occupy all the tetrahedral voids. The coordination number of an atom in a tetrahedral void is 4.
120 Medium
120 of 238
Understanding +4 | -1
The number of spheres contained (i) in one body centred cubic unit cell and (ii) in one face centred cubic unit cell, is
View answer and explanation
Correct option: A
In (i) 2 and in (ii) 4
Option A (In (i) 2 and in (ii) 4) is correct because a body-centered cubic unit cell contains 2 spheres, and a face-centered cubic unit cell contains 4 spheres.
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