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NEET • CHEMISTRY • ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

Organic chemistry-some basic principles and techniques practice · Mixed difficulty

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Showing 61-90 of 392 questions

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61 Hard
61 of 392
Understanding +4 | -1
Which of the following statement is correct for paper
chromatography?
View answer and explanation
Correct option: A
Water present in the pores of the paper forms
the stationary phase
Option A is correct because in paper chromatography, the water molecules trapped within the cellulose fibers of the paper act as the stationary phase.
62 Medium
62 of 392
Remembering +4 | -1
Which acid is an optically active:
View answer and explanation
Correct option: B
2-chloropropanoic acid
Option B (2-chloropropanoic acid) is correct because it has a chiral carbon (a carbon atom bonded to four different groups), making it optically active.
63 Easy
63 of 392
Application +4 | -1
IUPAC name of the compound  CH3−CH∣CH3−OCH3C{H_3} - \mathop {CH}\limits_{\mathop |\limits_{C{H_3}} } - OC{H_3} is .................
View answer and explanation
Correct option: C
2 – methoxy propane
Option C (2 – methoxy propane) is correct because it accurately represents the IUPAC naming conventions for ethers with substituents.
64 Medium
64 of 392
Analyzing +4 | -1
The correct order of stability of the given carbocation will be
I.NH2−CH2−C+H2 ,  II.CH3−O−C+H2 , III. NO2−C+H2I.N{H_2} - C{H_2} - \mathop C\limits^ + {H_2}\,,\,\,II.C{H_3} - O - \mathop C\limits^ + {H_2}\,,\,III.\,N{O_2} - \mathop C\limits^ + {H_2}
View answer and explanation
Correct option: C
II > I > III
Option C (II > I > III) is correct because the stability of carbocations is influenced by electron-donating groups, with resonance being more stabilizing than inductive effects, and electron-withdrawing groups destabilizing them.
65 Medium
65 of 392
Analyzing +4 | -1
What is the correct order of decreasing stability of the following cations

I) CH3−C⊕H−CH3C{H_3} - \mathop C\limits^ \oplus H - C{H_3}

II) CH3−C⊕H−OCH3C{H_3} - \mathop C\limits^ \oplus H - OC{H_3}

III) CH3−C⊕H−OCH3C{H_3} - \mathop C\limits^ \oplus H - OC{H_3}
View answer and explanation
Correct option: A
II > I > III
Option B (II > I > III) is correct because the carbocation is stabilized by the electron-donating effect of the methoxy group in II, and destabilized by the inductive effect in III.
66 Easy
66 of 392
Understanding +4 | -1
In hyper conjugation there is overlap between
View answer and explanation
Correct option: D
σ−and p−orbitals\sigma - and\,p - orbitals
Option D (σ−and p−orbitals\sigma - and\,p - orbitals) is correct because hyperconjugation involves the overlap of a sigma bond (usually C-H) with an adjacent p orbital.
67 Medium
67 of 392
Analyzing +4 | -1
Assertion: Pyridine is more basic than Pyrrole.

