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NEET • CHEMISTRY • HYDROGEN

Hydrogen practice · Easy

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Showing 1-30 of 78 questions
1 Easy
1 of 78
Understanding +4 | -1
Hydrogen accepts an electron to form inert gas configuration. In this it resembles
View answer and explanation
Correct option: A
halogens
Option A (halogens) is correct because hydrogen needs one electron to achieve an inert gas configuration, similar to halogens.
2 Easy
2 of 78
Application +4 | -1
CaC2+H2O⟶Ca(OH)2+′X ′\mathrm{CaC}_2+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Ca}(\mathrm{OH})_2+' \mathrm{X}\,'

Mg2C3+H2O⟶Mg(OH)2+′Y ′\mathrm{Mg}_2 \mathrm{C}_3+\mathrm{H}_2 \mathrm{O} \longrightarrow \mathrm{Mg}(\mathrm{OH})_2+'\mathrm{Y}\,'

The products ' X\mathrm{X} ' and ' Y\mathrm{Y} ' respectively are
View answer and explanation
Correct option: B
C2H2\mathrm{C}_2 \mathrm{H}_2 and C3H4\mathrm{C}_3 \mathrm{H}_4
Option B (C2H2\mathrm{C}_2 \mathrm{H}_2 and C3H4\mathrm{C}_3 \mathrm{H}_4) is correct because the hydrolysis of CaC2\mathrm{CaC}_2 produces acetylene (C2H2\mathrm{C}_2 \mathrm{H}_2) and the hydrolysis of Mg2C3\mathrm{Mg}_2 \mathrm{C}_3 produces propyne (C3H4\mathrm{C}_3 \mathrm{H}_4).
3 Easy
3 of 78
Understanding +4 | -1
H2O2→2H++O2+2e−;E0=−0.68V{H_2}{O_2} \to 2{H^ + } + {O_2} + 2{e^ - };{E^0} = - 0.68V
This equation represents which of the following behaviour of H2O2{\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}}
View answer and explanation
Correct option: A
reducing
Option A is correct because the equation H2O2→2H++O2+2e−;E0=−0.68V{H_2}{O_2} \to 2{H^ + } + {O_2} + 2{e^ - };{E^0} = - 0.68V represents the reducing behavior of H2O2{\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}}, as it is losing electrons.
4 Easy
4 of 78
Analyzing +4 | -1
Which reaction shows oxidizing nature of H2O2{\mathrm{H}_2}{\mathrm{O}_2}?
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Correct option: A
H2O2+2KI→2KOH+I2{\mathrm{H}_2}{\mathrm{O}_2} + 2\mathrm{KI} \to 2\mathrm{KOH} + {\mathrm{I}_2}
Option A (H2O2+2KI→2KOH+I2{\mathrm{H}_2}{\mathrm{O}_2} + 2\mathrm{KI} \to 2\mathrm{KOH} + {\mathrm{I}_2}) is correct because H2O2H_2O_2 oxidizes KIKI to I2I_2, indicating its oxidizing nature.
5 Easy
5 of 78
Understanding +4 | -1
Which of the following could act as propellent for rockets.
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Correct option: A
Liq. H2+Liq.O2{H_2} + Liq.{O_2}
Option A (Liq. H2+Liq.O2{H_2} + Liq.{O_2}) is correct because liquid hydrogen and liquid oxygen are a common and highly energetic propellant combination for rockets.
6 Easy
6 of 78
Remembering +4 | -1
Triple point of water is
View answer and explanation
Correct option: C
273 K
Option C is correct because the triple point of water is defined as the temperature and pressure at which water can exist in equilibrium in the solid, liquid, and gaseous phases, which is approximately 273.16 K (0.01 °C).
7 Easy
7 of 78
Understanding +4 | -1
Hard water when passed through ion exchange resin containing R−COOHR - COOH group, becomes free atom
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Correct option: D
Ca+2C{a^{ + 2}}
Option D is correct because the ion exchange resin replaces the calcium ions with hydrogen ions, thus removing calcium.
