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NEET • CHEMISTRY • ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES

Organic chemistry-some basic principles and techniques practice · Mixed difficulty

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Showing 1-30 of 392 questions
1 Medium
1 of 392
Analyzing +4 | -1
The number of different substitution products possible when ethane is allowed to react with bromine is sunlight are :
View answer and explanation
Correct option: A
9
Option A is correct because there are 9 different substitution products possible when ethane reacts with bromine in sunlight. These include mono-, di-, tri-, tetra-, penta-, and hexabrominated products, with structural isomers for some.
2 Medium
2 of 392
Understanding +4 | -1
Correct order of stability is
View answer and explanation
Correct option: A
HC≡Cˉ>CH2=CˉH>CH3−CˉH2\mathrm{HC} \equiv \mathrm{\bar C} > C{\mathrm{H}_2} = \mathrm{\bar CH} > C{\mathrm{H}_3} - \mathrm{\bar C}{\mathrm{H}_2}
Option D (2 – Chloro heptan – 6 – ol) is correct because the hydroxyl group (-OH) has higher priority than the chloro group (-Cl) in IUPAC naming, so the carbon chain is numbered to give the -OH group the lowest possible number.
3 Medium
3 of 392
Analyzing +4 | -1
Assertion (A) A mixture of o-nitrophenol and p-nitrophenol can be separated by steam distillation.

Reason (R) pp-nitrophenol is steam volatile whereas onitrophenol is not steam volatile.
View answer and explanation
Correct option: C
If Assertion is true but Reason is false.
Option C (If Assertion is true but Reason is false) is correct because o-nitrophenol is steam volatile due to intramolecular hydrogen bonding, while p-nitrophenol is not due to intermolecular hydrogen bonding.
4 Medium
4 of 392
Application +4 | -1
An organic compound having carbon, hydrogen and sulphur contains 4% of sulphur. The minimum molecular weight of the compound is
View answer and explanation
Correct option: B
800
Option B (800) is correct because the minimum molecular weight is calculated by assuming one sulfur atom per molecule, so MW = (atomic weight of S / percentage of S) * 100.
5 Hard
5 of 392
Analyzing +4 | -1
Increasing order of acid strength is