Reason: In Pyrrole, nitrogen has sp2sp^2 hybridisation
and the lone pair of nitrogen is not available for
donation.
View answer and explanation
Correct option: A
If both Assertion and Reason are correct and
Reason is the correct explanation of
Assertion
Option A is correct because Pyridine is indeed more basic than Pyrrole, and the reason provided correctly explains why: the lone pair in Pyrrole is involved in aromaticity and thus less available for donation.
68 Medium
68 of 392
Analyzing +4 | -1
Which one of the carbanions is the least stable?
View answer and explanation
Correct option: C
C−H2−CH3\stackrel{-}{\mathrm{C}} \mathrm{H}_2-\mathrm{CH}_3
Option C (C−H2−CH3\stackrel{-}{\mathrm{C}} \mathrm{H}_2-\mathrm{CH}_3) is the least stable carbanion because alkyl groups are electron-donating and destabilize the negative charge on the carbon.
69 Easy
69 of 392
Understanding +4 | -1
Racemic mixture is formed by mixing two
View answer and explanation
Correct option: D
enantiomers with chiral carbon
Option D (enantiomers with chiral carbon) is correct because a racemic mixture is formed by mixing equal amounts of two enantiomers, which are chiral compounds.
70 Easy
70 of 392
Understanding +4 | -1
When an organic compound is present in aqueous medium and is less soluble in any organic solvent, then it is separated by
View answer and explanation
Correct option: A
Continuous extraction
The correct answer is Continuous extraction because it is designed to efficiently extract a compound from an aqueous solution into an organic solvent, especially when the compound is only slightly soluble in the organic solvent.
71 Medium
71 of 392
Remembering +4 | -1
In Kjeldahl's method for the estimation of nitrogen, the formula used to
View answer and explanation
Correct option: B
%ofN=1.4VNw\% {\kern 1pt} {\kern 1pt} \mathrm{of}{\kern 1pt} {\kern 1pt} \mathrm{N} = \frac{{1.4{\kern 1pt} {\kern 1pt} V{\kern 1pt} {\kern 1pt} N}}{w}
Option B is correct because it represents the formula for calculating the percentage of nitrogen in Kjeldahl's method, relating volume, normality, and weight.
72 Easy
72 of 392
Understanding +4 | -1
A mixture of two organic compounds AA and BB can be separated by
(B. P of A=800CA = {80^0}C, B. P of B=1100CB = {110^0}C)
View answer and explanation
Correct option: B
Steam distillation
The correct answer is Steam distillation because it is suitable for separating immiscible liquids with relatively high boiling points.
73 Hard
73 of 392
Understanding +4 | -1
Which of the following orders is correct regarding the −I-I effect of the substituents?
View answer and explanation
Correct option: B
−NR2<−OR<−F- \mathrm{N}{R_2} < - \mathrm{O}R < - \mathrm{F}
Option B (−NR2<−OR<−F-\mathrm{N}{R_2} < -\mathrm{O}R < -\mathrm{F}) is correct because the -I effect (inductive electron-withdrawing effect) increases with increasing electronegativity. Fluorine is more electronegative than oxygen, which is more electronegative than nitrogen.
74 Medium
74 of 392
Analyzing +4 | -1
Identify, which of the below does not possess any element of symmetry?
View answer and explanation
Correct option: A
(+)(-) tartaric acid
Option A ((+)(-) tartaric acid) is correct because a racemic mixture of tartaric acid does not possess any element of symmetry.
75 Medium
75 of 392
Understanding +4 | -1
Di-chloroacetic acid is a stronger acid than acetic acid.

This due to occurrence of
View answer and explanation
Correct option: C
Inductive effect
Option C is correct because the electron-withdrawing inductive effect of the chlorine atoms stabilizes the conjugate base of dichloroacetic acid, making it a stronger acid.