8 Easy
8 of 78
Remembering +4 | -1
High boiling point of water is due to:
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Correct option: B
Hydrogen bonding
Option B is correct because the high boiling point of water is primarily due to the presence of strong hydrogen bonds between water molecules.
9 Easy
9 of 78
Understanding +4 | -1
Ortho Hydrogen and para Hydrogen resemble in which of the following property
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Correct option: C
chemical properties
Option C (chemical properties) is correct because ortho and para hydrogen are allotropes that differ in nuclear spin but have the same chemical properties.
10 Easy
10 of 78
Understanding +4 | -1
Which of the following pair of ions makes the water hard
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Correct option: B
Ca2+,HCO3−C{a^{2 + }},HCO_3^ -
Option B is correct because calcium and bicarbonate ions are the primary contributors to water hardness, especially temporary hardness.
11 Easy
11 of 78
Remembering +4 | -1
Permanent hardness can be removed by adding
View answer and explanation
Correct option: B
Na2CO3\mathrm{N}{\mathrm{a}_2}\mathrm{C}{\mathrm{O}_3}
Option B (Na2CO3\mathrm{N}{\mathrm{a}_2}\mathrm{C}{\mathrm{O}_3}) is correct because sodium carbonate (washing soda) is used to precipitate out the calcium and magnesium ions that cause permanent hardness.
12 Easy
12 of 78
Application +4 | -1
The amount of H2O2{\mathrm{H}_2}{\mathrm{O}_2} present in  1 L  of 1.5  N  H2O21.5\;N\;{\mathrm{H}_2}{\mathrm{O}_2} solution is:
View answer and explanation
Correct option: B
25.5  g25.5\;\mathrm{g}
The amount of H2O2 present in 1 L of 1.5 N H2O2 solution is 25.5 g because normality is used to calculate the mass of H2O2.
13 Easy
13 of 78
Remembering +4 | -1
Calgon used as water softner is
View answer and explanation
Correct option: A
Na2[Na4(PO3)6]\mathrm{N}{\mathrm{a}_2}\left[ {\mathrm{N}{\mathrm{a}_4}{{\left( {\mathrm{P}{\mathrm{O}_3}} \right)}_6}} \right]
Option A (Na2[Na4(PO3)6]\mathrm{N}{\mathrm{a}_2}[ {\mathrm{N}{\mathrm{a}_4}{{\left( {\mathrm{P}{\mathrm{O}_3}} \right)}_6}} ]) is correct because it is the correct chemical formula for Calgon.
14 Easy
14 of 78
Understanding +4 | -1
Blackened oil painting can be restored into original form by the action of
View answer and explanation
Correct option: B
H2O2{H_2}{O_2}
Option B (H2O2{H_2}{O_2}) is correct because hydrogen peroxide acts as a bleaching agent and oxidizes the blackened lead sulfide to lead sulfate, restoring the original color.
15 Easy
15 of 78
Analyzing +4 | -1
Which of the following cannot be oxidized by H2O2\mathrm{H}_2 \mathrm{O}_2 ?
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Correct option: B
O3\mathrm{O}_3
Option B (O3\mathrm{O}_3) is correct because ozone cannot be further oxidized by H2O2\mathrm{H}_2\mathrm{O}_2.
16 Easy
16 of 78
Understanding +4 | -1
The property of hydrogen which distinguishes it from alkali metals is
View answer and explanation
Correct option: D
Its metallic character
Option D (Its metallic character) is correct because hydrogen lacks metallic character, unlike alkali metals.
17 Easy
17 of 78
Remembering +4 | -1
Ordinary hydrogen is a mixture at:
View answer and explanation
Correct option: A
75%  ortho  H2+25%  para  H275\mathrm{\% }\;\mathrm{ ortho}\;{\mathrm{H}_2} + 25\mathrm{\% }\;\mathrm{para}\;{\mathrm{H}_2}
Ordinary hydrogen is a mixture of 75% ortho hydrogen and 25% para hydrogen at room temperature because this is the statistically favored distribution.
18 Easy
18 of 78
Understanding +4 | -1
The percentage of para hydrogen in ordinary hydrogen increases when:
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Correct option: A
Temperature is lowered
Option A (Temperature is lowered) is correct because the equilibrium shifts towards para hydrogen at lower temperatures.