a) Phenol \quad \quad b) 3-Nitrophenol

c) 3,5-dinitro phenol \quad 4) 2,4,6-trinitro phenol
View answer and explanation
Correct option: C
a < b < c < d
Option C (a < b < c < d) is correct because the acidity increases with the number of electron-withdrawing nitro groups attached to the phenol ring, which stabilize the phenoxide ion.
6 Medium
6 of 392
Understanding +4 | -1
Isobutyl chloride is :
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Correct option: B
(CH3)2CHCH2Cl{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{CHC}{\mathrm{H}_2}\mathrm{Cl}
Option B ((CH3)2CHCH2Cl{\left( {\mathrm{C}{\mathrm{H}_3}} \right)_2}\mathrm{CHC}{\mathrm{H}_2}\mathrm{Cl}) is correct because it represents a four-carbon chain with a methyl branch on the second carbon and chlorine on the first carbon.
7 Easy
7 of 392
Remembering +4 | -1
A neutral divalent carbon intermediate produced by the removal of two attached atoms is called :
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Correct option: D
Carbine
Option D is correct because a carbene is a neutral divalent carbon intermediate with two unshared electrons.
8 Easy
8 of 392
Application +4 | -1
IUPAC name of, CH3CH(OH)CH2CH2COOH\mathrm{C}{\mathrm{H}_3}\mathrm{CH}\left( {\mathrm{OH}} \right)\mathrm{C}{\mathrm{H}_2}\mathrm{C}{\mathrm{H}_2}\mathrm{COOH} is :
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Correct option: A
4-hydroxypentanoic acid
Option A (4-hydroxypentanoic acid) is correct because it correctly identifies the parent chain as pentanoic acid and the hydroxyl group as a substituent at the 4th position.
9 Easy
9 of 392
Understanding +4 | -1
Which of the following alkyl groups has the maximum +I+ I effect
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Correct option: B
(CH3)3C−{\left( {C{H_3}} \right)_3}C -
Option B ((CH3)3C−{\left( {C{H_3}} \right)_3}C -) is correct because the +I effect increases with the number of alkyl groups attached to the carbon, as alkyl groups are electron-donating.
10 Easy
10 of 392
Understanding +4 | -1
The best method for the separation of naphthalene and benzoic acid from their mixture is
View answer and explanation
Correct option: B
Crystallisation
The correct answer is Crystallisation because naphthalene and benzoic acid have different solubilities in various solvents, allowing for their separation through crystallization.
11 Medium
11 of 392
Understanding +4 | -1
All carbon atoms are sp2\mathrm{sp}^2 hybridised in
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Correct option: B
1, 3-butadiene
Option B (1,3-butadiene) is correct because all four carbon atoms in 1,3-butadiene are sp2sp^2 hybridized due to the presence of double bonds.
12 Easy
12 of 392
Analyzing +4 | -1
Only two isomeric mono chloro derivatives are possible for
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Correct option: D
2 – Methyl propane
Option D (2 – Methyl propane) is correct because it has only two types of non-equivalent hydrogens, leading to only two possible monochloro derivatives.
13 Hard
13 of 392
Analyzing +4 | -1
Which of the following resonance structure is least stable?
View answer and explanation
Correct option: B
CH2=CH−C + H−C−H−OCH3{\text{C}}{{\text{H}}_{\text{2}}} = {\text{CH}} - \mathop {\text{C}}\limits^{\text{ + }} {\text{H}} - \mathop {\text{C}}\limits^ - {\text{H}} - {\text{OC}}{{\text{H}}_{\text{3}}}
Option B (CH2=CH−C_+H−C_−H−OCH3{\text{C}}{{\text{H}}_{\text{2}}} = {\text{CH}} - \mathop {\text{C}}\_+ {\text{H}} - \mathop {\text{C}}\_- {\text{H}} - {\text{OC}}{{\text{H}}_{\text{3}}}) is correct because it has a positive charge on a carbon atom adjacent to a negatively charged carbon and the octet rule is violated for the carbon with the positive charge, making it less stable.
14 Medium
14 of 392
Remembering +4 | -1
Racemic compound has
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Correct option: A
Equimolar mixture of enantiomers
Option A (Equimolar mixture of enantiomers) is correct because a racemic compound is defined as an equimolar mixture of enantiomers.
15 Hard
15 of 392
Analyzing +4 | -1
An organic compound on heating with CuO produces CO2\mathrm{C}{\mathrm{O}_2} but no water. The organic compound may be
View answer and explanation
Correct option: A
Carbon tetrachloride
Option A (Carbon tetrachloride) is correct because it contains carbon but no hydrogen, so it can produce CO2 upon heating with CuO but no water.
16 Easy
16 of 392
Analyzing +4 | -1
Which one of the statements about HOH2CCH(OH)CHO\mathrm{H O H}_2 \mathrm{C C H}(\mathrm{OH}) \mathrm{CHO} is not correct? It
View answer and explanation
Correct option: B
Contains a tertiary alcoholic group
Option B is correct because the given compound, HOCH2-CCH(OH)-CHO, does not contain a tertiary alcoholic group. A tertiary alcohol is bonded to three other carbon atoms, which is not the case here.
17 Medium
17 of 392
Remembering +4 | -1
The correct decreasing order of priority for the functional groups of organic compounds in the IUPACIUPAC system of nomenclature is
View answer and explanation
Correct option: A
−COOH>−CONH2>−CN>−NC>−CHO>−NH2- COOH > - CON{H_2} > - CN > - NC > - CHO > - N{H_2}
Option A is correct because the correct decreasing order of priority for the functional groups of organic compounds in the IUPAC system of nomenclature is -COOH > -CONH₂ > -CN > -CHO > -NH₂.
18 Medium
18 of 392
Analyzing +4 | -1
Consider the following nucleophilic groups :

I. −O−SO2−C6H5\text{I. } -\mathrm{O}-\mathrm{SO}_2-\mathrm{C}_6 \mathrm{H}_5

II.  −O−CO∣∣−CH3{\text{II}}.\,\, - {\text{O}} - \mathop {\text{C}}\limits^{\begin{array}{cccccccccccccccccccc} {\text{O}} \\ {||} \end{array}} - {\text{C}}{{\text{H}}_3}

