Hydrogen practice · Easy

Option B (Only one third of a second) is correct because atomic hydrogen is highly reactive and has a very short lifespan, typically around one-third of a second.

Option D (More in ${\mathrm{H}_2}\mathrm{O}$) is correct because ${\mathrm{H}_2}\mathrm{O}$ has a slightly higher dielectric constant and better solvating power for ionic compounds like $\mathrm{NaCl}$.

Option B (water gas) is correct because water gas is primarily used in Bosch's process for hydrogen production.

Option D is correct because water can act as both a proton donor (acid) and a proton acceptor (base), making it an amphoteric solvent.

Option D (All of these) is correct because hydrogen can be manufactured through Lane's process, Bosch process, and from natural gas.

Option B is correct because the structure of ${\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}}$ is non - planar.

Option D is correct because filtration only removes suspended particles, not dissolved hardness-causing ions.

Option A (143) is correct because the combustion of 1g of H2 releases approximately 143 kJ of energy.

Option C ($\mathrm{PbS} + {\mathrm{H}_2}{\mathrm{O}_2} \to$) is correct because the reaction produces lead sulfate ($PbSO_4$) and water, both of which are not gases.

Option C (High density and different physical properties than those of water) is correct because heavy water has a higher density and different physical properties compared to regular water due to the presence of deuterium.

Option D (10000 ppm) is correct because hardness is calculated as the mass of calcium carbonate per million parts of solution.

Option B ($\mathrm{6}\mathrm{.07}\,\,\mathrm{\% }$) is correct because a 20 volume ${\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}}$ solution has a percentage strength of approximately 6.07%.

Option A is correct because ordinary hydrogen primarily consists of hydrogen atoms (protium), with only trace amounts of deuterium and tritium.

Option A ($\mathrm{Pb}{\mathrm{O}_\mathrm{2}}\mathrm{ + }\,{\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}} \to \mathrm{PbO}\,\,\mathrm{ + }\,{\mathrm{H}_\mathrm{2}}\mathrm{O}\,\,\mathrm{ + }\,{\mathrm{O}_\mathrm{2}}$) is correct because in this reaction, $H_2O_2$ reduces $PbO_2$ to $PbO$ and itself gets oxidized to $O_2$, thus acting as a reducing agent.

Option D ($Ca$) is correct because Calcium reacts with di-hydrogen to produce hydrolith ($CaH_2$).

Option D ($\mathrm{K}_{2} \mathrm{S}_{2} \mathrm{O}_{8}$) is correct because deuterated hydrogen peroxide ($D_2O_2$) can be prepared by reacting potassium persulfate ($K_2S_2O_8$) with heavy water ($D_2O$).

Option C is correct because Perhydrol is both a 30% solution of ${\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}}$ and a 100 volume ${\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}}$.

Option C is correct because ${\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}}$ is always stored in black bottles because it undergoes auto oxidation on prolonged standing.