Explore Other Chapters in CHEMISTRY

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CHEMICAL BONDING & MOLECULAR STRUCTURE 595 MCQs THERMODYNAMICS 583 MCQs STRUCTURE OF ATOM 499 MCQs CLASSIFICATION OF ELEMENTS AND PERIODICITY IN PROPERTIES 429 MCQs Equilibrium 412 MCQs STATES OF MATTER 410 MCQs
76 Easy
76 of 392
Remembering +4 | -1
Which method is used to separate sugars?
View answer and explanation
Correct option: C
Chromatography
The correct answer is Chromatography because it is a technique used to separate mixtures based on their different affinities for a stationary and mobile phase, making it suitable for separating sugars.
77 Medium
77 of 392
Analyzing +4 | -1
Which of the following compounds is isomeric with 2,2,42,2,4, 4- tetramethylhexane?
View answer and explanation
Correct option: B
4-isopropylheptane
Option B is correct because 4-isopropylheptane has the same number of carbon atoms as 2,2,4,4-tetramethylhexane (10 carbons), making them isomers.
78 Easy
78 of 392
Understanding +4 | -1
The family to which methoxyethene belongs, is :
View answer and explanation
Correct option: C
Unsaturated ether
Option C (Unsaturated ether) is correct because methoxyethene contains both an ether linkage (C-O-C) and a carbon-carbon double bond (unsaturation).
79 Easy
79 of 392
Understanding +4 | -1
Resonance effect involves
View answer and explanation
Correct option: D
all are correct
Option D (all are correct) is correct because resonance involves the delocalization of pi electrons, lone pairs, or negative charges along a conjugated system.
80 Medium
80 of 392
Analyzing +4 | -1
An organic compound (molar mass = 60) is found to containC= 20%,  H= 6.67% and N=  46.67%.C = {\text{ }}20\% ,\,\,H = {\text{ }}6.67\% {\text{ and}}\,N = \;46.67\% . While rest is oxygen. On heating it gives NH3N{H_3} along with a solid residue. The solid residue gives violet with alkaline CuSO4.CuS{O_4}. The organic compound is:
View answer and explanation
Correct option: C
NH2CONH2N{H_2}CON{H_2}
Option C (NH2CONH2N{H_2}CON{H_2}) is correct because the compound contains C, H, N, and O in the given percentages, releases ammonia upon heating, and the residue gives a violet color with alkaline CuSO4CuSO_4, indicating a peptide bond, which is consistent with urea.
81 Medium
81 of 392
Understanding +4 | -1
The compound which will not show geometrical isomerism is
View answer and explanation
Correct option: B
(Ph)2C=CHCH3{\left( {Ph} \right)_2}C = CHC{H_3}
Option B ((Ph)2C=CHCH3{( {Ph} )_2}C = CHC{H_3}) is correct because for geometrical isomerism to occur, each carbon of the double bond must have two different groups attached. In this case, one carbon has two identical phenyl groups.
82 Medium
82 of 392
Application +4 | -1
During hearing of a court case, the judge suspected that some changes in the documents had been carried out. He asked the forensic department to check the ink used at two different places. According to you which technique can give the best results?
View answer and explanation
Correct option: D
Thin layer chromatography
Option D (Thin layer chromatography) is correct because it is a suitable technique for comparing inks based on their different adsorption characteristics on a stationary phase.
83 Easy
83 of 392
Remembering +4 | -1
A carbonium ion contains :
View answer and explanation
Correct option: A
A + vely charged carbon centre
Option A (A + vely charged carbon centre) is correct because a carbonium ion is defined as a positively charged carbon species.
84 Easy
84 of 392
Remembering +4 | -1
Electrophiles are :
View answer and explanation
Correct option: A
Electron loving species
Option B (Short lived) is correct because free radicals are highly reactive due to the presence of an unpaired electron, making them short-lived.
85 Medium
85 of 392
Remembering +4 | -1
Dumas method involves the determination of nitrogen content in the organic compound in the form of
View answer and explanation
Correct option: B
N2{N_2}
The correct answer is N2{N_2} because in Dumas method, the nitrogen in the organic compound is converted to nitrogen gas (N2{N_2}), which is then measured to determine the nitrogen content.
86 Easy
86 of 392
Remembering +4 | -1
Qualitative test of halogens in an organic compound is made by
View answer and explanation
Correct option: B
Beilstein test
Option B (Beilstein test) is correct because the Beilstein test is a qualitative test used to detect the presence of halogens in organic compounds.
87 Easy
87 of 392
Remembering +4 | -1
The percentage ss-character in sp3s p^3-hybridisation is
View answer and explanation
Correct option: A
25% s25 \%\,s-character
Option A (25 % s-character) is correct because in sp3 hybridization, one s orbital mixes with three p orbitals, resulting in 25% s-character and 75% p-character.
88 Easy
88 of 392
Analyzing +4 | -1
Assertion (A): Carboxylic acid is more acidic than carbolic acid.

Reason (R): Conjugate base of carboxylic acid is more stable than conjugate base of carbolic acid.
View answer and explanation
Correct option: A
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Option A is correct because carboxylic acids are indeed more acidic than carbolic acids (phenols), and this is due to the greater stability of the carboxylate anion compared to the phenoxide ion.
89 Medium
89 of 392
Remembering +4 | -1
Reimer-Tiemann reaction involves a:
View answer and explanation
Correct option: B
Carbene intermediate
Option B is correct because the Reimer-Tiemann reaction involves the formation of dichlorocarbene as an intermediate, which then reacts with the phenol.
90 Easy
90 of 392
Application +4 | -1
Which of the following molecules represents the order of hybridization SP2,  SP2,  SP,   SPS{P^2},\,\,S{P^2},\,\,SP,\,\,\,SP from left to right atoms.
View answer and explanation
Correct option: B
CH2=CH−C≡CHC{H_2} = CH - C \equiv CH
Option B (CH2=CH−C≡CHCH_2 = CH - C \equiv CH) is correct because it correctly represents the hybridization order SP2,SP2,SP,SPSP^2, SP^2, SP, SP from left to right.
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