19 Easy
19 of 78
Understanding +4 | -1
Which is true statement about D2O  and H2O{D_2}O\,\,\mathrm{and}\,{H_2}O
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Correct option: A
D2O{D_2}O has lower dielectric constant than H2O{H_2}O
Option A (D2O{D_2}O has lower dielectric constant than H2O{H_2}O) is correct because D2O{D_2}O has a slightly lower dielectric constant due to its larger mass and lower vibrational frequencies.
20 Easy
20 of 78
Understanding +4 | -1
Temporary hardness may be removed from water by adding
View answer and explanation
Correct option: B
Ca(OH)2Ca{\left( {OH} \right)_2}
Option B is correct because adding calcium hydroxide (slaked lime) precipitates calcium carbonate, removing temporary hardness.
21 Easy
21 of 78
Remembering +4 | -1
Heavy water is represented as
View answer and explanation
Correct option: B
D2O{\mathrm{D}_2}\mathrm{O}
Option C (syn gas) is correct because synthesis gas (syn gas) is a mixture of carbon monoxide and hydrogen, which is used in the production of methanol.
22 Easy
22 of 78
Understanding +4 | -1
Saline hydrides react explosively with water, such fires can be extinguished by
View answer and explanation
Correct option: C
Sand
Option C (Sand) is correct because sand can smother the fire and prevent it from spreading, while water and carbon dioxide can react with the hydride.
23 Easy
23 of 78
Application +4 | -1
The best method to test whether a clear liquid is water, is to:
View answer and explanation
Correct option: D
Add few drops on anhydrous copper sulphate and look for colour change
Option D (Add few drops on anhydrous copper sulphate and look for colour change) is correct because anhydrous copper sulphate turns blue in the presence of water.
24 Easy
24 of 78
Remembering +4 | -1
H2O2{\mathrm{H}_\mathrm{2}}{\mathrm{O}_\mathrm{2}} is used as
View answer and explanation
Correct option: D
All
Option D (All) is correct because H2O2 is used as an antiseptic, bleaching agent, and propellant.
25 Easy
25 of 78
Remembering +4 | -1
Heavy water freezes at:
View answer and explanation
Correct option: B
3.8∘C3.8\mathrm{ }^\circ C
Heavy water freezes at 3.8 °C because the deuterium isotope causes stronger intermolecular forces compared to ordinary water.
26 Easy
26 of 78
Understanding +4 | -1
In one of these compounds does hydrogen have an oxidation state of −1- 1
View answer and explanation
Correct option: D
CaH2Ca{H_2}
Option D (CaH2Ca{H_2}) is correct because in CaH2Ca{H_2}, Calcium is +2 and Hydrogen is -1.
27 Easy
27 of 78
Understanding +4 | -1
Para and ortho H2{\mathrm{H}_2} differ in
View answer and explanation
Correct option: C
spin of protons
Option C (spin of protons) is correct because para and ortho H2{\mathrm{H}_2} differ in the relative spins of their protons (anti-parallel vs. parallel).
28 Easy
28 of 78
Remembering +4 | -1
Hydrogen was discovered by:
View answer and explanation
Correct option: C
Cavendish
Option C is correct because Henry Cavendish is credited with the discovery of hydrogen as a distinct element.
29 Easy
29 of 78
Understanding +4 | -1
What is formed when calcium carbide react with heavy water?
View answer and explanation
Correct option: A
C2D2{\mathrm{C}_2}{\mathrm{D}_2}
Option A (C2D2{\mathrm{C}_2}{\mathrm{D}_2}) is correct because calcium carbide reacts with heavy water to produce deuterated acetylene (C2D2{\mathrm{C}_2}{\mathrm{D}_2}).
30 Easy
30 of 78
Understanding +4 | -1
Which of the following is correct about heavy water?
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Correct option: C
It is formed by the combination of heavier isotope of hydrogen and oxygen
Option C (It is formed by the combination of heavier isotope of hydrogen and oxygen) is correct because heavy water (D2OD_2O) is formed by deuterium, the heavier isotope of hydrogen, and oxygen.
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