Hydrogen practice · Easy

Option C (1 electron, 1 proton, 2 neutrons) is correct because Tritium is an isotope of Hydrogen with one proton and two neutrons in its nucleus.

Option A (${F_2}$) is correct because Fluorine is the most reactive halogen and has the highest affinity for Hydrogen.

Option A (Chlorides and sulphates of $Mg$ and $Ca$) is correct because permanent hardness in water is caused by the presence of these salts.

Option D ($2 y-x$) is incorrect. The correct answer is C ($\frac{{x-2 y}}{{2}}$) because it follows from Hess's Law by manipulating the given equations.

Option A is correct because the formula for Calgon, a water softener, is indeed $\mathrm{N}{\mathrm{a}_\mathrm{2}}\left[ {\mathrm{N}{\mathrm{a}_\mathrm{4}}{{\left( {\mathrm{P}{\mathrm{O}_\mathrm{3}}} \right)}_\mathrm{6}}} \right]$.

Option B is correct because boiling converts bicarbonates to carbonates, which precipitate out, removing temporary hardness, and also removes dissolved gases.

Option B ($Pd$) is correct. Palladium (Pd) is well-known for its ability to absorb large volumes of hydrogen gas.

Option A (The ionisation energy of Hydrogen is too high for group of alkali metals, but too low of halogen group) is correct because the ionization energy of hydrogen lies between that of alkali metals and halogens, making its placement difficult.

Option A (s – block elements) is correct because ionic hydrides are formed by the highly electropositive s-block elements.

Option A ($1:1$) is correct because the same amount of Zinc will produce the same number of moles of hydrogen regardless of whether it reacts with sulfuric acid or sodium hydroxide.

The correct answer is C (it gives precipitate with soap) because hard water contains calcium and magnesium ions that react with soap to form scum, preventing the soap from lathering properly.

Option A is correct because in this reaction, ${H_2}{O_2}$ is oxidized to ${O_2}$, indicating it is acting as a reducing agent.

The concentration of a '10 volume' H2O2 solution is 3% because 1 volume of H2O2 gives 10 volumes of oxygen at STP.

Option A (Tritium) is correct because Tritium is the only radioactive isotope of hydrogen.

Option B (heavy water) is correct because heavy water (D2O) is commonly used as a moderator in nuclear reactors to slow down neutrons.

Option B (Hydrated silicate of aluminium and sodium) is correct because Permutit is a hydrated sodium aluminum silicate used for ion exchange.

Option A is correct because Glycerol does not speed up the decomposition of ${\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}}$. In fact, it acts as a stabilizer.

Option A ($\mathrm{Liq}\mathrm{.}{\mathrm{H}_2} + \mathrm{Liq}\mathrm{.}{\mathrm{O}_2}$) is correct because liquid hydrogen and liquid oxygen are commonly used as rocket propellants due to their high energy density and clean combustion.

Option B ($5.336\mathrm{ }\;N$) is correct because the normality of 30 volume ${\mathrm{H}_2}{\mathrm{O}_2}$ is calculated to be approximately 5.336 N.

Option C is correct because when ${\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}}$ is added to acidified potassium dichromate, a blue color is produced due to the formation of $\mathrm{Cr}{\mathrm{O}_\mathrm{5}}$.

Option C (An oxide of deuterium) is correct because heavy water is deuterium oxide ($D_2O$), where deuterium is a heavier isotope of hydrogen.

Option B (5.6 V) is correct because the volume strength of 1N ${H_2}{O_2}$ is 5.6 V, which is derived from the molar volume of oxygen at STP and the stoichiometry of the decomposition reaction.

Option A is correct because industrially, ${\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}}$ is obtained from 2 – Ethyl anthraquinol.

Option C (${Pbs}+4 {H}_2 {O}_2 \rightarrow {PbSO}_4+4 {H}_2 {O}$) is correct because ${H}_2 {O}_2$ oxidizes $PbS$ to ${PbSO}_4$, thus acting as an oxidizing agent.

Option A (Hydrated sodium aluminium silicate) is correct because Permutit is a synthetic zeolite, which is a hydrated sodium aluminum silicate.

Option D (They are covalent in nature) is correct because saline hydrides are ionic, not covalent, in nature.

Option A is correct because magnesium bicarbonate decomposes upon boiling to form magnesium hydroxide, which precipitates out.

Option C (${111.5^0}$) is correct because the dihedral angle in gaseous H2O2 is approximately 111.5 degrees.

Option C (Metallic hydride) is correct because $\mathrm{Ti}{\mathrm{H}_{1.73}}$ is a non-stoichiometric hydride formed by transition metals, which are metallic hydrides.

Option A ($10,\mathrm{ }10,\mathrm{ }10$) is correct because a molecule of heavy water ($D_2O$) contains 2 deuterium atoms (2 protons + 2 neutrons each) and 1 oxygen atom (8 protons + 8 neutrons + 8 electrons). Therefore, the total number of protons is 2+2+8=10, electrons is 8+2=10 and neutrons is 2+2+6=10.