III. −Cl\text{III. }-{Cl}

IV. −OCH3\text{IV. }-\mathrm{OCH}_3

What is the correct order of leaving power of the above nucleophilic substitution reaction?
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Correct option: C
IV>III>II>I\text{IV}>\text{III}>\text{II}>\text{I}
Option D (I > II > III > IV) is incorrect. The correct order of leaving group ability is I > II > III > IV, based on the stability of the leaving group after departure.
19 Easy
19 of 392
Application +4 | -1
The IUPAC name of the compound having the formulaCH≡  C  −  CH=CH2\mathrm{CH} \equiv \mathrm{\;C\;}-\mathrm{\;CH} = \mathrm{C}{\mathrm{H}_2} is :
View answer and explanation
Correct option: A
1-butene-3-yne
Option A (1-butene-3-yne) is correct because it correctly identifies the longest chain, the positions of the double and triple bonds, and prioritizes the double bond for numbering.
20 Hard
20 of 392
Analyzing +4 | -1
How many structural isomers are possible for C6H14{C_6}{H_{14}}
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Correct option: A
5
Option A (5) is correct because there are 5 structural isomers possible for C6H14{C_6}{H_{14}}.
21 Easy
21 of 392
Understanding +4 | -1
Which of the following statement is wrong?
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Correct option: D
In the estimation of carbon, an organic compound is heated with CaO in a combustion tube
Option D is the wrong statement because in the estimation of carbon, an organic compound is heated with CuO (copper oxide) in a combustion tube, not CaO.
22 Medium
22 of 392
Analyzing +4 | -1
Among the following anions (a)  CˉH3  (b)  NˉH2,  (c)OH−,  (d)F−\left( a \right){\kern 1pt} {\kern 1pt} \;\mathrm{\bar C}{\mathrm{H}_3}\;{\kern 1pt} {\kern 1pt} {\kern 1pt} \left( b \right)\;{\kern 1pt} {\kern 1pt} \mathrm{\bar N}{\mathrm{H}_2},{\kern 1pt} {\kern 1pt} {\kern 1pt} \;\left( c \right){\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} \mathrm{O}{\mathrm{H}^ - },\;{\kern 1pt} {\kern 1pt} {\kern 1pt} \left( d \right){\kern 1pt} {\kern 1pt} {\kern 1pt} {\kern 1pt} {\mathrm{F}^ - } the order of basicity is :
View answer and explanation
Correct option: A
a>b>c>da > b > c > d
Option A (a>b>c>da > b > c > d) is correct because basicity decreases with increasing electronegativity and stability of the conjugate acid, with carbon being the least electronegative and fluorine the most.
23 Medium
23 of 392
Understanding +4 | -1
The number of sp3s{p^3}- hybrid carbons in 2-butyne is :
View answer and explanation
Correct option: C
2
Option C (2) is correct because 2-butyne (CH3-C≡C-CH3) has two sp3 hybridized carbon atoms (the methyl groups).
24 Medium
24 of 392
Analyzing +4 | -1
Which of the following compounds is not chiral?
View answer and explanation
Correct option: C
1-chloropentane
Option C (1-chloropentane) is not chiral because it does not have a chiral center (a carbon atom bonded to four different groups).
25 Medium
25 of 392
Analyzing +4 | -1
Which structure can be explained by taking ground state configuration of atom?
View answer and explanation
Correct option: D
H2O{\mathrm{H}_2}\mathrm{O}
Option D (H2O{\mathrm{H}_2}\mathrm{O}) is correct because the bonding in water can be explained by the ground state configuration of oxygen without invoking hybridization.
26 Medium
26 of 392
Understanding +4 | -1
During AgNO3\mathrm{AgN}{\mathrm{O}_3} test for detection of halogens, sodium extract is boiled with few drops of conc. HNO3\mathrm{HN}{\mathrm{O}_3} to decompose
View answer and explanation
Correct option: C
Both (a) and (b)
Option C (Both (a) and (b)) is correct because the sodium extract contains NaCN and Na2S, which can interfere with the silver halide precipitation in the AgNO3 test for halogens. HNO3 decomposes these interfering ions.
27 Easy
27 of 392
Understanding +4 | -1
Which of the following statements for carbanion is correct
View answer and explanation
Correct option: D
It is SP3S{P^3} hybridized
Option D (It is SP3S{P^3} hybridized) is correct because carbanions have three bonding pairs and one lone pair, resulting in a tetrahedral electronic geometry and SP3S{P^3} hybridization.
28 Hard
28 of 392
Application +4 | -1
Caffeine has a molecular weight of 194. If it contains 28.9%28.9 \% by mass of nitrogen, number of atoms of nitrogen in one molecule of caffeine is
View answer and explanation
Correct option: A
4
Option A (4) is correct because the number of nitrogen atoms is calculated from the percentage of nitrogen by mass and the molecular weight of caffeine.
29 Medium
29 of 392
Analyzing +4 | -1
The order of decreasing reactivity towards SE  {S_E}\;reaction for the given compound is:
(i) C6H6{\mathrm{C}_6}{\mathrm{H}_6}
(ii) C6H5CH3{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{C}{\mathrm{H}_3}
(iii) C6H5Cl{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{Cl}
(iv) C6H5OH{\mathrm{C}_6}{\mathrm{H}_5}\mathrm{OH}
View answer and explanation
Correct option: C
(iv) > (ii) > (i) > (iii)
Option C (iv) > (ii) > (i) > (iii) is correct because electron donating groups increase reactivity towards electrophilic substitution, while electron withdrawing groups decrease it.
30 Medium
30 of 392
Understanding +4 | -1
Diastereomers can be separated by :
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Correct option: A
Fractional distillation
Option A is correct because diastereomers have different physical properties, including boiling points, allowing separation by fractional distillation.
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Key Takeaways

  • ✓ This set contains 392 single-correct-answer MCQs on ORGANIC CHEMISTRY-SOME BASIC PRINCIPLES AND TECHNIQUES.
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